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Find link is a tool written by Edward Betts.searching for K-1 500 found (14413 total)
alternate case: k-1
Standard deviation
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k − 1 + k − 1 k ( x k − A k − 1 ) 2 = Q k − 1 + ( x k − A k − 1 ) ( x k − A k ) {\displaystyle {\begin{aligned}Q_{0}&=0\\Q_{k}&=Q_{k-1}+{\frac {k-1Fibonacci sequence (13,044 words) [view diff] no match in snippet view article find links to article
k = 1 ∞ q k 1 − q k , {\displaystyle \textstyle L(q):=\sum _{k=1}^{\infty }{\frac {q^{k}}{1-q^{k}}},} since 1 F 2 k = 5 ( ψ 2 k 1 − ψ 2 k − ψ 4 k 1 −Poisson distribution (11,203 words) [view diff] no match in snippet view article find links to article
distribution is Pr ( X 1 = k 1 , X 2 = k 2 ) = exp ( − λ 1 − λ 2 − λ 3 ) λ 1 k 1 k 1 ! λ 2 k 2 k 2 ! ∑ k = 0 min ( k 1 , k 2 ) ( k 1 k ) ( k 2 k ) k ! ( λBinomial distribution (7,554 words) [view diff] no match in snippet view article find links to article
calculating f ( k + 1 , n , p ) f ( k , n , p ) = ( n − k ) p ( k + 1 ) ( 1 − p ) {\displaystyle {\frac {f(k+1,n,p)}{f(k,n,p)}}={\frac {(n-k)p}{(k+1)(1-p)}}}P-adic number (7,711 words) [view diff] no match in snippet view article find links to article
i p i = a k p k + a k + 1 p k + 1 + a k + 2 p k + 2 + ⋯ {\displaystyle s=\sum _{i=k}^{\infty }a_{i}p^{i}=a_{k}p^{k}+a_{k+1}p^{k+1}+a_{k+2}p^{k+2}+\cdotsKalman filter (20,932 words) [view diff] no match in snippet view article find links to article
k − 1 ] T Y k − 1 ∣ k − 1 F k − 1 C k = M k [ M k + Q k − 1 ] − 1 L k = I − C k Y k ∣ k − 1 = L k M k + C k Q k − 1 C k T y ^ k ∣ k − 1 = L k [ F k −Binomial coefficient (10,733 words) [view diff] exact match in snippet view article find links to article
× ⋯ × ( n − k + 1 ) k × ( k − 1 ) × ⋯ × 1 , {\displaystyle {\binom {n}{k}}={\frac {n\times (n-1)\times \cdots \times (n-k+1)}{k\times (k-1)\times \cdotsPermutation (11,667 words) [view diff] exact match in snippet view article find links to article
λ k − 1 ( p k − 1 k ) λ k − 1 ( p k − 2 k ) λ k − 1 ⋯ λ k − 1 ( p 1 k ) λ k − 1 {\displaystyle \lambda _{k}=\lambda _{k-1}(p_{k-1}k)\lambda _{k-1}(p_{k-2}k)\lambdaMichaelis–Menten kinetics (6,227 words) [view diff] no match in snippet view article find links to article
K_{\mathrm {m} }} is equal to k + 2 / k + 1 {\displaystyle k_{+2}/k_{+1}} or to k − 1 / k + 1 {\displaystyle k_{-1}/k_{+1}} or to something else. G. E. BriggsList of trigonometric identities (12,421 words) [view diff] exact match in snippet view article find links to article
identity can be proved: ∏ k = 1 n sin ( 2 k − 1 ) π 4 n = ∏ k = 1 n cos ( 2 k − 1 ) π 4 n = 2 2 n {\displaystyle \prod _{k=1}^{n}\sin {\frac {\left(2k-1\right)\piLogistic regression (20,641 words) [view diff] no match in snippet view article find links to article
case of a perfect prediction (i.e., when p k = 1 {\displaystyle p_{k}=1} and y k = 1 {\displaystyle y_{k}=1} , or p k = 0 {\displaystyle p_{k}=0} and yBinomial theorem (6,735 words) [view diff] exact match in snippet view article find links to article
( n − k + 1 ) k ( k − 1 ) ( k − 2 ) ⋯ 2 ⋅ 1 . {\displaystyle {\binom {n}{k}}={\frac {n!}{k!\,(n-k)!}}={\frac {n(n-1)(n-2)\cdots (n-k+1)}{k(k-1)(k-2)\cdotsSpecific heat capacity (8,537 words) [view diff] no match in snippet view article find links to article
among common substances, about 4184 J⋅kg−1⋅K−1 at 20 °C; but that of ice, just below 0 °C, is only 2093 J⋅kg−1⋅K−1. The specific heat capacities of iron,Boltzmann constant (2,946 words) [view diff] no match in snippet view article find links to article
constants defining the International System of Units, the SI, with k = 1.380649×10−23 J K−1. The Boltzmann constant is a proportionality constant between theGas constant (1,997 words) [view diff] no match in snippet view article find links to article
{\displaystyle R=N_{\rm {A}}k} = 6.02214076×1023 mol−1 × 1.380649×10−23 J⋅K−1 = 8.31446261815324 J⋅K−1⋅mol−1 Since the 2019 revision of the SI, both NA and k are definedNACA airfoil (2,605 words) [view diff] no match in snippet view article find links to article
0.3 - the value of r {\displaystyle r} , k 1 {\displaystyle k_{1}} and k 2 / k 1 {\displaystyle k_{2}/k_{1}} must be linearly scaled for a differentNatural logarithm (5,882 words) [view diff] exact match in snippet view article find links to article
( 1 + x ) = ∑ k = 1 ∞ ( − 1 ) k − 1 k x k = x − x 2 2 + x 3 3 − ⋯ , {\displaystyle \ln(1+x)=\sum _{k=1}^{\infty }{\frac {(-1)^{k-1}}{k}}x^{k}=x-{\fracMathematical induction (6,914 words) [view diff] no match in snippet view article find links to article
+k)+(k+1)={\frac {k(k+1)}{2}}+(k+1).} Algebraically, the right hand side simplifies as: k ( k + 1 ) 2 + ( k + 1 ) = k ( k + 1 ) + 2 ( k + 1 ) 2 = ( k + 1 )Moment of inertia (17,301 words) [view diff] no match in snippet view article find links to article
∑ k = 1 N m k ( y k 2 + z k 2 ) − ∑ k = 1 N m k x k y k − ∑ k = 1 N m k x k z k − ∑ k = 1 N m k x k y k ∑ k = 1 N m k ( x k 2 + z k 2 ) − ∑ k = 1 N mTaylor's theorem (9,632 words) [view diff] no match in snippet view article find links to article
| x − a | k + 1 ( k + 1 ) ! ≤ M r k + 1 ( k + 1 ) ! {\displaystyle |R_{k}(x)|\leq M{\frac {|x-a|^{k+1}}{(k+1)!}}\leq M{\frac {r^{k+1}}{(k+1)!}}} for allFinite element method (7,946 words) [view diff] no match in snippet view article find links to article
e., v k ( x ) = { x − x k − 1 x k − x k − 1 if x ∈ [ x k − 1 , x k ] , x k + 1 − x x k + 1 − x k if x ∈ [ x k , x k + 1 ] , 0 otherwise , {\displaystyleEnzyme kinetics (9,539 words) [view diff] no match in snippet view article find links to article
M S = ( k − 1 + k 2 ) / k 1 {\displaystyle K_{M}^{S}=(k_{-1}+k_{2})/k_{1}} and K M P = ( k − 1 + k 2 ) / k − 2 {\displaystyle K_{M}^{P}=(k_{-1}+k_{2})/k_{-2}}Taylor series (8,229 words) [view diff] no match in snippet view article find links to article
α n ) = ∏ k = 1 n α − k + 1 k = α ( α − 1 ) ⋯ ( α − n + 1 ) n ! . {\displaystyle {\binom {\alpha }{n}}=\prod _{k=1}^{n}{\frac {\alpha -k+1}{k}}={\fracGamma function (13,526 words) [view diff] no match in snippet view article find links to article
x 2 ) x − 1 ∏ k = 1 n k + 1 k + x {\displaystyle x!=\lim _{n\to \infty }\left(n+1+{\frac {x}{2}}\right)^{x-1}\prod _{k=1}^{n}{\frac {k+1}{k+x}}} whichWeibull distribution (5,823 words) [view diff] exact match in snippet view article find links to article
k − 1 e − ( x / λ ) k , x ≥ 0 , 0 , x < 0 , {\displaystyle f(x;\lambda ,k)={\begin{cases}{\frac {k}{\lambda }}\left({\frac {x}{\lambda }}\right)^{k-1}e^{-(x/\lambdaGeometric distribution (5,151 words) [view diff] exact match in snippet view article find links to article
trial is the first success is Pr ( X = k ) = ( 1 − p ) k − 1 p {\displaystyle \Pr(X=k)=(1-p)^{k-1}p} for k = 1 , 2 , 3 , 4 , … {\displaystyle k=1,2,3Euler's totient function (6,519 words) [view diff] exact match in snippet view article find links to article
and k ≥ 1, then φ ( p k ) = p k − p k − 1 = p k − 1 ( p − 1 ) = p k ( 1 − 1 p ) . {\displaystyle \varphi \left(p^{k}\right)=p^{k}-p^{k-1}=p^{k-1Triangular number (3,543 words) [view diff] no match in snippet view article find links to article
k = 1 n k = 1 + 2 + ⋯ + n = n 2 + n ( n + 1 ) 2 = n ( n + 1 ) 2 = ( n + 1 2 ) {\displaystyle \displaystyle {\begin{aligned}T_{n}&=\sum _{k=1}^{n}k=1+2+\dotsbPascal's triangle (7,606 words) [view diff] no match in snippet view article find links to article
∑ k = 1 n + 1 a k − 1 x k + ∑ k = 0 n a k x k = ∑ k = 1 n a k − 1 x k + a n x n + 1 + a 0 x 0 + ∑ k = 1 n a k x k = a 0 x 0 + ∑ k = 1 n ( a k − 1 + aEigenvalues and eigenvectors (13,582 words) [view diff] exact match in snippet view article find links to article
d t k + a k − 1 d k − 1 x d t k − 1 + ⋯ + a 1 d x d t + a 0 x = 0. {\displaystyle {\frac {d^{k}x}{dt^{k}}}+a_{k-1}{\frac {d^{k-1}x}{dt^{k-1}}}+\cdotsAcid (5,957 words) [view diff] no match in snippet view article find links to article
[ H + ] 2 + [ H + ] K 1 + K 1 K 2 = [ H 2 A ] [ H 2 A ] + [ H A − ] + [ A 2 − ] α HA − = [ H + ] K 1 [ H + ] 2 + [ H + ] K 1 + K 1 K 2 = [ HA − ] [ H 2Quantization (signal processing) (6,359 words) [view diff] no match in snippet view article
values of { b k } k = 1 M − 1 {\displaystyle \{b_{k}\}_{k=1}^{M-1}} , { c k } k = 1 M {\displaystyle \{c_{k}\}_{k=1}^{M}} and { y k } k = 1 M {\displaystyleSummation (4,576 words) [view diff] no match in snippet view article find links to article
{\displaystyle p>1} ∑ k = 1 n k p = n p + 1 p + 1 + 1 2 n p + ∑ k = 2 p ( p k ) B k p − k + 1 n p − k + 1 , {\displaystyle \sum _{k=1}^{n}k^{p}={\fracNegative binomial distribution (8,217 words) [view diff] no match in snippet view article find links to article
binomial": ( k + r − 1 ) ⋯ ( r ) k ! = ( − 1 ) k ( − r ) ( − r − 1 ) ( − r − 2 ) ⋯ ( − r − k + 1 ) ⏞ k factors k ! = ( − 1 ) k ( − r − k ) . {\displaystyleGini coefficient (10,898 words) [view diff] exact match in snippet view article find links to article
trapezoids and: G 1 = 1 − ∑ k = 1 n ( X k − X k − 1 ) ( Y k + Y k − 1 ) {\displaystyle G_{1}=1-\sum _{k=1}^{n}(X_{k}-X_{k-1})(Y_{k}+Y_{k-1})} is the resultingBernoulli distribution (2,196 words) [view diff] no match in snippet view article find links to article
) = p k ( 1 − p ) 1 − k for k ∈ { 0 , 1 } {\displaystyle f(k;p)=p^{k}(1-p)^{1-k}\quad {\text{for }}k\in \{0,1\}} or as f ( k ; p ) = p k + ( 1 − p )Quadrilateral (6,989 words) [view diff] no match in snippet view article find links to article
q: K = 1 2 ( m + n + p ) ( m + n − p ) ( m + n + q ) ( m + n − q ) , {\displaystyle K={\tfrac {1}{2}}{\sqrt {(m+n+p)(m+n-p)(m+n+q)(m+n-q)}},} K = 1 2 pCombination (3,806 words) [view diff] exact match in snippet view article find links to article
n k ) = n ( n − 1 ) ⋯ ( n − k + 1 ) k ( k − 1 ) ⋯ 1 , {\displaystyle {\binom {n}{k}}={\frac {n(n-1)\dotsb (n-k+1)}{k(k-1)\dotsb 1}},} which can be writtenFeynman diagram (15,967 words) [view diff] no match in snippet view article find links to article
k 1 ) ϕ ( k 2 ) ϕ ( k 3 ) ϕ ( k 4 ) ⟩ = δ ( k 1 − k 2 ) k 1 2 δ ( k 3 − k 4 ) k 3 2 + δ ( k 1 − k 3 ) k 3 2 δ ( k 2 − k 4 ) k 2 2 + δ ( k 1 − k 4 ) kSimplex (7,866 words) [view diff] case mismatch in snippet view article find links to article
k-dimensional polytope that is the convex hull of its k + 1 vertices. More formally, suppose the k + 1 points u 0 , … , u k {\displaystyle u_{0},\dots ,u_{k}}Perturbation theory (quantum mechanics) (15,990 words) [view diff] no match in snippet view article
k 1 n E n k 1 | k 1 ( 0 ) ⟩ | n ( 2 ) ⟩ = ( V k 1 k 2 V k 2 n E n k 1 E n k 2 − V n n V k 1 n E n k 1 2 ) | k 1 ( 0 ) ⟩ − 1 2 V n k 1 V k 1 n E k 1 nRunge–Kutta methods (7,392 words) [view diff] no match in snippet view article find links to article
_{i=1}^{s}b_{i}k_{i},} where k 1 = f ( t n , y n ) , k 2 = f ( t n + c 2 h , y n + ( a 21 k 1 ) h ) , k 3 = f ( t n + c 3 h , y n + ( a 31 k 1 + a 32 k 2 ) h )Euler's constant (9,582 words) [view diff] no match in snippet view article find links to article
n + ∑ k = 1 n 1 k ) = ∫ 1 ∞ ( − 1 x + 1 ⌊ x ⌋ ) d x . {\displaystyle {\begin{aligned}\gamma &=\lim _{n\to \infty }\left(-\log n+\sum _{k=1}^{n}{\fracDirichlet distribution (6,666 words) [view diff] exact match in snippet view article find links to article
_{i}-1}} where { x k } k = 1 k = K {\displaystyle \{x_{k}\}_{k=1}^{k=K}} belong to the standard K − 1 {\displaystyle K-1} simplex, or in other words:Lagrangian mechanics (14,691 words) [view diff] no match in snippet view article find links to article
− V , {\displaystyle L=T-V,} where T = 1 2 ∑ k = 1 N m k v k 2 {\displaystyle T={\frac {1}{2}}\sum _{k=1}^{N}m_{k}v_{k}^{2}} is the total kinetic energyRiemann zeta function (10,428 words) [view diff] no match in snippet view article find links to article
k 1 > k 2 > ⋯ > k n > 0 k 1 − s 1 k 2 − s 2 ⋯ k n − s n . {\displaystyle \zeta (s_{1},s_{2},\ldots ,s_{n})=\sum _{k_{1}>k_{2}>\cdots >k_{n}>0}{k_{1Bernoulli number (13,028 words) [view diff] no match in snippet view article find links to article
0 n ( n k ) 2 n − k + 1 n − k + 1 B k ( 1 ) = 2 n {\displaystyle -1+\sum _{k=0}^{n}{\binom {n}{k}}{\frac {2^{n-k+1}}{n-k+1}}B_{k}(1)=2^{n}} and − 1 +Lisa Carrington (1,930 words) [view diff] no match in snippet view article find links to article
and one bronze medal. She won three consecutive gold medals in the Women's K‑1 200 metres at the 2012 Summer Olympics, 2016 Summer Olympics and 2020 SummerDiscrete cosine transform (11,983 words) [view diff] no match in snippet view article find links to article
around k = − 1 / 2 {\displaystyle k=-1/2} and even around k = N − 1 / 2. {\displaystyle k=N-1/2.} X k = ∑ n = 0 N − 1 x n cos [ π N ( n + 1 2 ) ( k + 1 2Transcendental number (6,764 words) [view diff] no match in snippet view article find links to article
sufficient to prove that k + 1 {\displaystyle k+1} does not divide P {\displaystyle P} . To that end, let k + 1 {\displaystyle k+1} be any prime larger thanRate equation (7,576 words) [view diff] no match in snippet view article find links to article
0 1 k 1 + k − 1 ( k − 1 + k 1 e − ( k 1 + k − 1 ) t ) + [ P ] 0 k − 1 k 1 + k − 1 ( 1 − e − ( k 1 + k − 1 ) t ) [ P ] = [ A ] 0 k 1 k 1 + k − 1 ( 1 −Central limit theorem (9,169 words) [view diff] exact match in snippet view article find links to article
∑ k = 1 n E [ ( M k − M k − 1 ) 2 ∣ M 1 , … , M k − 1 ] → 1 {\displaystyle {\frac {1}{n}}\sum _{k=1}^{n}\operatorname {E} \left[\left(M_{k}-M_{k-1}\right)^{2}\midReal number (8,223 words) [view diff] exact match in snippet view article find links to article
infinite series x = b k 10 k + b k − 1 10 k − 1 + ⋯ + b 0 + a 1 10 + a 2 10 2 + ⋯ . {\displaystyle x=b_{k}10^{k}+b_{k-1}10^{k-1}+\cdots +b_{0}+{\frac {a_{1}}{10}}+{\fracSequence (6,158 words) [view diff] exact match in snippet view article find links to article
a_{k}=k^{2}} ( a 2 k − 1 ) k = 1 ∞ , a k = k 2 {\displaystyle {(a_{2k-1})}_{k=1}^{\infty },\qquad a_{k}=k^{2}} ( a k ) k = 1 ∞ , a k = ( 2 k − 1 ) 2 {\displaystyleInteger (3,935 words) [view diff] no match in snippet view article find links to article
= ⋯ = [ ( k , k ) ] 1 = [ ( 1 , 0 ) ] = [ ( 2 , 1 ) ] = ⋯ = [ ( k + 1 , k ) ] − 1 = [ ( 0 , 1 ) ] = [ ( 1 , 2 ) ] = ⋯ = [ ( k , k + 1 ) ] 2 = [ ( 2Chi-squared distribution (6,811 words) [view diff] no match in snippet view article find links to article
{\displaystyle k} with a width k 1 / 2 + α {\displaystyle k^{1/2+\alpha }} : P r ( ‖ Z ‖ 2 ∈ [ k − 2 k 1 / 2 + α , k + 2 k 1 / 2 + α + 2 k α ] ) ≥ 1 − eAdam van Koeverden (1,539 words) [view diff] exact match in snippet view article find links to article
is an Olympic gold medallist in the K-1 500m category (2004) and a two-time world champion in K-1 500 (2007) and K-1 1000 (2011), winning four Olympic andReed–Solomon error correction (12,677 words) [view diff] no match in snippet view article find links to article
k + 1 … g 1 , n 0 1 0 … 0 g 2 , k + 1 … g 2 , n 0 0 1 … 0 g 3 , k + 1 … g 3 , n ⋮ ⋮ ⋮ ⋮ ⋮ ⋮ 0 … 0 … 1 g k , k + 1 … g k , n ] [ m 0 m 1 ⋮ m k − 1 ]List of Olympic medalists in canoeing (men) (16 words) [view diff] no match in snippet view article
This is the complete list of men's Olympic medalists in canoeing. International Olympic Committee results databaseMoving average (3,168 words) [view diff] no match in snippet view article find links to article
k = p n − k + 1 + p n − k + 2 + ⋯ + p n k = 1 k ∑ i = n − k + 1 n p i {\displaystyle {\begin{aligned}{\textit {SMA}}_{k}&={\frac {p_{n-k+1}+p_{n-k+2}+\cdotsLogarithm (11,635 words) [view diff] no match in snippet view article find links to article
1 + 1 2 + 1 3 + ⋯ + 1 n = ∑ k = 1 n 1 k , {\displaystyle 1+{\frac {1}{2}}+{\frac {1}{3}}+\cdots +{\frac {1}{n}}=\sum _{k=1}^{n}{\frac {1}{k}},} is calledRussian roulette (2,825 words) [view diff] no match in snippet view article find links to article
