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Find link is a tool written by Edward Betts.searching for K-1 508 found (14413 total)
alternate case: k-1
Standard deviation
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k − 1 + k − 1 k ( x k − A k − 1 ) 2 = Q k − 1 + ( x k − A k − 1 ) ( x k − A k ) {\displaystyle {\begin{aligned}Q_{0}&=0\\Q_{k}&=Q_{k-1}+{\frac {k-1Fibonacci sequence (13,044 words) [view diff] no match in snippet view article find links to article
k = 1 ∞ q k 1 − q k , {\displaystyle \textstyle L(q):=\sum _{k=1}^{\infty }{\frac {q^{k}}{1-q^{k}}},} since 1 F 2 k = 5 ( ψ 2 k 1 − ψ 2 k − ψ 4 k 1 −Poisson distribution (11,203 words) [view diff] no match in snippet view article find links to article
distribution is Pr ( X 1 = k 1 , X 2 = k 2 ) = exp ( − λ 1 − λ 2 − λ 3 ) λ 1 k 1 k 1 ! λ 2 k 2 k 2 ! ∑ k = 0 min ( k 1 , k 2 ) ( k 1 k ) ( k 2 k ) k ! ( λBinomial distribution (7,554 words) [view diff] no match in snippet view article find links to article
calculating f ( k + 1 , n , p ) f ( k , n , p ) = ( n − k ) p ( k + 1 ) ( 1 − p ) {\displaystyle {\frac {f(k+1,n,p)}{f(k,n,p)}}={\frac {(n-k)p}{(k+1)(1-p)}}}Kalman filter (20,932 words) [view diff] no match in snippet view article find links to article
k − 1 ] T Y k − 1 ∣ k − 1 F k − 1 C k = M k [ M k + Q k − 1 ] − 1 L k = I − C k Y k ∣ k − 1 = L k M k + C k Q k − 1 C k T y ^ k ∣ k − 1 = L k [ F k −Permutation (11,667 words) [view diff] exact match in snippet view article find links to article
λ k − 1 ( p k − 1 k ) λ k − 1 ( p k − 2 k ) λ k − 1 ⋯ λ k − 1 ( p 1 k ) λ k − 1 {\displaystyle \lambda _{k}=\lambda _{k-1}(p_{k-1}k)\lambda _{k-1}(p_{k-2}k)\lambdaMichaelis–Menten kinetics (6,227 words) [view diff] no match in snippet view article find links to article
K_{\mathrm {m} }} is equal to k + 2 / k + 1 {\displaystyle k_{+2}/k_{+1}} or to k − 1 / k + 1 {\displaystyle k_{-1}/k_{+1}} or to something else. G. E. BriggsBinomial coefficient (10,733 words) [view diff] exact match in snippet view article find links to article
× ⋯ × ( n − k + 1 ) k × ( k − 1 ) × ⋯ × 1 , {\displaystyle {\binom {n}{k}}={\frac {n\times (n-1)\times \cdots \times (n-k+1)}{k\times (k-1)\times \cdotsList of trigonometric identities (12,421 words) [view diff] exact match in snippet view article find links to article
identity can be proved: ∏ k = 1 n sin ( 2 k − 1 ) π 4 n = ∏ k = 1 n cos ( 2 k − 1 ) π 4 n = 2 2 n {\displaystyle \prod _{k=1}^{n}\sin {\frac {\left(2k-1\right)\piGeometric distribution (5,151 words) [view diff] exact match in snippet view article find links to article
trial is the first success is Pr ( X = k ) = ( 1 − p ) k − 1 p {\displaystyle \Pr(X=k)=(1-p)^{k-1}p} for k = 1 , 2 , 3 , 4 , … {\displaystyle k=1,2,3Logistic regression (20,641 words) [view diff] no match in snippet view article find links to article
case of a perfect prediction (i.e., when p k = 1 {\displaystyle p_{k}=1} and y k = 1 {\displaystyle y_{k}=1} , or p k = 0 {\displaystyle p_{k}=0} and yBinomial theorem (6,735 words) [view diff] exact match in snippet view article find links to article
( n − k + 1 ) k ( k − 1 ) ( k − 2 ) ⋯ 2 ⋅ 1 . {\displaystyle {\binom {n}{k}}={\frac {n!}{k!\,(n-k)!}}={\frac {n(n-1)(n-2)\cdots (n-k+1)}{k(k-1)(k-2)\cdotsBoltzmann constant (2,946 words) [view diff] no match in snippet view article find links to article
constants defining the International System of Units, the SI, with k = 1.380649×10−23 J K−1. The Boltzmann constant is a proportionality constant between theSpecific heat capacity (8,537 words) [view diff] no match in snippet view article find links to article
among common substances, about 4184 J⋅kg−1⋅K−1 at 20 °C; but that of ice, just below 0 °C, is only 2093 J⋅kg−1⋅K−1. The specific heat capacities of iron,Natural logarithm (5,882 words) [view diff] exact match in snippet view article find links to article
( 1 + x ) = ∑ k = 1 ∞ ( − 1 ) k − 1 k x k = x − x 2 2 + x 3 3 − ⋯ , {\displaystyle \ln(1+x)=\sum _{k=1}^{\infty }{\frac {(-1)^{k-1}}{k}}x^{k}=x-{\fracGas constant (1,997 words) [view diff] no match in snippet view article find links to article
{\displaystyle R=N_{\rm {A}}k} = 6.02214076×1023 mol−1 × 1.380649×10−23 J⋅K−1 = 8.31446261815324 J⋅K−1⋅mol−1 Since the 2019 revision of the SI, both NA and k are definedNACA airfoil (2,605 words) [view diff] no match in snippet view article find links to article
0.3 - the value of r {\displaystyle r} , k 1 {\displaystyle k_{1}} and k 2 / k 1 {\displaystyle k_{2}/k_{1}} must be linearly scaled for a differentMoment of inertia (17,301 words) [view diff] no match in snippet view article find links to article
∑ k = 1 N m k ( y k 2 + z k 2 ) − ∑ k = 1 N m k x k y k − ∑ k = 1 N m k x k z k − ∑ k = 1 N m k x k y k ∑ k = 1 N m k ( x k 2 + z k 2 ) − ∑ k = 1 N mFinite element method (7,946 words) [view diff] no match in snippet view article find links to article
e., v k ( x ) = { x − x k − 1 x k − x k − 1 if x ∈ [ x k − 1 , x k ] , x k + 1 − x x k + 1 − x k if x ∈ [ x k , x k + 1 ] , 0 otherwise , {\displaystyleTaylor series (8,229 words) [view diff] no match in snippet view article find links to article
α n ) = ∏ k = 1 n α − k + 1 k = α ( α − 1 ) ⋯ ( α − n + 1 ) n ! . {\displaystyle {\binom {\alpha }{n}}=\prod _{k=1}^{n}{\frac {\alpha -k+1}{k}}={\fracMathematical induction (6,914 words) [view diff] no match in snippet view article find links to article
+k)+(k+1)={\frac {k(k+1)}{2}}+(k+1).} Algebraically, the right hand side simplifies as: k ( k + 1 ) 2 + ( k + 1 ) = k ( k + 1 ) + 2 ( k + 1 ) 2 = ( k + 1 )Gamma function (13,526 words) [view diff] no match in snippet view article find links to article
x 2 ) x − 1 ∏ k = 1 n k + 1 k + x {\displaystyle x!=\lim _{n\to \infty }\left(n+1+{\frac {x}{2}}\right)^{x-1}\prod _{k=1}^{n}{\frac {k+1}{k+x}}} whichEnzyme kinetics (9,539 words) [view diff] no match in snippet view article find links to article
M S = ( k − 1 + k 2 ) / k 1 {\displaystyle K_{M}^{S}=(k_{-1}+k_{2})/k_{1}} and K M P = ( k − 1 + k 2 ) / k − 2 {\displaystyle K_{M}^{P}=(k_{-1}+k_{2})/k_{-2}}Taylor's theorem (9,632 words) [view diff] no match in snippet view article find links to article
| x − a | k + 1 ( k + 1 ) ! ≤ M r k + 1 ( k + 1 ) ! {\displaystyle |R_{k}(x)|\leq M{\frac {|x-a|^{k+1}}{(k+1)!}}\leq M{\frac {r^{k+1}}{(k+1)!}}} for allEigenvalues and eigenvectors (13,582 words) [view diff] exact match in snippet view article find links to article
d t k + a k − 1 d k − 1 x d t k − 1 + ⋯ + a 1 d x d t + a 0 x = 0. {\displaystyle {\frac {d^{k}x}{dt^{k}}}+a_{k-1}{\frac {d^{k-1}x}{dt^{k-1}}}+\cdotsWeibull distribution (5,823 words) [view diff] exact match in snippet view article find links to article
k − 1 e − ( x / λ ) k , x ≥ 0 , 0 , x < 0 , {\displaystyle f(x;\lambda ,k)={\begin{cases}{\frac {k}{\lambda }}\left({\frac {x}{\lambda }}\right)^{k-1}e^{-(x/\lambdaEuler's totient function (6,519 words) [view diff] exact match in snippet view article find links to article
and k ≥ 1, then φ ( p k ) = p k − p k − 1 = p k − 1 ( p − 1 ) = p k ( 1 − 1 p ) . {\displaystyle \varphi \left(p^{k}\right)=p^{k}-p^{k-1}=p^{k-1Pascal's triangle (7,606 words) [view diff] no match in snippet view article find links to article
∑ k = 1 n + 1 a k − 1 x k + ∑ k = 0 n a k x k = ∑ k = 1 n a k − 1 x k + a n x n + 1 + a 0 x 0 + ∑ k = 1 n a k x k = a 0 x 0 + ∑ k = 1 n ( a k − 1 + aTriangular number (3,543 words) [view diff] no match in snippet view article find links to article
k = 1 n k = 1 + 2 + ⋯ + n = n 2 + n ( n + 1 ) 2 = n ( n + 1 ) 2 = ( n + 1 2 ) {\displaystyle \displaystyle {\begin{aligned}T_{n}&=\sum _{k=1}^{n}k=1+2+\dotsbAcid (5,957 words) [view diff] no match in snippet view article find links to article
[ H + ] 2 + [ H + ] K 1 + K 1 K 2 = [ H 2 A ] [ H 2 A ] + [ H A − ] + [ A 2 − ] α HA − = [ H + ] K 1 [ H + ] 2 + [ H + ] K 1 + K 1 K 2 = [ HA − ] [ H 2P-adic number (7,711 words) [view diff] no match in snippet view article find links to article
i p i = a k p k + a k + 1 p k + 1 + a k + 2 p k + 2 + ⋯ {\displaystyle s=\sum _{i=k}^{\infty }a_{i}p^{i}=a_{k}p^{k}+a_{k+1}p^{k+1}+a_{k+2}p^{k+2}+\cdotsSummation (4,576 words) [view diff] no match in snippet view article find links to article
{\displaystyle p>1} ∑ k = 1 n k p = n p + 1 p + 1 + 1 2 n p + ∑ k = 2 p ( p k ) B k p − k + 1 n p − k + 1 , {\displaystyle \sum _{k=1}^{n}k^{p}={\fracGini coefficient (10,898 words) [view diff] exact match in snippet view article find links to article
trapezoids and: G 1 = 1 − ∑ k = 1 n ( X k − X k − 1 ) ( Y k + Y k − 1 ) {\displaystyle G_{1}=1-\sum _{k=1}^{n}(X_{k}-X_{k-1})(Y_{k}+Y_{k-1})} is the resultingBirthday problem (7,114 words) [view diff] no match in snippet view article find links to article
p ¯ ( n ) = ∏ k = 1 n − 1 ( 1 − k 365 ) < ∏ k = 1 n − 1 ( e − k 365 ) = e − n ( n − 1 ) 730 . {\displaystyle {\bar {p}}(n)=\prod _{k=1}^{n-1}\left(1-{\fracLagrangian mechanics (14,691 words) [view diff] no match in snippet view article find links to article
− V , {\displaystyle L=T-V,} where T = 1 2 ∑ k = 1 N m k v k 2 {\displaystyle T={\frac {1}{2}}\sum _{k=1}^{N}m_{k}v_{k}^{2}} is the total kinetic energyTranscendental number (6,764 words) [view diff] no match in snippet view article find links to article
sufficient to prove that k + 1 {\displaystyle k+1} does not divide P {\displaystyle P} . To that end, let k + 1 {\displaystyle k+1} be any prime larger thanCombination (3,806 words) [view diff] exact match in snippet view article find links to article
n k ) = n ( n − 1 ) ⋯ ( n − k + 1 ) k ( k − 1 ) ⋯ 1 , {\displaystyle {\binom {n}{k}}={\frac {n(n-1)\dotsb (n-k+1)}{k(k-1)\dotsb 1}},} which can be writtenQuantization (signal processing) (6,359 words) [view diff] no match in snippet view article
values of { b k } k = 1 M − 1 {\displaystyle \{b_{k}\}_{k=1}^{M-1}} , { c k } k = 1 M {\displaystyle \{c_{k}\}_{k=1}^{M}} and { y k } k = 1 M {\displaystyleQuadrilateral (6,989 words) [view diff] no match in snippet view article find links to article
q: K = 1 2 ( m + n + p ) ( m + n − p ) ( m + n + q ) ( m + n − q ) , {\displaystyle K={\tfrac {1}{2}}{\sqrt {(m+n+p)(m+n-p)(m+n+q)(m+n-q)}},} K = 1 2 pNegative binomial distribution (8,217 words) [view diff] no match in snippet view article find links to article
binomial": ( k + r − 1 ) ⋯ ( r ) k ! = ( − 1 ) k ( − r ) ( − r − 1 ) ( − r − 2 ) ⋯ ( − r − k + 1 ) ⏞ k factors k ! = ( − 1 ) k ( − r − k ) . {\displaystyleBernoulli distribution (2,196 words) [view diff] no match in snippet view article find links to article
) = p k ( 1 − p ) 1 − k for k ∈ { 0 , 1 } {\displaystyle f(k;p)=p^{k}(1-p)^{1-k}\quad {\text{for }}k\in \{0,1\}} or as f ( k ; p ) = p k + ( 1 − p )Simplex (7,866 words) [view diff] case mismatch in snippet view article find links to article
k-dimensional polytope that is the convex hull of its k + 1 vertices. More formally, suppose the k + 1 points u 0 , … , u k {\displaystyle u_{0},\dots ,u_{k}}Runge–Kutta methods (7,392 words) [view diff] no match in snippet view article find links to article
_{i=1}^{s}b_{i}k_{i},} where k 1 = f ( t n , y n ) , k 2 = f ( t n + c 2 h , y n + ( a 21 k 1 ) h ) , k 3 = f ( t n + c 3 h , y n + ( a 31 k 1 + a 32 k 2 ) h )Integer (3,935 words) [view diff] no match in snippet view article find links to article
= ⋯ = [ ( k , k ) ] 1 = [ ( 1 , 0 ) ] = [ ( 2 , 1 ) ] = ⋯ = [ ( k + 1 , k ) ] − 1 = [ ( 0 , 1 ) ] = [ ( 1 , 2 ) ] = ⋯ = [ ( k , k + 1 ) ] 2 = [ ( 2Central limit theorem (9,169 words) [view diff] exact match in snippet view article find links to article
∑ k = 1 n E [ ( M k − M k − 1 ) 2 ∣ M 1 , … , M k − 1 ] → 1 {\displaystyle {\frac {1}{n}}\sum _{k=1}^{n}\operatorname {E} \left[\left(M_{k}-M_{k-1}\right)^{2}\midEuler's constant (9,582 words) [view diff] no match in snippet view article find links to article
n + ∑ k = 1 n 1 k ) = ∫ 1 ∞ ( − 1 x + 1 ⌊ x ⌋ ) d x . {\displaystyle {\begin{aligned}\gamma &=\lim _{n\to \infty }\left(-\log n+\sum _{k=1}^{n}{\fracReal number (8,223 words) [view diff] exact match in snippet view article find links to article
infinite series x = b k 10 k + b k − 1 10 k − 1 + ⋯ + b 0 + a 1 10 + a 2 10 2 + ⋯ . {\displaystyle x=b_{k}10^{k}+b_{k-1}10^{k-1}+\cdots +b_{0}+{\frac {a_{1}}{10}}+{\fracDiscrete cosine transform (11,983 words) [view diff] no match in snippet view article find links to article
around k = − 1 / 2 {\displaystyle k=-1/2} and even around k = N − 1 / 2. {\displaystyle k=N-1/2.} X k = ∑ n = 0 N − 1 x n cos [ π N ( n + 1 2 ) ( k + 1 2Feynman diagram (15,967 words) [view diff] no match in snippet view article find links to article
k 1 ) ϕ ( k 2 ) ϕ ( k 3 ) ϕ ( k 4 ) ⟩ = δ ( k 1 − k 2 ) k 1 2 δ ( k 3 − k 4 ) k 3 2 + δ ( k 1 − k 3 ) k 3 2 δ ( k 2 − k 4 ) k 2 2 + δ ( k 1 − k 4 ) kSequence (6,158 words) [view diff] exact match in snippet view article find links to article
a_{k}=k^{2}} ( a 2 k − 1 ) k = 1 ∞ , a k = k 2 {\displaystyle {(a_{2k-1})}_{k=1}^{\infty },\qquad a_{k}=k^{2}} ( a k ) k = 1 ∞ , a k = ( 2 k − 1 ) 2 {\displaystyleRiemann zeta function (10,428 words) [view diff] no match in snippet view article find links to article
k 1 > k 2 > ⋯ > k n > 0 k 1 − s 1 k 2 − s 2 ⋯ k n − s n . {\displaystyle \zeta (s_{1},s_{2},\ldots ,s_{n})=\sum _{k_{1}>k_{2}>\cdots >k_{n}>0}{k_{1Chi-squared distribution (6,811 words) [view diff] no match in snippet view article find links to article
{\displaystyle k} with a width k 1 / 2 + α {\displaystyle k^{1/2+\alpha }} : P r ( ‖ Z ‖ 2 ∈ [ k − 2 k 1 / 2 + α , k + 2 k 1 / 2 + α + 2 k α ] ) ≥ 1 − eBernoulli number (13,028 words) [view diff] no match in snippet view article find links to article
0 n ( n k ) 2 n − k + 1 n − k + 1 B k ( 1 ) = 2 n {\displaystyle -1+\sum _{k=0}^{n}{\binom {n}{k}}{\frac {2^{n-k+1}}{n-k+1}}B_{k}(1)=2^{n}} and − 1 +Dirichlet distribution (6,666 words) [view diff] exact match in snippet view article find links to article
_{i}-1}} where { x k } k = 1 k = K {\displaystyle \{x_{k}\}_{k=1}^{k=K}} belong to the standard K − 1 {\displaystyle K-1} simplex, or in other words:Logarithm (11,635 words) [view diff] no match in snippet view article find links to article
1 + 1 2 + 1 3 + ⋯ + 1 n = ∑ k = 1 n 1 k , {\displaystyle 1+{\frac {1}{2}}+{\frac {1}{3}}+\cdots +{\frac {1}{n}}=\sum _{k=1}^{n}{\frac {1}{k}},} is calledAdam van Koeverden (1,539 words) [view diff] exact match in snippet view article find links to article
is an Olympic gold medallist in the K-1 500m category (2004) and a two-time world champion in K-1 500 (2007) and K-1 1000 (2011), winning four Olympic andPerturbation theory (quantum mechanics) (15,990 words) [view diff] no match in snippet view article
k 1 n E n k 1 | k 1 ( 0 ) ⟩ | n ( 2 ) ⟩ = ( V k 1 k 2 V k 2 n E n k 1 E n k 2 − V n n V k 1 n E n k 1 2 ) | k 1 ( 0 ) ⟩ − 1 2 V n k 1 V k 1 n E k 1 nLisa Carrington (1,930 words) [view diff] no match in snippet view article find links to article
and one bronze medal. She won three consecutive gold medals in the Women's K‑1 200 metres at the 2012 Summer Olympics, 2016 Summer Olympics and 2020 SummerMoving average (3,168 words) [view diff] no match in snippet view article find links to article
k = p n − k + 1 + p n − k + 2 + ⋯ + p n k = 1 k ∑ i = n − k + 1 n p i {\displaystyle {\begin{aligned}{\textit {SMA}}_{k}&={\frac {p_{n-k+1}+p_{n-k+2}+\cdotsChaos theory (13,440 words) [view diff] no match in snippet view article find links to article
non-linear differential equations of the second order, I: The equation y" + k(1−y2)y' + y = bλkcos(λt + a), k large". Journal of the London MathematicalICF Canoe Sprint World Championships (734 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200 metres (660 ft), 500Russian roulette (2,825 words) [view diff] no match in snippet view article find links to article
