The pressure P, volume V and temperature T of a gas in the jar A and other gas in the jar B at Pressure 2P, volume V/4 and temperature 2T, then the ratio of number of molecules in jar A and B will be.
Select one:
V = nRT (n = number of moles)
(N = Number of molecules, N_{A} = Avogadro number)
∴
The correct answer is: 4 : 1
The equation of state corresponding to 8gm of O_{2} is.
Select one:
As 32gm O_{2} means 1 mole of O_{2} molecule, therefore 8gm of O_{2} means 1/4 mole i.e., n = 1/4
∴ pV = nRT
⇒ pV = 1/4 RT
The correct answer is:
The expansion of an ideal gas of mass m at a constant pressure P is given by the straight line D. Then the expansion of the same ideal gas of mass 2m at a pressure P/2 is given by the straight line.
Select one:
From PV α MT
or
Here (M/P) epresents the slope of curve drawn on volume and temperature axis.
For the first condition, slope (M/P) graph is D. (given)
For second condition,
Slope i.e., slope becomes four times so graph A is correct
for this condition.
The correct answer is:
A
At room temp. (300K), the rms speed of the molecules of certain diatomic gas is found to be 1930 m/s. The gas is
Select one:
⇒
⇒ gas is hydrogen.
The correct answer is: H_{2}
rms speed of gas molecule gas is v. If the pressure of the gas is doubled, what is the new rms speed?
Select one:
rms speed of gas, molecules does not depend on the pressure of gas (if temperature remains constant) because (boyle’s law).
If pressure is increased n times then density will also increase by n times butrms speed remains constant.
The correct answer is: v
At top of a mountain, a thermometer reads 7°C and a barometer reads 70cm, of Hg. At the bottom of the mountain, these read 27°C and 76cm of Hg respectively.
Comparison of density of air at the top with that of bottom is.
Select one:
Ideal gas equation, in terms of density is
⇒
⇒
The correct answer is: 75/76
An experiment is carried on a fixed amount of gas at different temperature at high pressure such that it deviates from the ideal gas behavior. The variation of with p is shown in the diagram. The correct variation will correspond to.
Select one:
At lower pressure, we can assume that given gas behaves as ideal gas so but when pressure increase, the decrease in volume will not take place in same proportion so PV/RT will increase.
The correct answer is: Curve B
Two containers of equal volume contain the same gas at pressure p_{1} and p_{2} and absolute temperature T_{1} and T_{2} respectively. On joining the vessels, the gas reaches a common pressure p and common temperature T. The ratio P/T is equal
to.
Select one:
Number of moles in first vessel
and number of moles in 2nd vessel
If both vessels are joined together, then quantity of gas remains same i.e.
The correct answer is:
The temperature of a gas is raised while its volume remains constant, the pressure exerted by a gas on the walls of the container increases because its molecules.
Select one:
Due to increase in temperature, root mean square velocity of gas molecule increases. So they strike the wall more often with higher velocity. Hence, the pressure exerted by a gas on the walls of the container increases.
The correct answer is: strike the wall more often with higher velocities
The conversion of ideal gas into solids is.
Select one:
Because there is zero attraction between the molecules of ideal gas.
The correct answer is: Impossible