{\displaystyle k} is 1 n − k ⋅ ∏ i = 0 k − 1 n − i − 1 n − i = n − 1 n ⋅ n − 2 n − 1 ⋅ . . . ⋅ n − k n − k − 1 ⋅ 1 n − k = 1 6 ≈ 16.7 % {\displaystyle {\tfracICF Canoe Sprint World Championships (734 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200 metres (660 ft), 500Dissociation constant (3,119 words) [view diff] no match in snippet view article find links to article
K 1 ′ = [ L ] [ M ] [ L M ] [ LM ] = [ L ] [ M ] K 1 ′ [ L ] + [ LM ] ↽ − − ⇀ [ L 2 M ] K 2 ′ = [ L ] [ LM ] [ L 2 M ] [ L 2 M ] = [ L ] 2 [ M ] K 1 ′Birthday problem (7,114 words) [view diff] no match in snippet view article find links to article
p ¯ ( n ) = ∏ k = 1 n − 1 ( 1 − k 365 ) < ∏ k = 1 n − 1 ( e − k 365 ) = e − n ( n − 1 ) 730 . {\displaystyle {\bar {p}}(n)=\prod _{k=1}^{n-1}\left(1-{\fracLehmer mean (837 words) [view diff] no match in snippet view article find links to article
as: L p ( x ) = ∑ k = 1 n x k p ∑ k = 1 n x k p − 1 . {\displaystyle L_{p}(\mathbf {x} )={\frac {\sum _{k=1}^{n}x_{k}^{p}}{\sum _{k=1}^{n}x_{k}^{p-1}}}Standard molar entropy (788 words) [view diff] no match in snippet view article find links to article
= ∑ k = 1 N Δ S k = ∑ k = 1 N d Q k T → ∫ 0 T 2 d S d T d T = ∫ 0 T 2 C p k T d T {\displaystyle S^{\circ }=\sum _{k=1}^{N}\Delta S_{k}=\sum _{k=1}^{N}{\fracPartial autocorrelation function (1,129 words) [view diff] exact match in snippet view article find links to article
k − 1 + ⋯ + β k − 1 z t + 1 and z ^ t = β 1 z t + 1 + ⋯ + β k − 1 z t + k − 1 . {\displaystyle {\hat {z}}_{t+k}=\beta _{1}z_{t+k-1}+\cdots +\beta _{k-1}z_{t+1}\qquadTrapezoidal rule (3,483 words) [view diff] exact match in snippet view article find links to article
(that is, Δ x k = x k − x k − 1 {\displaystyle \Delta x_{k}=x_{k}-x_{k-1}} ), then ∫ a b f ( x ) d x ≈ ∑ k = 1 N f ( x k − 1 ) + f ( x k ) 2 Δ x k . {\displaystyleExterior algebra (12,098 words) [view diff] exact match in snippet view article find links to article
k − 1 {\displaystyle k-1} elements of V ∗ {\displaystyle V^{*}} , then define ( ι α w ) ( u 1 , u 2 , … , u k − 1 ) = w ( α , u 1 , u 2 , … , u k −Chaos theory (13,440 words) [view diff] no match in snippet view article find links to article
non-linear differential equations of the second order, I: The equation y" + k(1−y2)y' + y = bλkcos(λt + a), k large". Journal of the London MathematicalPhase-shift keying (6,226 words) [view diff] exact match in snippet view article find links to article
number: r k r k − 1 ∗ = E s e j ( φ k − φ k − 1 ) + E s e j φ k n k − 1 ∗ + E s e − j φ k − 1 n k + n k n k − 1 ∗ {\displaystyle r_{k}r_{k-1}^{*}=E_{s}e^{j\left(\varphiErlang distribution (1,969 words) [view diff] no match in snippet view article find links to article
of time until the occurrence of a fixed number of events. When k = 1 {\displaystyle k=1} , the distribution simplifies to the exponential distributionExterior derivative (3,307 words) [view diff] no match in snippet view article find links to article
can be thought of as measuring the net flux through the boundary of a (k + 1)-parallelotope at each point. The exterior derivative of a differentialEntropy (14,024 words) [view diff] no match in snippet view article find links to article
temperature, which has a unit of joules per kelvin (J⋅K−1) in the International System of Units (or kg⋅m2⋅s−2⋅K−1 in terms of base units). The entropy of a substanceVariance (10,207 words) [view diff] no match in snippet view article find links to article
∑ k = 1 n Y k ] = 1 n ∑ i = 1 n ( E [ Y i 2 ] − 2 n ( ∑ j ≠ i E [ Y i Y j ] + E [ Y i 2 ] ) + 1 n 2 ∑ j = 1 n ∑ k ≠ j n E [ Y j Y k ] + 1 n 2Floor and ceiling functions (5,879 words) [view diff] no match in snippet view article find links to article
integer k is ⌊ log b k ⌋ + 1 = ⌈ log b ( k + 1 ) ⌉ . {\displaystyle \lfloor \log _{b}{k}\rfloor +1=\lceil \log _{b}{(k+1)}\rceil .} The number ofOrder statistic (4,933 words) [view diff] exact match in snippet view article find links to article
U ( k ) ( u ) = n ! ( k − 1 ) ! ( n − k ) ! u k − 1 ( 1 − u ) n − k {\displaystyle f_{U_{(k)}}(u)={n! \over (k-1)!(n-k)!}u^{k-1}(1-u)^{n-k}} that is,Sobolev space (6,658 words) [view diff] exact match in snippet view article find links to article
it is enough to assume that the ( k − 1 ) {\displaystyle (k{-}1)} -th derivative f ( k − 1 ) {\displaystyle f^{(k-1)}} is differentiable almost everywhereExponential family (11,203 words) [view diff] exact match in snippet view article find links to article
{\displaystyle \sum _{i=1}^{k}p_{i}=1\,.} Thus, there are only k − 1 {\displaystyle k-1} independent parameters. Variant 1 uses k {\displaystyle k} naturalThermal conductivity and resistivity (8,365 words) [view diff] no match in snippet view article find links to article
{\displaystyle \lambda } , or κ {\displaystyle \kappa } and is measured in W·m−1·K−1. Heat transfer occurs at a lower rate in materials of low thermal conductivityGenerating function (14,464 words) [view diff] no match in snippet view article find links to article
, 1 k 1 , 1 0 0 ⋯ k 0 , 2 k 1 , 2 k 2 , 2 0 ⋯ k 0 , 3 k 1 , 3 k 2 , 3 k 3 , 3 ⋯ ⋮ ⋮ ⋮ ⋮ ] = [ k 0 , 0 0 0 0 ⋯ k 0 , 1 k 1 , 1 0 0 ⋯ k 0 , 2 k 1 , 2 kEuclidean algorithm (15,336 words) [view diff] exact match in snippet view article find links to article
m k = q k m k − 1 + m k − 2 n k = q k n k − 1 + n k − 2 , {\displaystyle {\begin{aligned}m_{k}&=q_{k}m_{k-1}+m_{k-2}\\n_{k}&=q_{k}n_{k-1}+n_{k-2},\end{aligned}}}Galois group (3,232 words) [view diff] no match in snippet view article find links to article
G_{2}.} The field K 1 K 2 {\displaystyle K_{1}K_{2}} with Galois group G = Gal ( K 1 K 2 / k ) {\displaystyle G=\operatorname {Gal} (K_{1}K_{2}/k)} hasSmoothness (3,923 words) [view diff] exact match in snippet view article find links to article
at least in the class C k − 1 {\displaystyle C^{k-1}} since f ′ , f ″ , … , f ( k − 1 ) {\displaystyle f',f'',\dots ,f^{(k-1)}} are continuous on U .Proportional–integral–derivative controller (12,059 words) [view diff] no match in snippet view article find links to article
u ( t k ) − u ( t k − 1 ) Δ t = K p e ( t k ) − e ( t k − 1 ) Δ t + K i e ( t k ) + K d e ( t k ) − e ( t k − 1 ) Δ t − e ( t k − 1 ) − e ( t k − 2 )Recurrence relation (4,166 words) [view diff] exact match in snippet view article find links to article
uni-dimensional recurrence: ( n k ) = ( n k − 1 ) ( n − k + 1 ) / k , {\displaystyle {\binom {n}{k}}={\binom {n}{k-1}}(n-k+1)/k,} with the initial value ( n 0Finite difference (5,863 words) [view diff] exact match in snippet view article find links to article
k − 1 ∑ i 2 = 0 k − 1 ⋯ ∑ i n = 0 k − 1 Δ h n ( f , x + i 1 h + i 2 h + ⋯ + i n h ) . {\displaystyle \Delta _{kh}^{n}(f,x)=\sum \limits _{i_{1}=0}^{k-1}\sumCompetitive inhibition (2,864 words) [view diff] no match in snippet view article find links to article
rearranging to k 1 [ E ] [ S ] = ( k − 1 + k 2 ) [ ES ] {\displaystyle k_{1}[{\ce {E}}][{\ce {S}}]=(k_{-1}+k_{2})[{\ce {ES}}]} Dividing by k 1 [ S ] {\displaystyleInvertible matrix (6,996 words) [view diff] exact match in snippet view article find links to article
A k − 1 A k ) − 1 = A k − 1 A k − 1 − 1 ⋯ A 2 − 1 A 1 − 1 . {\displaystyle (\mathbf {A} _{1}\mathbf {A} _{2}\cdots \mathbf {A} _{k-1}\mathbf {A} _{k})^{-1}=\mathbfEuclidean algorithm (15,336 words) [view diff] exact match in snippet view article find links to article
m k = q k m k − 1 + m k − 2 n k = q k n k − 1 + n k − 2 , {\displaystyle {\begin{aligned}m_{k}&=q_{k}m_{k-1}+m_{k-2}\\n_{k}&=q_{k}n_{k-1}+n_{k-2},\end{aligned}}}Gram–Schmidt process (4,423 words) [view diff] no match in snippet view article find links to article
( k − 1 ) = u k ( k − 2 ) − proj u k − 1 ( u k ( k − 2 ) ) , e k = u k ( k − 1 ) ‖ u k ( k − 1 ) ‖ {\displaystyle {\begin{aligned}\mathbf {u} _{k}^{(1)}&=\mathbfMin-max theorem (4,542 words) [view diff] exact match in snippet view article find links to article
to pick a ( i k − 1 − ( i 1 − 1 ) ) {\textstyle (i_{k-1}-(i_{1}-1))} -dimensional subspace W k − 1 ′ ⊂ W k ∩ V i k − 1 {\textstyle W_{k-1}'\subset W_{k}\capMoment (mathematics) (3,066 words) [view diff] no match in snippet view article
X 1 k 1 ⋯ X n k n ] {\displaystyle E[{X_{1}}^{k_{1}}\cdots {X_{n}}^{k_{n}}]} is called a mixed moment of order k {\displaystyle k} (where k = k 1 + .Galois group (3,232 words) [view diff] no match in snippet view article find links to article
G_{2}.} The field K 1 K 2 {\displaystyle K_{1}K_{2}} with Galois group G = Gal ( K 1 K 2 / k ) {\displaystyle G=\operatorname {Gal} (K_{1}K_{2}/k)} hasKronecker delta (3,740 words) [view diff] exact match in snippet view article find links to article
_{p-1}}-\sum _{k=1}^{p-1}\delta _{\nu _{k}}^{\mu _{p}}\delta _{\nu _{1}\dots \nu _{k-1}\,\nu _{p}\,\nu _{k+1}\dots \nu _{p-1}}^{\mu _{1}\dots \mu _{k-1}\,\mu _{k}\List of Olympic medalists in canoeing (women) (16 words) [view diff] no match in snippet view article
This is the complete list of women's Olympic medalists in kayaking. International Olympic Committee results databaseExtrapolation (1,869 words) [view diff] exact match in snippet view article find links to article
= y k − 1 + x ∗ − x k − 1 x k − x k − 1 ( y k − y k − 1 ) . {\displaystyle y(x_{*})=y_{k-1}+{\frac {x_{*}-x_{k-1}}{x_{k}-x_{k-1}}}(y_{k}-y_{k-1}).} (whichCanoeing at the 2016 Summer Olympics (685 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 200 m men C-1 1000 m men C-2 1000 m men K-1 200 m men women K-1 500 m women K-1 1000 m men K-2 200 m menError function (7,304 words) [view diff] exact match in snippet view article find links to article
) k − 1 π H k − 1 ( z ) e − z 2 = 2 π d k − 1 d z k − 1 ( e − z 2 ) , k = 1 , 2 , … {\displaystyle \operatorname {erf} ^{(k)}z={\frac {2(-1)^{k-1}}{\sqrtCanoeing at the 2020 Summer Olympics (435 words) [view diff] exact match in snippet view article find links to article
C-1 men women K-1 men women Sprint C-1 200 m women C-1 1000 m men C-2 500 m women C-2 1000 m men K-1 200 m men women K-1 500 m women K-1 1000 m men K-2Arithmetic progression (2,297 words) [view diff] no match in snippet view article find links to article
n , k ) = 1 2 ( k − 1 ) ( n 2 − ( k − 1 ) n + ( k − 2 ) + ϕ ( n + 1 , k − 1 ) ) = 1 2 ( k − 1 ) ( ( n − 1 ) ( n − ( k − 2 ) ) + ϕ ( n + 1 , k − 1 ) )Probability density function (4,940 words) [view diff] no match in snippet view article find links to article
for y is ∑ k = 1 n ( y ) | d d y g k − 1 ( y ) | ⋅ f X ( g k − 1 ( y ) ) , {\displaystyle \sum _{k=1}^{n(y)}\left|{\frac {d}{dy}}g_{k}^{-1}(y)\right|\cdotSoftmax function (5,286 words) [view diff] no match in snippet view article find links to article
{\displaystyle \sigma \colon \mathbb {R} ^{K}\to (0,1)^{K}} , where K > 1 {\displaystyle K>1} , takes a vector z = ( z 1 , … , z K ) ∈ R K {\displaystyle \mathbfPrincipal component analysis (14,450 words) [view diff] no match in snippet view article find links to article
of the normalization constraints: α k ′ α k = 1 , k = 1 , … , p {\displaystyle \alpha _{k}'\alpha _{k}=1,k=1,\dots ,p} . As noted above, the results ofKosambi–Karhunen–Loève theorem (10,711 words) [view diff] no match in snippet view article find links to article
∑ k = 1 N p k ≥ ∑ k = 1 N q k {\displaystyle \sum _{k=1}^{N}p_{k}\geq \sum _{k=1}^{N}q_{k}} This implies that: − ∑ k = 1 ∞ p k log ( p k ) ≤ − ∑ k =Hypergeometric distribution (4,115 words) [view diff] no match in snippet view article find links to article
hypergeometric distribution: Pr ( X 1 = k 1 , … , X c = k c ) = ∏ i = 1 c ( K i k i ) ( N n ) {\displaystyle \Pr(X_{1}=k_{1},\ldots ,X_{c}=k_{c})={\frac {\prodElliptic integral (7,832 words) [view diff] no match in snippet view article find links to article
}})={\tfrac {1}{2}}\pi } For example: 4 3 K ( 1 3 ) E ( 1 2 ) + 3 2 E ( 1 3 ) K ( 1 2 ) − 2 K ( 1 3 ) K ( 1 2 ) = 1 2 π {\displaystyle {\tfrac {4}{3}}K({\color1000 (number) (24,094 words) [view diff] no match in snippet view article
k = 1 46 σ ( k ) {\displaystyle \sum _{k=1}^{46}\sigma (k)} 1759 = de Polignac prime 1760 = the number of yards in a mile 1761 = k such that k, k+1 andMax Hoff (canoeist) (198 words) [view diff] exact match in snippet view article
Championships with five golds (K-1 1000 m: 2009, 2010, 2013; K-1 5000 m: 2011 and K-4 1000 m: 2011 ) and three silvers (K-1 5000 m: 2010, 2014, 2015). AtQuaternion (12,634 words) [view diff] no match in snippet view article find links to article
quaternions, i 2 = j 2 = k 2 = i j k = − 1 {\displaystyle \mathbf {i} ^{2}=\mathbf {j} ^{2}=\mathbf {k} ^{2}=\mathbf {i\,j\,k} =-1} into the stone of BroughamLagrange polynomial (3,973 words) [view diff] no match in snippet view article find links to article
F^{(k+1)}(\xi )} : F ( k + 1 ) ( ξ ) = f ( k + 1 ) ( ξ ) − L ( k + 1 ) ( ξ ) − R ~ ( k + 1 ) ( ξ ) {\displaystyle F^{(k+1)}(\xi )=f^{(k+1)}(\xi )-L^{(k+1)}(\xiEuler–Maclaurin formula (3,779 words) [view diff] exact match in snippet view article find links to article
∑ k = 1 p B k k ! ( f ( k − 1 ) ( n ) − f ( k − 1 ) ( m ) ) + R p , {\displaystyle S-I=\sum _{k=1}^{p}{{\frac {B_{k}}{k!}}\left(f^{(k-1)}(n)-f^{(k-1)}(m)\right)}+R_{p}Canoeing at the Summer Olympics (333 words) [view diff] exact match in snippet view article find links to article
200 m events with one of them being K-1 200 m for the women. The other events for men at 200 m will be C-1, K-1, and K-2. This was confirmed at theirIdeal gas law (4,622 words) [view diff] no match in snippet view article find links to article
−273.15 °C, the lowest possible temperature). R has for value 8.314 J/(mol·K) = 1.989 ≈ 2 cal/(mol·K), or 0.0821 L⋅atm/(mol⋅K). How much gas is present couldHandley Page Victor (9,400 words) [view diff] no match in snippet view article find links to article
tanker (renamed K.1 after bombing capability removed), 11 converted. Victor BK.1A 3-point in-flight refuelling tanker (renamed K.1A as for K.1), 14 convertedRatio test (5,987 words) [view diff] no match in snippet view article find links to article
a subsequence ( a n k ) k = 1 ∞ {\displaystyle \left(a_{n_{k}}\right)_{k=1}^{\infty }} satisfying lim sup n → ∞ | a n k + 1 a n k | ≤ ℓ < r {\displaystyleOzone (18,196 words) [view diff] no match in snippet view article find links to article
intermediate can be determined as follows: K 1 = K 1 K − 1 = [ O 2 ] ⋅ [ O ] [ O 3 ] {\displaystyle K_{1}={\frac {K_{1}}{K_{-1}}}={\frac {[{\ce {O2}}]\cdot [{\ceHölder's inequality (7,917 words) [view diff] no match in snippet view article find links to article
functions for k = 1 , . . . , m {\displaystyle k=1,...,m} . Then ‖ ∏ k = 1 m f k ‖ 1 ≥ ∏ k = 1 m ‖ f k ‖ p k . {\displaystyle \left\|\prod _{k=1}^{m}f_{k}\right\|_{1}\geq2015 ICF Canoe Sprint World Championships (642 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200 metres (660 ft), 500Approximations of π (12,280 words) [view diff] no match in snippet view article find links to article
{2}}} and y k + 1 = ( 1 − f ( y k ) ) / ( 1 + f ( y k ) ) , a k + 1 = a k ( 1 + y k + 1 ) 4 − 2 2 k + 3 y k + 1 ( 1 + y k + 1 + y k + 1 2 ) {\displaystyleHarmonic series (mathematics) (6,219 words) [view diff] no match in snippet view article
{1}{k(k+1)}}=\sum _{k=1}^{\infty }\sum _{n=1}^{k}{\frac {1}{k(k+1)}}} = ∑ k = 1 ∞ k k ( k + 1 ) = ∑ k = 1 ∞ 1 k + 1 = S − 1 {\displaystyle =\sum _{k=1}^{\inftyLogistic function (8,029 words) [view diff] no match in snippet view article find links to article
standard logistic function, depicted at right, where L = 1 , k = 1 , x 0 = 0 {\displaystyle L=1,k=1,x_{0}=0} , has the equation f ( x ) = 1 1 + e − x {\displaystyleList of ICF Canoe Sprint World Championships medalists in men's kayak (269 words) [view diff] no match in snippet view article find links to article