{\displaystyle k} is 1 n − k ⋅ ∏ i = 0 k − 1 n − i − 1 n − i = n − 1 n ⋅ n − 2 n − 1 ⋅ . . . ⋅ n − k n − k − 1 ⋅ 1 n − k = 1 6 ≈ 16.7 % {\displaystyle {\tfracEntropy (14,024 words) [view diff] no match in snippet view article find links to article
temperature, which has a unit of joules per kelvin (J⋅K−1) in the International System of Units (or kg⋅m2⋅s−2⋅K−1 in terms of base units). The entropy of a substanceRate equation (7,576 words) [view diff] no match in snippet view article find links to article
0 1 k 1 + k − 1 ( k − 1 + k 1 e − ( k 1 + k − 1 ) t ) + [ P ] 0 k − 1 k 1 + k − 1 ( 1 − e − ( k 1 + k − 1 ) t ) [ P ] = [ A ] 0 k 1 k 1 + k − 1 ( 1 −Variance (10,207 words) [view diff] no match in snippet view article find links to article
∑ k = 1 n Y k ] = 1 n ∑ i = 1 n ( E [ Y i 2 ] − 2 n ( ∑ j ≠ i E [ Y i Y j ] + E [ Y i 2 ] ) + 1 n 2 ∑ j = 1 n ∑ k ≠ j n E [ Y j Y k ] + 1 n 2List of Olympic medalists in canoeing (men) (16 words) [view diff] no match in snippet view article
This is the complete list of men's Olympic medalists in canoeing. International Olympic Committee results databaseReed–Solomon error correction (12,677 words) [view diff] no match in snippet view article find links to article
k + 1 … g 1 , n 0 1 0 … 0 g 2 , k + 1 … g 2 , n 0 0 1 … 0 g 3 , k + 1 … g 3 , n ⋮ ⋮ ⋮ ⋮ ⋮ ⋮ 0 … 0 … 1 g k , k + 1 … g k , n ] [ m 0 m 1 ⋮ m k − 1 ]Dissociation constant (3,119 words) [view diff] no match in snippet view article find links to article
K 1 ′ = [ L ] [ M ] [ L M ] [ LM ] = [ L ] [ M ] K 1 ′ [ L ] + [ LM ] ↽ − − ⇀ [ L 2 M ] K 2 ′ = [ L ] [ LM ] [ L 2 M ] [ L 2 M ] = [ L ] 2 [ M ] K 1 ′Exterior algebra (12,098 words) [view diff] exact match in snippet view article find links to article
k − 1 {\displaystyle k-1} elements of V ∗ {\displaystyle V^{*}} , then define ( ι α w ) ( u 1 , u 2 , … , u k − 1 ) = w ( α , u 1 , u 2 , … , u k −Thermal conductivity and resistivity (8,365 words) [view diff] no match in snippet view article find links to article
{\displaystyle \lambda } , or κ {\displaystyle \kappa } and is measured in W·m−1·K−1. Heat transfer occurs at a lower rate in materials of low thermal conductivityFloor and ceiling functions (5,879 words) [view diff] no match in snippet view article find links to article
integer k is ⌊ log b k ⌋ + 1 = ⌈ log b ( k + 1 ) ⌉ . {\displaystyle \lfloor \log _{b}{k}\rfloor +1=\lceil \log _{b}{(k+1)}\rceil .} The number ofLehmer mean (837 words) [view diff] no match in snippet view article find links to article
as: L p ( x ) = ∑ k = 1 n x k p ∑ k = 1 n x k p − 1 . {\displaystyle L_{p}(\mathbf {x} )={\frac {\sum _{k=1}^{n}x_{k}^{p}}{\sum _{k=1}^{n}x_{k}^{p-1}}}Trapezoidal rule (3,483 words) [view diff] exact match in snippet view article find links to article
(that is, Δ x k = x k − x k − 1 {\displaystyle \Delta x_{k}=x_{k}-x_{k-1}} ), then ∫ a b f ( x ) d x ≈ ∑ k = 1 N f ( x k − 1 ) + f ( x k ) 2 Δ x k . {\displaystyleExterior derivative (3,307 words) [view diff] no match in snippet view article find links to article
can be thought of as measuring the net flux through the boundary of a (k + 1)-parallelotope at each point. The exterior derivative of a differentialStandard molar entropy (788 words) [view diff] no match in snippet view article find links to article
= ∑ k = 1 N Δ S k = ∑ k = 1 N d Q k T → ∫ 0 T 2 d S d T d T = ∫ 0 T 2 C p k T d T {\displaystyle S^{\circ }=\sum _{k=1}^{N}\Delta S_{k}=\sum _{k=1}^{N}{\fracInvertible matrix (6,996 words) [view diff] exact match in snippet view article find links to article
A k − 1 A k ) − 1 = A k − 1 A k − 1 − 1 ⋯ A 2 − 1 A 1 − 1 . {\displaystyle (\mathbf {A} _{1}\mathbf {A} _{2}\cdots \mathbf {A} _{k-1}\mathbf {A} _{k})^{-1}=\mathbfSobolev space (6,658 words) [view diff] exact match in snippet view article find links to article
it is enough to assume that the ( k − 1 ) {\displaystyle (k{-}1)} -th derivative f ( k − 1 ) {\displaystyle f^{(k-1)}} is differentiable almost everywhereExponential family (11,203 words) [view diff] exact match in snippet view article find links to article
{\displaystyle \sum _{i=1}^{k}p_{i}=1\,.} Thus, there are only k − 1 {\displaystyle k-1} independent parameters. Variant 1 uses k {\displaystyle k} naturalEuclidean algorithm (15,336 words) [view diff] exact match in snippet view article find links to article
m k = q k m k − 1 + m k − 2 n k = q k n k − 1 + n k − 2 , {\displaystyle {\begin{aligned}m_{k}&=q_{k}m_{k-1}+m_{k-2}\\n_{k}&=q_{k}n_{k-1}+n_{k-2},\end{aligned}}}Recurrence relation (4,166 words) [view diff] exact match in snippet view article find links to article
uni-dimensional recurrence: ( n k ) = ( n k − 1 ) ( n − k + 1 ) / k , {\displaystyle {\binom {n}{k}}={\binom {n}{k-1}}(n-k+1)/k,} with the initial value ( n 0Generating function (14,464 words) [view diff] no match in snippet view article find links to article
, 1 k 1 , 1 0 0 ⋯ k 0 , 2 k 1 , 2 k 2 , 2 0 ⋯ k 0 , 3 k 1 , 3 k 2 , 3 k 3 , 3 ⋯ ⋮ ⋮ ⋮ ⋮ ] = [ k 0 , 0 0 0 0 ⋯ k 0 , 1 k 1 , 1 0 0 ⋯ k 0 , 2 k 1 , 2 kSmoothness (3,923 words) [view diff] exact match in snippet view article find links to article
at least in the class C k − 1 {\displaystyle C^{k-1}} since f ′ , f ″ , … , f ( k − 1 ) {\displaystyle f',f'',\dots ,f^{(k-1)}} are continuous on U .Partial autocorrelation function (1,129 words) [view diff] exact match in snippet view article find links to article
k − 1 + ⋯ + β k − 1 z t + 1 and z ^ t = β 1 z t + 1 + ⋯ + β k − 1 z t + k − 1 . {\displaystyle {\hat {z}}_{t+k}=\beta _{1}z_{t+k-1}+\cdots +\beta _{k-1}z_{t+1}\qquadPrincipal component analysis (14,450 words) [view diff] no match in snippet view article find links to article
of the normalization constraints: α k ′ α k = 1 , k = 1 , … , p {\displaystyle \alpha _{k}'\alpha _{k}=1,k=1,\dots ,p} . As noted above, the results ofApproximations of π (12,280 words) [view diff] no match in snippet view article find links to article
{2}}} and y k + 1 = ( 1 − f ( y k ) ) / ( 1 + f ( y k ) ) , a k + 1 = a k ( 1 + y k + 1 ) 4 − 2 2 k + 3 y k + 1 ( 1 + y k + 1 + y k + 1 2 ) {\displaystyleFinite difference (5,863 words) [view diff] exact match in snippet view article find links to article
k − 1 ∑ i 2 = 0 k − 1 ⋯ ∑ i n = 0 k − 1 Δ h n ( f , x + i 1 h + i 2 h + ⋯ + i n h ) . {\displaystyle \Delta _{kh}^{n}(f,x)=\sum \limits _{i_{1}=0}^{k-1}\sumProbability density function (4,940 words) [view diff] no match in snippet view article find links to article
for y is ∑ k = 1 n ( y ) | d d y g k − 1 ( y ) | ⋅ f X ( g k − 1 ( y ) ) , {\displaystyle \sum _{k=1}^{n(y)}\left|{\frac {d}{dy}}g_{k}^{-1}(y)\right|\cdotPhase-shift keying (6,226 words) [view diff] exact match in snippet view article find links to article
number: r k r k − 1 ∗ = E s e j ( φ k − φ k − 1 ) + E s e j φ k n k − 1 ∗ + E s e − j φ k − 1 n k + n k n k − 1 ∗ {\displaystyle r_{k}r_{k-1}^{*}=E_{s}e^{j\left(\varphiOrder statistic (4,933 words) [view diff] exact match in snippet view article find links to article
U ( k ) ( u ) = n ! ( k − 1 ) ! ( n − k ) ! u k − 1 ( 1 − u ) n − k {\displaystyle f_{U_{(k)}}(u)={n! \over (k-1)!(n-k)!}u^{k-1}(1-u)^{n-k}} that is,Phase-shift keying (6,226 words) [view diff] exact match in snippet view article find links to article
number: r k r k − 1 ∗ = E s e j ( φ k − φ k − 1 ) + E s e j φ k n k − 1 ∗ + E s e − j φ k − 1 n k + n k n k − 1 ∗ {\displaystyle r_{k}r_{k-1}^{*}=E_{s}e^{j\left(\varphiErlang distribution (1,969 words) [view diff] no match in snippet view article find links to article
of time until the occurrence of a fixed number of events. When k = 1 {\displaystyle k=1} , the distribution simplifies to the exponential distributionQuaternion (12,634 words) [view diff] no match in snippet view article find links to article
quaternions, i 2 = j 2 = k 2 = i j k = − 1 {\displaystyle \mathbf {i} ^{2}=\mathbf {j} ^{2}=\mathbf {k} ^{2}=\mathbf {i\,j\,k} =-1} into the stone of BroughamArithmetic progression (2,297 words) [view diff] no match in snippet view article find links to article
n , k ) = 1 2 ( k − 1 ) ( n 2 − ( k − 1 ) n + ( k − 2 ) + ϕ ( n + 1 , k − 1 ) ) = 1 2 ( k − 1 ) ( ( n − 1 ) ( n − ( k − 2 ) ) + ϕ ( n + 1 , k − 1 ) )Kronecker delta (3,740 words) [view diff] exact match in snippet view article find links to article
_{p-1}}-\sum _{k=1}^{p-1}\delta _{\nu _{k}}^{\mu _{p}}\delta _{\nu _{1}\dots \nu _{k-1}\,\nu _{p}\,\nu _{k+1}\dots \nu _{p-1}}^{\mu _{1}\dots \mu _{k-1}\,\mu _{k}\Convergent series (1,966 words) [view diff] no match in snippet view article find links to article
that is denoted S = a 1 + a 2 + a 3 + ⋯ = ∑ k = 1 ∞ a k . {\displaystyle S=a_{1}+a_{2}+a_{3}+\cdots =\sum _{k=1}^{\infty }a_{k}.} The nth partial sum SnCanoeing at the 2020 Summer Olympics (435 words) [view diff] exact match in snippet view article find links to article
C-1 men women K-1 men women Sprint C-1 200 m women C-1 1000 m men C-2 500 m women C-2 1000 m men K-1 200 m men women K-1 500 m women K-1 1000 m men K-2Softmax function (5,286 words) [view diff] no match in snippet view article find links to article
{\displaystyle \sigma \colon \mathbb {R} ^{K}\to (0,1)^{K}} , where K > 1 {\displaystyle K>1} , takes a vector z = ( z 1 , … , z K ) ∈ R K {\displaystyle \mathbfError function (7,304 words) [view diff] exact match in snippet view article find links to article
) k − 1 π H k − 1 ( z ) e − z 2 = 2 π d k − 1 d z k − 1 ( e − z 2 ) , k = 1 , 2 , … {\displaystyle \operatorname {erf} ^{(k)}z={\frac {2(-1)^{k-1}}{\sqrtProportional–integral–derivative controller (12,059 words) [view diff] no match in snippet view article find links to article
u ( t k ) − u ( t k − 1 ) Δ t = K p e ( t k ) − e ( t k − 1 ) Δ t + K i e ( t k ) + K d e ( t k ) − e ( t k − 1 ) Δ t − e ( t k − 1 ) − e ( t k − 2 )Stirling numbers of the second kind (4,313 words) [view diff] exact match in snippet view article find links to article
n k − 1 } {\displaystyle \left\{{n \atop k-1}\right\}} since we must partition the remaining n objects into the available k − 1 {\displaystyle k-1} Ozone (18,196 words) [view diff] no match in snippet view article find links to article
intermediate can be determined as follows: K 1 = K 1 K − 1 = [ O 2 ] ⋅ [ O ] [ O 3 ] {\displaystyle K_{1}={\frac {K_{1}}{K_{-1}}}={\frac {[{\ce {O2}}]\cdot [{\ceIdeal gas law (4,622 words) [view diff] no match in snippet view article find links to article
−273.15 °C, the lowest possible temperature). R has for value 8.314 J/(mol·K) = 1.989 ≈ 2 cal/(mol·K), or 0.0821 L⋅atm/(mol⋅K). How much gas is present couldHypergeometric distribution (4,115 words) [view diff] no match in snippet view article find links to article
hypergeometric distribution: Pr ( X 1 = k 1 , … , X c = k c ) = ∏ i = 1 c ( K i k i ) ( N n ) {\displaystyle \Pr(X_{1}=k_{1},\ldots ,X_{c}=k_{c})={\frac {\prodMin-max theorem (4,542 words) [view diff] exact match in snippet view article find links to article
to pick a ( i k − 1 − ( i 1 − 1 ) ) {\textstyle (i_{k-1}-(i_{1}-1))} -dimensional subspace W k − 1 ′ ⊂ W k ∩ V i k − 1 {\textstyle W_{k-1}'\subset W_{k}\capSodium cyanide (989 words) [view diff] no match in snippet view article find links to article
452 Thermochemistry Heat capacity (C) 70.4 J·mol−1·K−1 Std molar entropy (S⦵298) 115.6 J·mol−1·K−1 Std enthalpy of formation (ΔfH⦵298) −87.5 kJ·mol−1Kosambi–Karhunen–Loève theorem (10,711 words) [view diff] no match in snippet view article find links to article
∑ k = 1 N p k ≥ ∑ k = 1 N q k {\displaystyle \sum _{k=1}^{N}p_{k}\geq \sum _{k=1}^{N}q_{k}} This implies that: − ∑ k = 1 ∞ p k log ( p k ) ≤ − ∑ k =Canoeing at the 2016 Summer Olympics (685 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 200 m men C-1 1000 m men C-2 1000 m men K-1 200 m men women K-1 500 m women K-1 1000 m men K-2 200 m menList of Olympic medalists in canoeing (women) (16 words) [view diff] no match in snippet view article
This is the complete list of women's Olympic medalists in kayaking. International Olympic Committee results databaseExtrapolation (1,869 words) [view diff] exact match in snippet view article find links to article
= y k − 1 + x ∗ − x k − 1 x k − x k − 1 ( y k − y k − 1 ) . {\displaystyle y(x_{*})=y_{k-1}+{\frac {x_{*}-x_{k-1}}{x_{k}-x_{k-1}}}(y_{k}-y_{k-1}).} (whichGram–Schmidt process (4,423 words) [view diff] no match in snippet view article find links to article
( k − 1 ) = u k ( k − 2 ) − proj u k − 1 ( u k ( k − 2 ) ) , e k = u k ( k − 1 ) ‖ u k ( k − 1 ) ‖ {\displaystyle {\begin{aligned}\mathbf {u} _{k}^{(1)}&=\mathbfLogistic function (8,029 words) [view diff] no match in snippet view article find links to article
standard logistic function, depicted at right, where L = 1 , k = 1 , x 0 = 0 {\displaystyle L=1,k=1,x_{0}=0} , has the equation f ( x ) = 1 1 + e − x {\displaystyleMaximum likelihood estimation (9,703 words) [view diff] no match in snippet view article find links to article
functions: f n ( y ; θ ) = ∏ k = 1 n f k u n i v a r ( y k ; θ ) . {\displaystyle f_{n}(\mathbf {y} ;\theta )=\prod _{k=1}^{n}\,f_{k}^{\mathsf {univar}}(y_{k};\theta1000 (number) (24,094 words) [view diff] no match in snippet view article
k = 1 46 σ ( k ) {\displaystyle \sum _{k=1}^{46}\sigma (k)} 1759 = de Polignac prime 1760 = the number of yards in a mile 1761 = k such that k, k+1 andDiscrete Fourier transform (12,311 words) [view diff] no match in snippet view article find links to article
case above: X k 1 , k 2 , … , k d = X N 1 − k 1 , N 2 − k 2 , … , N d − k d ∗ , {\displaystyle X_{k_{1},k_{2},\dots ,k_{d}}=X_{N_{1}-k_{1},N_{2}-k_{2}Differential form (10,058 words) [view diff] case mismatch in snippet view article find links to article
differential forms that, given a k-form φ {\displaystyle \varphi } , produces a (k+1)-form d φ . {\displaystyle d\varphi .} This operation extends the differentialCanoeing at the Summer Olympics (333 words) [view diff] exact match in snippet view article find links to article
200 m events with one of them being K-1 200 m for the women. The other events for men at 200 m will be C-1, K-1, and K-2. This was confirmed at theirElliptic integral (7,832 words) [view diff] no match in snippet view article find links to article
}})={\tfrac {1}{2}}\pi } For example: 4 3 K ( 1 3 ) E ( 1 2 ) + 3 2 E ( 1 3 ) K ( 1 2 ) − 2 K ( 1 3 ) K ( 1 2 ) = 1 2 π {\displaystyle {\tfrac {4}{3}}K({\colorHarmonic series (mathematics) (6,219 words) [view diff] no match in snippet view article
{1}{k(k+1)}}=\sum _{k=1}^{\infty }\sum _{n=1}^{k}{\frac {1}{k(k+1)}}} = ∑ k = 1 ∞ k k ( k + 1 ) = ∑ k = 1 ∞ 1 k + 1 = S − 1 {\displaystyle =\sum _{k=1}^{\inftyContinuous uniform distribution (4,219 words) [view diff] case mismatch in snippet view article find links to article
{a^{2}+ab+b^{2}}{3}},} m k = ∑ i = 0 k a i b k − i k + 1 . {\displaystyle m_{k}={\frac {\sum _{i=0}^{k}a^{i}b^{k-i}}{k+1}}.} For a random variable following theMax Hoff (canoeist) (198 words) [view diff] exact match in snippet view article
Championships with five golds (K-1 1000 m: 2009, 2010, 2013; K-1 5000 m: 2011 and K-4 1000 m: 2011 ) and three silvers (K-1 5000 m: 2010, 2014, 2015). AtEuler–Maclaurin formula (3,779 words) [view diff] exact match in snippet view article find links to article
∑ k = 1 p B k k ! ( f ( k − 1 ) ( n ) − f ( k − 1 ) ( m ) ) + R p , {\displaystyle S-I=\sum _{k=1}^{p}{{\frac {B_{k}}{k!}}\left(f^{(k-1)}(n)-f^{(k-1)}(m)\right)}+R_{p}Handley Page Victor (9,400 words) [view diff] no match in snippet view article find links to article
tanker (renamed K.1 after bombing capability removed), 11 converted. Victor BK.1A 3-point in-flight refuelling tanker (renamed K.1A as for K.1), 14 convertedList of ICF Canoe Sprint World Championships medalists in men's kayak (269 words) [view diff] no match in snippet view article find links to article
This is a list of medalists from the ICF Canoe Sprint World Championships in men's kayak. Debuted: 1994. Debuted: 1948. Debuted: 1938. Not held: 1948.Numeral system (3,494 words) [view diff] no match in snippet view article find links to article