This is a list of medalists from the ICF Canoe Sprint World Championships in men's kayak. Debuted: 1994. Debuted: 1948. Debuted: 1938. Not held: 1948.Discrete Fourier transform (12,311 words) [view diff] no match in snippet view article find links to article
case above: X k 1 , k 2 , … , k d = X N 1 − k 1 , N 2 − k 2 , … , N d − k d ∗ , {\displaystyle X_{k_{1},k_{2},\dots ,k_{d}}=X_{N_{1}-k_{1},N_{2}-k_{2}Paul MacDonald (canoeist) (352 words) [view diff] exact match in snippet view article
1988; K-4 1000 m: 1984), one silver (K-2 1000 m: 1988), and one bronze (K-1 500 m: 1988). His five Olympic medals is the record for the second most OlympicCanoeing at the 2012 Summer Olympics (574 words) [view diff] exact match in snippet view article find links to article
by a 200m race; in addition, the men's C-2 500m was replaced by a women's K-1 200m sprint. This was confirmed at an International Canoe Federation boardDifferential form (10,058 words) [view diff] case mismatch in snippet view article find links to article
differential forms that, given a k-form φ {\displaystyle \varphi } , produces a (k+1)-form d φ . {\displaystyle d\varphi .} This operation extends the differentialConjugate gradient method (7,493 words) [view diff] no match in snippet view article find links to article
_{k}} is rewritten as r k + 1 T A p k = 1 α k r k + 1 T ( r k − r k + 1 ) = − 1 α k r k + 1 T r k + 1 {\displaystyle \mathbf {r} _{k+1}^{\mathsf {T}}\mathbfNewton's method in optimization (1,857 words) [view diff] no match in snippet view article find links to article
obtains the iterative scheme x k + 1 = x k − [ f ″ ( x k ) ] − 1 f ′ ( x k ) , k ≥ 0. {\displaystyle x_{k+1}=x_{k}-[f''(x_{k})]^{-1}f'(x_{k}),\qquad k\geq 0Molar heat capacity (5,707 words) [view diff] no match in snippet view article find links to article
mass. The SI unit of molar heat capacity is joule per kelvin per mole, J⋅K−1⋅mol−1. Like the specific heat, the measured molar heat capacity of a substanceEuler numbers (2,049 words) [view diff] no match in snippet view article find links to article
}{q}}(2q-\ell )^{2n},} E 2 n = ∑ k = 1 2 n ( − 1 ) k 1 2 k ∑ ℓ = 0 2 k ( − 1 ) ℓ ( 2 k ℓ ) ( k − ℓ ) 2 n . {\displaystyle E_{2n}=\sum _{k=1}^{2n}(-1)^{k}{\frac {1}{2^{k}}}\sumBinomial series (1,904 words) [view diff] no match in snippet view article find links to article
) ( α − 2 ) ⋯ ( α − k + 1 ) k ! . {\displaystyle {\binom {\alpha }{k}}:={\frac {\alpha (\alpha -1)(\alpha -2)\cdots (\alpha -k+1)}{k!}}.} Note that ifMaximum likelihood estimation (9,703 words) [view diff] no match in snippet view article find links to article
functions: f n ( y ; θ ) = ∏ k = 1 n f k u n i v a r ( y k ; θ ) . {\displaystyle f_{n}(\mathbf {y} ;\theta )=\prod _{k=1}^{n}\,f_{k}^{\mathsf {univar}}(y_{k};\thetaChi distribution (1,726 words) [view diff] exact match in snippet view article find links to article
( x ; k ) = { x k − 1 e − x 2 / 2 2 k / 2 − 1 Γ ( k 2 ) , x ≥ 0 ; 0 , otherwise . {\displaystyle f(x;k)={\begin{cases}{\dfrac {x^{k-1}e^{-x^{2}/2}}{2^{k/2-1}\GammaEuler numbers (2,049 words) [view diff] no match in snippet view article find links to article
}{q}}(2q-\ell )^{2n},} E 2 n = ∑ k = 1 2 n ( − 1 ) k 1 2 k ∑ ℓ = 0 2 k ( − 1 ) ℓ ( 2 k ℓ ) ( k − ℓ ) 2 n . {\displaystyle E_{2n}=\sum _{k=1}^{2n}(-1)^{k}{\frac {1}{2^{k}}}\sumAnalytic continuation (3,886 words) [view diff] no match in snippet view article find links to article
π ∑ n = k ∞ ( − 1 ) n ( n k ) ( a − 1 ) n − k ∫ 0 2 π d θ = ∑ n = k ∞ ( − 1 ) n ( n k ) ( a − 1 ) n − k = ( − 1 ) k ∑ m = 0 ∞ ( m + k k ) ( 1 − a ) mICF Canoe Marathon World Championships (371 words) [view diff] no match in snippet view article find links to article
ICF Canoe Marathon World Championships is an International Canoe Federation competition in canoe marathon in which athletes compete over long distancesLogarithmic distribution (377 words) [view diff] no match in snippet view article find links to article
the identity ∑ k = 1 ∞ − 1 ln ( 1 − p ) p k k = 1. {\displaystyle \sum _{k=1}^{\infty }{\frac {-1}{\ln(1-p)}}\;{\frac {p^{k}}{k}}=1.} This leads directlyBinomial series (1,904 words) [view diff] no match in snippet view article find links to article
) ( α − 2 ) ⋯ ( α − k + 1 ) k ! . {\displaystyle {\binom {\alpha }{k}}:={\frac {\alpha (\alpha -1)(\alpha -2)\cdots (\alpha -k+1)}{k!}}.} Note that ifStirling's approximation (4,758 words) [view diff] no match in snippet view article find links to article
) + 1 2 ln n = n ln n − n + 1 + ∑ k = 2 m ( − 1 ) k B k k ( k − 1 ) ( 1 n k − 1 − 1 ) + R m , n , {\displaystyle {\begin{aligned}\ln(n!)-{\tfracStirling numbers of the first kind (7,262 words) [view diff] no match in snippet view article find links to article
1 ) z Γ ( z + 1 ) ( k − 1 ) ! ∑ r = 1 k − 1 s ( k − 1 , r ) ∑ m = 0 r ( r m ) ( k − 2 ) r − m ζ ( z + 1 − m ) , ℜ ( z ) > k − 1 , k = 3 , 4 , 5 , … {\displaystyleChi distribution (1,726 words) [view diff] exact match in snippet view article find links to article
( x ; k ) = { x k − 1 e − x 2 / 2 2 k / 2 − 1 Γ ( k 2 ) , x ≥ 0 ; 0 , otherwise . {\displaystyle f(x;k)={\begin{cases}{\dfrac {x^{k-1}e^{-x^{2}/2}}{2^{k/2-1}\GammaExact sequence (2,577 words) [view diff] exact match in snippet view article find links to article
A k + 1 {\displaystyle A_{k+1}} and morphism A k → A k + 1 {\displaystyle A_{k}\to A_{k+1}} such that A k − 1 → A k → A k + 1 {\displaystyle A_{k-1}\toRademacher distribution (1,065 words) [view diff] no match in snippet view article find links to article
( k ) = { 1 / 2 if k = − 1 , 1 / 2 if k = + 1 , 0 otherwise. {\displaystyle f(k)=\left\{{\begin{matrix}1/2&{\text{if }}k=-1,\\1/2&{\text{if }}k=+1,\\0&{\text{otherwiseMultiset (4,955 words) [view diff] exact match in snippet view article find links to article
+ k − 1 k ) = ( n + k − 1 ) ! k ! ( n − 1 ) ! = n ( n + 1 ) ( n + 2 ) ⋯ ( n + k − 1 ) k ! , {\displaystyle \left(\!\!{n \choose k}\!\!\right)={n+k-1 \chooseAlan Thompson (canoeist) (528 words) [view diff] exact match in snippet view article
silvers (K-1 1000 m and K-2 500 m: both 1982), and a bronze (K-1 1000 m: 1983). He won both of his Olympic gold medals at Los Angeles in 1984, in the K-1 10002017 ICF Canoe Sprint World Championships (567 words) [view diff] exact match in snippet view article find links to article
Women's C–2 500 m results Women's K-1 200 m results Women's K-1 500 m results Women's K-1 1000 m results Women's K-1 5000 m results Women's K-2 200 m resultsOscillation (3,045 words) [view diff] no match in snippet view article find links to article
1 x ¨ 1 = − ( k 1 + k 2 ) x 1 + k 2 x 2 m 2 x ¨ 2 = k 2 x 1 − ( k 2 + k 3 ) x 2 {\displaystyle {\begin{cases}m_{1}{\ddot {x}}_{1}=-(k_{1Flory–Schulz distribution (288 words) [view diff] exact match in snippet view article find links to article
length k {\displaystyle k} is: w a ( k ) = a 2 k ( 1 − a ) k − 1 . {\displaystyle w_{a}(k)=a^{2}k(1-a)^{k-1}{\text{.}}} In this equation, k is the numberTopological sorting (3,170 words) [view diff] exact match in snippet view article find links to article
indices a k − 1 + ∑ i = 0 j − 1 | Q i k | , … , a k − 1 + ( ∑ i = 0 j | Q i k | ) − 1 {\textstyle a_{k-1}+\sum _{i=0}^{j-1}|Q_{i}^{k}|,\dots ,a_{k-1}+\left(\sumLebesgue measure (2,678 words) [view diff] no match in snippet view article find links to article
as an infimum λ ∗ ( E ) = inf { ∑ k = 1 ∞ ℓ ( I k ) : ( I k ) k ∈ N is a sequence of open intervals with E ⊂ ⋃ k = 1 ∞ I k } . {\displaystyle \lambdaNumeral system (3,494 words) [view diff] no match in snippet view article find links to article
k b k + ∑ k = 1 ∞ c k b − k . {\displaystyle (a_{n}a_{n-1}\cdots a_{1}a_{0}.c_{1}c_{2}c_{3}\cdots )_{b}=\sum _{k=0}^{n}a_{k}b^{k}+\sum _{k=1}^{\infty }c_{k}b^{-k}Kaprekar's routine (3,143 words) [view diff] no match in snippet view article find links to article
) = α − β = ( ( 2 k − 1 ) − ( k − 1 ) ) b 2 n + 2 ( ∑ i = 0 n b i ) + ( k − k ) b n + 1 ( ∑ i = 0 n b i ) + ( ( k − 1 ) − ( 2 k − 1 ) ) ( ∑ i = 0 n bAC power (4,388 words) [view diff] no match in snippet view article find links to article
result. A cos ( ω 1 t + k 1 ) cos ( ω 2 t + k 2 ) = A 2 cos [ ( ω 1 t + k 1 ) + ( ω 2 t + k 2 ) ] + A 2 cos [ ( ω 1 t + k 1 ) − ( ω 2 t + k 2 ) ]Asymptotic analysis (2,774 words) [view diff] exact match in snippet view article find links to article
1 − ⋯ − g k − 1 ∼ g k {\displaystyle f-g_{1}-\cdots -g_{k-1}\sim g_{k}} takes its full meaning if g k + 1 = o ( g k ) {\displaystyle g_{k+1}=o(g_{k})}Algebra over a field (3,122 words) [view diff] no match in snippet view article find links to article
k 1 , k 2 ∈ K {\displaystyle k_{1},k_{2}\in K} and v 1 , v 2 ∈ V {\displaystyle v_{1},v_{2}\in V} , one has ( k 1 + v 1 ) ( k 2 + v 2 ) = k 1 kKaprekar number (4,058 words) [view diff] no match in snippet view article find links to article
= 2 k + 1 + ∑ i = 1 n ( 2 k + 1 ) b 2 i + ( 2 k + 1 ) b 2 i − 1 = 2 k + 1 + ∑ i = 1 2 n ( 2 k + 1 ) b i = ∑ i = 0 2 n ( 2 k + 1 ) b i = ( 2 k + 1 ) ∑Generalized Dirichlet distribution (1,861 words) [view diff] exact match in snippet view article find links to article
function of p 1 , … , p k − 1 {\displaystyle p_{1},\ldots ,p_{k-1}} is [ ∏ i = 1 k − 1 B ( a i , b i ) ] − 1 p k b k − 1 − 1 ∏ i = 1 k − 1 [ p i a i − 1 ( ∑Trapezoid (4,042 words) [view diff] exact match in snippet view article find links to article
≈ ∑ k = 1 N 1 2 ( f ( x k − 1 ) + f ( x k ) ) Δ x , {\displaystyle \int _{a}^{b}f(x)\,dx\approx \sum _{k=1}^{N}{\tfrac {1}{2}}{\bigl (}f(x_{k-1})+f(x_{k}){\bigrRational function (2,421 words) [view diff] exact match in snippet view article find links to article
− 2 x k − ∑ k = 1 ∞ a k − 1 x k + 2 ∑ k = 0 ∞ a k x k . {\displaystyle 1=\sum _{k=2}^{\infty }a_{k-2}x^{k}-\sum _{k=1}^{\infty }a_{k-1}x^{k}+2\sum _{k=0}^{\inftyMeasure (mathematics) (5,550 words) [view diff] no match in snippet view article
collections { E k } k = 1 ∞ {\displaystyle \{E_{k}\}_{k=1}^{\infty }} of pairwise disjoint sets in Σ, μ ( ⋃ k = 1 ∞ E k ) = ∑ k = 1 ∞ μ ( E k ) . {\displaystyleFactorization (7,851 words) [view diff] no match in snippet view article find links to article
E 2 n + F 2 n = ∏ k = 1 n ( E 2 + 2 E F cos ( 2 k − 1 ) π 2 n + F 2 ) = ∏ k = 1 n ( E 2 − 2 E F cos ( 2 k − 1 ) π 2 n + F 2 ) {\displaystyle2010 ICF Canoe Sprint World Championships (1,990 words) [view diff] exact match in snippet view article find links to article
winningest medalist in men's kayak with his 21st career medal, earning that in a K-1 200 m silver. Rauhe eclipsed that record he had tied at the previous championshipsCanoeing at the 2008 Summer Olympics (70 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menBurr distribution (604 words) [view diff] no match in snippet view article find links to article
k + 1 f ( x ; c , k , λ ) = c k λ ( x λ ) c − 1 [ 1 + ( x λ ) c ] − k − 1 {\displaystyle {\begin{aligned}f(x;c,k)&=ck{\frac {x^{c-1}}{(1+x^{c})^{k+1}}}\\[6pt]f(x;cBose–Einstein statistics (6,024 words) [view diff] no match in snippet view article find links to article
following formula w ( n , g ) = ∑ k 1 = 0 n ∑ k 2 = 0 n − k 1 w ( n − k 1 − k 2 , g − 2 ) = ∑ k 1 = 0 n ∑ k 2 = 0 n − k 1 ⋯ ∑ k g = 0 n − ∑ j = 1 g − 1 kHexagonal number (1,028 words) [view diff] no match in snippet view article find links to article
∑ k = 1 ∞ 1 k ( 2 k − 1 ) = lim n → ∞ 2 ∑ k = 1 n ( 1 2 k − 1 − 1 2 k ) = lim n → ∞ 2 ∑ k = 1 n ( 1 2 k − 1 + 1 2 k − 1 k ) = 2 lim n → ∞ ( ∑ k = 1 2Root test (1,926 words) [view diff] exact match in snippet view article find links to article
K − 1 1 ∏ k = 1 i ln ( k ) ( n ) − ρ n ∏ k = 1 K ln ( k ) ( n ) + O ( 1 n ) . {\displaystyle \ln a_{n}=-1-\sum _{i=1}^{K-1}{\frac {1}{\prod _{k=1}^{i}\lnCanoeing at the 2004 Summer Olympics (96 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menDirichlet's test (999 words) [view diff] no match in snippet view article find links to article
k = 1 n M | a k − a k + 1 | = ∑ k = 1 n M ( a k − a k + 1 ) = M ∑ k = 1 n ( a k − a k + 1 ) , {\displaystyle \sum _{k=1}^{n}M|a_{k}-a_{k+1}|=\sum _{kFloyd–Warshall algorithm (3,071 words) [view diff] exact match in snippet view article find links to article
t h ( i , j , k − 1 ) , {\displaystyle \mathrm {min} {\Big (}\mathrm {shortestPath} (i,j,k-1),} s h o r t e s t P a t h ( i , k , k − 1 ) + s h o r tSpline (mathematics) (3,784 words) [view diff] no match in snippet view article
0 , … , k − 1 [ a , b ] = [ t 0 , t 1 ) ∪ [ t 1 , t 2 ) ∪ ⋯ ∪ [ t k − 2 , t k − 1 ) ∪ [ t k − 1 , t k ) ∪ [ t k ] a = t 0 ≤ t 1 ≤ ⋯ ≤ t k − 1 ≤ t k =Particle filter (16,882 words) [view diff] no match in snippet view article find links to article
k − 1 ) ) = p ( y k − 1 | x k − 1 ) p ( x k | x k − 1 ) p ( x k − 1 | y 0 , ⋯ , y k − 2 ) ∫ p ( y k − 1 | x k − 1 ′ ) p ( x k | x k − 1 ′ ) p ( x k −Integer partition (3,396 words) [view diff] no match in snippet view article find links to article
= ∏ k = 1 ∞ ( 1 + x k ) = ∏ k = 1 ∞ 1 1 − x 2 k − 1 . {\displaystyle \sum _{n=0}^{\infty }q(n)x^{n}=\prod _{k=1}^{\infty }(1+x^{k})=\prod _{k=1}^{\inftyMyanmar kyat (3,449 words) [view diff] no match in snippet view article find links to article
(plural), placed before the numerals followed by "/-". Amounts less than K. 1/- are typically denoted with the number of pyas following "-/" (e.g. -/50Integral test for convergence (1,727 words) [view diff] exact match in snippet view article find links to article
( x ) for k = 1 , ln ( ln k − 1 ( x ) ) for k ≥ 2. {\displaystyle \ln _{k}(x)={\begin{cases}\ln(x)&{\text{for }}k=1,\\\ln(\ln _{k-1}(x))&{\text{forPink noise (6,607 words) [view diff] no match in snippet view article find links to article
the interval [ k τ , ( k + 1 ) τ ] {\displaystyle [k\tau ,(k+1)\tau ]} as y k = 1 τ ∫ k τ ( k + 1 ) τ x ˙ ( t ) d t = x ( ( k + 1 ) τ ) − x ( k τ ) τ {\displaystyleInductance (8,763 words) [view diff] no match in snippet view article find links to article
authors define the range as 0 ≤ k < 1 {\displaystyle 0\leq k<1} , but some define it as − 1 < k < 1 {\displaystyle -1<k<1\,} . Allowing negative valuesPhase velocity (1,075 words) [view diff] no match in snippet view article find links to article
x , t ) = cos ( k 1 x − ω 1 t ) + cos ( k 2 x − ω 2 t ) = 2 cos ( ( k 2 − k 1 ) x − ( ω 2 − ω 1 ) t 2 ) cos ( ( k 2 + k 1 ) x − ( ω 2 + ω 1 )2019 K-1 Air Base attack (1,303 words) [view diff] exact match in snippet view article find links to article
A rocket attack was carried out on the K-1 Air Base in Kirkuk province in Iraq on 27 December 2019. The air base was one of many Iraqi military basesRüdiger Helm (313 words) [view diff] exact match in snippet view article find links to article
medals which included three golds (1976: K-1 1000 m, 1980: K-1 1000 m, K-4 1000 m) and three bronzes (1976: K-1 500 m, K-4 1000 m; 1980: K-2 500 m). HelmDivisor function (3,781 words) [view diff] no match in snippet view article find links to article
k + 1 ) n k {\displaystyle \zeta (k+1)n^{k}} : σ k ( n ) = ζ ( k + 1 ) n k [ 1 + ( − 1 ) n 2 k + 1 + 2 cos 2 π n 3 3 k + 1 + 2 cos π n 2 4 k + 1 +Rüdiger Helm (313 words) [view diff] exact match in snippet view article find links to article
medals which included three golds (1976: K-1 1000 m, 1980: K-1 1000 m, K-4 1000 m) and three bronzes (1976: K-1 500 m, K-4 1000 m; 1980: K-2 500 m). HelmGreen's theorem (4,074 words) [view diff] no match in snippet view article find links to article
\varepsilon } . We have | ∑ i = k + 1 s ∫ Γ i A d x + B d y | ≤ 1 2 ε ∑ i = k + 1 s Λ i . {\displaystyle \left\vert \sum _{i=k+1}^{s}\int _{\Gamma _{i}}A\,dx+B\Extended Euclidean algorithm (4,467 words) [view diff] no match in snippet view article find links to article
k + 1 {\displaystyle s_{k+1}} and t k + 1 {\displaystyle t_{k+1}} are coprime. The relation a s k + 1 + b t k + 1 = 0 {\displaystyle as_{k+1}+bt_{k+1}=0}Danuta Kozák (615 words) [view diff] exact match in snippet view article find links to article
fourteen golds (K-1 500 m: 2013, 2014, 2018; K-2 200 m: 2011; K-2 500 m: 2009, 2010, 2015, 2018; K-4 500 m: 2009, 2011, 2013, 2014, 2018 and K-1 200 m relay:Pigeonhole principle (4,155 words) [view diff] no match in snippet view article find links to article
contain at least k + 1 objects. For arbitrary n and m, this generalizes to k + 1 = ⌊ ( n − 1 ) / m ⌋ + 1 = ⌈ n / m ⌉ {\displaystyle k+1=\lfloor (n-1)/m\rfloorVirial theorem (7,675 words) [view diff] no match in snippet view article find links to article
virial is − 1 2 ∑ k = 1 N F k ⋅ r k = 1 2 ∑ k = 1 N ∑ j < k d V j k d r j k r j k = 1 2 ∑ k = 1 N ∑ j < k n α r j k n − 1 r j k = 1 2 ∑ k = 1 N ∑ j < k n VBroyden–Fletcher–Goldfarb–Shanno algorithm (2,987 words) [view diff] no match in snippet view article find links to article
B k + 1 ( x k + 1 − x k ) = ∇ f ( x k + 1 ) − ∇ f ( x k ) . {\displaystyle B_{k+1}(\mathbf {x} _{k+1}-\mathbf {x} _{k})=\nabla f(\mathbf {x} _{k+1})-\nablaKatalin Kovács (500 words) [view diff] exact match in snippet view article find links to article
seven silvers (K-1 1000 m: 2010, K-2 500 m: 2013, K-4 200 m: 2007, 2009, K-4 500 m: 1997, 1998, 2007), and three bronzes (K-1 500 m: 2001, K-1 1000 m: 1999Goodness of fit (1,150 words) [view diff] no match in snippet view article find links to article
any k − 1 are known, the remaining one is uniquely determined. Basically, one can say, there are only k − 1 freely determined binn counts, thus k − 1 degreesChain rule (7,087 words) [view diff] no match in snippet view article find links to article
( D f 2 ∘ f 3 . . n ) ⋯ ( D f n − 1 ∘ f n . . n ) D f n = ∏ k = 1 n [ D f k ∘ f ( k + 1 ) . . n ] {\displaystyle {\begin{aligned}Df_{1\,.\,.\,n}&=(Df_{1}\circNoncentral chi-squared distribution (3,719 words) [view diff] no match in snippet view article find links to article
variable is developed as V 1 / k 1 V 2 / k 2 ∼ F k 1 , k 2 ′ ( λ ) {\displaystyle {\frac {V_{1}/k_{1}}{V_{2}/k_{2}}}\sim F'_{k_{1},k_{2}}(\lambda )} If J ∼S-matrix (9,208 words) [view diff] no match in snippet view article find links to article
, k 1 … k n ⟩ = a i † ( k 1 ) ⋯ a i † ( k n ) | i , 0 ⟩ } , {\displaystyle {\mathcal {H}}_{\rm {i}}=\operatorname {span} \{\left|\mathrm {i} ,k_{1}\ldots2019 K-1 Air Base attack (1,303 words) [view diff] exact match in snippet view article find links to article
A rocket attack was carried out on the K-1 Air Base in Kirkuk province in Iraq on 27 December 2019. The air base was one of many Iraqi military basesElliptic Curve Digital Signature Algorithm (2,833 words) [view diff] no match in snippet view article find links to article
{\displaystyle r=0} , go back to step 3. Calculate s = k − 1 ( z + r d A ) mod n {\displaystyle s=k^{-1}(z+rd_{A})\,{\bmod {\,}}n} . If s = 0 {\displaystyleEulerian number (2,460 words) [view diff] no match in snippet view article find links to article
( n , k ) = ∑ i = 0 k ( − 1 ) i ( n + 1 i ) ( k + 1 − i ) n . {\displaystyle A(n,k)=\sum _{i=0}^{k}(-1)^{i}{\binom {n+1}{i}}(k+1-i)^{n}.} For fixed nNegative hypergeometric distribution (1,911 words) [view diff] no match in snippet view article find links to article
− 1 k ) ( N − r − k K − k ) ( N K ) = 1 ( N K ) ∑ k = 0 K ( k + r − 1 k ) ( N − r − k K − k ) = 1 ( N K ) ( N K ) = 1 , {\displaystyle \sum _{k=0}^{K}\Pr(X=k)=\sum2013 ICF Canoe Sprint World Championships (710 words) [view diff] exact match in snippet view article find links to article
Men's C–1 200 m Relay Results Men's K–1 200 m Results Men's K–1 500 m Results Men's K–1 1000 m Results Men's K–1 5000 m Results Men's K–2 200 m ResultsIan Ferguson (canoeist) (638 words) [view diff] exact match in snippet view article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanRate of convergence (5,628 words) [view diff] no match in snippet view article find links to article
x k + 1 − x k x k − x k − 1 | log | x k − x k − 1 x k − 1 − x k − 2 | . {\displaystyle q\approx {\frac {\log \left|\displaystyle {\frac {x_{k+12021 ICF Canoe Sprint World Championships (447 words) [view diff] exact match in snippet view article find links to article
September 2021. "Men's K-1 200" (PDF). Retrieved 19 September 2021. "Men's K-1 500" (PDF). Retrieved 19 September 2021. "Men's K-1 1000" (PDF). RetrievedSubstitution reaction (1,456 words) [view diff] no match in snippet view article find links to article
described with k1, k−1 and k2, which are the rate constants of their corresponding intermediate reaction steps: L n M − L ⇌ + L , k − 1 − L , k 1 L n M − ◻ →1999 ICF Canoe Sprint World Championships (79 words) [view diff] exact match in snippet view article find links to article
Time K-1 200 m Caroline Brunet (CAN) Josefa Idem (ITA) Rita Kőbán (HUN) K-1 500 m Caroline Brunet (CAN) Josefa Idem (ITA) Rita Kőbán (HUN) K-1 1000Aleksandr Shaparenko (208 words) [view diff] exact match in snippet view article find links to article
1972: K-1 1000 m) and one silver (1968: K-1 1000 m). Shaparenko also won 13 medals at the ICF Canoe Sprint World Championships with seven golds (K-1 10002001 ICF Canoe Sprint World Championships (143 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Ronald Rauhe (GER) Oleksiy Slivinskiy (UKR) Anton Ryakhov (UZB) K-1 500 m Ákos Verecki (HUN) Anton Ryakhov (UZB)Dirichlet-multinomial distribution (6,950 words) [view diff] exact match in snippet view article find links to article
^{k}|n_{1}+\cdots +n_{k}=n\}.\,} Its number of elements is ( n + k − 1 k − 1 ) . {\displaystyle {n+k-1 \choose k-1}.} In matrix notation, E ( X ) = n p , {\displaystyleAbelian group (5,284 words) [view diff] no match in snippet view article find links to article
numbers k 1 , k 2 , … , k u {\displaystyle k_{1},k_{2},\dots ,k_{u}} are powers of (not necessarily distinct) primes, or k 1 {\displaystyle k_{1}} dividesHome advantage (7,714 words) [view diff] no match in snippet view article find links to article
season to obtain k 1 {\displaystyle k_{1}} , k 0 {\displaystyle k_{0}} , and k − 1 {\displaystyle k_{-1}} . Values of k 1 {\displaystyle k_{1}} , k 0 {\displaystyleHodge star operator (6,501 words) [view diff] no match in snippet view article find links to article
i k + 1 , … , i n d x i k + 1 ∧ ⋯ ∧ d x i n . {\displaystyle {\star }\alpha ={\frac {1}{(n-k)!}}({\star }\alpha )_{i_{k+1},\dots ,i_{n}}dx^{i_{k+1}}\wedgeList of ICF Canoe Sprint World Championships medalists in women's kayak (222 words) [view diff] no match in snippet view article find links to article
This is a list of medalists from the ICF Canoe Sprint World Championships in women's kayak. Debuted: 1994. Debuted: 1938. Not held: 1948. Resumed: 1950Interest (9,217 words) [view diff] exact match in snippet view article find links to article
k − 1 r = k [ 1 + ( k − 1 ) r 2 + ⋯ ] {\displaystyle \lambda _{k}={\frac {p_{k}}{p}}={\frac {r_{k}}{r}}={\frac {(1+r)^{k}-1}{r}}=k\left[1+{\frac {(k-1)r}{2}}+\cdotsDiscretization (2,400 words) [view diff] no match in snippet view article find links to article
− τ ) B u ( τ ) d τ x [ k + 1 ] = e A ( k + 1 ) T x ( 0 ) + ∫ 0 ( k + 1 ) T e A [ ( k + 1 ) T − τ ] B u ( τ ) d τ x [ k + 1 ] = e A T [ e A k T x ( 0Dispersion (water waves) (3,434 words) [view diff] no match in snippet view article
c g = lim k 1 → k 2 ω 1 − ω 2 k 1 − k 2 = lim k 1 → k 2 Ω ( k 1 ) − Ω ( k 2 ) k 1 − k 2 = d Ω ( k ) d k . {\displaystyle c_{g}=\lim _{k_{1}\,\to \,k_{2}}{\fracFermat number (4,717 words) [view diff] no match in snippet view article find links to article
( 2 k + 1 ) . {\displaystyle (2^{r}+1)\mid (2^{k}+1).} Because 1 < 2 r + 1 < 2 k + 1 {\displaystyle 1<2^{r}+1<2^{k}+1} , it follows that 2 k + 1 {\displaystyleCanoeing at the 1996 Summer Olympics (81 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menGreatest common divisor (4,717 words) [view diff] exact match in snippet view article find links to article
d 1 − k ζ ( k ) − 1 = ζ ( k − 1 ) ζ ( k ) . {\displaystyle \mathrm {E} (k)=\sum _{d=1}^{\infty }d^{1-k}\zeta (k)^{-1}={\frac {\zeta (k-1)}{\zeta (k)}}Josefa Idem (966 words) [view diff] exact match in snippet view article find links to article
Schüttpelz. The next year, Idem switched to the K-1 events. At the 1988 Olympics in Seoul, she finished ninth in the K-1 500 m and fifth with the West German quartetK-nearest neighbors algorithm (4,316 words) [view diff] no match in snippet view article find links to article
its k nearest neighbors (k is a positive integer, typically small). If k = 1, then the object is simply assigned to the class of that single nearestRita Kőbán (398 words) [view diff] exact match in snippet view article find links to article
(K-1 200 m: 1994, 1995; K-1 500 m: 1995, K-2 200 m: 1994, K-4 200 m: 1994, 1998, 1999; K-4 500 m: 1986, 1999), ten silvers (K-1 500 m: 1991, 1994; K-1Kolmogorov–Smirnov test (3,912 words) [view diff] no match in snippet view article find links to article
k = 1 ∞ ( − 1 ) k − 1 e − 2 k 2 x 2 = 2 π x ∑ k = 1 ∞ e − ( 2 k − 1 ) 2 π 2 / ( 8 x 2 ) , {\displaystyle \operatorname {Pr} (K\leq x)=1-2\sum _{k=1}^{\inftyAlmost prime (402 words) [view diff] exact match in snippet view article find links to article
log log n ) k − 1 ( k − 1 ) ! , {\displaystyle \pi _{k}(n)\sim \left({\frac {n}{\log n}}\right){\frac {(\log \log n)^{k-1}}{(k-1)!}},} a result ofCohen's kappa (3,698 words) [view diff] no match in snippet view article find links to article
following construction: p e = ∑ k p k 12 ^ = ind. ∑ k p k 1 ^ p k 2 ^ = ∑ k n k 1 N n k 2 N = 1 N 2 ∑ k n k 1 n k 2 {\displaystyle p_{e}=\sum _{k}{\widehat {p_{k12}}}{\oversetPolytope (3,119 words) [view diff] case mismatch in snippet view article find links to article
context, "flat sides" means that the sides of a (k + 1)-polytope consist of k-polytopes that may have (k – 1)-polytopes in common. Some theories further generalizeLevi-Civita symbol (5,174 words) [view diff] no match in snippet view article find links to article
2-spinors. In three dimensions, the Levi-Civita symbol is defined by: ε i j k = { + 1 if ( i , j , k ) is ( 1 , 2 , 3 ) , ( 2 , 3 , 1 ) , or ( 3 , 1 ,General Leibniz rule (1,247 words) [view diff] no match in snippet view article find links to article
_{t=1}^{m}k_{t}=n,} and ( n k 1 , k 2 , … , k m ) = n ! k 1 ! k 2 ! ⋯ k m ! {\displaystyle {n \choose k_{1},k_{2},\ldots ,k_{m}}={\frac {n!}{k_{1}!\,k_{2}!\cdotsInternational System of Units (6,146 words) [view diff] no match in snippet view article find links to article
the fixed numerical value of the Boltzmann constant k to 1.380649×10−23 J⋅K−1, (J = kg⋅m2⋅s−2), given the definition of the kilogram, the metre, and the1999 ICF Canoe Sprint World Championships (79 words) [view diff] exact match in snippet view article find links to article
Time K-1 200 m Caroline Brunet (CAN) Josefa Idem (ITA) Rita Kőbán (HUN) K-1 500 m Caroline Brunet (CAN) Josefa Idem (ITA) Rita Kőbán (HUN) K-1 1000Dispersion (water waves) (3,434 words) [view diff] no match in snippet view article
c g = lim k 1 → k 2 ω 1 − ω 2 k 1 − k 2 = lim k 1 → k 2 Ω ( k 1 ) − Ω ( k 2 ) k 1 − k 2 = d Ω ( k ) d k . {\displaystyle c_{g}=\lim _{k_{1}\,\to \,k_{2}}{\fracInternational System of Units (6,146 words) [view diff] no match in snippet view article find links to article
the fixed numerical value of the Boltzmann constant k to 1.380649×10−23 J⋅K−1, (J = kg⋅m2⋅s−2), given the definition of the kilogram, the metre, and theLebesgue integral (5,919 words) [view diff] no match in snippet view article find links to article
positive, we set ∫ ( ∑ k a k 1 S k ) d μ = ∑ k a k ∫ 1 S k d μ = ∑ k a k μ ( S k ) {\displaystyle \int \left(\sum _{k}a_{k}1_{S_{k}}\right)\,d\mu =\sum2001 ICF Canoe Sprint World Championships (143 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Ronald Rauhe (GER) Oleksiy Slivinskiy (UKR) Anton Ryakhov (UZB) K-1 500 m Ákos Verecki (HUN) Anton Ryakhov (UZB)(a,b,0) class of distributions (797 words) [view diff] exact match in snippet view article
satisfies the recurrence formula p k p k − 1 = a + b k , k = 1 , 2 , 3 , … {\displaystyle {\frac {p_{k}}{p_{k-1}}}=a+{\frac {b}{k}},\qquad k=1,2,3,\dotsPartial fraction decomposition (7,008 words) [view diff] exact match in snippet view article find links to article
\deg H_{k}<\deg G.} Setting F k − 1 = F C + Q , {\displaystyle F_{k-1}=FC+Q,} one gets F G k = H k G k + F k − 1 G k − 1 , {\displaystyle {\frac {F}{G^{k}}}={\fracMie scattering (9,207 words) [view diff] no match in snippet view article find links to article
{M} _{o1n}^{(1)}(k_{1},\mathbf {r} )\right),} H 1 = − k 1 ω μ 1 ∑ n = 1 ∞ E n ( d n M e 1 n ( 1 ) ( k 1 , r ) + i c n N o 1 n ( 1 ) ( k 1 , r ) ) . {\displaystyleFundamental theorem of algebra (7,621 words) [view diff] no match in snippet view article find links to article
( z − z 0 ) k + c k + 1 ( z − z 0 ) k + 1 + ⋯ + c n ( z − z 0 ) n . {\displaystyle p(z)=a+c_{k}(z-z_{0})^{k}+c_{k+1}(z-z_{0})^{k+1}+\cdots +c_{n}(z-z_{0})^{n}Reversible reaction (894 words) [view diff] no match in snippet view article find links to article
at the final kinetic expression: [ A ] = k -1 [ A ] 0 k 1 + k -1 + k 1 [ A ] 0 k 1 + k -1 exp ( − k 1 + k -1 ) t {\displaystyle [A]={\frac2022 ICF Canoe Sprint World Championships (70 words) [view diff] exact match in snippet view article find links to article
C-2 1000m men C-4 500m men women Kayak events K-1 200m men women K-1 500m men women K-1 1000m men women K-1 5000m men women K-2 200m women K-2 500m menFriedman test (1,169 words) [view diff] no match in snippet view article find links to article
12 n k ( k + 1 ) ∑ j = 1 k ( r ¯ ⋅ j − k + 1 2 ) 2 {\displaystyle Q={\frac {12n}{k(k+1)}}\sum _{j=1}^{k}\left({\bar {r}}_{\cdot j}-{\frac {k+1}{2}}\right)^{2}}Lah number (1,812 words) [view diff] exact match in snippet view article find links to article
, k − 1 ) = k ( k + 1 ) L ( n , k + 1 ) + 2 k L ( n , k ) + L ( n , k − 1 ) {\displaystyle {\begin{aligned}L(n+1,k)&=(n+k)L(n,k)+L(n,k-1)\\&=k(k+1)L(nFerenc Csipes (356 words) [view diff] exact match in snippet view article find links to article
with eight golds (K-1 1000 m: 1985, K-1 10000 m: 1986, K-2 500 m: 1987, K-4 1000 m: 1986, 1987, 1989, 1990, 1991), four silvers (K-1 1000 m: 1986, 1987Rita Kőbán (398 words) [view diff] exact match in snippet view article find links to article
(K-1 200 m: 1994, 1995; K-1 500 m: 1995, K-2 200 m: 1994, K-4 200 m: 1994, 1998, 1999; K-4 500 m: 1986, 1999), ten silvers (K-1 500 m: 1991, 1994; K-1Almost prime (402 words) [view diff] exact match in snippet view article find links to article
log log n ) k − 1 ( k − 1 ) ! , {\displaystyle \pi _{k}(n)\sim \left({\frac {n}{\log n}}\right){\frac {(\log \log n)^{k-1}}{(k-1)!}},} a result ofSquare triangular number (1,478 words) [view diff] exact match in snippet view article find links to article
x k + 1 = 2 x k x 1 − x k − 1 , y k + 1 = 2 y k x 1 − y k − 1 . {\displaystyle \displaystyle {\begin{aligned}x_{k+1}&=2x_{k}x_{1}-x_{k-1},\\y_{k+1}&=2y_{k}x_{1}-y_{k-1}Hermite polynomials (12,119 words) [view diff] exact match in snippet view article find links to article
k + 1 ) a n , k + 1 k = 0 , a n , k − 1 − ( k + 1 ) a n , k + 1 k > 0 , {\displaystyle a_{n+1,k}={\begin{cases}-(k+1)a_{n,k+1}&k=0,\\a_{n,k-1}-(k+1)a_{nSquare wave (waveform) (1,295 words) [view diff] no match in snippet view article
an infinite sum of sinusoidal waves: x ( t ) = 4 π ∑ k = 1 ∞ sin ( 2 π ( 2 k − 1 ) f t ) 2 k − 1 = 4 π ( sin ( ω t ) + 1 3 sin ( 3 ω t ) + 1 5 sinHypoexponential distribution (1,758 words) [view diff] no match in snippet view article find links to article
finite state Markov process. If we have a k+1 state process, where the first k states are transient and the state k+1 is an absorbing state, then the distribution1 + 2 + 3 + 4 + ⋯ (4,221 words) [view diff] no match in snippet view article find links to article