k b k + ∑ k = 1 ∞ c k b − k . {\displaystyle (a_{n}a_{n-1}\cdots a_{1}a_{0}.c_{1}c_{2}c_{3}\cdots )_{b}=\sum _{k=0}^{n}a_{k}b^{k}+\sum _{k=1}^{\infty }c_{k}b^{-k}Competitive inhibition (2,864 words) [view diff] no match in snippet view article find links to article
rearranging to k 1 [ E ] [ S ] = ( k − 1 + k 2 ) [ ES ] {\displaystyle k_{1}[{\ce {E}}][{\ce {S}}]=(k_{-1}+k_{2})[{\ce {ES}}]} Dividing by k 1 [ S ] {\displaystyleLebesgue measure (2,678 words) [view diff] no match in snippet view article find links to article
as an infimum λ ∗ ( E ) = inf { ∑ k = 1 ∞ ℓ ( I k ) : ( I k ) k ∈ N is a sequence of open intervals with E ⊂ ⋃ k = 1 ∞ I k } . {\displaystyle \lambdaTrapezoid (4,042 words) [view diff] exact match in snippet view article find links to article
≈ ∑ k = 1 N 1 2 ( f ( x k − 1 ) + f ( x k ) ) Δ x , {\displaystyle \int _{a}^{b}f(x)\,dx\approx \sum _{k=1}^{N}{\tfrac {1}{2}}{\bigl (}f(x_{k-1})+f(x_{k}){\bigrOscillation (3,045 words) [view diff] no match in snippet view article find links to article
1 x ¨ 1 = − ( k 1 + k 2 ) x 1 + k 2 x 2 m 2 x ¨ 2 = k 2 x 1 − ( k 2 + k 3 ) x 2 {\displaystyle {\begin{cases}m_{1}{\ddot {x}}_{1}=-(k_{1Canoeing at the 2012 Summer Olympics (574 words) [view diff] exact match in snippet view article find links to article
by a 200m race; in addition, the men's C-2 500m was replaced by a women's K-1 200m sprint. This was confirmed at an International Canoe Federation boardHölder's inequality (7,917 words) [view diff] no match in snippet view article find links to article
functions for k = 1 , . . . , m {\displaystyle k=1,...,m} . Then ‖ ∏ k = 1 m f k ‖ 1 ≥ ∏ k = 1 m ‖ f k ‖ p k . {\displaystyle \left\|\prod _{k=1}^{m}f_{k}\right\|_{1}\geqStirling's approximation (4,758 words) [view diff] no match in snippet view article find links to article
) + 1 2 ln n = n ln n − n + 1 + ∑ k = 2 m ( − 1 ) k B k k ( k − 1 ) ( 1 n k − 1 − 1 ) + R m , n , {\displaystyle {\begin{aligned}\ln(n!)-{\tfracAlgebra over a field (3,122 words) [view diff] no match in snippet view article find links to article
k 1 , k 2 ∈ K {\displaystyle k_{1},k_{2}\in K} and v 1 , v 2 ∈ V {\displaystyle v_{1},v_{2}\in V} , one has ( k 1 + v 1 ) ( k 2 + v 2 ) = k 1 kStirling numbers of the first kind (7,262 words) [view diff] no match in snippet view article find links to article
1 ) z Γ ( z + 1 ) ( k − 1 ) ! ∑ r = 1 k − 1 s ( k − 1 , r ) ∑ m = 0 r ( r m ) ( k − 2 ) r − m ζ ( z + 1 − m ) , ℜ ( z ) > k − 1 , k = 3 , 4 , 5 , … {\displaystyleMeasure (mathematics) (5,550 words) [view diff] no match in snippet view article
collections { E k } k = 1 ∞ {\displaystyle \{E_{k}\}_{k=1}^{\infty }} of pairwise disjoint sets in Σ, μ ( ⋃ k = 1 ∞ E k ) = ∑ k = 1 ∞ μ ( E k ) . {\displaystyleConjugate gradient method (7,493 words) [view diff] no match in snippet view article find links to article
_{k}} is rewritten as r k + 1 T A p k = 1 α k r k + 1 T ( r k − r k + 1 ) = − 1 α k r k + 1 T r k + 1 {\displaystyle \mathbf {r} _{k+1}^{\mathsf {T}}\mathbfPaul MacDonald (canoeist) (352 words) [view diff] exact match in snippet view article
1988; K-4 1000 m: 1984), one silver (K-2 1000 m: 1988), and one bronze (K-1 500 m: 1988). His five Olympic medals is the record for the second most OlympicLebesgue measure (2,678 words) [view diff] no match in snippet view article find links to article
as an infimum λ ∗ ( E ) = inf { ∑ k = 1 ∞ ℓ ( I k ) : ( I k ) k ∈ N is a sequence of open intervals with E ⊂ ⋃ k = 1 ∞ I k } . {\displaystyle \lambdaAlan Thompson (canoeist) (528 words) [view diff] exact match in snippet view article
silvers (K-1 1000 m and K-2 500 m: both 1982), and a bronze (K-1 1000 m: 1983). He won both of his Olympic gold medals at Los Angeles in 1984, in the K-1 1000AC power (4,388 words) [view diff] no match in snippet view article find links to article
result. A cos ( ω 1 t + k 1 ) cos ( ω 2 t + k 2 ) = A 2 cos [ ( ω 1 t + k 1 ) + ( ω 2 t + k 2 ) ] + A 2 cos [ ( ω 1 t + k 1 ) − ( ω 2 t + k 2 ) ]Algebra over a field (3,122 words) [view diff] no match in snippet view article find links to article
k 1 , k 2 ∈ K {\displaystyle k_{1},k_{2}\in K} and v 1 , v 2 ∈ V {\displaystyle v_{1},v_{2}\in V} , one has ( k 1 + v 1 ) ( k 2 + v 2 ) = k 1 kMultinomial logistic regression (5,225 words) [view diff] no match in snippet view article find links to article
= ∑ k = 1 K Pr ( Y i = k ) = ∑ k = 1 K 1 Z e β k ⋅ X i = 1 Z ∑ k = 1 K e β k ⋅ X i . {\displaystyle 1=\sum _{k=1}^{K}\Pr(Y_{i}=k)\;=\;\sum _{k=1}^{K}{\fracTetrahedral number (1,343 words) [view diff] no match in snippet view article find links to article
n = ∑ k = 1 n T k = ∑ k = 1 n k ( k + 1 ) 2 = ∑ k = 1 n ( ∑ i = 1 k i ) {\displaystyle Te_{n}=\sum _{k=1}^{n}T_{k}=\sum _{k=1}^{n}{\frac {k(k+1)}{2}}=\sumMultiset (4,955 words) [view diff] exact match in snippet view article find links to article
+ k − 1 k ) = ( n + k − 1 ) ! k ! ( n − 1 ) ! = n ( n + 1 ) ( n + 2 ) ⋯ ( n + k − 1 ) k ! , {\displaystyle \left(\!\!{n \choose k}\!\!\right)={n+k-1 \chooseMolar heat capacity (5,707 words) [view diff] no match in snippet view article find links to article
mass. The SI unit of molar heat capacity is joule per kelvin per mole, J⋅K−1⋅mol−1. Like the specific heat, the measured molar heat capacity of a substanceEuler numbers (2,049 words) [view diff] no match in snippet view article find links to article
}{q}}(2q-\ell )^{2n},} E 2 n = ∑ k = 1 2 n ( − 1 ) k 1 2 k ∑ ℓ = 0 2 k ( − 1 ) ℓ ( 2 k ℓ ) ( k − ℓ ) 2 n . {\displaystyle E_{2n}=\sum _{k=1}^{2n}(-1)^{k}{\frac {1}{2^{k}}}\sumRatio test (5,987 words) [view diff] no match in snippet view article find links to article
a subsequence ( a n k ) k = 1 ∞ {\displaystyle \left(a_{n_{k}}\right)_{k=1}^{\infty }} satisfying lim sup n → ∞ | a n k + 1 a n k | ≤ ℓ < r {\displaystyleLagrange polynomial (3,973 words) [view diff] no match in snippet view article find links to article
F^{(k+1)}(\xi )} : F ( k + 1 ) ( ξ ) = f ( k + 1 ) ( ξ ) − L ( k + 1 ) ( ξ ) − R ~ ( k + 1 ) ( ξ ) {\displaystyle F^{(k+1)}(\xi )=f^{(k+1)}(\xi )-L^{(k+1)}(\xiRational function (2,421 words) [view diff] exact match in snippet view article find links to article
− 2 x k − ∑ k = 1 ∞ a k − 1 x k + 2 ∑ k = 0 ∞ a k x k . {\displaystyle 1=\sum _{k=2}^{\infty }a_{k-2}x^{k}-\sum _{k=1}^{\infty }a_{k-1}x^{k}+2\sum _{k=0}^{\inftyAsymptotic analysis (2,774 words) [view diff] exact match in snippet view article find links to article
1 − ⋯ − g k − 1 ∼ g k {\displaystyle f-g_{1}-\cdots -g_{k-1}\sim g_{k}} takes its full meaning if g k + 1 = o ( g k ) {\displaystyle g_{k+1}=o(g_{k})}Thermal expansion (6,133 words) [view diff] no match in snippet view article find links to article
K − 1 {\displaystyle \alpha \approx {\frac {0.038}{T_{m}}}-7.0\cdot 10^{-6}\,\mathrm {K} ^{-1}} In the table below, the range for α is from 10−7 K−1 forExact sequence (2,577 words) [view diff] exact match in snippet view article find links to article
A k + 1 {\displaystyle A_{k+1}} and morphism A k → A k + 1 {\displaystyle A_{k}\to A_{k+1}} such that A k − 1 → A k → A k + 1 {\displaystyle A_{k-1}\toInductance (8,763 words) [view diff] no match in snippet view article find links to article
authors define the range as 0 ≤ k < 1 {\displaystyle 0\leq k<1} , but some define it as − 1 < k < 1 {\displaystyle -1<k<1\,} . Allowing negative valuesStirling numbers of the first kind (7,262 words) [view diff] no match in snippet view article find links to article
1 ) z Γ ( z + 1 ) ( k − 1 ) ! ∑ r = 1 k − 1 s ( k − 1 , r ) ∑ m = 0 r ( r m ) ( k − 2 ) r − m ζ ( z + 1 − m ) , ℜ ( z ) > k − 1 , k = 3 , 4 , 5 , … {\displaystyleFactorization (7,851 words) [view diff] no match in snippet view article find links to article
E 2 n + F 2 n = ∏ k = 1 n ( E 2 + 2 E F cos ( 2 k − 1 ) π 2 n + F 2 ) = ∏ k = 1 n ( E 2 − 2 E F cos ( 2 k − 1 ) π 2 n + F 2 ) {\displaystyleGalois group (3,232 words) [view diff] no match in snippet view article find links to article
G_{2}.} The field K 1 K 2 {\displaystyle K_{1}K_{2}} with Galois group G = Gal ( K 1 K 2 / k ) {\displaystyle G=\operatorname {Gal} (K_{1}K_{2}/k)} hasAnalytic continuation (3,886 words) [view diff] no match in snippet view article find links to article
π ∑ n = k ∞ ( − 1 ) n ( n k ) ( a − 1 ) n − k ∫ 0 2 π d θ = ∑ n = k ∞ ( − 1 ) n ( n k ) ( a − 1 ) n − k = ( − 1 ) k ∑ m = 0 ∞ ( m + k k ) ( 1 − a ) mChi distribution (1,726 words) [view diff] exact match in snippet view article find links to article
( x ; k ) = { x k − 1 e − x 2 / 2 2 k / 2 − 1 Γ ( k 2 ) , x ≥ 0 ; 0 , otherwise . {\displaystyle f(x;k)={\begin{cases}{\dfrac {x^{k-1}e^{-x^{2}/2}}{2^{k/2-1}\GammaGert Fredriksson (427 words) [view diff] exact match in snippet view article find links to article
(1948: K-1 1000 m, K-1 10000 m; 1952: K-1 1000 m, 1956: K-1 1000 m, K-1 10000 m; 1960: K-2 1000 m), one silver (1952: K-1 10000 m), and one bronze (K-1 1000Topological sorting (3,170 words) [view diff] exact match in snippet view article find links to article
indices a k − 1 + ∑ i = 0 j − 1 | Q i k | , … , a k − 1 + ( ∑ i = 0 j | Q i k | ) − 1 {\textstyle a_{k-1}+\sum _{i=0}^{j-1}|Q_{i}^{k}|,\dots ,a_{k-1}+\left(\sumRademacher distribution (1,065 words) [view diff] no match in snippet view article find links to article
( k ) = { 1 / 2 if k = − 1 , 1 / 2 if k = + 1 , 0 otherwise. {\displaystyle f(k)=\left\{{\begin{matrix}1/2&{\text{if }}k=-1,\\1/2&{\text{if }}k=+1,\\0&{\text{otherwiseKaprekar's routine (3,143 words) [view diff] no match in snippet view article find links to article
) = α − β = ( ( 2 k − 1 ) − ( k − 1 ) ) b 2 n + 2 ( ∑ i = 0 n b i ) + ( k − k ) b n + 1 ( ∑ i = 0 n b i ) + ( ( k − 1 ) − ( 2 k − 1 ) ) ( ∑ i = 0 n bChain rule (7,087 words) [view diff] no match in snippet view article find links to article
( D f 2 ∘ f 3 . . n ) ⋯ ( D f n − 1 ∘ f n . . n ) D f n = ∏ k = 1 n [ D f k ∘ f ( k + 1 ) . . n ] {\displaystyle {\begin{aligned}Df_{1\,.\,.\,n}&=(Df_{1}\circBose–Einstein statistics (6,024 words) [view diff] no match in snippet view article find links to article
following formula w ( n , g ) = ∑ k 1 = 0 n ∑ k 2 = 0 n − k 1 w ( n − k 1 − k 2 , g − 2 ) = ∑ k 1 = 0 n ∑ k 2 = 0 n − k 1 ⋯ ∑ k g = 0 n − ∑ j = 1 g − 1 kInternational System of Units (6,146 words) [view diff] no match in snippet view article find links to article
the fixed numerical value of the Boltzmann constant k to 1.380649×10−23 J⋅K−1, (J = kg⋅m2⋅s−2), given the definition of the kilogram, the metre, and theRoot test (1,926 words) [view diff] exact match in snippet view article find links to article
K − 1 1 ∏ k = 1 i ln ( k ) ( n ) − ρ n ∏ k = 1 K ln ( k ) ( n ) + O ( 1 n ) . {\displaystyle \ln a_{n}=-1-\sum _{i=1}^{K-1}{\frac {1}{\prod _{k=1}^{i}\lnGeneralized Dirichlet distribution (1,861 words) [view diff] exact match in snippet view article find links to article
function of p 1 , … , p k − 1 {\displaystyle p_{1},\ldots ,p_{k-1}} is [ ∏ i = 1 k − 1 B ( a i , b i ) ] − 1 p k b k − 1 − 1 ∏ i = 1 k − 1 [ p i a i − 1 ( ∑Kaprekar number (4,058 words) [view diff] no match in snippet view article find links to article
= 2 k + 1 + ∑ i = 1 n ( 2 k + 1 ) b 2 i + ( 2 k + 1 ) b 2 i − 1 = 2 k + 1 + ∑ i = 1 2 n ( 2 k + 1 ) b i = ∑ i = 0 2 n ( 2 k + 1 ) b i = ( 2 k + 1 ) ∑Myanmar kyat (3,449 words) [view diff] no match in snippet view article find links to article
(plural), placed before the numerals followed by "/-". Amounts less than K. 1/- are typically denoted with the number of pyas following "-/" (e.g. -/50Alex Pereira (6,324 words) [view diff] exact match in snippet view article find links to article
losing by TKO in the second round. In 2013 he won the WAKO Pro Panamerican K-1 -85 kg/187 lb Championship. In late 2013 he went back to the amateurs toFloyd–Warshall algorithm (3,071 words) [view diff] exact match in snippet view article find links to article
t h ( i , j , k − 1 ) , {\displaystyle \mathrm {min} {\Big (}\mathrm {shortestPath} (i,j,k-1),} s h o r t e s t P a t h ( i , k , k − 1 ) + s h o r tInterest (9,217 words) [view diff] exact match in snippet view article find links to article
k − 1 r = k [ 1 + ( k − 1 ) r 2 + ⋯ ] {\displaystyle \lambda _{k}={\frac {p_{k}}{p}}={\frac {r_{k}}{r}}={\frac {(1+r)^{k}-1}{r}}=k\left[1+{\frac {(k-1)r}{2}}+\cdots2017 ICF Canoe Sprint World Championships (567 words) [view diff] exact match in snippet view article find links to article
Women's C–2 500 m results Women's K-1 200 m results Women's K-1 500 m results Women's K-1 1000 m results Women's K-1 5000 m results Women's K-2 200 m resultsDirichlet's test (999 words) [view diff] no match in snippet view article find links to article
k = 1 n M | a k − a k + 1 | = ∑ k = 1 n M ( a k − a k + 1 ) = M ∑ k = 1 n ( a k − a k + 1 ) , {\displaystyle \sum _{k=1}^{n}M|a_{k}-a_{k+1}|=\sum _{kInteger partition (3,396 words) [view diff] no match in snippet view article find links to article
= ∏ k = 1 ∞ ( 1 + x k ) = ∏ k = 1 ∞ 1 1 − x 2 k − 1 . {\displaystyle \sum _{n=0}^{\infty }q(n)x^{n}=\prod _{k=1}^{\infty }(1+x^{k})=\prod _{k=1}^{\inftyCanoeing at the 2008 Summer Olympics (70 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menSpline (mathematics) (3,784 words) [view diff] no match in snippet view article
0 , … , k − 1 [ a , b ] = [ t 0 , t 1 ) ∪ [ t 1 , t 2 ) ∪ ⋯ ∪ [ t k − 2 , t k − 1 ) ∪ [ t k − 1 , t k ) ∪ [ t k ] a = t 0 ≤ t 1 ≤ ⋯ ≤ t k − 1 ≤ t k =Abelian group (5,284 words) [view diff] no match in snippet view article find links to article
numbers k 1 , k 2 , … , k u {\displaystyle k_{1},k_{2},\dots ,k_{u}} are powers of (not necessarily distinct) primes, or k 1 {\displaystyle k_{1}} dividesFlory–Schulz distribution (288 words) [view diff] exact match in snippet view article find links to article
length k {\displaystyle k} is: w a ( k ) = a 2 k ( 1 − a ) k − 1 . {\displaystyle w_{a}(k)=a^{2}k(1-a)^{k-1}{\text{.}}} In this equation, k is the numberNewton's method in optimization (1,857 words) [view diff] no match in snippet view article find links to article
obtains the iterative scheme x k + 1 = x k − [ f ″ ( x k ) ] − 1 f ′ ( x k ) , k ≥ 0. {\displaystyle x_{k+1}=x_{k}-[f''(x_{k})]^{-1}f'(x_{k}),\qquad k\geq 0Pink noise (6,607 words) [view diff] no match in snippet view article find links to article
the interval [ k τ , ( k + 1 ) τ ] {\displaystyle [k\tau ,(k+1)\tau ]} as y k = 1 τ ∫ k τ ( k + 1 ) τ x ˙ ( t ) d t = x ( ( k + 1 ) τ ) − x ( k τ ) τ {\displaystyleMultinomial distribution (6,412 words) [view diff] exact match in snippet view article find links to article
n_{1}+\cdots +n_{k}=n\}.\,} Its number of elements is ( n + k − 1 k − 1 ) . {\displaystyle {n+k-1 \choose k-1}.} In matrix notation, E ( X ) = n p , {\displaystyleGoodness of fit (1,150 words) [view diff] no match in snippet view article find links to article
any k − 1 are known, the remaining one is uniquely determined. Basically, one can say, there are only k − 1 freely determined binn counts, thus k − 1 degreesGreen's theorem (4,074 words) [view diff] no match in snippet view article find links to article
\varepsilon } . We have | ∑ i = k + 1 s ∫ Γ i A d x + B d y | ≤ 1 2 ε ∑ i = k + 1 s Λ i . {\displaystyle \left\vert \sum _{i=k+1}^{s}\int _{\Gamma _{i}}A\,dx+B\Canoeing at the 2004 Summer Olympics (96 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menHexagonal number (1,028 words) [view diff] no match in snippet view article find links to article
∑ k = 1 ∞ 1 k ( 2 k − 1 ) = lim n → ∞ 2 ∑ k = 1 n ( 1 2 k − 1 − 1 2 k ) = lim n → ∞ 2 ∑ k = 1 n ( 1 2 k − 1 + 1 2 k − 1 k ) = 2 lim n → ∞ ( ∑ k = 1 2Home advantage (7,714 words) [view diff] no match in snippet view article find links to article