partial sum of the series is the triangular number ∑ k = 1 n k = n ( n + 1 ) 2 , {\displaystyle \sum _{k=1}^{n}k={\frac {n(n+1)}{2}},} which increases withoutHalf-logistic distribution (247 words) [view diff] no match in snippet view article find links to article
2F(k) − 1 is the cdf of a half-logistic distribution. Specifically, G ( k ) = 1 − e − k 1 + e − k for k ≥ 0. {\displaystyle G(k)={\frac {1-e^{-k}}{1+e^{-k}}}{\text{General Leibniz rule (1,247 words) [view diff] no match in snippet view article find links to article
_{t=1}^{m}k_{t}=n,} and ( n k 1 , k 2 , … , k m ) = n ! k 1 ! k 2 ! ⋯ k m ! {\displaystyle {n \choose k_{1},k_{2},\ldots ,k_{m}}={\frac {n!}{k_{1}!\,k_{2}!\cdotsSquared triangular number (1,867 words) [view diff] no match in snippet view article find links to article
mathematical notation for summation: ∑ k = 1 n k 3 = ( ∑ k = 1 n k ) 2 . {\displaystyle \sum _{k=1}^{n}k^{3}=\left(\sum _{k=1}^{n}k\right)^{2}.} This identityPercentile (2,647 words) [view diff] no match in snippet view article find links to article
C} , and v = v k + P − p k p k + 1 − p k ( v k + 1 − v k ) . {\displaystyle v=v_{k}+{\frac {P-p_{k}}{p_{k+1}-p_{k}}}(v_{k+1}-v_{k}).} The 50% weighted percentileTensor algebra (4,161 words) [view diff] no match in snippet view article find links to article
one has scalar multiplication on the field: k 1 ⊗ k 2 = k 1 k 2 . {\displaystyle k_{1}\otimes k_{2}=k_{1}k_{2}.} The most difficult to verify is the compatibilityChebyshev polynomials (11,475 words) [view diff] no match in snippet view article find links to article
k ) ( 1 − x − 2 ) k = n 2 ∑ k = 0 ⌊ n 2 ⌋ ( − 1 ) k ( n − k − 1 ) ! k ! ( n − 2 k ) ! ( 2 x ) n − 2 k for n > 0 = n ∑ k = 0 n ( − 2 ) k ( n + k2005 ICF Canoe Sprint World Championships (330 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Carlos Pérez (ESP) 35.289 Tomasz Mendelski (POL) 35.697 Anton Ryakhov (RUS) 35.733 K-1 500 m Nathan Baggaley (AUS)Characteristic polynomial (3,040 words) [view diff] exact match in snippet view article find links to article
A^{k}} because A k v = A k − 1 A v = λ A k − 1 v = ⋯ = λ k v . {\displaystyle A^{k}{\textbf {v}}=A^{k-1}A{\textbf {v}}=\lambda A^{k-1}{\textbf {v}}=\dots =\lambdaKelvin (4,784 words) [view diff] no match in snippet view article find links to article
adopted at the 26th CGPM in late 2018, with a value of kB = 1.380649×10−23 J⋅K−1. In fundamental physics, the mapping E=kBT which converts between the characteristicMaximum entropy probability distribution (4,530 words) [view diff] no match in snippet view article find links to article
x k } = p k for k = 1 , 2 , … {\displaystyle \operatorname {Pr} \{\ X=x_{k}\}=p_{k}\qquad ~{\mbox{ for }}~\quad k=1,\ 2,\ \ldots ~} then theFalling and rising factorials (3,377 words) [view diff] no match in snippet view article find links to article
= x n _ = x ( x − 1 ) ( x − 2 ) ⋯ ( x − n + 1 ) ⏞ n factors = ∏ k = 1 n ( x − k + 1 ) = ∏ k = 0 n − 1 ( x − k ) . {\displaystyle {\begin{aligned}(x)_{n}=x^{\underlineColor index (1,031 words) [view diff] no match in snippet view article find links to article
formula (also implemented in the PyAstronomy package for Python): T = 4600 K ( 1 0.92 ( B - V ) + 1.7 + 1 0.92 ( B - V ) + 0.62 ) . {\displaystyle T=4600\Canoeing at the 1976 Summer Olympics (76 words) [view diff] exact match in snippet view article find links to article
in the Montreal program though four 500 m events for men were (C-1, C-2, K-1, and K-2). 1976 Summer Olympics official report Volume 3. pp. 167–85. (inFaà di Bruno's formula (3,788 words) [view diff] no match in snippet view article find links to article
noticing that m j {\displaystyle m_{j}} has to be zero for j > n − k + 1 {\displaystyle j>n-k+1} leads to a somewhat simpler formula expressed in terms of partialVampire number (730 words) [view diff] exact match in snippet view article find links to article
digits: A = a k a k − 1 . . . a 1 {\displaystyle A={a_{k}}{a_{k-1}}...{a_{1}}} B = b k b k − 1 . . . b 1 {\displaystyle B={b_{k}}{b_{k-1}}...{b_{1}}} suchBorosilicate glass (3,691 words) [view diff] no match in snippet view article find links to article
are known for having very low coefficients of thermal expansion (≈3 × 10−6 K−1 at 20 °C), making them more resistant to thermal shock than any other commonMoiré pattern (4,166 words) [view diff] no match in snippet view article find links to article
= k 1 + k 2 2 {\displaystyle A={\frac {k_{1}+k_{2}}{2}}} and B = k 1 − k 2 2 . {\displaystyle B={\frac {k_{1}-k_{2}}{2}}.} This function average, f32006 ICF Canoe Sprint World Championships (337 words) [view diff] exact match in snippet view article find links to article
final, giving Mexico their first-ever world championship gold medal. The K-1 1000 m, the Blue Riband event, was won by Markus Oscarsson of Sweden. Germany'sCanoeing at the 1992 Summer Olympics (88 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menAbel's test (1,047 words) [view diff] no match in snippet view article find links to article
absolutely: ∑ k = 1 ∞ | ( a k − a k − 1 ) z k | = ∑ k = 1 ∞ | a k − a k − 1 | ⋅ | z | k ≤ ∑ k = 1 ∞ ( a k − 1 − a k ) {\displaystyle \sum _{k=1}^{\inftyCross-polytope (1,106 words) [view diff] no match in snippet view article find links to article
is thus given by (see binomial coefficient): 2 k + 1 ( n k + 1 ) {\displaystyle 2^{k+1}{n \choose {k+1}}} The extended f-vector for an n-orthoplex canSawtooth wave (1,102 words) [view diff] no match in snippet view article find links to article
sawtooth ( t ) = − 2 a π ∑ k = 1 ∞ ( − 1 ) k sin ( 2 π k f t ) k {\displaystyle x_{\text{sawtooth}}(t)=-{\frac {2a}{\pi }}\sum _{k=1}^{\infty }{(-1)}^{k}{\fracSampling distribution (731 words) [view diff] exact match in snippet view article find links to article
k ) ( x ) = ( 2 k − 1 ) ! ( k − 1 ) ! 2 f ( x ) ( F ( x ) ( 1 − F ( x ) ) ) k − 1 {\displaystyle f_{X_{(k)}}(x)={\frac {(2k-1)!}{(k-1)!^{2}}}f(x){\BigPerfect digital invariant (5,240 words) [view diff] no match in snippet view article find links to article
1 ) ( 3 k + 1 ) − k ( 3 k + 1 ) = ( k + 1 ) ( 3 k + 1 ) ( 3 k + 1 ) − k ( 3 k + 1 ) = k ( 3 k + 1 ) ( 3 k + 1 ) + ( 3 k + 1 ) ( 3 k + 1 ) − k ( 3 k +Ken Wallace (canoeist) (270 words) [view diff] exact match in snippet view article
gold in the K-1 500 m and bronze in the K-1 1000 m events. He also won two medals at the ICF Canoe Sprint World Championships with a gold (K-1 5000 m: 2010)2019 ICF Canoe Sprint World Championships (1,279 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200, 500, 1000 or 5000 metresZsolt Gyulay (337 words) [view diff] exact match in snippet view article find links to article
(1988: K-1 500 m, K-4 1000 m) and two silver (1992: K-1 500 m, K-4 1000 m). He also won fourteen medals at the world championships: six golds (K-1 1000Cumulant (8,867 words) [view diff] exact match in snippet view article find links to article
∑ k = 1 n ( − 1 ) k − 1 ( k − 1 ) ! B n , k ( μ 1 ′ , … , μ n − k + 1 ′ ) , {\displaystyle \kappa _{n}=\sum _{k=1}^{n}(-1)^{k-1}(k-1)!B_{n,k}(\mu '_{1}Mathematical economics (13,624 words) [view diff] no match in snippet view article find links to article
) k / ( 1 − τ ) {\textstyle dw/d\tau =-f'(k)k/(1-\tau )} , we have that: d w d x = − f ′ ( k ) k 1 − τ f ′ ( k ) 1 − τ [ τ f ′ ( k ) f ″ ( k ) + k ] =Knot theory (6,292 words) [view diff] no match in snippet view article find links to article
{R} ^{3}} , with the only "non-injectivity" being K ( 0 ) = K ( 1 ) {\displaystyle K(0)=K(1)} . Topologists consider knots and other entanglements suchDistortion (optics) (2,784 words) [view diff] no match in snippet view article
given by x d = x c + x u − x c 2 K 1 r u 2 ( 1 − 1 − 4 K 1 r u 2 ) y d = y c + y u − y c 2 K 1 r u 2 ( 1 − 1 − 4 K 1 r u 2 ) , {\displaystyle {\begin{aligned}x_{\mathrmZeta distribution (1,030 words) [view diff] no match in snippet view article find links to article
defined for positive integers k ≥ 1 {\displaystyle k\geq 1} , and its probability mass function is given by P ( x = k ) = 1 ζ ( s ) k − s , {\displaystyleGauss–Kuzmin distribution (569 words) [view diff] no match in snippet view article find links to article
_{2}\left(1-{\frac {1}{(1+k)^{2}}}\right)~.} Let x = 1 k 1 + 1 k 2 + ⋯ {\displaystyle x={\cfrac {1}{k_{1}+{\cfrac {1}{k_{2}+\cdots }}}}} be the continued fractionFactorion (1,282 words) [view diff] exact match in snippet view article find links to article
the following: SFD b ( n ) = ∑ i = 0 k − 1 d i ! . {\displaystyle \operatorname {SFD} _{b}(n)=\sum _{i=0}^{k-1}d_{i}!.} where k = ⌊ log b n ⌋ + 1 {\displaystyleKen Wallace (canoeist) (270 words) [view diff] exact match in snippet view article
gold in the K-1 500 m and bronze in the K-1 1000 m events. He also won two medals at the ICF Canoe Sprint World Championships with a gold (K-1 5000 m: 2010)Cube (algebra) (3,026 words) [view diff] exact match in snippet view article
well-known identity: n 2 = ∑ k = 1 n ( 2 k − 1 ) , {\displaystyle n^{2}=\sum _{k=1}^{n}(2k-1),} we obtain the following derivation: ∑ k = 1 n k 3 = 1 + 8 + 27 +Least squares (5,702 words) [view diff] no match in snippet view article find links to article
are obtained by successive approximation: β j k + 1 = β j k + Δ β j , {\displaystyle {\beta _{j}}^{k+1}={\beta _{j}}^{k}+\Delta \beta _{j},} where a superscriptFalling and rising factorials (3,377 words) [view diff] no match in snippet view article find links to article
= x n _ = x ( x − 1 ) ( x − 2 ) ⋯ ( x − n + 1 ) ⏞ n factors = ∏ k = 1 n ( x − k + 1 ) = ∏ k = 0 n − 1 ( x − k ) . {\displaystyle {\begin{aligned}(x)_{n}=x^{\underlineNatasa Dusev-Janics (717 words) [view diff] exact match in snippet view article find links to article
won 26 medals at the ICF Canoe Sprint World Championships with 20 golds (K-1 200 m: 2007, 2009, 2010; K-2 200 m: 2005, 2006, 2009, 2010; K-2 500 m: 2005Root of unity (5,939 words) [view diff] no match in snippet view article find links to article
of unity, as ( z k ) n = z k n = ( z n ) k = 1 k = 1. {\displaystyle (z^{k})^{n}=z^{kn}=(z^{n})^{k}=1^{k}=1.} This is also true for negative exponentsRaman Piatrushenka (603 words) [view diff] exact match in snippet view article find links to article
m bronze. In the K-1 1000m however, he could only finish 17th. At the 2002 European under-23 Championships in Zagreb, he won the K-1 1000 m gold medalSampling distribution (731 words) [view diff] exact match in snippet view article find links to article
k ) ( x ) = ( 2 k − 1 ) ! ( k − 1 ) ! 2 f ( x ) ( F ( x ) ( 1 − F ( x ) ) ) k − 1 {\displaystyle f_{X_{(k)}}(x)={\frac {(2k-1)!}{(k-1)!^{2}}}f(x){\BigRegular polygon (3,223 words) [view diff] no match in snippet view article find links to article
{1}{n}}\sum _{i=1}^{n}d_{i}^{2m}} , then S n ( 2 m ) = ( S n ( 2 ) ) m + ∑ k = 1 ⌊ m / 2 ⌋ ( m 2 k ) ( 2 k k ) R 2 k ( S n ( 2 ) − R 2 ) k ( S n ( 2 ) )Quasi-Newton method (2,264 words) [view diff] no match in snippet view article find links to article
approximate Hessian B k + 1 {\displaystyle B_{k+1}} , or directly its inverse H k + 1 = B k + 1 − 1 {\displaystyle H_{k+1}=B_{k+1}^{-1}} using the Sherman–MorrisonArithmetic function (7,550 words) [view diff] no match in snippet view article find links to article
k 1 , n ) = 1 1 ≤ k 1 , k 2 , … , k s ≤ n gcd ( k 1 − 1 , k 2 , … , k s , n ) = φ ( n ) σ s − 1 ( n ) . {\displaystyle \sum _{\stackrel {1\leq k_{1}Phytomenadione (1,333 words) [view diff] no match in snippet view article find links to article
Phytomenadione, also known as vitamin K1 or phylloquinone, is a vitamin found in food and used as a dietary supplement. It is on the World Health Organization'sInitial condition (1,362 words) [view diff] exact match in snippet view article find links to article
d t k + a k − 1 d k − 1 x d t k − 1 + ⋯ + a 1 d x d t + a 0 x = 0. {\displaystyle {\frac {d^{k}x}{dt^{k}}}+a_{k-1}{\frac {d^{k-1}x}{dt^{k-1}}}+\cdotsBirth–death process (3,948 words) [view diff] exact match in snippet view article find links to article
= λ k − 1 p k − 1 ( t ) + μ k + 1 p k + 1 ( t ) − ( λ k + μ k ) p k ( t ) , k = 1 , 2 , … , {\displaystyle p_{k}^{\prime }(t)=\lambda _{k-1}p_{k-1}(t)+\mu2009 ICF Canoe Sprint World Championships (3,937 words) [view diff] exact match in snippet view article find links to article
men's 500 m events (C-1, C-2, K-1 and K-2) at the Summer Olympics with the 200 m events (men's C-1, K-1 and K-2; and women's K-1) for the upcoming Summer OlympicsCyclic permutation (2,039 words) [view diff] no match in snippet view article find links to article
= ( k k + 1 ) ⋅ ( k + 1 k + 2 ) ⋯ ( l − 1 l ) ⋅ ( l − 2 l − 1 ) ⋯ ( k k + 1 ) . {\displaystyle (k~~l)=(k~~k+1)\cdot (k+1~~k+2)\cdotsCholesky decomposition (8,335 words) [view diff] no match in snippet view article find links to article
for k = 1:n r = sqrt(L(k, k)^2 + x(k)^2); c = r / L(k, k); s = x(k) / L(k, k); L(k, k) = r; if k < n L((k+1):n, k) = (L((k+1):n, k) + s * x((k+1):n))Discrete phase-type distribution (596 words) [view diff] no match in snippet view article find links to article
distribution function is F ( k ) = 1 − τ T k 1 , {\displaystyle F(k)=1-{\boldsymbol {\tau }}{T}^{k}\mathbf {1} ,} for k = 1 , 2 , . . . {\displaystyle k=1Probability mass function (1,539 words) [view diff] exact match in snippet view article find links to article
success. Its probability mass function is p X ( k ) = ( 1 − p ) k − 1 p {\textstyle p_{X}(k)=(1-p)^{k-1}p} . An example is tossing a coin until the firstPower rule (2,631 words) [view diff] exact match in snippet view article find links to article
i.e. d d x x k = k x k − 1 . {\displaystyle {\frac {d}{dx}}x^{k}=kx^{k-1}.} When n = k + 1 {\displaystyle n=k+1} , d d x x k + 1 = d d x ( x k ⋅ x ) =Proof that 22/7 exceeds π (2,814 words) [view diff] no match in snippet view article find links to article
≥ 0 and ℓ ≥ 2 we have x k ( 1 − x ) ℓ = ( 1 − 2 x + x 2 ) x k ( 1 − x ) ℓ − 2 = ( 1 + x 2 ) x k ( 1 − x ) ℓ − 2 − 2 x k + 1 ( 1 − x ) ℓ − 2 . {\displaystyleLists of integrals (5,611 words) [view diff] no match in snippet view article find links to article
( x ) − ( − 1 ) n d n f ( x ) d x n ) d x = e x ∑ k = 1 n ( − 1 ) k − 1 d k − 1 f ( x ) d x k − 1 + C {\displaystyle \int {e^{x}\left(f\left(x\rightCaroline Brunet (212 words) [view diff] exact match in snippet view article find links to article
(K-1 200 m: 1997, 1998, 1999, 2003; K-1 500 m: 1997, 1998, 1999; K-1 1000 m: 1997, 1999; K-4 200 m: 1995), seven silvers (K-1 200 m: 1995, 2002; K-1 5002007 ICF Canoe Sprint World Championships (267 words) [view diff] exact match in snippet view article find links to article
K-2 races were ruled by the German paddlers. However, Katalin Kovács won K-1 1000 m and 500 m, and gained two silvers in the K-4 events, while formerIterative method (1,546 words) [view diff] no match in snippet view article find links to article
defined as M x k + 1 = N x k + b , k ≥ 0 , {\displaystyle M\mathbf {x} ^{k+1}=N\mathbf {x} ^{k}+b,\quad k\geq 0,} or, equivalently, x k + 1 = x k + M − 1Interior product (1,587 words) [view diff] no match in snippet view article find links to article
i = k + 1 n ( ∂ i a ) d ξ i ∧ d ξ 2 ∧ ⋯ ∧ d ξ k , d α = ∑ i = k + 1 n ( ∂ i a ) d ξ i ∧ d ξ 1 ∧ d ξ 2 ∧ ⋯ ∧ d ξ k , ι X ( d α ) = − ∑ i = k + 1 n ( ∂Hypocycloid (1,350 words) [view diff] exact match in snippet view article find links to article
( k − 1 ) cos θ + r cos ( ( k − 1 ) θ ) y ( θ ) = r ( k − 1 ) sin θ − r sin ( ( k − 1 ) θ ) {\displaystyle {\begin{aligned}&x(\theta )=r(k-1)\cosPopulation model (734 words) [view diff] no match in snippet view article find links to article
equations: d N 1 d t = r 1 N 1 K 1 − N 1 − α N 2 K 1 {\displaystyle {\frac {dN_{1}}{dt}}=r_{1}N_{1}{\frac {K_{1}-N_{1}-\alpha N_{2}}{K_{1}}}\,} Island biogeography:Markov chain (12,894 words) [view diff] no match in snippet view article find links to article
X_{0}=i)>0\}} The state is periodic if k > 1 {\displaystyle k>1} ; otherwise k = 1 {\displaystyle k=1} and the state is aperiodic. A state i is saidMerit order (2,602 words) [view diff] no match in snippet view article find links to article
total welfare is then W = ∑ k = 1 n V k ( D k ) − ∑ k = 1 n C k ( S k ) {\displaystyle W=\sum _{k=1}^{n}V_{k}(D_{k})-\sum _{k=1}^{n}C_{k}(S_{k})} The economicCharacteristic function (probability theory) (5,208 words) [view diff] no match in snippet view article
) − k 1 ( 1 − θ i t ) − k 2 = ( 1 − θ i t ) − ( k 1 + k 2 ) . {\displaystyle \varphi _{X+Y}(t)=\varphi _{X}(t)\varphi _{Y}(t)=(1-\theta it)^{-k_{1}}(1-\theta2003 ICF Canoe Sprint World Championships (217 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Ronald Rauhe (GER) 35.798 Vince Fehérvári (AUS) 36.411 Anton Ryakhov (UZB) 36.417 K-1 500 m Nathan Baggaley (AUS)2002 ICF Canoe Sprint World Championships (136 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Ronald Rauhe (GER) Anton Ryakhov (UZB) Roman Petrukanecas (LTU) K-1 500 m Nathan Baggaley (AUS) Petar Merkov (BUL)Canoeing at the 1984 Summer Olympics (66 words) [view diff] exact match in snippet view article find links to article
Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m men women K-2 1000 m men K-4 500 m women K-4Gauss–Markov theorem (4,717 words) [view diff] no match in snippet view article find links to article
variable β K + 1 {\displaystyle \beta _{K+1}} with a newly introduced last column of X being unity i.e., X i ( K + 1 ) = 1 {\displaystyle X_{i(K+1)}=1} forNewton's identities (7,644 words) [view diff] case mismatch in snippet view article find links to article
including general relativity. Let x1, ..., xn be variables, denote for k ≥ 1 by pk(x1, ..., xn) the k-th power sum: p k ( x 1 , … , x n ) = ∑ i = 1 nVibration (7,235 words) [view diff] no match in snippet view article find links to article
defined by the following formula. X = F 0 k 1 ( 1 − r 2 ) 2 + ( 2 ζ r ) 2 . {\displaystyle X={F_{0} \over k}{1 \over {\sqrt {(1-r^{2})^{2}+(2\zeta r)^{2}}}}Lewandowski-Kurowicka-Joe distribution (425 words) [view diff] no match in snippet view article find links to article
k = 1 d − 1 ( 2 η − 2 + d − k ) ( d − k ) ∏ k = 1 d − 1 [ B ( η + ( d − k − 1 ) / 2 , η + ( d − k − 1 ) / 2 ) ] d − k {\displaystyle C=2^{\sum _{k=1}^{d-1}(2\etaGaussian elimination (4,368 words) [view diff] exact match in snippet view article find links to article
R_{i}} with r k , k R i − r i , k R k r k − 1 , k − 1 . {\textstyle {\frac {r_{k,k}R_{i}-r_{i,k}R_{k}}{r_{k-1,k-1}}}.} This produces a row echelon formBotond Storcz (378 words) [view diff] exact match in snippet view article find links to article
medals at the ICF Canoe Sprint World Championships with four golds (K-1 500 m: 1997, K-1 1000 m: 1997, K-4 500 m: 1997, K-4 1000 m: 1999), five silvers (K-2Canoeing at the 2000 Summer Olympics (131 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menBen Fouhy (485 words) [view diff] exact match in snippet view article find links to article
2000s. He competed in three Summer Olympics, winning a silver medal in the K-1 1000 m event at Athens in 2004. He also finished fourth in the 2008 OlympicsSchröder–Bernstein theorem (2,374 words) [view diff] no match in snippet view article find links to article
x = ∑ k = 1 ∞ a k ⋅ 10 − k {\displaystyle x=\sum _{k=1}^{\infty }a_{k}\cdot 10^{-k}} and y = ∑ k = 1 ∞ b k ⋅ 10 − k {\displaystyle y=\sum _{k=1}^{\inftyFunction of several complex variables (17,688 words) [view diff] no match in snippet view article find links to article
∂ k 1 + ⋯ + k n f ( ζ 1 , ζ 2 , … , ζ n ) ∂ z 1 k 1 ⋯ ∂ z n k n | ≤ M k 1 ! ⋯ k n ! r 1 k 1 ⋯ r n k n {\displaystyle \left|{\frac {\partial ^{k_{1}+\cdotsProjection (linear algebra) (5,806 words) [view diff] no match in snippet view article
i 2 1 ≤ i ≤ k 1 k + 1 ≤ i ≤ n − k 0 otherwise {\displaystyle \sigma _{i}={\begin{cases}{\sqrt {1+\gamma _{i}^{2}}}&1\leq i\leq k\\1&k+1\leq i\leqTriple DES (2,946 words) [view diff] no match in snippet view article find links to article
would be to use two keys ( K 1 , K 2 ) {\displaystyle (K1,K2)} instead of one, and encrypt each block twice: E K 2 ( E K 1 ( plaintext ) ) {\displaystyleArithmetico-geometric sequence (2,160 words) [view diff] no match in snippet view article find links to article
arithmetico-geometric series has the form S n = ∑ k = 1 n A k G k = ∑ k = 1 n ( a + ( k − 1 ) d ) b r k − 1 = b ∑ k = 0 n − 1 ( a + k d ) r k = a b + ( aMonotone convergence theorem (5,489 words) [view diff] no match in snippet view article find links to article
k ( x ) ≤ f k + 1 ( x ) {\displaystyle (1-\varepsilon )s(x)\leq f_{k}(x)\leq f_{k+1}(x)} so x ∈ B k + 1 s , ε . {\displaystyle x\in B_{k+1}^{s,\varepsilonNeighbor joining (2,881 words) [view diff] no match in snippet view article find links to article
) d ( a , b ) − ∑ k = 1 5 d ( a , k ) − ∑ k = 1 5 d ( b , k ) {\displaystyle Q_{1}(a,b)=(n-2)d(a,b)-\sum _{k=1}^{5}d(a,k)-\sum _{k=1}^{5}d(b,k)} = ( 5Saúl Craviotto (553 words) [view diff] exact match in snippet view article find links to article
the K-1 200 m event at the 2012 Summer Olympics in London, a gold medal (with Cristian Toro) in the K-2 200 m event and a bronze medal in the K-1 200Geometric process (858 words) [view diff] no match in snippet view article find links to article
k = 1 , 2 , … } {\displaystyle \{X_{k},k=1,2,\dots \}} , if they are independent and the cdf of X k {\displaystyle X_{k}} is given by F ( a k − 1 xDiagonalizable matrix (4,692 words) [view diff] no match in snippet view article find links to article
1 k 0 0 0 1 k 0 0 0 2 k ] [ 1 0 1 1 2 0 0 1 − 1 ] − 1 = [ 2 − 2 k − 1 + 2 k 2 − 2 k + 1 0 1 0 − 1 + 2 k 1 − 2 k − 1 + 2 k + 1 ] . {\displaystyleList of ICF Canoe Sprint World Championships medalists in paracanoe (365 words) [view diff] exact match in snippet view article find links to article
2010. Classed as K-1 A before 2015. First contested in 2010. Classed as K-1 TA before 2015. First contested in 2010. Classed as K-1 LTA before 2015. WasGreg Barton (415 words) [view diff] exact match in snippet view article find links to article
Championships with four golds (K-1 1000 m: 1987, K-1 10000 m: 1985, 1987, 1991), a silver (K-1 10000 m: 1990), and a bronze (K-1 1000 m: 1991). He received2018 ICF Canoe Sprint World Championships (1,178 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200, 500, 1000 or 5000 metresMultiplicative digital root (965 words) [view diff] exact match in snippet view article find links to article
k − 1 d i b i {\displaystyle n=\sum _{i=0}^{k-1}d_{i}b^{i}} and therefore F b ( n ) = ∏ i = 0 k − 1 d i = d k − 1 ∏ i = 0 k − 2 d i < d k − 1 b k − 1Dick Joyce (rower) (511 words) [view diff] exact match in snippet view article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanCauchy–Schwarz inequality (5,175 words) [view diff] no match in snippet view article find links to article
⟩ | 2 = | ∑ k = 1 n u k v ¯ k | 2 ≤ ⟨ u , u ⟩ ⟨ v , v ⟩ = ( ∑ k = 1 n u k u ¯ k ) ( ∑ k = 1 n v k v ¯ k ) = ∑ j = 1 n | u j | 2 ∑ k = 1 n | v k | 2Josef Dostál (canoeist) (328 words) [view diff] exact match in snippet view article
Summer Olympics in the K-4 1000 m event. He won the silver medal in the K-1 1000 metres event at the 2016 Summer Olympics in Rio de Janeiro. He was alsoRandom forest (6,483 words) [view diff] no match in snippet view article find links to article
function, or connection function is K k c c ( x , z ) = ∑ k 1 , … , k d , ∑ j = 1 d k j = k k ! k 1 ! ⋯ k d ! ( 1 d ) k ∏ j = 1 d 1 ⌈ 2 k j x j ⌉ = ⌈ 2 kKatrin Wagner-Augustin (325 words) [view diff] exact match in snippet view article find links to article
bronze (K-1 500 m: 2008). Wagner-Augustin also won 26 medals at the ICF Canoe Sprint World Championships with ten golds (K-1 1000 m: 2005, K-1 4 × 200Alternating series test (1,825 words) [view diff] no match in snippet view article find links to article
S k − L | ≤ | S k − S k + 1 | = a k + 1 . {\displaystyle \left|S_{k}-L\right\vert \leq \left|S_{k}-S_{k+1}\right\vert =a_{k+1}.\!} Suppose we are givenWrapped normal distribution (1,707 words) [view diff] no match in snippet view article find links to article
expansion for the logarithm: ln ( 1 + x ) = − ∑ k = 1 ∞ ( − 1 ) k k x k {\displaystyle \ln(1+x)=-\sum _{k=1}^{\infty }{\frac {(-1)^{k}}{k}}\,x^{k}} the logarithmicConvergence tests (2,222 words) [view diff] no match in snippet view article find links to article
case of p = 1 , k = 1 {\displaystyle p=1,k=1} yields the harmonic series, which diverges. The case of p = 2 , k = 1 {\displaystyle p=2,k=1} is the BaselHSL and HSV (10,785 words) [view diff] case mismatch in snippet view article find links to article
f ( n ) = L − a max ( − 1 , min ( k − 3 , 9 − k , 1 ) ) {\displaystyle f(n)=L-a\max(-1,\min(k-3,9-k,1))} where k , n ∈ R ≥ 0 {\displaystyle k,n\in \mathbbList of integrals of exponential functions (3,291 words) [view diff] exact match in snippet view article find links to article
_{k=1}^{n}{\left(-1\right)^{k-1}{\frac {d^{k-1}f\left(x\right)}{dx^{k-1}}}}+C} ∫ e − x ( f ( x ) − d n f ( x ) d x n ) d x = − e − x ∑ k = 1 n d k − 1 fHeat exchanger (9,485 words) [view diff] no match in snippet view article find links to article
where k 1 = γ / J 1 {\displaystyle k_{1}=\gamma /J_{1}} , k 2 = γ / J 2 {\displaystyle k_{2}=\gamma /J_{2}} , k = k 1 + k 2 {\displaystyle k=k_{1}+k_{2}}Haralambie Ivanov (233 words) [view diff] exact match in snippet view article find links to article
with four golds (K-1 4 x 500 m: 1963, K-2 500 m: 1963, K-2 1000 m: 1963, K-4 1000 m: 1966), a silver (K-4 1000 m: 1963), and a bronze (K-1 4 x 500 m: 1966)Fourier series (11,131 words) [view diff] no match in snippet view article find links to article
1 1 φ ( y ) cos ( 2 k + 1 ) π y 2 d y = ∫ − 1 1 ( a cos π y 2 cos ( 2 k + 1 ) π y 2 + a ′ cos 3 π y 2 cos ( 2 k + 1 ) π y 2 + ⋯ ) d y {\displaystyleArnaud Hybois (177 words) [view diff] exact match in snippet view article find links to article
m in 2011), a silver (K-1 4 x 200 m, 2014) and two bronze (K-1 4 x 200 m: 2009, K-1 500 m 2013). Hybois also competed in the K-1 500 m event at the 2008Standard RAID levels (4,551 words) [view diff] exact match in snippet view article find links to article
{\displaystyle D} as polynomials D = d k − 1 x k − 1 + d k − 2 x k − 2 + . . . + d 1 x + d 0 {\displaystyle \mathbf {D} =d_{k-1}x^{k-1}+d_{k-2}x^{k-2}+...+d_{1}x+d_{0}}Yokosuka MXY-7 Ohka (3,234 words) [view diff] exact match in snippet view article find links to article
had the engine of the Model 11 and the airframe of the Model 22. The Ohka K-1 was an unpowered trainer version with water ballast instead of warhead andHomothety (2,065 words) [view diff] no match in snippet view article find links to article
for k {\displaystyle k} : for k = 1 {\displaystyle k=1} one gets the identity mapping, for k = − 1 {\displaystyle k=-1} one gets the reflection at theCzech Republic at the Olympics (269 words) [view diff] exact match in snippet view article find links to article
Dostál Canoeing Men's K-1 1000 m Silver Jaroslav Kulhavý Cycling Men's cross-country Bronze Jiří Prskavec Canoeing Men's slalom K-1 Bronze Ondřej SynekLennart Klingström (144 words) [view diff] exact match in snippet view article find links to article
Sprint World Championships with three golds (K-1 4×500 m: 1948, 1950; K-4 1000 m: 1948) and a silver (K-1 500 m: 1950). Lennart Klingström. Sports-reference1997 ICF Canoe Sprint World Championships (97 words) [view diff] exact match in snippet view article find links to article
kayak events. Eight events were held for the women, all in kayak. Women's K-1 1000 m and K-2 1000 m events were added. This was the 28th championshipsBirgit Fischer (480 words) [view diff] exact match in snippet view article find links to article
Germany 1980 Moscow K-1 500 m 1988 Seoul K-2 500 m 1988 Seoul K-4 500 m 1988 Seoul K-1 500 m Representing Germany 1992 Barcelona K-1 500 m 1996 AtlantaSinc function (3,074 words) [view diff] exact match in snippet view article find links to article
k − 1 ∑ n = 1 2 k − 1 cos ( n − 1 / 2 2 k − 1 x ) , ∀ k ≥ 1 , {\displaystyle \prod _{n=1}^{k}\cos \left({\frac {x}{2^{n}}}\right)={\frac {1}{2^{k-1}}}\sumSI derived unit (387 words) [view diff] no match in snippet view article find links to article
conductivity m⋅kg⋅s−3⋅K−1 kelvin per watt K/W thermal resistance m−2⋅kg−1⋅s3⋅K reciprocal kelvin K−1 thermal expansion coefficient K−1 kelvin per metre K/mGroup velocity (3,504 words) [view diff] no match in snippet view article find links to article
x , t ) = cos ( k 1 x − ω 1 t ) + cos ( k 2 x − ω 2 t ) = 2 cos ( ( k 2 − k 1 ) x − ( ω 2 − ω 1 ) t 2 ) cos ( ( k 2 + k 1 ) x − ( ω 2 + ω 1 )F-test (2,188 words) [view diff] exact match in snippet view article find links to article
1 K n i ( Y ¯ i ⋅ − Y ¯ ) 2 / ( K − 1 ) {\displaystyle \sum _{i=1}^{K}n_{i}({\bar {Y}}_{i\cdot }-{\bar {Y}})^{2}/(K-1)} where Y ¯ i ⋅ {\displaystyle {\barSum-product number (973 words) [view diff] exact match in snippet view article find links to article
) k + 1 . {\displaystyle F_{b}(n)=k(b-1)^{k+1}.} This suggests that k ( b − 1 ) k + 1 ≥ n ≥ b k − 1 , {\displaystyle k(b-1)^{k+1}\geq n\geq b^{k-1},}Latent Dirichlet allocation (7,614 words) [view diff] no match in snippet view article find links to article
we get: A = ∑ k = 1 K α β C k ¬ n + V β {\displaystyle A=\sum _{k=1}^{K}{\frac {\alpha \beta }{C_{k}^{\neg n}+V\beta }}} B = ∑ k = 1 K C k d β C k ¬Solenoid (mathematics) (1,488 words) [view diff] no match in snippet view article
θ = ∑ k = 1 ∞ r k e 2 π i ω k t {\displaystyle \zeta =2\pi t,\quad re^{i\theta }=\sum _{k=1}^{\infty }r_{k}e^{2\pi i\omega _{k}t}} where ω k = 1 n 1 ⋯Czech Republic at the Olympics (269 words) [view diff] exact match in snippet view article find links to article
Dostál Canoeing Men's K-1 1000 m Silver Jaroslav Kulhavý Cycling Men's cross-country Bronze Jiří Prskavec Canoeing Men's slalom K-1 Bronze Ondřej SynekHarmonic number (5,594 words) [view diff] no match in snippet view article find links to article
u d u = ∫ 0 1 [ ∑ k = 1 n ( n k ) ( − u ) k − 1 ] d u = ∑ k = 1 n ( n k ) ∫ 0 1 ( − u ) k − 1 d u = ∑ k = 1 n ( n k ) ( − 1 ) k − 1 k . {\displaystyleNarcissistic number (1,082 words) [view diff] exact match in snippet view article find links to article
{N} } to be the following: F b ( n ) = ∑ i = 0 k − 1 d i k . {\displaystyle F_{b}(n)=\sum _{i=0}^{k-1}d_{i}^{k}.} where k = ⌊ log b n ⌋ + 1 {\displaystyleSum-product number (973 words) [view diff] exact match in snippet view article find links to article
) k + 1 . {\displaystyle F_{b}(n)=k(b-1)^{k+1}.} This suggests that k ( b − 1 ) k + 1 ≥ n ≥ b k − 1 , {\displaystyle k(b-1)^{k+1}\geq n\geq b^{k-1},}Recursion (3,677 words) [view diff] no match in snippet view article find links to article
{\displaystyle k\in \mathbb {N} } . Then F(k + 1) = f(F(k)) = f(G(k)) = G(k + 1). Hence F(k) = G(k) implies F(k + 1) = G(k + 1). By induction, F(n) = G(n) for allBeta function (4,110 words) [view diff] no match in snippet view article find links to article
adjusting indices: ( n k ) = 1 ( n + 1 ) B ( n − k + 1 , k + 1 ) . {\displaystyle {\binom {n}{k}}={\frac {1}{(n+1)\,\mathrm {B} (n-k+1,k+1)}}.} Moreover, for1st Army (German Empire) (625 words) [view diff] no match in snippet view article
The 1st Army (German: 1. Armee / Armeeoberkommando 1 / A.O.K. 1) was an army level command of the German Army in World War I. It was formed on mobilizationSquare root (6,182 words) [view diff] no match in snippet view article find links to article