season to obtain k 1 {\displaystyle k_{1}} , k 0 {\displaystyle k_{0}} , and k − 1 {\displaystyle k_{-1}} . Values of k 1 {\displaystyle k_{1}} , k 0 {\displaystyle2010 ICF Canoe Sprint World Championships (1,990 words) [view diff] exact match in snippet view article find links to article
winningest medalist in men's kayak with his 21st career medal, earning that in a K-1 200 m silver. Rauhe eclipsed that record he had tied at the previous championshipsPhase velocity (1,075 words) [view diff] no match in snippet view article find links to article
x , t ) = cos ( k 1 x − ω 1 t ) + cos ( k 2 x − ω 2 t ) = 2 cos ( ( k 2 − k 1 ) x − ( ω 2 − ω 1 ) t 2 ) cos ( ( k 2 + k 1 ) x − ( ω 2 + ω 1 )Greatest common divisor (4,717 words) [view diff] exact match in snippet view article find links to article
d 1 − k ζ ( k ) − 1 = ζ ( k − 1 ) ζ ( k ) . {\displaystyle \mathrm {E} (k)=\sum _{d=1}^{\infty }d^{1-k}\zeta (k)^{-1}={\frac {\zeta (k-1)}{\zeta (k)}}Divisor function (3,781 words) [view diff] no match in snippet view article find links to article
k + 1 ) n k {\displaystyle \zeta (k+1)n^{k}} : σ k ( n ) = ζ ( k + 1 ) n k [ 1 + ( − 1 ) n 2 k + 1 + 2 cos 2 π n 3 3 k + 1 + 2 cos π n 2 4 k + 1 +Kolmogorov–Smirnov test (3,912 words) [view diff] no match in snippet view article find links to article
k = 1 ∞ ( − 1 ) k − 1 e − 2 k 2 x 2 = 2 π x ∑ k = 1 ∞ e − ( 2 k − 1 ) 2 π 2 / ( 8 x 2 ) , {\displaystyle \operatorname {Pr} (K\leq x)=1-2\sum _{k=1}^{\inftyCapacitance (4,187 words) [view diff] no match in snippet view article find links to article
with a Z/1 − K impedance between the first node and ground and a KZ/K − 1 impedance between the second node and ground. Since impedance varies inverselyPigeonhole principle (4,155 words) [view diff] no match in snippet view article find links to article
contain at least k + 1 objects. For arbitrary n and m, this generalizes to k + 1 = ⌊ ( n − 1 ) / m ⌋ + 1 = ⌈ n / m ⌉ {\displaystyle k+1=\lfloor (n-1)/m\rfloorLagrange multiplier (7,987 words) [view diff] no match in snippet view article find links to article
∇ f ( x ) = ∑ k = 1 M λ k ∇ g k ( x ) ⟺ ∇ f ( x ) − ∑ k = 1 M λ k ∇ g k ( x ) = 0 . {\displaystyle \nabla f(\mathbf {x} )=\sum _{k=1}^{M}\lambda _{k}\Elliptic Curve Digital Signature Algorithm (2,833 words) [view diff] no match in snippet view article find links to article
{\displaystyle r=0} , go back to step 3. Calculate s = k − 1 ( z + r d A ) mod n {\displaystyle s=k^{-1}(z+rd_{A})\,{\bmod {\,}}n} . If s = 0 {\displaystyleK-nearest neighbors algorithm (4,316 words) [view diff] no match in snippet view article find links to article
its k nearest neighbors (k is a positive integer, typically small). If k = 1, then the object is simply assigned to the class of that single nearestSubstitution reaction (1,456 words) [view diff] no match in snippet view article find links to article
described with k1, k−1 and k2, which are the rate constants of their corresponding intermediate reaction steps: L n M − L ⇌ + L , k − 1 − L , k 1 L n M − ◻ →Root test (1,926 words) [view diff] exact match in snippet view article find links to article
K − 1 1 ∏ k = 1 i ln ( k ) ( n ) − ρ n ∏ k = 1 K ln ( k ) ( n ) + O ( 1 n ) . {\displaystyle \ln a_{n}=-1-\sum _{i=1}^{K-1}{\frac {1}{\prod _{k=1}^{i}\lnParticle filter (16,882 words) [view diff] no match in snippet view article find links to article
k − 1 ) ) = p ( y k − 1 | x k − 1 ) p ( x k | x k − 1 ) p ( x k − 1 | y 0 , ⋯ , y k − 2 ) ∫ p ( y k − 1 | x k − 1 ′ ) p ( x k | x k − 1 ′ ) p ( x k −Ian Ferguson (canoeist) (638 words) [view diff] exact match in snippet view article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanKelvin (4,784 words) [view diff] no match in snippet view article find links to article
adopted at the 26th CGPM in late 2018, with a value of kB = 1.380649×10−23 J⋅K−1. In fundamental physics, the mapping E=kBT which converts between the characteristicRüdiger Helm (313 words) [view diff] exact match in snippet view article find links to article
medals which included three golds (1976: K-1 1000 m, 1980: K-1 1000 m, K-4 1000 m) and three bronzes (1976: K-1 500 m, K-4 1000 m; 1980: K-2 500 m). HelmS-matrix (9,208 words) [view diff] no match in snippet view article find links to article
, k 1 … k n ⟩ = a i † ( k 1 ) ⋯ a i † ( k n ) | i , 0 ⟩ } , {\displaystyle {\mathcal {H}}_{\rm {i}}=\operatorname {span} \{\left|\mathrm {i} ,k_{1}\ldotsDirichlet's test (999 words) [view diff] no match in snippet view article find links to article
k = 1 n M | a k − a k + 1 | = ∑ k = 1 n M ( a k − a k + 1 ) = M ∑ k = 1 n ( a k − a k + 1 ) , {\displaystyle \sum _{k=1}^{n}M|a_{k}-a_{k+1}|=\sum _{kZipf's law (4,591 words) [view diff] no match in snippet view article find links to article
&\ {\mbox{ if }}\ k<1\ {\mbox{ or }}\ N<k~.\end{cases}}} where HN is a normalization constant: The Nth harmonic number: H N ≡ ∑ k = 1 N 1 k . {\displaystyle2019 K-1 Air Base attack (1,303 words) [view diff] exact match in snippet view article find links to article
A rocket attack was carried out on the K-1 Air Base in Kirkuk province in Iraq on 27 December 2019. The air base was one of many Iraqi military basesExpectation–maximization algorithm (7,512 words) [view diff] no match in snippet view article find links to article
via F ^ = ∑ k = 1 N ( x ^ k + 1 − F ^ x ^ k ) 2 ∑ k = 1 N x ^ k 2 . {\displaystyle {\widehat {F}}={\frac {\sum _{k=1}^{N}{({\widehat {x}}_{k+1}-{\widehatCohen's kappa (3,698 words) [view diff] no match in snippet view article find links to article
following construction: p e = ∑ k p k 12 ^ = ind. ∑ k p k 1 ^ p k 2 ^ = ∑ k n k 1 N n k 2 N = 1 N 2 ∑ k n k 1 n k 2 {\displaystyle p_{e}=\sum _{k}{\widehat {p_{k12}}}{\oversetBroyden–Fletcher–Goldfarb–Shanno algorithm (2,987 words) [view diff] no match in snippet view article find links to article
B k + 1 ( x k + 1 − x k ) = ∇ f ( x k + 1 ) − ∇ f ( x k ) . {\displaystyle B_{k+1}(\mathbf {x} _{k+1}-\mathbf {x} _{k})=\nabla f(\mathbf {x} _{k+1})-\nablaSquare wave (waveform) (1,295 words) [view diff] no match in snippet view article
an infinite sum of sinusoidal waves: x ( t ) = 4 π ∑ k = 1 ∞ sin ( 2 π ( 2 k − 1 ) f t ) 2 k − 1 = 4 π ( sin ( ω t ) + 1 3 sin ( 3 ω t ) + 1 5 sinFermat number (4,717 words) [view diff] no match in snippet view article find links to article
( 2 k + 1 ) . {\displaystyle (2^{r}+1)\mid (2^{k}+1).} Because 1 < 2 r + 1 < 2 k + 1 {\displaystyle 1<2^{r}+1<2^{k}+1} , it follows that 2 k + 1 {\displaystyleLevi-Civita symbol (5,174 words) [view diff] no match in snippet view article find links to article
2-spinors. In three dimensions, the Levi-Civita symbol is defined by: ε i j k = { + 1 if ( i , j , k ) is ( 1 , 2 , 3 ) , ( 2 , 3 , 1 ) , or ( 3 , 1 ,Lebesgue integral (5,919 words) [view diff] no match in snippet view article find links to article
positive, we set ∫ ( ∑ k a k 1 S k ) d μ = ∑ k a k ∫ 1 S k d μ = ∑ k a k μ ( S k ) {\displaystyle \int \left(\sum _{k}a_{k}1_{S_{k}}\right)\,d\mu =\sumList of fighting games (2,012 words) [view diff] exact match in snippet view article find links to article
Fu Factory K-1 World GP K-1 World GP 2006 K-1 Premium 2005 Dynamite!! K-1 World GP 2005 K-1 World Max 2005 K-1 Premium 2004 Dynamite!! K-1 World GrandPercentile (2,647 words) [view diff] no match in snippet view article find links to article
C} , and v = v k + P − p k p k + 1 − p k ( v k + 1 − v k ) . {\displaystyle v=v_{k}+{\frac {P-p_{k}}{p_{k+1}-p_{k}}}(v_{k+1}-v_{k}).} The 50% weighted percentileKatalin Kovács (500 words) [view diff] exact match in snippet view article find links to article
seven silvers (K-1 1000 m: 2010, K-2 500 m: 2013, K-4 200 m: 2007, 2009, K-4 500 m: 1997, 1998, 2007), and three bronzes (K-1 500 m: 2001, K-1 1000 m: 1999Extended Euclidean algorithm (4,467 words) [view diff] no match in snippet view article find links to article
k + 1 {\displaystyle s_{k+1}} and t k + 1 {\displaystyle t_{k+1}} are coprime. The relation a s k + 1 + b t k + 1 = 0 {\displaystyle as_{k+1}+bt_{k+1}=0}Noncentral chi-squared distribution (3,719 words) [view diff] no match in snippet view article find links to article
variable is developed as V 1 / k 1 V 2 / k 2 ∼ F k 1 , k 2 ′ ( λ ) {\displaystyle {\frac {V_{1}/k_{1}}{V_{2}/k_{2}}}\sim F'_{k_{1},k_{2}}(\lambda )} If J ∼Danuta Kozák (615 words) [view diff] exact match in snippet view article find links to article
fourteen golds (K-1 500 m: 2013, 2014, 2018; K-2 200 m: 2011; K-2 500 m: 2009, 2010, 2015, 2018; K-4 500 m: 2009, 2011, 2013, 2014, 2018 and K-1 200 m relay:Polytope (3,119 words) [view diff] case mismatch in snippet view article find links to article
context, "flat sides" means that the sides of a (k + 1)-polytope consist of k-polytopes that may have (k – 1)-polytopes in common. Some theories further generalizeColor index (1,031 words) [view diff] no match in snippet view article find links to article
formula (also implemented in the PyAstronomy package for Python): T = 4600 K ( 1 0.92 ( B - V ) + 1.7 + 1 0.92 ( B - V ) + 0.62 ) . {\displaystyle T=4600\Rate of convergence (5,628 words) [view diff] no match in snippet view article find links to article
x k + 1 − x k x k − x k − 1 | log | x k − x k − 1 x k − 1 − x k − 2 | . {\displaystyle q\approx {\frac {\log \left|\displaystyle {\frac {x_{k+1Virial theorem (7,675 words) [view diff] no match in snippet view article find links to article
virial is − 1 2 ∑ k = 1 N F k ⋅ r k = 1 2 ∑ k = 1 N ∑ j < k d V j k d r j k r j k = 1 2 ∑ k = 1 N ∑ j < k n α r j k n − 1 r j k = 1 2 ∑ k = 1 N ∑ j < k n VDiscretization (2,400 words) [view diff] no match in snippet view article find links to article
− τ ) B u ( τ ) d τ x [ k + 1 ] = e A ( k + 1 ) T x ( 0 ) + ∫ 0 ( k + 1 ) T e A [ ( k + 1 ) T − τ ] B u ( τ ) d τ x [ k + 1 ] = e A T [ e A k T x ( 0Eulerian number (2,460 words) [view diff] no match in snippet view article find links to article
( n , k ) = ∑ i = 0 k ( − 1 ) i ( n + 1 i ) ( k + 1 − i ) n . {\displaystyle A(n,k)=\sum _{i=0}^{k}(-1)^{i}{\binom {n+1}{i}}(k+1-i)^{n}.} For fixed n2013 ICF Canoe Sprint World Championships (710 words) [view diff] exact match in snippet view article find links to article
Men's C–1 200 m Relay Results Men's K–1 200 m Results Men's K–1 500 m Results Men's K–1 1000 m Results Men's K–1 5000 m Results Men's K–2 200 m ResultsHodge star operator (6,501 words) [view diff] no match in snippet view article find links to article
i k + 1 , … , i n d x i k + 1 ∧ ⋯ ∧ d x i n . {\displaystyle {\star }\alpha ={\frac {1}{(n-k)!}}({\star }\alpha )_{i_{k+1},\dots ,i_{n}}dx^{i_{k+1}}\wedge2021 ICF Canoe Sprint World Championships (447 words) [view diff] exact match in snippet view article find links to article
September 2021. "Men's K-1 200" (PDF). Retrieved 19 September 2021. "Men's K-1 500" (PDF). Retrieved 19 September 2021. "Men's K-1 1000" (PDF). RetrievedRegular polygon (3,223 words) [view diff] no match in snippet view article find links to article
{1}{n}}\sum _{i=1}^{n}d_{i}^{2m}} , then S n ( 2 m ) = ( S n ( 2 ) ) m + ∑ k = 1 ⌊ m / 2 ⌋ ( m 2 k ) ( 2 k k ) R 2 k ( S n ( 2 ) − R 2 ) k ( S n ( 2 ) )Partial fraction decomposition (7,008 words) [view diff] exact match in snippet view article find links to article
\deg H_{k}<\deg G.} Setting F k − 1 = F C + Q , {\displaystyle F_{k-1}=FC+Q,} one gets F G k = H k G k + F k − 1 G k − 1 , {\displaystyle {\frac {F}{G^{k}}}={\fracList of ICF Canoe Sprint World Championships medalists in women's kayak (222 words) [view diff] no match in snippet view article find links to article
This is a list of medalists from the ICF Canoe Sprint World Championships in women's kayak. Debuted: 1994. Debuted: 1938. Not held: 1948. Resumed: 1950Vampire number (730 words) [view diff] exact match in snippet view article find links to article
digits: A = a k a k − 1 . . . a 1 {\displaystyle A={a_{k}}{a_{k-1}}...{a_{1}}} B = b k b k − 1 . . . b 1 {\displaystyle B={b_{k}}{b_{k-1}}...{b_{1}}} suchCanoeing at the 1996 Summer Olympics (81 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m men1 + 2 + 3 + 4 + ⋯ (4,221 words) [view diff] no match in snippet view article find links to article
partial sum of the series is the triangular number ∑ k = 1 n k = n ( n + 1 ) 2 , {\displaystyle \sum _{k=1}^{n}k={\frac {n(n+1)}{2}},} which increases withoutJosefa Idem (966 words) [view diff] exact match in snippet view article find links to article
Schüttpelz. The next year, Idem switched to the K-1 events. At the 1988 Olympics in Seoul, she finished ninth in the K-1 500 m and fifth with the West German quartetBorosilicate glass (3,666 words) [view diff] no match in snippet view article find links to article
are known for having very low coefficients of thermal expansion (≈3 × 10−6 K−1 at 20 °C), making them more resistant to thermal shock than any other commonMoiré pattern (4,166 words) [view diff] no match in snippet view article find links to article
= k 1 + k 2 2 {\displaystyle A={\frac {k_{1}+k_{2}}{2}}} and B = k 1 − k 2 2 . {\displaystyle B={\frac {k_{1}-k_{2}}{2}}.} This function average, f3Proof that 22/7 exceeds π (2,814 words) [view diff] no match in snippet view article find links to article
≥ 0 and ℓ ≥ 2 we have x k ( 1 − x ) ℓ = ( 1 − 2 x + x 2 ) x k ( 1 − x ) ℓ − 2 = ( 1 + x 2 ) x k ( 1 − x ) ℓ − 2 − 2 x k + 1 ( 1 − x ) ℓ − 2 . {\displaystyle2001 ICF Canoe Sprint World Championships (143 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Ronald Rauhe (GER) Oleksiy Slivinskiy (UKR) Anton Ryakhov (UZB) K-1 500 m Ákos Verecki (HUN) Anton Ryakhov (UZB)Dirichlet-multinomial distribution (6,950 words) [view diff] exact match in snippet view article find links to article
^{k}|n_{1}+\cdots +n_{k}=n\}.\,} Its number of elements is ( n + k − 1 k − 1 ) . {\displaystyle {n+k-1 \choose k-1}.} In matrix notation, E ( X ) = n p , {\displaystyleNegative hypergeometric distribution (1,911 words) [view diff] no match in snippet view article find links to article
− 1 k ) ( N − r − k K − k ) ( N K ) = 1 ( N K ) ∑ k = 0 K ( k + r − 1 k ) ( N − r − k K − k ) = 1 ( N K ) ( N K ) = 1 , {\displaystyle \sum _{k=0}^{K}\Pr(X=k)=\sumMathematical economics (13,624 words) [view diff] no match in snippet view article find links to article
) k / ( 1 − τ ) {\textstyle dw/d\tau =-f'(k)k/(1-\tau )} , we have that: d w d x = − f ′ ( k ) k 1 − τ f ′ ( k ) 1 − τ [ τ f ′ ( k ) f ″ ( k ) + k ] =Least squares (5,702 words) [view diff] no match in snippet view article find links to article
are obtained by successive approximation: β j k + 1 = β j k + Δ β j , {\displaystyle {\beta _{j}}^{k+1}={\beta _{j}}^{k}+\Delta \beta _{j},} where a superscriptMie scattering (9,207 words) [view diff] no match in snippet view article find links to article
{M} _{o1n}^{(1)}(k_{1},\mathbf {r} )\right),} H 1 = − k 1 ω μ 1 ∑ n = 1 ∞ E n ( d n M e 1 n ( 1 ) ( k 1 , r ) + i c n N o 1 n ( 1 ) ( k 1 , r ) ) . {\displaystyle1999 ICF Canoe Sprint World Championships (79 words) [view diff] exact match in snippet view article find links to article
Time K-1 200 m Caroline Brunet (CAN) Josefa Idem (ITA) Rita Kőbán (HUN) K-1 500 m Caroline Brunet (CAN) Josefa Idem (ITA) Rita Kőbán (HUN) K-1 1000(a,b,0) class of distributions (797 words) [view diff] exact match in snippet view article
satisfies the recurrence formula p k p k − 1 = a + b k , k = 1 , 2 , 3 , … {\displaystyle {\frac {p_{k}}{p_{k-1}}}=a+{\frac {b}{k}},\qquad k=1,2,3,\dotsAleksandr Shaparenko (208 words) [view diff] exact match in snippet view article find links to article
1972: K-1 1000 m) and one silver (1968: K-1 1000 m). Shaparenko also won 13 medals at the ICF Canoe Sprint World Championships with seven golds (K-1 1000Friedman test (1,169 words) [view diff] no match in snippet view article find links to article
12 n k ( k + 1 ) ∑ j = 1 k ( r ¯ ⋅ j − k + 1 2 ) 2 {\displaystyle Q={\frac {12n}{k(k+1)}}\sum _{j=1}^{k}\left({\bar {r}}_{\cdot j}-{\frac {k+1}{2}}\right)^{2}}Integral test for convergence (1,727 words) [view diff] exact match in snippet view article find links to article