e k + 1 p k + 1 2 e k + 1 … p n 2 e n = p 1 e 1 … p n e n p 1 … p k . {\displaystyle {\sqrt {p_{1}^{2e_{1}+1}\cdots p_{k}^{2e_{k}+1}p_{k+1}^{2e_{k+1}}\dots1994 ICF Canoe Sprint World Championships (211 words) [view diff] exact match in snippet view article find links to article
and men's and women's K-1) resumed at the 2010 championships.) and the 200 m events for C-1, C-2, and C-4 (men only), and K-1, K-2, and K-4 (both menNumerical methods for ordinary differential equations (3,916 words) [view diff] no match in snippet view article find links to article
form α k y n + k + α k − 1 y n + k − 1 + ⋯ + α 0 y n = h [ β k f ( t n + k , y n + k ) + β k − 1 f ( t n + k − 1 , y n + k − 1 ) + ⋯ + β 0 f ( t n ,Spectral radius (3,196 words) [view diff] no match in snippet view article find links to article
formula states that ρ ( A ) = lim k → ∞ ‖ A k ‖ 1 / k {\displaystyle \rho (A)=\lim _{k\to \infty }\|A^{k}\|^{1/k}} . Both of these results are shown belowDifferential operator (3,693 words) [view diff] no match in snippet view article find links to article
Laplacian operator, defined by Δ = ∇ 2 = ∑ k = 1 n ∂ 2 ∂ x k 2 . {\displaystyle \Delta =\nabla ^{2}=\sum _{k=1}^{n}{\frac {\partial ^{2}}{\partial x_{k}^{2}}}B-spline (5,717 words) [view diff] exact match in snippet view article find links to article
, k − 1 ( x ) + t i + k + 1 − x t i + k + 1 − t i + 1 B i + 1 , k − 1 ( x ) . {\displaystyle B_{i,k}(x):={\frac {x-t_{i}}{t_{i+k}-t_{i}}}B_{i,k-1}(x)+{\fracCompound Poisson distribution (2,307 words) [view diff] no match in snippet view article find links to article
( ∑ k = 1 ∞ α k λ ( z k − 1 ) ) , ( | z | ≤ 1 ) {\displaystyle P_{Y}(z)=\sum \limits _{i=0}^{\infty }P(Y=i)z^{i}=\exp \left(\sum \limits _{k=1}^{\inftyLatent Dirichlet allocation (7,614 words) [view diff] no match in snippet view article find links to article
we get: A = ∑ k = 1 K α β C k ¬ n + V β {\displaystyle A=\sum _{k=1}^{K}{\frac {\alpha \beta }{C_{k}^{\neg n}+V\beta }}} B = ∑ k = 1 K C k d β C k ¬Ernesto Hoost (1,810 words) [view diff] exact match in snippet view article find links to article
kickboxer. A four-time K-1 World Champion, Hoost is considered to be one of the greatest kickboxers of all time. Debuting in 1993 at the K-1 World Grand PrixQuadratic variation (1,539 words) [view diff] exact match in snippet view article find links to article
‖ P ‖ → 0 ∑ k = 1 n ( X t k − X t k − 1 ) 2 {\displaystyle [X]_{t}=\lim _{\Vert P\Vert \rightarrow 0}\sum _{k=1}^{n}(X_{t_{k}}-X_{t_{k-1}})^{2}} whereSteven Ferguson (253 words) [view diff] exact match in snippet view article find links to article
finished eighth in the K-2 1000 m event, but was eliminated in the heats of the K-1 500 m event. He competed again in the K-2 1000 m at the 2008 Summer OlympicsInterpolation attack (2,288 words) [view diff] no match in snippet view article find links to article
+ k 1 ) 3 = ( x 2 + k 1 2 ) ( x + k 1 ) = x 3 + k 1 2 x + x 2 k 1 + k 1 3 , {\displaystyle c_{1}=(x+k_{1})^{3}=(x^{2}+k_{1}^{2})(x+k_{1})=x^{3}+k_{1Linear independence (4,286 words) [view diff] no match in snippet view article find links to article
{v} _{k},} if k > 1 , {\displaystyle k>1,} and v 1 = 0 {\displaystyle \mathbf {v} _{1}=\mathbf {0} } if k = 1. {\displaystyle k=1.} Thus, a set ofBasel problem (8,692 words) [view diff] no match in snippet view article find links to article
be defined by S n ( x ) x := ∏ k = 1 n ( 1 − x 2 k 2 ⋅ π 2 ) {\displaystyle {\frac {S_{n}(x)}{x}}:=\prod \limits _{k=1}^{n}\left(1-{\frac {x^{2}}{k^{2}\cdotList of airships of the United States Navy (553 words) [view diff] exact match in snippet view article find links to article
airship) (ZNN-G) (ZGT) H class blimp (observation) J class blimp (trainer) K-1 blimp (experimental) K class blimp (anti-submarine patrol) (ZNP-K) (ZSG-2Shellsort (3,436 words) [view diff] exact match in snippet view article find links to article
of passes p {\displaystyle p} to Ω ( N ∑ k = 1 p h k − 1 / h k ) {\displaystyle \Omega (N\sum _{k=1}^{p}h_{k-1}/h_{k})} where h 0 = N {\displaystyle h_{0}=N}Multivariate normal distribution (9,619 words) [view diff] no match in snippet view article find links to article
k 1 {\displaystyle k_{1}} and k 2 {\displaystyle k_{2}} dimensional marginal distributions X {\displaystyle X} and Y {\displaystyle Y} , such that k 1Yoshihiro Akiyama (3,777 words) [view diff] exact match in snippet view article find links to article
for South Korea and for Japan at the 2002 Asian Games. He is the former K-1 HERO's Light Heavyweight Grand Prix Tournament Champion. Before his professional1995 ICF Canoe Sprint World Championships (102 words) [view diff] exact match in snippet view article find links to article
Gold Time Silver Time Bronze Time K-1 200 m Piotr Markiewicz (POL) Sergey Kalesnik (BLR) Renn Crichlow (CAN) K-1 500 m Piotr Markiewicz (POL) KnutEast Germany at the 1980 Summer Olympics (2,024 words) [view diff] exact match in snippet view article find links to article
Men's K-1 1000m Gold Rüdiger Helm Bernd Olbricht Harald Marg Bernd Duvigneau Canoeing Men's K-4 1000m Gold Birgit Fischer Canoeing Women's K-1 500m GoldBox spread (1,710 words) [view diff] no match in snippet view article find links to article
consider the put/call parity equation at two different strike prices K 1 {\displaystyle K_{1}} and K 2 {\displaystyle K_{2}} . The stock price S will disappearPerfect digit-to-digit invariant (1,095 words) [view diff] exact match in snippet view article find links to article
base b {\displaystyle b} as the k-digit number d k − 1 d k − 2 . . . d 1 d 0 {\displaystyle d_{k-1}d_{k-2}...d_{1}d_{0}} where each digit d i {\displaystyleButterworth filter (4,135 words) [view diff] no match in snippet view article find links to article
recursion formula a k + 1 a k = cos ( k γ ) sin ( ( k + 1 ) γ ) {\displaystyle {\frac {a_{k+1}}{a_{k}}}={\frac {\cos(k\gamma )}{\sin((k+1)\gamma )}}} andDouble factorial (4,286 words) [view diff] exact match in snippet view article find links to article
while for odd n it is n ! ! = ∏ k = 1 n + 1 2 ( 2 k − 1 ) = n ( n − 2 ) ( n − 4 ) ⋯ 3 ⋅ 1 . {\displaystyle n!!=\prod _{k=1}^{\frac {n+1}{2}}(2k-1)=n(n-2)(n-4)\cdotsMass–energy equivalence (11,628 words) [view diff] no match in snippet view article find links to article
energy K by an additive constant, which gives K 0 − K 1 = E ( 1 1 − v 2 c 2 − 1 ) {\displaystyle K_{0}-K_{1}=E\left({\frac {1}{\sqrt {1-{\frac {v^{2}}{c^{2}}}}}}-1\right)}Inclusion–exclusion principle (6,851 words) [view diff] no match in snippet view article find links to article
k = 1 n ( − 1 ) k + 1 ( ∑ 1 ⩽ i 1 < ⋯ < i k ⩽ n | A i 1 ∩ ⋯ ∩ A i k | ) {\displaystyle \left|\bigcup _{i=1}^{n}A_{i}\right|=\sum _{k=1}^{n}(-1)^{k+1}\left(\sumMultinomial theorem (2,059 words) [view diff] no match in snippet view article find links to article
power: ( x 1 + x 2 + ⋯ + x m ) n = ∑ k 1 + k 2 + ⋯ + k m = n k 1 , k 2 , ⋯ , k m ≥ 0 ( n k 1 , k 2 , … , k m ) x 1 k 1 ⋅ x 2 k 2 ⋯ x m k m {\displaystyleTom Liebscher (84 words) [view diff] exact match in snippet view article find links to article
96 kg (212 lb) Sport Country Germany Sport Sprint kayak Event(s) K-1 200 m, K-1 500 m, K-1 1000 m, K-2 200 m, K-4 500 m, K-4 1000 m Club Kanu Club DresdenScale (map) (5,382 words) [view diff] no match in snippet view article
should be within 4 parts in 10,000, or 0.04%, corresponding to k = 1.0004 {\displaystyle k=1.0004} . Since sec φ {\displaystyle \sec \varphi } attainsNewton's method (8,748 words) [view diff] no match in snippet view article find links to article
x_{2}-3~\end{bmatrix}}_{k}\end{aligned}}} and X k + 1 = X k − C k + 1 {\displaystyle X_{k+1}~=~X_{k}-C_{k+1}} The iterations should be repeated until [Quaternion group (3,716 words) [view diff] no match in snippet view article find links to article
isomorphic to the eight-element subset { 1 , i , j , k , − 1 , − i , − j , − k } {\displaystyle \{1,i,j,k,-1,-i,-j,-k\}} of the quaternions under multiplicationTamara Csipes (244 words) [view diff] exact match in snippet view article find links to article
gold medal in Women's K-4 500 metres, and a silver medal in the Women's K-1 500 metres At the 2010 ICF Canoe Sprint World Championships in Poznań, sheNarayana number (1,088 words) [view diff] exact match in snippet view article find links to article
coefficients: N ( n , k ) = 1 n ( n k ) ( n k − 1 ) {\displaystyle \operatorname {N} (n,k)={\frac {1}{n}}{n \choose k}{n \choose k-1}} The first eight rowsJapanese submarine I-15 (2,880 words) [view diff] exact match in snippet view article find links to article
Harbor, operated off the United States West Coast, and took part in Operation K-1, the Aleutian Islands campaign, and the Guadalcanal campaign, including theScale (map) (5,382 words) [view diff] no match in snippet view article
should be within 4 parts in 10,000, or 0.04%, corresponding to k = 1.0004 {\displaystyle k=1.0004} . Since sec φ {\displaystyle \sec \varphi } attainsTechnology (10,447 words) [view diff] no match in snippet view article find links to article
Yael; Chazan, Michael; Arnold, M.; Aumaître, G.; Bourlès, D.; Keddadouche, K. (1 May 2021). "Magnetostratigraphy and cosmogenic dating of Wonderwerk Cave:Quartile (2,225 words) [view diff] no match in snippet view article find links to article
{\displaystyle x_{k}} and x k + 1 {\displaystyle x_{k+1}} . q ( p / 4 ) = x k + α ( x k + 1 − x k ) {\displaystyle q(p/4)=x_{k}+\alpha (x_{k+1}-x_{k})} , where kJapanese submarine I-15 (2,880 words) [view diff] exact match in snippet view article find links to article
Harbor, operated off the United States West Coast, and took part in Operation K-1, the Aleutian Islands campaign, and the Guadalcanal campaign, including theSatisfaction equilibrium (3,856 words) [view diff] exact match in snippet view article find links to article
× A k − 1 × A k + 1 × … , × A K → 2 A k {\displaystyle f_{k}:{\mathcal {A}}_{1}\times \ldots \times {\mathcal {A}}_{k-1}\times {\mathcal {A}}_{k+1}\timesEinar Rasmussen (200 words) [view diff] exact match in snippet view article find links to article
golds (K-1 10000 m: 1981, 1983; K-2 1000 m: 1979, K-4 10000 m: 1975), three silvers (K-1 10000 m: 1979, 1982; K-2 1000 m: 1978), and three bronzes (K-1 1000Ball (mathematics) (1,840 words) [view diff] no match in snippet view article
r ) = π k k ! r 2 k , V 2 k + 1 ( r ) = 2 k + 1 π k ( 2 k + 1 ) ! ! r 2 k + 1 = 2 ( k ! ) ( 4 π ) k ( 2 k + 1 ) ! r 2 k + 1 . {\displaystyleTrigonometric functions (10,611 words) [view diff] no match in snippet view article find links to article
square ( t ) = 4 π ∑ k = 1 ∞ sin ( ( 2 k − 1 ) t ) 2 k − 1 . {\displaystyle f_{\text{square}}(t)={\frac {4}{\pi }}\sum _{k=1}^{\infty }{\sin {\bigIrwin–Hall distribution (1,358 words) [view diff] no match in snippet view article find links to article
identically distributed U(0, 1) random variables: X = ∑ k = 1 n U k . {\displaystyle X=\sum _{k=1}^{n}U_{k}.} The probability density function (pdf) forBates distribution (695 words) [view diff] no match in snippet view article find links to article
variables on the unit interval, Uk: X = 1 n ∑ k = 1 n U k . {\displaystyle X={\frac {1}{n}}\sum _{k=1}^{n}U_{k}.} The equation defining the probabilityEMER-K1 (724 words) [view diff] exact match in snippet view article find links to article
The EMER K-1, sometimes known as the EMER K1 or EMERK-1, was a prototype bullpup assault rifle made in Myanmar by the Electrical Mechanical and EngineeringHungary at the 1956 Summer Olympics (256 words) [view diff] exact match in snippet view article find links to article
Farkas József Hunics C-2 10000 m — 55:15.6 Lajos Kiss K-1 1000 m 4:35.8 2 Q 4:16.2 Ferenc Hatlaczky K-1 10000 m — 47:53.3 Imre Vágyóczky Zoltán Szigeti K-2Outer product (2,942 words) [view diff] no match in snippet view article find links to article
{\displaystyle \mathbf {u} ,\mathbf {v} } with dimensions ( k 1 , k 2 , … , k m ) {\displaystyle (k_{1},k_{2},\dots ,k_{m})} and ( l 1 , l 2 , … , l n ) {\displaystyle2011 ICF Canoe Sprint World Championships (3,160 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200 metres (660 ft), 500Motzkin number (846 words) [view diff] exact match in snippet view article find links to article
This gives ∑ k = 0 n C k = 1 + ∑ k = 1 n ( n k ) M k − 1 . {\displaystyle \sum _{k=0}^{n}C_{k}=1+\sum _{k=1}^{n}{\binom {n}{k}}M_{k-1}.} The generating functionCanoeing at the 1988 Summer Olympics (51 words) [view diff] exact match in snippet view article find links to article
Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m men women K-2 1000 m men K-4 500 m women K-4Mark and recapture (3,122 words) [view diff] no match in snippet view article find links to article
K + 1 ) k + 1 − 1 {\displaystyle {\hat {N}}_{C}={\frac {(n+1)(K+1)}{k+1}}-1} The example (n, K, k) = (10, 15, 5) gives N ^ C = ( n + 1 ) ( K + 1 ) k +SN1 reaction (1,970 words) [view diff] no match in snippet view article find links to article
= k 1 [ tBuBr ] − k − 1 [ tBu + ] [ Br − ] − k 2 [ tBu + ] [ H 2 O ] {\displaystyle {\frac {d[{\text{tBu}}^{+}]}{dt}}=0=k_{1}[{\text{tBuBr}}]-k_{-1Friedmann–Lemaître–Robertson–Walker metric (3,622 words) [view diff] no match in snippet view article find links to article
r ) = { k − 1 sin ( r k ) , k > 0 r , k = 0 | k | − 1 sinh ( r | k | ) , k < 0. {\displaystyle S_{k}(r)={\begin{cases}{\sqrt {k}}^{\,-1}\sin(r{\sqrtApéry's constant (3,021 words) [view diff] no match in snippet view article find links to article
= 1 4 ∑ k = 1 ∞ ( − 1 ) k − 1 ( k − 1 ) ! 3 ( 56 k 2 − 32 k + 5 ) ( 2 k − 1 ) 2 ( 3 k ) ! . {\displaystyle \zeta (3)={\frac {1}{4}}\sum _{k=1}^{\inftyIntegral transform (1,278 words) [view diff] no match in snippet view article find links to article
kernel K − 1 ( u , t ) {\displaystyle K^{-1}(u,t)} which (roughly speaking) yields an inverse transform: f ( t ) = ∫ u 1 u 2 ( T f ) ( u ) K − 1 ( u ,Cubic Hermite spline (3,102 words) [view diff] exact match in snippet view article find links to article
m k = ( 1 − c ) p k + 1 − p k − 1 x k + 1 − x k − 1 {\displaystyle {\boldsymbol {m}}_{k}=(1-c){\frac {{\boldsymbol {p}}_{k+1}-{\boldsymbol {p}}_{k-1}}{x_{k+1}-x_{k-1}}}}Deficient number (560 words) [view diff] exact match in snippet view article find links to article
, p k − 1 {\displaystyle 1,p,p^{2},\dots ,p^{k-1}} which sum to p k − 1 p − 1 {\displaystyle {\frac {p^{k}-1}{p-1}}} , which is at most p k − 1 {\displaystyleKatrin Borchert (641 words) [view diff] exact match in snippet view article find links to article
500 m for Germany) and two bronzes (both Australia, 1996: K-2 500 m, 2000: K-1 500 m). During her career, she has represented four countries: East GermanyColossally abundant number (1,635 words) [view diff] no match in snippet view article find links to article
that for all k > 1, σ ( n ) n 1 + ε ≥ σ ( k ) k 1 + ε {\displaystyle {\frac {\sigma (n)}{n^{1+\varepsilon }}}\geq {\frac {\sigma (k)}{k^{1+\varepsilonReflexive space (6,409 words) [view diff] no match in snippet view article find links to article
{\displaystyle x_{\varnothing },} the root of the tree, followed, for k = 1 , … , n , {\displaystyle k=1,\ldots ,n,} by a family of s k {\displaystyle s^{k}} 2 vectorsN-sphere (7,312 words) [view diff] exact match in snippet view article find links to article
r 2 + ∑ k = 1 n − 1 r 2 ( ∏ m = 1 k − 1 sin 2 ( φ m ) ) d φ k 2 {\displaystyle ds^{2}=dr^{2}+\sum _{k=1}^{n-1}r^{2}\left(\prod _{m=1}^{k-1}\sin ^{2}\left(\varphiBessel function (12,179 words) [view diff] no match in snippet view article find links to article