( x ) for k = 1 , ln ( ln k − 1 ( x ) ) for k ≥ 2. {\displaystyle \ln _{k}(x)={\begin{cases}\ln(x)&{\text{for }}k=1,\\\ln(\ln _{k-1}(x))&{\text{forAutoregressive model (5,421 words) [view diff] no match in snippet view article find links to article
expressed as [citation needed] ρ ( τ ) = ∑ k = 1 p a k y k − | τ | , {\displaystyle \rho (\tau )=\sum _{k=1}^{p}a_{k}y_{k}^{-|\tau |},} where y k {\displaystyleLah number (1,812 words) [view diff] exact match in snippet view article find links to article
, k − 1 ) = k ( k + 1 ) L ( n , k + 1 ) + 2 k L ( n , k ) + L ( n , k − 1 ) {\displaystyle {\begin{aligned}L(n+1,k)&=(n+k)L(n,k)+L(n,k-1)\\&=k(k+1)L(nKnot theory (6,292 words) [view diff] no match in snippet view article find links to article
{R} ^{3}} , with the only "non-injectivity" being K ( 0 ) = K ( 1 ) {\displaystyle K(0)=K(1)} . Topologists consider knots and other entanglements suchMarkov chain (12,894 words) [view diff] no match in snippet view article find links to article
X_{0}=i)>0\}} The state is periodic if k > 1 {\displaystyle k>1} ; otherwise k = 1 {\displaystyle k=1} and the state is aperiodic. A state i is saidCharacteristic polynomial (3,040 words) [view diff] exact match in snippet view article find links to article
A^{k}} because A k v = A k − 1 A v = λ A k − 1 v = ⋯ = λ k v . {\displaystyle A^{k}{\textbf {v}}=A^{k-1}A{\textbf {v}}=\lambda A^{k-1}{\textbf {v}}=\dots =\lambdaRita Kőbán (398 words) [view diff] exact match in snippet view article find links to article
(K-1 200 m: 1994, 1995; K-1 500 m: 1995, K-2 200 m: 1994, K-4 200 m: 1994, 1998, 1999; K-4 500 m: 1986, 1999), ten silvers (K-1 500 m: 1991, 1994; K-1Almost prime (402 words) [view diff] exact match in snippet view article find links to article
log log n ) k − 1 ( k − 1 ) ! , {\displaystyle \pi _{k}(n)\sim \left({\frac {n}{\log n}}\right){\frac {(\log \log n)^{k-1}}{(k-1)!}},} a result ofGeneral Leibniz rule (1,247 words) [view diff] no match in snippet view article find links to article
_{t=1}^{m}k_{t}=n,} and ( n k 1 , k 2 , … , k m ) = n ! k 1 ! k 2 ! ⋯ k m ! {\displaystyle {n \choose k_{1},k_{2},\ldots ,k_{m}}={\frac {n!}{k_{1}!\,k_{2}!\cdotsCube (algebra) (3,026 words) [view diff] exact match in snippet view article
well-known identity: n 2 = ∑ k = 1 n ( 2 k − 1 ) , {\displaystyle n^{2}=\sum _{k=1}^{n}(2k-1),} we obtain the following derivation: ∑ k = 1 n k 3 = 1 + 8 + 27 +Hermite polynomials (12,119 words) [view diff] exact match in snippet view article find links to article
k + 1 ) a n , k + 1 k = 0 , a n , k − 1 − ( k + 1 ) a n , k + 1 k > 0 , {\displaystyle a_{n+1,k}={\begin{cases}-(k+1)a_{n,k+1}&k=0,\\a_{n,k-1}-(k+1)a_{nYule–Simon distribution (1,312 words) [view diff] exact match in snippet view article find links to article
is an integer, f ( k ; ρ ) = ρ ρ ! ( k − 1 ) ! ( k + ρ ) ! . {\displaystyle f(k;\rho )={\frac {\rho \,\rho !\,(k-1)!}{(k+\rho )!}}.} The parameter ρ {\displaystyleChebyshev polynomials (11,475 words) [view diff] no match in snippet view article find links to article
k ) ( 1 − x − 2 ) k = n 2 ∑ k = 0 ⌊ n 2 ⌋ ( − 1 ) k ( n − k − 1 ) ! k ! ( n − 2 k ) ! ( 2 x ) n − 2 k for n > 0 = n ∑ k = 0 n ( − 2 ) k ( n + kHypoexponential distribution (1,758 words) [view diff] no match in snippet view article find links to article
finite state Markov process. If we have a k+1 state process, where the first k states are transient and the state k+1 is an absorbing state, then the distributionFerenc Csipes (356 words) [view diff] exact match in snippet view article find links to article
with eight golds (K-1 1000 m: 1985, K-1 10000 m: 1986, K-2 500 m: 1987, K-4 1000 m: 1986, 1987, 1989, 1990, 1991), four silvers (K-1 1000 m: 1986, 19872022 ICF Canoe Sprint World Championships (70 words) [view diff] exact match in snippet view article find links to article
C-2 1000m men C-4 500m men women Kayak events K-1 200m men women K-1 500m men women K-1 1000m men women K-1 5000m men women K-2 200m women K-2 500m menRonald Rauhe (647 words) [view diff] exact match in snippet view article find links to article
years older he won two medals – gold in the K-4 500 m and silver in the K-1 500 m, an unprecedented achievement for a fifteen-year-old. After winningCanoeing at the 1992 Summer Olympics (88 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menMaximum entropy probability distribution (4,530 words) [view diff] no match in snippet view article find links to article
x k } = p k for k = 1 , 2 , … {\displaystyle \operatorname {Pr} \{\ X=x_{k}\}=p_{k}\qquad ~{\mbox{ for }}~\quad k=1,\ 2,\ \ldots ~} then the2019 ICF Canoe Sprint World Championships (1,279 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200, 500, 1000 or 5000 metresHalf-logistic distribution (247 words) [view diff] no match in snippet view article find links to article
2F(k) − 1 is the cdf of a half-logistic distribution. Specifically, G ( k ) = 1 − e − k 1 + e − k for k ≥ 0. {\displaystyle G(k)={\frac {1-e^{-k}}{1+e^{-k}}}{\text{Canoeing at the 1976 Summer Olympics (76 words) [view diff] exact match in snippet view article find links to article
in the Montreal program though four 500 m events for men were (C-1, C-2, K-1, and K-2). 1976 Summer Olympics official report Volume 3. pp. 167–85. (in2005 ICF Canoe Sprint World Championships (330 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Carlos Pérez (ESP) 35.289 Tomasz Mendelski (POL) 35.697 Anton Ryakhov (RUS) 35.733 K-1 500 m Nathan Baggaley (AUS)Faà di Bruno's formula (3,788 words) [view diff] no match in snippet view article find links to article
noticing that m j {\displaystyle m_{j}} has to be zero for j > n − k + 1 {\displaystyle j>n-k+1} leads to a somewhat simpler formula expressed in terms of partialSquare triangular number (1,478 words) [view diff] exact match in snippet view article find links to article
x k + 1 = 2 x k x 1 − x k − 1 , y k + 1 = 2 y k x 1 − y k − 1 . {\displaystyle \displaystyle {\begin{aligned}x_{k+1}&=2x_{k}x_{1}-x_{k-1},\\y_{k+1}&=2y_{k}x_{1}-y_{k-1}Tensor algebra (4,161 words) [view diff] no match in snippet view article find links to article
one has scalar multiplication on the field: k 1 ⊗ k 2 = k 1 k 2 . {\displaystyle k_{1}\otimes k_{2}=k_{1}k_{2}.} The most difficult to verify is the compatibilityPythagorean theorem (12,704 words) [view diff] no match in snippet view article find links to article
equation ‖ ∑ k = 1 n v k ‖ 2 = ∑ k = 1 n ‖ v k ‖ 2 {\displaystyle {\biggl \|}\sum _{k=1}^{n}\mathbf {v} _{k}{\biggr \|}^{2}=\sum _{k=1}^{n}\|\mathbfPythagorean theorem (12,704 words) [view diff] no match in snippet view article find links to article
equation ‖ ∑ k = 1 n v k ‖ 2 = ∑ k = 1 n ‖ v k ‖ 2 {\displaystyle {\biggl \|}\sum _{k=1}^{n}\mathbf {v} _{k}{\biggr \|}^{2}=\sum _{k=1}^{n}\|\mathbfRoot of unity (5,939 words) [view diff] no match in snippet view article find links to article
of unity, as ( z k ) n = z k n = ( z n ) k = 1 k = 1. {\displaystyle (z^{k})^{n}=z^{kn}=(z^{n})^{k}=1^{k}=1.} This is also true for negative exponents2005 ICF Canoe Sprint World Championships (330 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Carlos Pérez (ESP) 35.289 Tomasz Mendelski (POL) 35.697 Anton Ryakhov (RUS) 35.733 K-1 500 m Nathan Baggaley (AUS)Arithmetic function (7,550 words) [view diff] no match in snippet view article find links to article
k 1 , n ) = 1 1 ≤ k 1 , k 2 , … , k s ≤ n gcd ( k 1 − 1 , k 2 , … , k s , n ) = φ ( n ) σ s − 1 ( n ) . {\displaystyle \sum _{\stackrel {1\leq k_{1}Squared triangular number (1,867 words) [view diff] no match in snippet view article find links to article
mathematical notation for summation: ∑ k = 1 n k 3 = ( ∑ k = 1 n k ) 2 . {\displaystyle \sum _{k=1}^{n}k^{3}=\left(\sum _{k=1}^{n}k\right)^{2}.} This identityGaussian elimination (4,368 words) [view diff] exact match in snippet view article find links to article
R_{i}} with r k , k R i − r i , k R k r k − 1 , k − 1 . {\textstyle {\frac {r_{k,k}R_{i}-r_{i,k}R_{k}}{r_{k-1,k-1}}}.} This produces a row echelon formProbability mass function (1,539 words) [view diff] exact match in snippet view article find links to article
success. Its probability mass function is p X ( k ) = ( 1 − p ) k − 1 p {\textstyle p_{X}(k)=(1-p)^{k-1}p} . An example is tossing a coin until the firstVibration (7,235 words) [view diff] no match in snippet view article find links to article
defined by the following formula. X = F 0 k 1 ( 1 − r 2 ) 2 + ( 2 ζ r ) 2 . {\displaystyle X={F_{0} \over k}{1 \over {\sqrt {(1-r^{2})^{2}+(2\zeta r)^{2}}}}2006 ICF Canoe Sprint World Championships (337 words) [view diff] exact match in snippet view article find links to article
final, giving Mexico their first-ever world championship gold medal. The K-1 1000 m, the Blue Riband event, was won by Markus Oscarsson of Sweden. Germany'sPower rule (2,631 words) [view diff] exact match in snippet view article find links to article
i.e. d d x x k = k x k − 1 . {\displaystyle {\frac {d}{dx}}x^{k}=kx^{k-1}.} When n = k + 1 {\displaystyle n=k+1} , d d x x k + 1 = d d x ( x k ⋅ x ) =Droop quota (2,336 words) [view diff] no match in snippet view article find links to article
and truncate: ⌈ total votes k + 1 ⌉ ≈ ⌊ total votes k + 1 + 1 ⌋ {\displaystyle \left\lceil {\frac {\text{total votes}}{k+1}}\right\rceil \approx \left\lfloorCholesky decomposition (8,335 words) [view diff] no match in snippet view article find links to article
for k = 1:n r = sqrt(L(k, k)^2 + x(k)^2); c = r / L(k, k); s = x(k) / L(k, k); L(k, k) = r; if k < n L((k+1):n, k) = (L((k+1):n, k) + s * x((k+1):n))Distortion (optics) (2,784 words) [view diff] no match in snippet view article
given by x d = x c + x u − x c 2 K 1 r u 2 ( 1 − 1 − 4 K 1 r u 2 ) y d = y c + y u − y c 2 K 1 r u 2 ( 1 − 1 − 4 K 1 r u 2 ) , {\displaystyle {\begin{aligned}x_{\mathrmLists of integrals (5,611 words) [view diff] no match in snippet view article find links to article
( x ) − ( − 1 ) n d n f ( x ) d x n ) d x = e x ∑ k = 1 n ( − 1 ) k − 1 d k − 1 f ( x ) d x k − 1 + C {\displaystyle \int {e^{x}\left(f\left(x\rightPerfect digital invariant (5,240 words) [view diff] no match in snippet view article find links to article
1 ) ( 3 k + 1 ) − k ( 3 k + 1 ) = ( k + 1 ) ( 3 k + 1 ) ( 3 k + 1 ) − k ( 3 k + 1 ) = k ( 3 k + 1 ) ( 3 k + 1 ) + ( 3 k + 1 ) ( 3 k + 1 ) − k ( 3 k +Zeta distribution (1,030 words) [view diff] no match in snippet view article find links to article
defined for positive integers k ≥ 1 {\displaystyle k\geq 1} , and its probability mass function is given by P ( x = k ) = 1 ζ ( s ) k − s , {\displaystyleRaman Piatrushenka (603 words) [view diff] exact match in snippet view article find links to article
m bronze. In the K-1 1000m however, he could only finish 17th. At the 2002 European under-23 Championships in Zagreb, he won the K-1 1000 m gold medalQuasi-Newton method (2,264 words) [view diff] no match in snippet view article find links to article
approximate Hessian B k + 1 {\displaystyle B_{k+1}} , or directly its inverse H k + 1 = B k + 1 − 1 {\displaystyle H_{k+1}=B_{k+1}^{-1}} using the Sherman–MorrisonFalling and rising factorials (3,377 words) [view diff] no match in snippet view article find links to article
= x n _ = x ( x − 1 ) ( x − 2 ) ⋯ ( x − n + 1 ) ⏞ n factors = ∏ k = 1 n ( x − k + 1 ) = ∏ k = 0 n − 1 ( x − k ) . {\displaystyle {\begin{aligned}(x)_{n}=x^{\underlineAbel's test (1,047 words) [view diff] no match in snippet view article find links to article
absolutely: ∑ k = 1 ∞ | ( a k − a k − 1 ) z k | = ∑ k = 1 ∞ | a k − a k − 1 | ⋅ | z | k ≤ ∑ k = 1 ∞ ( a k − 1 − a k ) {\displaystyle \sum _{k=1}^{\inftyCharacteristic function (probability theory) (5,208 words) [view diff] no match in snippet view article
) − k 1 ( 1 − θ i t ) − k 2 = ( 1 − θ i t ) − ( k 1 + k 2 ) . {\displaystyle \varphi _{X+Y}(t)=\varphi _{X}(t)\varphi _{Y}(t)=(1-\theta it)^{-k_{1}}(1-\thetaFourier series (11,131 words) [view diff] no match in snippet view article find links to article
1 1 φ ( y ) cos ( 2 k + 1 ) π y 2 d y = ∫ − 1 1 ( a cos π y 2 cos ( 2 k + 1 ) π y 2 + a ′ cos 3 π y 2 cos ( 2 k + 1 ) π y 2 + ⋯ ) d y {\displaystyleKen Wallace (canoeist) (270 words) [view diff] exact match in snippet view article
gold in the K-1 500 m and bronze in the K-1 1000 m events. He also won two medals at the ICF Canoe Sprint World Championships with a gold (K-1 5000 m: 2010)Reversible reaction (894 words) [view diff] no match in snippet view article find links to article
at the final kinetic expression: [ A ] = k -1 [ A ] 0 k 1 + k -1 + k 1 [ A ] 0 k 1 + k -1 exp ( − k 1 + k -1 ) t {\displaystyle [A]={\fracCross-polytope (1,106 words) [view diff] no match in snippet view article find links to article
is thus given by (see binomial coefficient): 2 k + 1 ( n k + 1 ) {\displaystyle 2^{k+1}{n \choose {k+1}}} The extended f-vector for an n-orthoplex canRandom forest (6,483 words) [view diff] no match in snippet view article find links to article
function, or connection function is K k c c ( x , z ) = ∑ k 1 , … , k d , ∑ j = 1 d k j = k k ! k 1 ! ⋯ k d ! ( 1 d ) k ∏ j = 1 d 1 ⌈ 2 k j x j ⌉ = ⌈ 2 kHSL and HSV (10,785 words) [view diff] case mismatch in snippet view article find links to article
f ( n ) = L − a max ( − 1 , min ( k − 3 , 9 − k , 1 ) ) {\displaystyle f(n)=L-a\max(-1,\min(k-3,9-k,1))} where k , n ∈ R ≥ 0 {\displaystyle k,n\in \mathbbHeat exchanger (9,485 words) [view diff] no match in snippet view article find links to article
where k 1 = γ / J 1 {\displaystyle k_{1}=\gamma /J_{1}} , k 2 = γ / J 2 {\displaystyle k_{2}=\gamma /J_{2}} , k = k 1 + k 2 {\displaystyle k=k_{1}+k_{2}}Natasa Dusev-Janics (717 words) [view diff] exact match in snippet view article find links to article
won 26 medals at the ICF Canoe Sprint World Championships with 20 golds (K-1 200 m: 2007, 2009, 2010; K-2 200 m: 2005, 2006, 2009, 2010; K-2 500 m: 2005Zsolt Gyulay (337 words) [view diff] exact match in snippet view article find links to article
(1988: K-1 500 m, K-4 1000 m) and two silver (1992: K-1 500 m, K-4 1000 m). He also won fourteen medals at the world championships: six golds (K-1 10002009 ICF Canoe Sprint World Championships (3,937 words) [view diff] exact match in snippet view article find links to article
men's 500 m events (C-1, C-2, K-1 and K-2) at the Summer Olympics with the 200 m events (men's C-1, K-1 and K-2; and women's K-1) for the upcoming Summer OlympicsCauchy–Schwarz inequality (5,175 words) [view diff] no match in snippet view article find links to article
⟩ | 2 = | ∑ k = 1 n u k v ¯ k | 2 ≤ ⟨ u , u ⟩ ⟨ v , v ⟩ = ( ∑ k = 1 n u k u ¯ k ) ( ∑ k = 1 n v k v ¯ k ) = ∑ j = 1 n | u j | 2 ∑ k = 1 n | v k | 2Sampling distribution (731 words) [view diff] exact match in snippet view article find links to article
k ) ( x ) = ( 2 k − 1 ) ! ( k − 1 ) ! 2 f ( x ) ( F ( x ) ( 1 − F ( x ) ) ) k − 1 {\displaystyle f_{X_{(k)}}(x)={\frac {(2k-1)!}{(k-1)!^{2}}}f(x){\BigGauss–Kuzmin distribution (569 words) [view diff] no match in snippet view article find links to article
_{2}\left(1-{\frac {1}{(1+k)^{2}}}\right)~.} Let x = 1 k 1 + 1 k 2 + ⋯ {\displaystyle x={\cfrac {1}{k_{1}+{\cfrac {1}{k_{2}+\cdots }}}}} be the continued fractionConvergence tests (2,222 words) [view diff] no match in snippet view article find links to article
case of p = 1 , k = 1 {\displaystyle p=1,k=1} yields the harmonic series, which diverges. The case of p = 2 , k = 1 {\displaystyle p=2,k=1} is the BaselFactorion (1,282 words) [view diff] exact match in snippet view article find links to article
the following: SFD b ( n ) = ∑ i = 0 k − 1 d i ! . {\displaystyle \operatorname {SFD} _{b}(n)=\sum _{i=0}^{k-1}d_{i}!.} where k = ⌊ log b n ⌋ + 1 {\displaystyleDiscrete phase-type distribution (596 words) [view diff] no match in snippet view article find links to article
distribution function is F ( k ) = 1 − τ T k 1 , {\displaystyle F(k)=1-{\boldsymbol {\tau }}{T}^{k}\mathbf {1} ,} for k = 1 , 2 , . . . {\displaystyle k=1Population model (734 words) [view diff] no match in snippet view article find links to article
equations: d N 1 d t = r 1 N 1 K 1 − N 1 − α N 2 K 1 {\displaystyle {\frac {dN_{1}}{dt}}=r_{1}N_{1}{\frac {K_{1}-N_{1}-\alpha N_{2}}{K_{1}}}\,} Island biogeography:Merit order (2,602 words) [view diff] no match in snippet view article find links to article
total welfare is then W = ∑ k = 1 n V k ( D k ) − ∑ k = 1 n C k ( S k ) {\displaystyle W=\sum _{k=1}^{n}V_{k}(D_{k})-\sum _{k=1}^{n}C_{k}(S_{k})} The economicTriple point (1,328 words) [view diff] no match in snippet view article find links to article
was redefined so that the Boltzmann constant is exactly 1.380649×10−23 J⋅K−1, and the triple point of water became an experimentally measured constantPhytomenadione (1,333 words) [view diff] no match in snippet view article find links to article
Phytomenadione, also known as vitamin K1 or phylloquinone, is a vitamin found in food and used as a dietary supplement. It is on the World Health Organization'sInitial condition (1,362 words) [view diff] exact match in snippet view article find links to article
d t k + a k − 1 d k − 1 x d t k − 1 + ⋯ + a 1 d x d t + a 0 x = 0. {\displaystyle {\frac {d^{k}x}{dt^{k}}}+a_{k-1}{\frac {d^{k-1}x}{dt^{k-1}}}+\cdotsCumulant (8,867 words) [view diff] exact match in snippet view article find links to article
∑ k = 1 n ( − 1 ) k − 1 ( k − 1 ) ! B n , k ( μ 1 ′ , … , μ n − k + 1 ′ ) , {\displaystyle \kappa _{n}=\sum _{k=1}^{n}(-1)^{k-1}(k-1)!B_{n,k}(\mu '_{1}Standard RAID levels (4,551 words) [view diff] exact match in snippet view article find links to article
{\displaystyle D} as polynomials D = d k − 1 x k − 1 + d k − 2 x k − 2 + . . . + d 1 x + d 0 {\displaystyle \mathbf {D} =d_{k-1}x^{k-1}+d_{k-2}x^{k-2}+...+d_{1}x+d_{0}}2003 ICF Canoe Sprint World Championships (217 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Ronald Rauhe (GER) 35.798 Vince Fehérvári (AUS) 36.411 Anton Ryakhov (UZB) 36.417 K-1 500 m Nathan Baggaley (AUS)Triple DES (2,946 words) [view diff] no match in snippet view article find links to article
would be to use two keys ( K 1 , K 2 ) {\displaystyle (K1,K2)} instead of one, and encrypt each block twice: E K 2 ( E K 1 ( plaintext ) ) {\displaystyleNewton's identities (7,644 words) [view diff] case mismatch in snippet view article find links to article
including general relativity. Let x1, ..., xn be variables, denote for k ≥ 1 by pk(x1, ..., xn) the k-th power sum: p k ( x 1 , … , x n ) = ∑ i = 1 nCanoeing at the 1984 Summer Olympics (66 words) [view diff] exact match in snippet view article find links to article
Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m men women K-2 1000 m men K-4 500 m women K-4Gauss–Markov theorem (4,717 words) [view diff] no match in snippet view article find links to article
variable β K + 1 {\displaystyle \beta _{K+1}} with a newly introduced last column of X being unity i.e., X i ( K + 1 ) = 1 {\displaystyle X_{i(K+1)}=1} forFunction of several complex variables (17,688 words) [view diff] no match in snippet view article find links to article
∂ k 1 + ⋯ + k n f ( ζ 1 , ζ 2 , … , ζ n ) ∂ z 1 k 1 ⋯ ∂ z n k n | ≤ M k 1 ! ⋯ k n ! r 1 k 1 ⋯ r n k n {\displaystyle \left|{\frac {\partial ^{k_{1}+\cdotsRecursion (3,677 words) [view diff] no match in snippet view article find links to article
{\displaystyle k\in \mathbb {N} } . Then F(k + 1) = f(F(k)) = f(G(k)) = G(k + 1). Hence F(k) = G(k) implies F(k + 1) = G(k + 1). By induction, F(n) = G(n) for allMerit order (2,602 words) [view diff] no match in snippet view article find links to article
total welfare is then W = ∑ k = 1 n V k ( D k ) − ∑ k = 1 n C k ( S k ) {\displaystyle W=\sum _{k=1}^{n}V_{k}(D_{k})-\sum _{k=1}^{n}C_{k}(S_{k})} The economicCyclic permutation (2,039 words) [view diff] no match in snippet view article find links to article
= ( k k + 1 ) ⋅ ( k + 1 k + 2 ) ⋯ ( l − 1 l ) ⋅ ( l − 2 l − 1 ) ⋯ ( k k + 1 ) . {\displaystyle (k~~l)=(k~~k+1)\cdot (k+1~~k+2)\cdotsDiagonalizable matrix (4,692 words) [view diff] no match in snippet view article find links to article
1 k 0 0 0 1 k 0 0 0 2 k ] [ 1 0 1 1 2 0 0 1 − 1 ] − 1 = [ 2 − 2 k − 1 + 2 k 2 − 2 k + 1 0 1 0 − 1 + 2 k 1 − 2 k − 1 + 2 k + 1 ] . {\displaystyleYokosuka MXY-7 Ohka (3,234 words) [view diff] exact match in snippet view article find links to article
had the engine of the Model 11 and the airframe of the Model 22. The Ohka K-1 was an unpowered trainer version with water ballast instead of warhead andSquare root (6,182 words) [view diff] no match in snippet view article find links to article
e k + 1 p k + 1 2 e k + 1 … p n 2 e n = p 1 e 1 … p n e n p 1 … p k . {\displaystyle {\sqrt {p_{1}^{2e_{1}+1}\cdots p_{k}^{2e_{k}+1}p_{k+1}^{2e_{k+1}}\dotsInitial condition (1,362 words) [view diff] exact match in snippet view article find links to article
d t k + a k − 1 d k − 1 x d t k − 1 + ⋯ + a 1 d x d t + a 0 x = 0. {\displaystyle {\frac {d^{k}x}{dt^{k}}}+a_{k-1}{\frac {d^{k-1}x}{dt^{k-1}}}+\cdots2007 ICF Canoe Sprint World Championships (267 words) [view diff] exact match in snippet view article find links to article
K-2 races were ruled by the German paddlers. However, Katalin Kovács won K-1 1000 m and 500 m, and gained two silvers in the K-4 events, while formerLewandowski-Kurowicka-Joe distribution (425 words) [view diff] no match in snippet view article find links to article
k = 1 d − 1 ( 2 η − 2 + d − k ) ( d − k ) ∏ k = 1 d − 1 [ B ( η + ( d − k − 1 ) / 2 , η + ( d − k − 1 ) / 2 ) ] d − k {\displaystyle C=2^{\sum _{k=1}^{d-1}(2\etaMultivariate normal distribution (9,619 words) [view diff] no match in snippet view article find links to article
k 1 {\displaystyle k_{1}} and k 2 {\displaystyle k_{2}} dimensional marginal distributions X {\displaystyle X} and Y {\displaystyle Y} , such that k 1F-test (2,188 words) [view diff] exact match in snippet view article find links to article
1 K n i ( Y ¯ i ⋅ − Y ¯ ) 2 / ( K − 1 ) {\displaystyle \sum _{i=1}^{K}n_{i}({\bar {Y}}_{i\cdot }-{\bar {Y}})^{2}/(K-1)} where Y ¯ i ⋅ {\displaystyle {\barConvergence tests (2,222 words) [view diff] no match in snippet view article find links to article
case of p = 1 , k = 1 {\displaystyle p=1,k=1} yields the harmonic series, which diverges. The case of p = 2 , k = 1 {\displaystyle p=2,k=1} is the BaselNewton's identities (7,644 words) [view diff] case mismatch in snippet view article find links to article
including general relativity. Let x1, ..., xn be variables, denote for k ≥ 1 by pk(x1, ..., xn) the k-th power sum: p k ( x 1 , … , x n ) = ∑ i = 1 n2003 ICF Canoe Sprint World Championships (217 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Ronald Rauhe (GER) 35.798 Vince Fehérvári (AUS) 36.411 Anton Ryakhov (UZB) 36.417 K-1 500 m Nathan Baggaley (AUS)Canoeing at the 2000 Summer Olympics (131 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menCaroline Brunet (212 words) [view diff] exact match in snippet view article find links to article
(K-1 200 m: 1997, 1998, 1999, 2003; K-1 500 m: 1997, 1998, 1999; K-1 1000 m: 1997, 1999; K-4 200 m: 1995), seven silvers (K-1 200 m: 1995, 2002; K-1 500Mass–energy equivalence (11,628 words) [view diff] no match in snippet view article find links to article
energy K by an additive constant, which gives K 0 − K 1 = E ( 1 1 − v 2 c 2 − 1 ) {\displaystyle K_{0}-K_{1}=E\left({\frac {1}{\sqrt {1-{\frac {v^{2}}{c^{2}}}}}}-1\right)}2018 ICF Canoe Sprint World Championships (1,178 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200, 500, 1000 or 5000 metresProjection (linear algebra) (5,806 words) [view diff] no match in snippet view article
i 2 1 ≤ i ≤ k 1 k + 1 ≤ i ≤ n − k 0 otherwise {\displaystyle \sigma _{i}={\begin{cases}{\sqrt {1+\gamma _{i}^{2}}}&1\leq i\leq k\\1&k+1\leq i\leqMonotone convergence theorem (5,489 words) [view diff] no match in snippet view article find links to article
k ( x ) ≤ f k + 1 ( x ) {\displaystyle (1-\varepsilon )s(x)\leq f_{k}(x)\leq f_{k+1}(x)} so x ∈ B k + 1 s , ε . {\displaystyle x\in B_{k+1}^{s,\varepsilonArithmetico-geometric sequence (2,160 words) [view diff] no match in snippet view article find links to article
arithmetico-geometric series has the form S n = ∑ k = 1 n A k G k = ∑ k = 1 n ( a + ( k − 1 ) d ) b r k − 1 = b ∑ k = 0 n − 1 ( a + k d ) r k = a b + ( a2002 ICF Canoe Sprint World Championships (136 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Ronald Rauhe (GER) Anton Ryakhov (UZB) Roman Petrukanecas (LTU) K-1 500 m Nathan Baggaley (AUS) Petar Merkov (BUL)Sinc function (3,074 words) [view diff] exact match in snippet view article find links to article
k − 1 ∑ n = 1 2 k − 1 cos ( n − 1 / 2 2 k − 1 x ) , ∀ k ≥ 1 , {\displaystyle \prod _{n=1}^{k}\cos \left({\frac {x}{2^{n}}}\right)={\frac {1}{2^{k-1}}}\sumEast Germany at the 1980 Summer Olympics (2,024 words) [view diff] exact match in snippet view article find links to article
Men's K-1 1000m Gold Rüdiger Helm Bernd Olbricht Harald Marg Bernd Duvigneau Canoeing Men's K-4 1000m Gold Birgit Fischer Canoeing Women's K-1 500m GoldBotond Storcz (378 words) [view diff] exact match in snippet view article find links to article
medals at the ICF Canoe Sprint World Championships with four golds (K-1 500 m: 1997, K-1 1000 m: 1997, K-4 500 m: 1997, K-4 1000 m: 1999), five silvers (K-2Dick Joyce (rower) (511 words) [view diff] exact match in snippet view article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanDivergent series (5,028 words) [view diff] exact match in snippet view article find links to article
if we define the sequence pk by p n k = ( n + k − 1 k − 1 ) {\displaystyle p_{n}^{k}={n+k-1 \choose k-1}} then the Cesàro sum Ck is defined by Ck(s) =Trigonometric functions (10,611 words) [view diff] no match in snippet view article find links to article
square ( t ) = 4 π ∑ k = 1 ∞ sin ( ( 2 k − 1 ) t ) 2 k − 1 . {\displaystyle f_{\text{square}}(t)={\frac {4}{\pi }}\sum _{k=1}^{\infty }{\sin {\bigSI derived unit (387 words) [view diff] no match in snippet view article find links to article
conductivity m⋅kg⋅s−3⋅K−1 kelvin per watt K/W thermal resistance m−2⋅kg−1⋅s3⋅K reciprocal kelvin K−1 thermal expansion coefficient K−1 kelvin per metre K/mList of ICF Canoe Sprint World Championships medalists in paracanoe (365 words) [view diff] exact match in snippet view article find links to article
2010. Classed as K-1 A before 2015. First contested in 2010. Classed as K-1 TA before 2015. First contested in 2010. Classed as K-1 LTA before 2015. WasGroup velocity (3,504 words) [view diff] no match in snippet view article find links to article
x , t ) = cos ( k 1 x − ω 1 t ) + cos ( k 2 x − ω 2 t ) = 2 cos ( ( k 2 − k 1 ) x − ( ω 2 − ω 1 ) t 2 ) cos ( ( k 2 + k 1 ) x − ( ω 2 + ω 1 )Chain reaction (2,580 words) [view diff] no match in snippet view article find links to article
obtain k 1 [ CH 3 CHO ] − 2 k 4 [ CH 3 ] 2 = 0 {\displaystyle k_{1}{\ce {[CH3CHO]}}-2k_{4}{\ce {[CH3]}}^{2}=0} so that ( 4 ) . . . [ CH 3 ] = k 1 2 k 4Newton's method (8,748 words) [view diff] no match in snippet view article find links to article
x_{2}-3~\end{bmatrix}}_{k}\end{aligned}}} and X k + 1 = X k − C k + 1 {\displaystyle X_{k+1}~=~X_{k}-C_{k+1}} The iterations should be repeated until [Czech Republic at the Olympics (269 words) [view diff] exact match in snippet view article find links to article
Dostál Canoeing Men's K-1 1000 m Silver Jaroslav Kulhavý Cycling Men's cross-country Bronze Jiří Prskavec Canoeing Men's slalom K-1 Bronze Ondřej SynekHypocycloid (1,350 words) [view diff] exact match in snippet view article find links to article
( k − 1 ) cos θ + r cos ( ( k − 1 ) θ ) y ( θ ) = r ( k − 1 ) sin θ − r sin ( ( k − 1 ) θ ) {\displaystyle {\begin{aligned}&x(\theta )=r(k-1)\cosWrapped normal distribution (1,707 words) [view diff] no match in snippet view article find links to article
expansion for the logarithm: ln ( 1 + x ) = − ∑ k = 1 ∞ ( − 1 ) k k x k {\displaystyle \ln(1+x)=-\sum _{k=1}^{\infty }{\frac {(-1)^{k}}{k}}\,x^{k}} the logarithmicAlternating series test (1,825 words) [view diff] no match in snippet view article find links to article
S k − L | ≤ | S k − S k + 1 | = a k + 1 . {\displaystyle \left|S_{k}-L\right\vert \leq \left|S_{k}-S_{k+1}\right\vert =a_{k+1}.\!} Suppose we are givenBeta function (4,110 words) [view diff] no match in snippet view article find links to article
adjusting indices: ( n k ) = 1 ( n + 1 ) B ( n − k + 1 , k + 1 ) . {\displaystyle {\binom {n}{k}}={\frac {1}{(n+1)\,\mathrm {B} (n-k+1,k+1)}}.} Moreover, forBirth–death process (3,948 words) [view diff] exact match in snippet view article find links to article
= λ k − 1 p k − 1 ( t ) + μ k + 1 p k + 1 ( t ) − ( λ k + μ k ) p k ( t ) , k = 1 , 2 , … , {\displaystyle p_{k}^{\prime }(t)=\lambda _{k-1}p_{k-1}(t)+\muList of integrals of exponential functions (3,291 words) [view diff] exact match in snippet view article find links to article
_{k=1}^{n}{\left(-1\right)^{k-1}{\frac {d^{k-1}f\left(x\right)}{dx^{k-1}}}}+C} ∫ e − x ( f ( x ) − d n f ( x ) d x n ) d x = − e − x ∑ k = 1 n d k − 1 f1st Army (German Empire) (625 words) [view diff] no match in snippet view article
The 1st Army (German: 1. Armee / Armeeoberkommando 1 / A.O.K. 1) was an army level command of the German Army in World War I. It was formed on mobilizationHaralambie Ivanov (233 words) [view diff] exact match in snippet view article find links to article
with four golds (K-1 4 x 500 m: 1963, K-2 500 m: 1963, K-2 1000 m: 1963, K-4 1000 m: 1966), a silver (K-4 1000 m: 1963), and a bronze (K-1 4 x 500 m: 1966)Linear independence (4,286 words) [view diff] no match in snippet view article find links to article
{v} _{k},} if k > 1 , {\displaystyle k>1,} and v 1 = 0 {\displaystyle \mathbf {v} _{1}=\mathbf {0} } if k = 1. {\displaystyle k=1.} Thus, a set ofBasel problem (8,692 words) [view diff] no match in snippet view article find links to article
be defined by S n ( x ) x := ∏ k = 1 n ( 1 − x 2 k 2 ⋅ π 2 ) {\displaystyle {\frac {S_{n}(x)}{x}}:=\prod \limits _{k=1}^{n}\left(1-{\frac {x^{2}}{k^{2}\cdot1st Army (German Empire) (625 words) [view diff] no match in snippet view article
The 1st Army (German: 1. Armee / Armeeoberkommando 1 / A.O.K. 1) was an army level command of the German Army in World War I. It was formed on mobilizationGreg Barton (415 words) [view diff] exact match in snippet view article find links to article
Championships with four golds (K-1 1000 m: 1987, K-1 10000 m: 1985, 1987, 1991), a silver (K-1 10000 m: 1990), and a bronze (K-1 1000 m: 1991). He receivedBirgit Fischer (480 words) [view diff] exact match in snippet view article find links to article
Germany 1980 Moscow K-1 500 m 1988 Seoul K-2 500 m 1988 Seoul K-4 500 m 1988 Seoul K-1 500 m Representing Germany 1992 Barcelona K-1 500 m 1996 AtlantaBasel problem (8,692 words) [view diff] no match in snippet view article find links to article
be defined by S n ( x ) x := ∏ k = 1 n ( 1 − x 2 k 2 ⋅ π 2 ) {\displaystyle {\frac {S_{n}(x)}{x}}:=\prod \limits _{k=1}^{n}\left(1-{\frac {x^{2}}{k^{2}\cdotLatent Dirichlet allocation (7,614 words) [view diff] no match in snippet view article find links to article
we get: A = ∑ k = 1 K α β C k ¬ n + V β {\displaystyle A=\sum _{k=1}^{K}{\frac {\alpha \beta }{C_{k}^{\neg n}+V\beta }}} B = ∑ k = 1 K C k d β C k ¬Neighbor joining (2,881 words) [view diff] no match in snippet view article find links to article