π ∑ k = 0 n − 1 ( n − k − 1 ) ! k ! ( z 2 4 ) k + 2 π J n ( z ) ln z 2 − ( z 2 ) n π ∑ k = 0 ∞ ( ψ ( k + 1 ) + ψ ( n + k + 1 ) ) ( − z 2 4 ) k k ! (Simon Dickie (722 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanJoule per mole (467 words) [view diff] no match in snippet view article find links to article
particle, 0.239 kcal·mol−1, or 83.6 cm−1. At room temperature (25 °C, or 298.15 K) 1 kJ·mol−1 is approximately equal to 0.4034 k B T {\displaystyle k_{B}T}Nicole Reinhardt (276 words) [view diff] exact match in snippet view article find links to article
ICF Canoe Sprint World Championships with eight golds (K-1 500 m: 2005, 2011, K-2 200 m: 2007, K-1 4 × 200 m: 2009, 2010, 2011, K-2 500 m: 2007, K-4 200Householder transformation (3,241 words) [view diff] no match in snippet view article find links to article
− sgn ( a k + 1 , k k ) ∑ j = k + 1 n ( a j k k ) 2 r = 1 2 ( α 2 − a k + 1 , k k α ) v 1 k = v 2 k = ⋯ = v k k = 0 v k + 1 k = a k + 1 , k k − α 2East Germany at the 1976 Summer Olympics (932 words) [view diff] exact match in snippet view article find links to article
Helm Canoeing men's K-1 1000 m Gold Joachim Mattern Bernd Olbricht Canoeing men's K-2 500 m Gold Carola Zirzow Canoeing women's K-1 500 m Gold Klaus-JürgenDeterminant (13,785 words) [view diff] no match in snippet view article find links to article
c n − m = − 1 m ∑ k = 1 m c n − m + k tr ( A k ) ( 1 ≤ m ≤ n ) . {\displaystyle c_{n}=1;~~~c_{n-m}=-{\frac {1}{m}}\sum _{k=1}^{m}c_{n-m+k}\operatornameTímea Paksy (200 words) [view diff] exact match in snippet view article find links to article
golds (K-1 200 m: 2006, K-2 200 m: 2003, K-2 1000 m: 2003, K-4 200 m: 2002, 2006; K-4 500 m: 2006, K-4 1000 m: 2005, 2006, 2007), six silvers (K-1 4 × 200Quasinorm (936 words) [view diff] no match in snippet view article find links to article
+ ‖ y ‖ ) {\displaystyle \|x+y\|\leq K(\|x\|+\|y\|)} for some K > 1. {\displaystyle K>1.} A quasi-seminorm on a vector space X {\displaystyle X} is aEuclid's theorem (3,429 words) [view diff] no match in snippet view article find links to article
integers) is equivalent to the statement that we have ∏ p ∈ P k 1 1 − 1 p = ∑ n ∈ N k 1 n , {\displaystyle \prod _{p\in P_{k}}{\frac {1}{1-{\frac {1}{p}}}}=\sumDouble factorial (4,286 words) [view diff] exact match in snippet view article find links to article
while for odd n it is n ! ! = ∏ k = 1 n + 1 2 ( 2 k − 1 ) = n ( n − 2 ) ( n − 4 ) ⋯ 3 ⋅ 1 . {\displaystyle n!!=\prod _{k=1}^{\frac {n+1}{2}}(2k-1)=n(n-2)(n-4)\cdotsOreste Perri (200 words) [view diff] exact match in snippet view article find links to article
Championships with four golds (K-1 1000 m: 1975 (tied with Poland's Grzegorz Śledziewski, K-1 10000 m: 1974, 1975, 1977) and two bronzes (K-1 1000 m: 1974, 1977)Bálint Kopasz (79 words) [view diff] exact match in snippet view article find links to article
(born 20 June 1997) is a Hungarian sprint canoeist. He competed in the men's K-1 1000 metres event at the 2016 Summer Olympics. He won the same event in theLaurent series (2,675 words) [view diff] exact match in snippet view article find links to article
) n − k − 1 d z = ∮ γ ∑ n = − ∞ ∞ b n ( z − c ) n − k − 1 d z . {\displaystyle \oint _{\gamma }\,\sum _{n=-\infty }^{\infty }a_{n}(z-c)^{n-k-1}\,dz=\ointDynamic programming (9,282 words) [view diff] no match in snippet view article find links to article
equation: J k ∗ ( x n − k ) = min u n − k { f ^ ( x n − k , u n − k ) + J k − 1 ∗ ( g ^ ( x n − k , u n − k ) ) } {\displaystyle J_{k}^{\ast }\left(\mathbfB+ tree (3,417 words) [view diff] no match in snippet view article find links to article
K + 1 ) / 2 ⌉ {\displaystyle \lceil (K+1)/2\rceil } items new node has ⌊ ( K + 1 ) / 2 ⌋ {\displaystyle \lfloor (K+1)/2\rfloor } items Copy ⌈ ( K + 1Pentax K-1 (522 words) [view diff] exact match in snippet view article find links to article
The Pentax K-1 is the first production Pentax full-frame digital SLR camera. As the flagship model of the Pentax K-mount system, it includes several newInterspecific competition (3,334 words) [view diff] no match in snippet view article find links to article
respectively: d N 1 d t = r 1 N 1 K 1 − N 1 − α N 2 K 1 {\displaystyle {dN_{1} \over dt}=r_{1}N_{1}{K_{1}-N_{1}-\alpha N_{2} \over K_{1}}} d N 2 d t = r 2 N 2 KCoxeter group (3,763 words) [view diff] no match in snippet view article find links to article
a 3-cycle : ( k k + 1 ) ⋅ ( k + 1 k + 2 ) = ( k k + 2 k + 1 ) {\displaystyle (k~~k+1)\cdot (k+1~~k+2)=(k~~k+2~~k+1)} . Therefore S n +Perfect power (1,027 words) [view diff] no match in snippet view article find links to article
formally, n is a perfect power if there exist natural numbers m > 1, and k > 1 such that mk = n. In this case, n may be called a perfect kth power. IfDeficient number (560 words) [view diff] exact match in snippet view article find links to article
, p k − 1 {\displaystyle 1,p,p^{2},\dots ,p^{k-1}} which sum to p k − 1 p − 1 {\displaystyle {\frac {p^{k}-1}{p-1}}} , which is at most p k − 1 {\displaystyleSaitama Super Arena (1,366 words) [view diff] exact match in snippet view article find links to article
2008 featured Dream and K-1 fights Dynamite!! 2009 featured fights by Dream, Sengoku and K-1 Dynamite!! 2010 featured Dream and K-1 fights. Fight For Japan:Togo at the 2008 Summer Olympics (164 words) [view diff] exact match in snippet view article find links to article
in Beijing, China from August 8 to August 24, 2008. At the men's slalom K-1 event, Benjamin Boukpeti won a bronze medal in canoeing, the first OlympicOreste Perri (200 words) [view diff] exact match in snippet view article find links to article
Championships with four golds (K-1 1000 m: 1975 (tied with Poland's Grzegorz Śledziewski, K-1 10000 m: 1974, 1975, 1977) and two bronzes (K-1 1000 m: 1974, 1977)Householder transformation (3,241 words) [view diff] no match in snippet view article find links to article
− sgn ( a k + 1 , k k ) ∑ j = k + 1 n ( a j k k ) 2 r = 1 2 ( α 2 − a k + 1 , k k α ) v 1 k = v 2 k = ⋯ = v k k = 0 v k + 1 k = a k + 1 , k k − α 2Hamiltonian mechanics (9,287 words) [view diff] no match in snippet view article find links to article
2 ∑ k = 1 N ( m k r ˙ k ( q , q ˙ ) ⋅ r ˙ k ( q , q ˙ ) ) {\displaystyle T({\boldsymbol {q}},{\boldsymbol {\dot {q}}})={\frac {1}{2}}\sum _{k=1}^{N}{\bigglGéza Csapó (309 words) [view diff] exact match in snippet view article find links to article
with six golds (K-1 500 m: 1973, 1975; K-1 1000 m: 1973, 1974; K-1 4 x 500 m: 1971, K-2 10000 m: 1973), two silvers (K-1 500 m: 1973, K-1 4 x 500 m: 1973)Banach space (17,005 words) [view diff] no match in snippet view article find links to article
proved that if c − 2 ∑ k = 1 n ‖ x k ‖ 2 ≤ Ave ± ‖ ∑ k = 1 n ± x k ‖ 2 ≤ c 2 ∑ k = 1 n ‖ x k ‖ 2 {\displaystyle c^{-2}\sum _{k=1}^{n}\|x_{k}\|^{2}\leqPolylogarithm (10,139 words) [view diff] no match in snippet view article find links to article
series in s: Li s ( z ) = ∑ k = 1 ∞ z k k s = z + z 2 2 s + z 3 3 s + ⋯ {\displaystyle \operatorname {Li} _{s}(z)=\sum _{k=1}^{\infty }{z^{k} \over k^{s}}=z+{z^{2}Big O notation (8,444 words) [view diff] no match in snippet view article find links to article
below (with constant factor k 1 {\displaystyle k_{1}} ) ∃ k 1 > 0 ∃ k 2 > 0 ∃ n 0 ∀ n > n 0 : {\displaystyle \exists k_{1}>0\,\exists k_{2}>0\,\existsPolar decomposition (4,254 words) [view diff] no match in snippet view article find links to article
= ‖ U k − 1 ‖ 1 ‖ U k − 1 ‖ ∞ ‖ U k ‖ 1 ‖ U k ‖ ∞ 4 {\displaystyle \gamma _{k}={\sqrt[{4}]{\frac {\left\|U_{k}^{-1}\right\|_{1}\left\|U_{k}^{-1}\right\|_{\inftyDirichlet process (4,861 words) [view diff] no match in snippet view article find links to article
k = 1 ∞ β k δ x k ( x ) {\displaystyle f(x)=\sum _{k=1}^{\infty }\beta _{k}\delta _{x_{k}}(x)} , where { x k } k = 1 ∞ {\displaystyle \{x_{k}\}_{k=1}^{\inftyAcid dissociation constant (11,513 words) [view diff] no match in snippet view article find links to article
A−, so [ H + ] 2 = K 1 K 2 {\displaystyle [{\ce {H+}}]^{2}=K_{1}K_{2}} Therefore, taking cologarithms, the pH is given by p I = p K 1 + p K 2 2 {\displaystyleCaroline Evers-Swindell (555 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanCompressor (6,856 words) [view diff] exact match in snippet view article find links to article
− T 1 ) k − 1 = k R T 1 k − 1 [ ( P 2 P 1 ) ( k − 1 ) / k − 1 ] {\displaystyle W_{comp,in}={\frac {kR(T_{2}-T_{1})}{k-1}}={\frac {kRT_{1}}{k-1}}\left[\left({\fracDanyon Loader (359 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanAppell's equation of motion (1,565 words) [view diff] no match in snippet view article find links to article
the particle accelerations squared, S = 1 2 ∑ k = 1 N m k a k 2 , {\displaystyle S={\frac {1}{2}}\sum _{k=1}^{N}m_{k}\mathbf {a} _{k}^{2}\,,} where theList of mathematical constants (3,561 words) [view diff] no match in snippet view article find links to article
root of x k + 1 = 2 k + 1 ( x − 1 ) , β k = 2 − α k k + 1 − k α k {\displaystyle x^{k+1}=2^{k+1}(x-1),\beta _{k}={\frac {2-\alpha _{k}}{k+1-k\alpha _{k}}}}Pythagorean theorem (12,704 words) [view diff] no match in snippet view article find links to article
equation ‖ ∑ k = 1 n v k ‖ 2 = ∑ k = 1 n ‖ v k ‖ 2 {\displaystyle {\biggl \|}\sum _{k=1}^{n}\mathbf {v} _{k}{\biggr \|}^{2}=\sum _{k=1}^{n}\|\mathbfVladimir Parfenovich (446 words) [view diff] exact match in snippet view article find links to article
he entered: K-1 500 m, K-2 500 m and K-2 1000 m. He also won twelve medals at the ICF Canoe Sprint World Championships, with nine golds (K-1 500 m: 1979Nikolay Astapkovich (146 words) [view diff] exact match in snippet view article find links to article
10000 m: 1983), four silvers (K-1 4 x 500 m: 1974, K-2 500 m: 1977, K-2 10000 m: 1979, K-4 1000 m: 1974) and a bronze (K-1 10000 m: 1982). Динамо. ЭнциклопедияMatrix-exponential distribution (379 words) [view diff] no match in snippet view article find links to article
given by E ( X k ) = ( − 1 ) k + 1 k ! α T − ( k + 1 ) s . {\displaystyle \operatorname {E} (X^{k})=(-1)^{k+1}k!\mathbf {\alpha } T^{-(k+1)}\mathbf {s}Vandermonde matrix (5,263 words) [view diff] no match in snippet view article find links to article
v o l ( F ) = 1 k ! ∏ 1 ≤ m < n ≤ k + 1 ( t i n − t i m ) . {\displaystyle \mathrm {nvol} (F)={\frac {1}{k!}}\prod _{1\leq m<n\leq k+1}{(t_{i_{n}}-t_{i_{m}})}Pentax K-1 (522 words) [view diff] exact match in snippet view article find links to article
The Pentax K-1 is the first production Pentax full-frame digital SLR camera. As the flagship model of the Pentax K-mount system, it includes several newDiscrete uniform distribution (772 words) [view diff] no match in snippet view article find links to article
k, the sample size, is N ^ = k + 1 k m − 1 = m + m k − 1 {\displaystyle {\hat {N}}={\frac {k+1}{k}}m-1=m+{\frac {m}{k}}-1} . This can be seen as a veryArithmetic coding (5,380 words) [view diff] no match in snippet view article find links to article
the computation of the product ∏ k = 1 n f k = ∏ k = 1 A f k f k . {\displaystyle \prod _{k=1}^{n}f_{k}=\prod _{k=1}^{A}f_{k}^{f_{k}}.} Applying log2Analysis of variance (7,645 words) [view diff] no match in snippet view article find links to article
{\displaystyle b} . Thus, v k = [ g 1 ( Z k , 1 ) , g 2 ( Z k , 2 ) , … , g B ( Z k , B ) ] {\displaystyle v_{k}=[g_{1}(Z_{k,1}),g_{2}(Z_{k,2}),\ldots ,g_{B}(Z_{kFock state (5,644 words) [view diff] no match in snippet view article find links to article
| n k 1 , n k 2 . . . ⟩ = ( b k 1 † ) n k 1 n k 1 ! ( b k 2 † ) n k 2 n k 2 ! . . . | 0 k 1 , 0 k 2 , . . . ⟩ {\displaystyle |n_{\mathbf {k} _{1}},n_{\mathbfGrzegorz Śledziewski (201 words) [view diff] exact match in snippet view article find links to article
with three golds (K-1 1000 m: 1971, 1975 (tied with Italy's Oreste Perri); K-2 500 m: 1974), five silvers (K-1 500 m: 1970, 1977; K-1 1000 m: 1973, 1974;Absolute convergence (5,193 words) [view diff] no match in snippet view article find links to article
have 0 ≤ ∑ k = 1 n ( a k + | a k | ) ≤ ∑ k = 1 n 2 | a k | . {\displaystyle 0\leq \sum _{k=1}^{n}(a_{k}+\left|a_{k}\right|)\leq \sum _{k=1}^{n}2\left|a_{k}\right|Lars Glassér (305 words) [view diff] exact match in snippet view article find links to article
five golds (K-1 4 x 500 m: 1948, 1950, 1954; K-2 500 m: 1950, K-2 1000 m: 1950) and one silver (K-1 500 m: 1948). Note that the K-1 500 m, K-1 4 x 500 mHadamard matrix (3,698 words) [view diff] exact match in snippet view article find links to article
k − 1 H 2 k − 1 H 2 k − 1 − H 2 k − 1 ] = H 2 ⊗ H 2 k − 1 , {\displaystyle H_{2^{k}}={\begin{bmatrix}H_{2^{k-1}}&H_{2^{k-1}}\\H_{2^{k-1}}&-H_{2^{k-1Bijective numeration (2,021 words) [view diff] exact match in snippet view article find links to article
− 1 d k − 1 d k − 1 = d k − 1 ¯ {\displaystyle \ldots d_{k-1}d_{k-1}d_{k-1}={\overline {d_{k-1}}}} . This is because the Euler summation g ( d k − 1 ¯André Wohllebe (240 words) [view diff] exact match in snippet view article find links to article
he won three medals with a gold (1992: K-4 1000 m) and two bronzes (1988: K-1 1000 m, K-4 1000 m). He was born in Berlin. Wohllebe also won eighteen medalsOperation K (1,326 words) [view diff] no match in snippet view article find links to article
Operation K (K作戦, Kē-Sakusen) was a Japanese naval operation in World War II, intended as reconnaissance of Pearl Harbor and disruption of repair and salvageBeta negative binomial distribution (1,541 words) [view diff] no match in snippet view article find links to article
+ r − 1 k ) ( 1 − q ) k q r ⋅ q α − 1 ( 1 − q ) β − 1 B ( α , β ) d q = 1 B ( α , β ) ( k + r − 1 k ) ∫ 0 1 q α + r − 1 ( 1 − q ) β + k − 1 d q {\displaystyleGeorgina Evers-Swindell (552 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanVan der Waerden test (772 words) [view diff] exact match in snippet view article find links to article
1 > χ α , k − 1 2 {\displaystyle T_{1}>\chi _{\alpha ,k-1}^{2}} where Χα,k − 12 is the α-quantile of the chi-squared distribution with k − 1 degrees ofLjung–Box test (870 words) [view diff] no match in snippet view article find links to article
correlation. The test statistic is: Q = n ( n + 2 ) ∑ k = 1 h ρ ^ k 2 n − k {\displaystyle Q=n(n+2)\sum _{k=1}^{h}{\frac {{\hat {\rho }}_{k}^{2}}{n-k}}} whereHeat capacity (2,775 words) [view diff] no match in snippet view article find links to article
The SI unit for heat capacity of an object is joule per kelvin (J/K or J⋅K−1). Since an increment of temperature of one degree Celsius is the same asSecond-order logic (4,387 words) [view diff] no match in snippet view article find links to article
{\displaystyle \phi } is a Π k 1 {\displaystyle \Pi _{k}^{1}} formula, and similar, Π k + 1 1 {\displaystyle \Pi _{k+1}^{1}} has the form ∀ R 0 … ∀ RFernando Pimenta (832 words) [view diff] exact match in snippet view article find links to article
silvers (K-1 5000 metres and K-4 1000 metres) at the European Championships, held in Portugal's Montemor-o-Velho racing course, and two golds (K-1 500 andInverse trigonometric functions (10,605 words) [view diff] no match in snippet view article find links to article
2 ∑ n = 0 ∞ ∏ k = 1 n 2 k z 2 ( 2 k + 1 ) ( 1 + z 2 ) . {\displaystyle \arctan(z)={\frac {z}{1+z^{2}}}\sum _{n=0}^{\infty }\prod _{k=1}^{n}{\fracShell integration (549 words) [view diff] no match in snippet view article find links to article
rectangle, its made by obtaining a cylinder of radius a + ( k + 1 ) Δ x {\displaystyle a+(k+1)\Delta x} with height f ( a + k Δ x ) {\displaystyle f(a+k\DeltaPerfect number (5,168 words) [view diff] exact match in snippet view article find links to article
is at most k − 1 2 . {\displaystyle {\frac {k-1}{2}}.} At least one of the prime powers dividing N exceeds 1062. N < 2 ( 4 k + 1 − 2 k + 1 ) {\displaystyle