) d ( a , b ) − ∑ k = 1 5 d ( a , k ) − ∑ k = 1 5 d ( b , k ) {\displaystyle Q_{1}(a,b)=(n-2)d(a,b)-\sum _{k=1}^{5}d(a,k)-\sum _{k=1}^{5}d(b,k)} = ( 52014 ICF Canoe Sprint World Championships (442 words) [view diff] exact match in snippet view article find links to article
Men's C–1 200 m Relay Results Men's K–1 200 m Results Men's K–1 500 m Results Men's K–1 1000 m Results Men's K–1 5000 m Results Men's K–2 200 m ResultsSaúl Craviotto (553 words) [view diff] exact match in snippet view article find links to article
the K-1 200 m event at the 2012 Summer Olympics in London, a gold medal (with Cristian Toro) in the K-2 200 m event and a bronze medal in the K-1 200List of airships of the United States Navy (553 words) [view diff] exact match in snippet view article find links to article
airship) (ZNN-G) (ZGT) H class blimp (observation) J class blimp (trainer) K-1 blimp (experimental) K class blimp (anti-submarine patrol) (ZNP-K) (ZSG-2Arnaud Hybois (177 words) [view diff] exact match in snippet view article find links to article
m in 2011), a silver (K-1 4 x 200 m, 2014) and two bronze (K-1 4 x 200 m: 2009, K-1 500 m 2013). Hybois also competed in the K-1 500 m event at the 2008Solenoid (mathematics) (1,488 words) [view diff] no match in snippet view article
θ = ∑ k = 1 ∞ r k e 2 π i ω k t {\displaystyle \zeta =2\pi t,\quad re^{i\theta }=\sum _{k=1}^{\infty }r_{k}e^{2\pi i\omega _{k}t}} where ω k = 1 n 1 ⋯Steven Ferguson (253 words) [view diff] exact match in snippet view article find links to article
finished eighth in the K-2 1000 m event, but was eliminated in the heats of the K-1 500 m event. He competed again in the K-2 1000 m at the 2008 Summer OlympicsCompressor (6,856 words) [view diff] exact match in snippet view article find links to article
− T 1 ) k − 1 = k R T 1 k − 1 [ ( P 2 P 1 ) ( k − 1 ) / k − 1 ] {\displaystyle W_{comp,in}={\frac {kR(T_{2}-T_{1})}{k-1}}={\frac {kRT_{1}}{k-1}}\left[\left({\fracKatrin Wagner-Augustin (325 words) [view diff] exact match in snippet view article find links to article
bronze (K-1 500 m: 2008). Wagner-Augustin also won 26 medals at the ICF Canoe Sprint World Championships with ten golds (K-1 1000 m: 2005, K-1 4 × 200Geometric process (858 words) [view diff] exact match in snippet view article find links to article
{\displaystyle F(a^{k-1}x)} for k = 1 , 2 , … {\displaystyle k=1,2,\dots } , where a {\displaystyle a} is a positive constant, then { X k , k = 1 , 2 , … } {\displaystyleBessel function (12,179 words) [view diff] no match in snippet view article find links to article
π ∑ k = 0 n − 1 ( n − k − 1 ) ! k ! ( z 2 4 ) k + 2 π J n ( z ) ln z 2 − ( z 2 ) n π ∑ k = 0 ∞ ( ψ ( k + 1 ) + ψ ( n + k + 1 ) ) ( − z 2 4 ) k k ! (Differential operator (3,693 words) [view diff] no match in snippet view article find links to article
Laplacian operator, defined by Δ = ∇ 2 = ∑ k = 1 n ∂ 2 ∂ x k 2 . {\displaystyle \Delta =\nabla ^{2}=\sum _{k=1}^{n}{\frac {\partial ^{2}}{\partial x_{k}^{2}}}Josef Dostál (canoeist) (328 words) [view diff] exact match in snippet view article
Summer Olympics in the K-4 1000 m event. He won the silver medal in the K-1 1000 metres event at the 2016 Summer Olympics in Rio de Janeiro. He was alsoDeterminant (13,785 words) [view diff] no match in snippet view article find links to article
c n − m = − 1 m ∑ k = 1 m c n − m + k tr ( A k ) ( 1 ≤ m ≤ n ) . {\displaystyle c_{n}=1;~~~c_{n-m}=-{\frac {1}{m}}\sum _{k=1}^{m}c_{n-m+k}\operatornameB-spline (5,717 words) [view diff] exact match in snippet view article find links to article
, k − 1 ( x ) + t i + k + 1 − x t i + k + 1 − t i + 1 B i + 1 , k − 1 ( x ) . {\displaystyle B_{i,k}(x):={\frac {x-t_{i}}{t_{i+k}-t_{i}}}B_{i,k-1}(x)+{\frac1997 ICF Canoe Sprint World Championships (97 words) [view diff] exact match in snippet view article find links to article
kayak events. Eight events were held for the women, all in kayak. Women's K-1 1000 m and K-2 1000 m events were added. This was the 28th championshipsFriedmann–Lemaître–Robertson–Walker metric (3,622 words) [view diff] no match in snippet view article find links to article
r ) = { k − 1 sin ( r k ) , k > 0 r , k = 0 | k | − 1 sinh ( r | k | ) , k < 0. {\displaystyle S_{k}(r)={\begin{cases}{\sqrt {k}}^{\,-1}\sin(r{\sqrtLennart Klingström (144 words) [view diff] exact match in snippet view article find links to article
Sprint World Championships with three golds (K-1 4×500 m: 1948, 1950; K-4 1000 m: 1948) and a silver (K-1 500 m: 1950). Lennart Klingström. Sports-referenceTechnology (10,447 words) [view diff] no match in snippet view article find links to article
Yael; Chazan, Michael; Arnold, M.; Aumaître, G.; Bourlès, D.; Keddadouche, K. (1 May 2021). "Magnetostratigraphy and cosmogenic dating of Wonderwerk Cave:Antonio Rossi (270 words) [view diff] exact match in snippet view article find links to article
in five Summer Olympics, he won five medals which included three golds (K-1 500 m: 1996, K-2 1000 m: 1996, 2000), one silver (K-2 1000 m: 2004), andHarmonic number (5,594 words) [view diff] no match in snippet view article find links to article
u d u = ∫ 0 1 [ ∑ k = 1 n ( n k ) ( − u ) k − 1 ] d u = ∑ k = 1 n ( n k ) ∫ 0 1 ( − u ) k − 1 d u = ∑ k = 1 n ( n k ) ( − 1 ) k − 1 k . {\displaystyleBig O notation (8,444 words) [view diff] no match in snippet view article find links to article
below (with constant factor k 1 {\displaystyle k_{1}} ) ∃ k 1 > 0 ∃ k 2 > 0 ∃ n 0 ∀ n > n 0 : {\displaystyle \exists k_{1}>0\,\exists k_{2}>0\,\existsDynamic programming (9,282 words) [view diff] no match in snippet view article find links to article
equation: J k ∗ ( x n − k ) = min u n − k { f ^ ( x n − k , u n − k ) + J k − 1 ∗ ( g ^ ( x n − k , u n − k ) ) } {\displaystyle J_{k}^{\ast }\left(\mathbfMaryna Litvinchuk (272 words) [view diff] exact match in snippet view article find links to article
K-1 5000 m 2014 Moscow K-1 5000 m 2018 Montemor-o-Velho K-1 5000 m 2019 Szeged K-4 500 m 2021 Copenhagen K-2 500 m 2011 Szeged K-1 5000 m 2011 Szeged K-4Hamiltonian mechanics (9,287 words) [view diff] no match in snippet view article find links to article
2 ∑ k = 1 N ( m k r ˙ k ( q , q ˙ ) ⋅ r ˙ k ( q , q ˙ ) ) {\displaystyle T({\boldsymbol {q}},{\boldsymbol {\dot {q}}})={\frac {1}{2}}\sum _{k=1}^{N}{\bigglSemiprime (866 words) [view diff] no match in snippet view article find links to article
than or equal to n. Then π 2 ( n ) = ∑ k = 1 π ( n ) [ π ( n p k ) − k + 1 ] {\displaystyle \pi _{2}(n)=\sum _{k=1}^{\pi \left({\sqrt {n}}\right)}\left[\piEast Germany at the 1976 Summer Olympics (932 words) [view diff] exact match in snippet view article find links to article
Helm Canoeing men's K-1 1000 m Gold Joachim Mattern Bernd Olbricht Canoeing men's K-2 500 m Gold Carola Zirzow Canoeing women's K-1 500 m Gold Klaus-JürgenSum-product number (973 words) [view diff] exact match in snippet view article find links to article
) k + 1 . {\displaystyle F_{b}(n)=k(b-1)^{k+1}.} This suggests that k ( b − 1 ) k + 1 ≥ n ≥ b k − 1 , {\displaystyle k(b-1)^{k+1}\geq n\geq b^{k-1},}Scale (map) (5,382 words) [view diff] no match in snippet view article
should be within 4 parts in 10,000, or 0.04%, corresponding to k = 1.0004 {\displaystyle k=1.0004} . Since sec φ {\displaystyle \sec \varphi } attainsAcid dissociation constant (11,513 words) [view diff] no match in snippet view article find links to article
A−, so [ H + ] 2 = K 1 K 2 {\displaystyle [{\ce {H+}}]^{2}=K_{1}K_{2}} Therefore, taking cologarithms, the pH is given by p I = p K 1 + p K 2 2 {\displaystyleBanach space (17,005 words) [view diff] no match in snippet view article find links to article
proved that if c − 2 ∑ k = 1 n ‖ x k ‖ 2 ≤ Ave ± ‖ ∑ k = 1 n ± x k ‖ 2 ≤ c 2 ∑ k = 1 n ‖ x k ‖ 2 {\displaystyle c^{-2}\sum _{k=1}^{n}\|x_{k}\|^{2}\leqCompound Poisson distribution (2,307 words) [view diff] no match in snippet view article find links to article
( ∑ k = 1 ∞ α k λ ( z k − 1 ) ) , ( | z | ≤ 1 ) {\displaystyle P_{Y}(z)=\sum \limits _{i=0}^{\infty }P(Y=i)z^{i}=\exp \left(\sum \limits _{k=1}^{\inftyList of mathematical constants (3,561 words) [view diff] no match in snippet view article find links to article
root of x k + 1 = 2 k + 1 ( x − 1 ) , β k = 2 − α k k + 1 − k α k {\displaystyle x^{k+1}=2^{k+1}(x-1),\beta _{k}={\frac {2-\alpha _{k}}{k+1-k\alpha _{k}}}}Joule per mole (467 words) [view diff] no match in snippet view article find links to article
particle, 0.239 kcal·mol−1, or 83.6 cm−1. At room temperature (25 °C, or 298.15 K) 1 kJ·mol−1 is approximately equal to 0.4034 k B T {\displaystyle k_{B}T}Reflexive space (6,409 words) [view diff] no match in snippet view article find links to article
{\displaystyle x_{\varnothing },} the root of the tree, followed, for k = 1 , … , n , {\displaystyle k=1,\ldots ,n,} by a family of s k {\displaystyle s^{k}} 2 vectorsSpectral radius (3,196 words) [view diff] no match in snippet view article find links to article
formula states that ρ ( A ) = lim k → ∞ ‖ A k ‖ 1 / k {\displaystyle \rho (A)=\lim _{k\to \infty }\|A^{k}\|^{1/k}} . Both of these results are shown belowHomothety (2,065 words) [view diff] no match in snippet view article find links to article
for k {\displaystyle k} : for k = 1 {\displaystyle k=1} one gets the identity mapping, for k = − 1 {\displaystyle k=-1} one gets the reflection at theN-sphere (7,312 words) [view diff] exact match in snippet view article find links to article
r 2 + ∑ k = 1 n − 1 r 2 ( ∏ m = 1 k − 1 sin 2 ( φ m ) ) d φ k 2 {\displaystyle ds^{2}=dr^{2}+\sum _{k=1}^{n-1}r^{2}\left(\prod _{m=1}^{k-1}\sin ^{2}\left(\varphiBall (mathematics) (1,840 words) [view diff] no match in snippet view article
r ) = π k k ! r 2 k , V 2 k + 1 ( r ) = 2 k + 1 π k ( 2 k + 1 ) ! ! r 2 k + 1 = 2 ( k ! ) ( 4 π ) k ( 2 k + 1 ) ! r 2 k + 1 . {\displaystyleLine integral (3,183 words) [view diff] no match in snippet view article find links to article
considering the expression ∑ k = 1 n f ( γ ( t k ) ) [ γ ( t k ) − γ ( t k − 1 ) ] = ∑ k = 1 n f ( γ k ) Δ γ k . {\displaystyle \sum _{k=1}^{n}f(\gamma (t_{k}))\Quadratic variation (1,539 words) [view diff] exact match in snippet view article find links to article
‖ P ‖ → 0 ∑ k = 1 n ( X t k − X t k − 1 ) 2 {\displaystyle [X]_{t}=\lim _{\Vert P\Vert \rightarrow 0}\sum _{k=1}^{n}(X_{t_{k}}-X_{t_{k-1}})^{2}} wherePerfect digit-to-digit invariant (1,095 words) [view diff] exact match in snippet view article find links to article
base b {\displaystyle b} as the k-digit number d k − 1 d k − 2 . . . d 1 d 0 {\displaystyle d_{k-1}d_{k-2}...d_{1}d_{0}} where each digit d i {\displaystyleInclusion–exclusion principle (6,851 words) [view diff] no match in snippet view article find links to article
k = 1 n ( − 1 ) k + 1 ( ∑ 1 ⩽ i 1 < ⋯ < i k ⩽ n | A i 1 ∩ ⋯ ∩ A i k | ) {\displaystyle \left|\bigcup _{i=1}^{n}A_{i}\right|=\sum _{k=1}^{n}(-1)^{k+1}\left(\sumBall (mathematics) (1,840 words) [view diff] no match in snippet view article
r ) = π k k ! r 2 k , V 2 k + 1 ( r ) = 2 k + 1 π k ( 2 k + 1 ) ! ! r 2 k + 1 = 2 ( k ! ) ( 4 π ) k ( 2 k + 1 ) ! r 2 k + 1 . {\displaystyleQuadratic variation (1,539 words) [view diff] exact match in snippet view article find links to article
‖ P ‖ → 0 ∑ k = 1 n ( X t k − X t k − 1 ) 2 {\displaystyle [X]_{t}=\lim _{\Vert P\Vert \rightarrow 0}\sum _{k=1}^{n}(X_{t_{k}}-X_{t_{k-1}})^{2}} whereNarayana number (1,088 words) [view diff] exact match in snippet view article find links to article
coefficients: N ( n , k ) = 1 n ( n k ) ( n k − 1 ) {\displaystyle \operatorname {N} (n,k)={\frac {1}{n}}{n \choose k}{n \choose k-1}} The first eight rowsSum-product number (973 words) [view diff] exact match in snippet view article find links to article
) k + 1 . {\displaystyle F_{b}(n)=k(b-1)^{k+1}.} This suggests that k ( b − 1 ) k + 1 ≥ n ≥ b k − 1 , {\displaystyle k(b-1)^{k+1}\geq n\geq b^{k-1},}EMER-K1 (724 words) [view diff] exact match in snippet view article find links to article
The EMER K-1, sometimes known as the EMER K1 or EMERK-1, was a prototype bullpup assault rifle made in Myanmar by the Electrical Mechanical and EngineeringEuclid's theorem (3,429 words) [view diff] no match in snippet view article find links to article
integers) is equivalent to the statement that we have ∏ p ∈ P k 1 1 − 1 p = ∑ n ∈ N k 1 n , {\displaystyle \prod _{p\in P_{k}}{\frac {1}{1-{\frac {1}{p}}}}=\sumHungary at the 1956 Summer Olympics (256 words) [view diff] exact match in snippet view article find links to article
Farkas József Hunics C-2 10000 m — 55:15.6 Lajos Kiss K-1 1000 m 4:35.8 2 Q 4:16.2 Ferenc Hatlaczky K-1 10000 m — 47:53.3 Imre Vágyóczky Zoltán Szigeti K-2Harmonic number (5,594 words) [view diff] no match in snippet view article find links to article
u d u = ∫ 0 1 [ ∑ k = 1 n ( n k ) ( − u ) k − 1 ] d u = ∑ k = 1 n ( n k ) ∫ 0 1 ( − u ) k − 1 d u = ∑ k = 1 n ( n k ) ( − 1 ) k − 1 k . {\displaystyleJoule per mole (467 words) [view diff] no match in snippet view article find links to article
particle, 0.239 kcal·mol−1, or 83.6 cm−1. At room temperature (25 °C, or 298.15 K) 1 kJ·mol−1 is approximately equal to 0.4034 k B T {\displaystyle k_{B}T}Interpolation attack (2,288 words) [view diff] no match in snippet view article find links to article
+ k 1 ) 3 = ( x 2 + k 1 2 ) ( x + k 1 ) = x 3 + k 1 2 x + x 2 k 1 + k 1 3 , {\displaystyle c_{1}=(x+k_{1})^{3}=(x^{2}+k_{1}^{2})(x+k_{1})=x^{3}+k_{1Saitama Super Arena (1,366 words) [view diff] exact match in snippet view article find links to article
2008 featured Dream and K-1 fights Dynamite!! 2009 featured fights by Dream, Sengoku and K-1 Dynamite!! 2010 featured Dream and K-1 fights. Fight For Japan:Quartile (2,225 words) [view diff] no match in snippet view article find links to article
{\displaystyle x_{k}} and x k + 1 {\displaystyle x_{k+1}} . q ( p / 4 ) = x k + α ( x k + 1 − x k ) {\displaystyle q(p/4)=x_{k}+\alpha (x_{k+1}-x_{k})} , where kErnesto Hoost (1,810 words) [view diff] exact match in snippet view article find links to article
kickboxer. A four-time K-1 World Champion, Hoost is considered to be one of the greatest kickboxers of all time. Debuting in 1993 at the K-1 World Grand PrixSpectral radius (3,196 words) [view diff] no match in snippet view article find links to article
formula states that ρ ( A ) = lim k → ∞ ‖ A k ‖ 1 / k {\displaystyle \rho (A)=\lim _{k\to \infty }\|A^{k}\|^{1/k}} . Both of these results are shown belowList of mathematical constants (3,561 words) [view diff] no match in snippet view article find links to article
root of x k + 1 = 2 k + 1 ( x − 1 ) , β k = 2 − α k k + 1 − k α k {\displaystyle x^{k+1}=2^{k+1}(x-1),\beta _{k}={\frac {2-\alpha _{k}}{k+1-k\alpha _{k}}}}Homothety (2,065 words) [view diff] no match in snippet view article find links to article
for k {\displaystyle k} : for k = 1 {\displaystyle k=1} one gets the identity mapping, for k = − 1 {\displaystyle k=-1} one gets the reflection at theHeat capacity (2,775 words) [view diff] no match in snippet view article find links to article
The SI unit for heat capacity of an object is joule per kelvin (J/K or J⋅K−1). Since an increment of temperature of one degree Celsius is the same asHouseholder transformation (3,241 words) [view diff] no match in snippet view article find links to article
− sgn ( a k + 1 , k k ) ∑ j = k + 1 n ( a j k k ) 2 r = 1 2 ( α 2 − a k + 1 , k k α ) v 1 k = v 2 k = ⋯ = v k k = 0 v k + 1 k = a k + 1 , k k − α 2Bates distribution (695 words) [view diff] no match in snippet view article find links to article
variables on the unit interval, Uk: X = 1 n ∑ k = 1 n U k . {\displaystyle X={\frac {1}{n}}\sum _{k=1}^{n}U_{k}.} The equation defining the probability1994 ICF Canoe Sprint World Championships (211 words) [view diff] exact match in snippet view article find links to article
and men's and women's K-1) resumed at the 2010 championships.) and the 200 m events for C-1, C-2, and C-4 (men only), and K-1, K-2, and K-4 (both menInverse trigonometric functions (10,605 words) [view diff] no match in snippet view article find links to article
2 ∑ n = 0 ∞ ∏ k = 1 n 2 k z 2 ( 2 k + 1 ) ( 1 + z 2 ) . {\displaystyle \arctan(z)={\frac {z}{1+z^{2}}}\sum _{n=0}^{\infty }\prod _{k=1}^{n}{\fracAbsolute magnitude (5,779 words) [view diff] no match in snippet view article find links to article
approximated as m 1 = M 1 + 2.5 ⋅ K 1 log 10 ( d B S d 0 ) + 5 log 10 ( d B O d 0 ) {\displaystyle m_{1}=M_{1}+2.5\cdot K_{1}\log _{10}{\left({\fracLazdijai District Municipality (142 words) [view diff] no match in snippet view article find links to article
K 1 0 1 Paulenka K 0 0 0 Paveisininkai K 7 3 4 Pertakas K 5 3 2 Purviniai K 3 2 1 Semoškai K 26 13 13 Simaniškė K 1 0 1 Sirguškė K 6 4 2 Stalai K 1 11995 ICF Canoe Sprint World Championships (102 words) [view diff] exact match in snippet view article find links to article
Gold Time Silver Time Bronze Time K-1 200 m Piotr Markiewicz (POL) Sergey Kalesnik (BLR) Renn Crichlow (CAN) K-1 500 m Piotr Markiewicz (POL) KnutDiscrete uniform distribution (772 words) [view diff] no match in snippet view article find links to article
k, the sample size, is N ^ = k + 1 k m − 1 = m + m k − 1 {\displaystyle {\hat {N}}={\frac {k+1}{k}}m-1=m+{\frac {m}{k}}-1} . This can be seen as a veryPerfect number (5,168 words) [view diff] exact match in snippet view article find links to article
is at most k − 1 2 . {\displaystyle {\frac {k-1}{2}}.} At least one of the prime powers dividing N exceeds 1062. N < 2 ( 4 k + 1 − 2 k + 1 ) {\displaystyleB+ tree (3,417 words) [view diff] no match in snippet view article find links to article
K + 1 ) / 2 ⌉ {\displaystyle \lceil (K+1)/2\rceil } items new node has ⌊ ( K + 1 ) / 2 ⌋ {\displaystyle \lfloor (K+1)/2\rfloor } items Copy ⌈ ( K + 1Outer product (2,942 words) [view diff] no match in snippet view article find links to article
{\displaystyle \mathbf {u} ,\mathbf {v} } with dimensions ( k 1 , k 2 , … , k m ) {\displaystyle (k_{1},k_{2},\dots ,k_{m})} and ( l 1 , l 2 , … , l n ) {\displaystyleInterspecific competition (3,334 words) [view diff] no match in snippet view article find links to article
respectively: d N 1 d t = r 1 N 1 K 1 − N 1 − α N 2 K 1 {\displaystyle {dN_{1} \over dt}=r_{1}N_{1}{K_{1}-N_{1}-\alpha N_{2} \over K_{1}}} d N 2 d t = r 2 N 2 KLorentz factor (1,692 words) [view diff] no match in snippet view article find links to article
has the Maclaurin series: γ = 1 1 − β 2 = ∑ n = 0 ∞ β 2 n ∏ k = 1 n ( 2 k − 1 2 k ) = 1 + 1 2 β 2 + 3 8 β 4 + 5 16 β 6 + 35 128 β 8 + 63 256 β 10 + ⋯Deficient number (560 words) [view diff] exact match in snippet view article find links to article
, p k − 1 {\displaystyle 1,p,p^{2},\dots ,p^{k-1}} which sum to p k − 1 p − 1 {\displaystyle {\frac {p^{k}-1}{p-1}}} , which is at most p k − 1 {\displaystyleMark and recapture (3,122 words) [view diff] no match in snippet view article find links to article
K + 1 ) k + 1 − 1 {\displaystyle {\hat {N}}_{C}={\frac {(n+1)(K+1)}{k+1}}-1} The example (n, K, k) = (10, 15, 5) gives N ^ C = ( n + 1 ) ( K + 1 ) k +Irwin–Hall distribution (1,358 words) [view diff] no match in snippet view article find links to article
identically distributed U(0, 1) random variables: X = ∑ k = 1 n U k . {\displaystyle X=\sum _{k=1}^{n}U_{k}.} The probability density function (pdf) forMotzkin number (846 words) [view diff] exact match in snippet view article find links to article
This gives ∑ k = 0 n C k = 1 + ∑ k = 1 n ( n k ) M k − 1 . {\displaystyle \sum _{k=0}^{n}C_{k}=1+\sum _{k=1}^{n}{\binom {n}{k}}M_{k-1}.} The generating functionSimon Dickie (722 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanHadamard matrix (3,698 words) [view diff] exact match in snippet view article find links to article
k − 1 H 2 k − 1 H 2 k − 1 − H 2 k − 1 ] = H 2 ⊗ H 2 k − 1 , {\displaystyle H_{2^{k}}={\begin{bmatrix}H_{2^{k-1}}&H_{2^{k-1}}\\H_{2^{k-1}}&-H_{2^{k-1SN1 reaction (1,970 words) [view diff] no match in snippet view article find links to article
= k 1 [ tBuBr ] − k − 1 [ tBu + ] [ Br − ] − k 2 [ tBu + ] [ H 2 O ] {\displaystyle {\frac {d[{\text{tBu}}^{+}]}{dt}}=0=k_{1}[{\text{tBuBr}}]-k_{-1Laurent series (2,675 words) [view diff] exact match in snippet view article find links to article
) n − k − 1 d z = ∮ γ ∑ n = − ∞ ∞ b n ( z − c ) n − k − 1 d z . {\displaystyle \oint _{\gamma }\,\sum _{n=-\infty }^{\infty }a_{n}(z-c)^{n-k-1}\,dz=\ointYoshihiro Akiyama (3,777 words) [view diff] exact match in snippet view article find links to article
for South Korea and for Japan at the 2002 Asian Games. He is the former K-1 HERO's Light Heavyweight Grand Prix Tournament Champion. Before his professionalColossally abundant number (1,635 words) [view diff] no match in snippet view article find links to article
that for all k > 1, σ ( n ) n 1 + ε ≥ σ ( k ) k 1 + ε {\displaystyle {\frac {\sigma (n)}{n^{1+\varepsilon }}}\geq {\frac {\sigma (k)}{k^{1+\varepsilonMatrix-exponential distribution (379 words) [view diff] no match in snippet view article find links to article
given by E ( X k ) = ( − 1 ) k + 1 k ! α T − ( k + 1 ) s . {\displaystyle \operatorname {E} (X^{k})=(-1)^{k+1}k!\mathbf {\alpha } T^{-(k+1)}\mathbf {s}Canoeing at the 1988 Summer Olympics (51 words) [view diff] exact match in snippet view article find links to article
Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m men women K-2 1000 m men K-4 500 m women K-42011 ICF Canoe Sprint World Championships (3,160 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200 metres (660 ft), 500Satisfaction equilibrium (3,856 words) [view diff] exact match in snippet view article find links to article
× A k − 1 × A k + 1 × … , × A K → 2 A k {\displaystyle f_{k}:{\mathcal {A}}_{1}\times \ldots \times {\mathcal {A}}_{k-1}\times {\mathcal {A}}_{k+1}\timesEMER-K1 (724 words) [view diff] exact match in snippet view article find links to article
The EMER K-1, sometimes known as the EMER K1 or EMERK-1, was a prototype bullpup assault rifle made in Myanmar by the Electrical Mechanical and EngineeringDanyon Loader (359 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanLaurent series (2,675 words) [view diff] exact match in snippet view article find links to article
) n − k − 1 d z = ∮ γ ∑ n = − ∞ ∞ b n ( z − c ) n − k − 1 d z . {\displaystyle \oint _{\gamma }\,\sum _{n=-\infty }^{\infty }a_{n}(z-c)^{n-k-1}\,dz=\ointHouseholder transformation (3,241 words) [view diff] no match in snippet view article find links to article
− sgn ( a k + 1 , k k ) ∑ j = k + 1 n ( a j k k ) 2 r = 1 2 ( α 2 − a k + 1 , k k α ) v 1 k = v 2 k = ⋯ = v k k = 0 v k + 1 k = a k + 1 , k k − α 2Second-order logic (4,387 words) [view diff] no match in snippet view article find links to article
{\displaystyle \phi } is a Π k 1 {\displaystyle \Pi _{k}^{1}} formula, and similar, Π k + 1 1 {\displaystyle \Pi _{k+1}^{1}} has the form ∀ R 0 … ∀ RNicole Reinhardt (276 words) [view diff] exact match in snippet view article find links to article
ICF Canoe Sprint World Championships with eight golds (K-1 500 m: 2005, 2011, K-2 200 m: 2007, K-1 4 × 200 m: 2009, 2010, 2011, K-2 500 m: 2007, K-4 200Numerical methods for ordinary differential equations (3,916 words) [view diff] no match in snippet view article find links to article
form α k y n + k + α k − 1 y n + k − 1 + ⋯ + α 0 y n = h [ β k f ( t n + k , y n + k ) + β k − 1 f ( t n + k − 1 , y n + k − 1 ) + ⋯ + β 0 f ( t n ,Decimal representation (1,815 words) [view diff] exact match in snippet view article find links to article
traditionally written with a single separator: r = b k b k − 1 ⋯ b 0 . a 1 a 2 ⋯ {\displaystyle r=b_{k}b_{k-1}\cdots b_{0}.a_{1}a_{2}\cdots } Here . is the decimalMultinomial theorem (2,059 words) [view diff] no match in snippet view article find links to article
power: ( x 1 + x 2 + ⋯ + x m ) n = ∑ k 1 + k 2 + ⋯ + k m = n k 1 , k 2 , ⋯ , k m ≥ 0 ( n k 1 , k 2 , … , k m ) x 1 k 1 ⋅ x 2 k 2 ⋯ x m k m {\displaystyleCaroline Evers-Swindell (555 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanHadamard matrix (3,698 words) [view diff] exact match in snippet view article find links to article
k − 1 H 2 k − 1 H 2 k − 1 − H 2 k − 1 ] = H 2 ⊗ H 2 k − 1 , {\displaystyle H_{2^{k}}={\begin{bmatrix}H_{2^{k-1}}&H_{2^{k-1}}\\H_{2^{k-1}}&-H_{2^{k-1Oreste Perri (200 words) [view diff] exact match in snippet view article find links to article
Championships with four golds (K-1 1000 m: 1975 (tied with Poland's Grzegorz Śledziewski, K-1 10000 m: 1974, 1975, 1977) and two bronzes (K-1 1000 m: 1974, 1977)Ernesto Hoost (1,810 words) [view diff] exact match in snippet view article find links to article
kickboxer. A four-time K-1 World Champion, Hoost is considered to be one of the greatest kickboxers of all time. Debuting in 1993 at the K-1 World Grand PrixDeficient number (560 words) [view diff] exact match in snippet view article find links to article
, p k − 1 {\displaystyle 1,p,p^{2},\dots ,p^{k-1}} which sum to p k − 1 p − 1 {\displaystyle {\frac {p^{k}-1}{p-1}}} , which is at most p k − 1 {\displaystyleTogo at the 2008 Summer Olympics (164 words) [view diff] exact match in snippet view article find links to article
in Beijing, China from August 8 to August 24, 2008. At the men's slalom K-1 event, Benjamin Boukpeti won a bronze medal in canoeing, the first OlympicPerfect power (1,027 words) [view diff] no match in snippet view article find links to article
formally, n is a perfect power if there exist natural numbers m > 1, and k > 1 such that mk = n. In this case, n may be called a perfect kth power. IfGeorgina Evers-Swindell (552 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanKatrin Borchert (641 words) [view diff] exact match in snippet view article find links to article
500 m for Germany) and two bronzes (both Australia, 1996: K-2 500 m, 2000: K-1 500 m). During her career, she has represented four countries: East GermanyDouble factorial (4,286 words) [view diff] exact match in snippet view article find links to article
while for odd n it is n ! ! = ∏ k = 1 n + 1 2 ( 2 k − 1 ) = n ( n − 2 ) ( n − 4 ) ⋯ 3 ⋅ 1 . {\displaystyle n!!=\prod _{k=1}^{\frac {n+1}{2}}(2k-1)=n(n-2)(n-4)\cdotsCubic Hermite spline (3,102 words) [view diff] exact match in snippet view article find links to article
m k = ( 1 − c ) p k + 1 − p k − 1 x k + 1 − x k − 1 {\displaystyle {\boldsymbol {m}}_{k}=(1-c){\frac {{\boldsymbol {p}}_{k+1}-{\boldsymbol {p}}_{k-1}}{x_{k+1}-x_{k-1}}}}Quasinorm (936 words) [view diff] no match in snippet view article find links to article
+ ‖ y ‖ ) {\displaystyle \|x+y\|\leq K(\|x\|+\|y\|)} for some K > 1. {\displaystyle K>1.} A quasi-seminorm on a vector space X {\displaystyle X} is aPhonon (6,944 words) [view diff] no match in snippet view article find links to article
momenta" Πk defined as the Fourier transforms of the pk: Q k = 1 N ∑ l e i k a l x l Π k = 1 N ∑ l e − i k a l p l . {\displaystyle {\begin{aligned}Q_{k}&={\fracVan der Waerden test (772 words) [view diff] exact match in snippet view article find links to article
1 > χ α , k − 1 2 {\displaystyle T_{1}>\chi _{\alpha ,k-1}^{2}} where Χα,k − 12 is the α-quantile of the chi-squared distribution with k − 1 degrees ofEinar Rasmussen (200 words) [view diff] exact match in snippet view article find links to article
golds (K-1 10000 m: 1981, 1983; K-2 1000 m: 1979, K-4 10000 m: 1975), three silvers (K-1 10000 m: 1979, 1982; K-2 1000 m: 1978), and three bronzes (K-1 1000Sorting algorithm (6,572 words) [view diff] no match in snippet view article find links to article
⋅ k 1 {\displaystyle n\cdot {\frac {k}{1}}} n ⋅ k 1 {\displaystyle n\cdot {\frac {k}{1}}} 2 1 {\displaystyle 2^{1}} No No d=1 for in-place, k / 1 {\displaystyleVandermonde matrix (5,263 words) [view diff] no match in snippet view article find links to article
v o l ( F ) = 1 k ! ∏ 1 ≤ m < n ≤ k + 1 ( t i n − t i m ) . {\displaystyle \mathrm {nvol} (F)={\frac {1}{k!}}\prod _{1\leq m<n\leq k+1}{(t_{i_{n}}-t_{i_{m}})}Proof that π is irrational (5,785 words) [view diff] no match in snippet view article find links to article
{\displaystyle x} : x 2 k ( k + 1 ) f k + 2 ( x ) = f k + 1 ( x ) − f k ( x ) . {\displaystyle {\frac {x^{2}}{k(k+1)}}f_{k+2}(x)=f_{k+1}(x)-f_{k}(x).} Proof:Bound state (2,314 words) [view diff] no match in snippet view article find links to article
a stable bound state of n particles with masses { m k } k = 1 n {\displaystyle \{m_{k}\}_{k=1}^{n}} corresponds to a pole in the S-matrix with a center-of-massSN1 reaction (1,970 words) [view diff] no match in snippet view article find links to article
= k 1 [ tBuBr ] − k − 1 [ tBu + ] [ Br − ] − k 2 [ tBu + ] [ H 2 O ] {\displaystyle {\frac {d[{\text{tBu}}^{+}]}{dt}}=0=k_{1}[{\text{tBuBr}}]-k_{-1Leibniz formula for π (1,518 words) [view diff] no match in snippet view article find links to article
states that π 4 = 1 − 1 3 + 1 5 − 1 7 + 1 9 − ⋯ = ∑ k = 0 ∞ ( − 1 ) k 2 k + 1 , {\displaystyle {\frac {\pi }{4}}=1-{\frac {1}{3}}+{\frac {1}{5}}-{\fracDistributed hash table (4,185 words) [view diff] no match in snippet view article find links to article
function δ ( k 1 , k 2 ) {\displaystyle \delta (k_{1},k_{2})} that defines an abstract notion of the distance between the keys k 1 {\displaystyle k_{1}} andMatrix-exponential distribution (379 words) [view diff] no match in snippet view article find links to article
given by E ( X k ) = ( − 1 ) k + 1 k ! α T − ( k + 1 ) s . {\displaystyle \operatorname {E} (X^{k})=(-1)^{k+1}k!\mathbf {\alpha } T^{-(k+1)}\mathbf {s}Absolute convergence (5,193 words) [view diff] no match in snippet view article find links to article
have 0 ≤ ∑ k = 1 n ( a k + | a k | ) ≤ ∑ k = 1 n 2 | a k | . {\displaystyle 0\leq \sum _{k=1}^{n}(a_{k}+\left|a_{k}\right|)\leq \sum _{k=1}^{n}2\left|a_{k}\right|Polar decomposition (4,254 words) [view diff] no match in snippet view article find links to article
= ‖ U k − 1 ‖ 1 ‖ U k − 1 ‖ ∞ ‖ U k ‖ 1 ‖ U k ‖ ∞ 4 {\displaystyle \gamma _{k}={\sqrt[{4}]{\frac {\left\|U_{k}^{-1}\right\|_{1}\left\|U_{k}^{-1}\right\|_{\inftyMean time between failures (2,994 words) [view diff] no match in snippet view article find links to article
mtbf ( c 1 ; … ; c n ) = ( ∑ k = 1 n 1 mtbf ( c k ) ) − 1 , {\displaystyle {\text{mtbf}}(c_{1};\dots ;c_{n})=\left(\sum _{k=1}^{n}{\fracTímea Paksy (200 words) [view diff] exact match in snippet view article find links to article
golds (K-1 200 m: 2006, K-2 200 m: 2003, K-2 1000 m: 2003, K-4 200 m: 2002, 2006; K-4 500 m: 2006, K-4 1000 m: 2005, 2006, 2007), six silvers (K-1 4 × 200Ljung–Box test (870 words) [view diff] no match in snippet view article find links to article
correlation. The test statistic is: Q = n ( n + 2 ) ∑ k = 1 h ρ ^ k 2 n − k {\displaystyle Q=n(n+2)\sum _{k=1}^{h}{\frac {{\hat {\rho }}_{k}^{2}}{n-k}}} whereHamilton–Jacobi equation (8,148 words) [view diff] exact match in snippet view article find links to article
… , q k − 1 , q k + 1 , … , q N ; p 1 , p 2 , … , p k − 1 , p k + 1 , … , p N ; ψ ; t ) . {\displaystyle H=H(q_{1},q_{2},\ldots ,q_{k-1},q_{k+1},\ldotsDirichlet process (4,861 words) [view diff] no match in snippet view article find links to article
k = 1 ∞ β k δ x k ( x ) {\displaystyle f(x)=\sum _{k=1}^{\infty }\beta _{k}\delta _{x_{k}}(x)} , where { x k } k = 1 ∞ {\displaystyle \{x_{k}\}_{k=1}^{\inftyGas laws (1,770 words) [view diff] no match in snippet view article find links to article
meaning "Pressure is inversely proportional to Volume", or P V = k 1 {\displaystyle PV=k_{1}} , or P 1 V 1 = P 2 V 2 {\displaystyle P_{1}V_{1}=P_{2}V_{2}}Grant Bramwell (231 words) [view diff] exact match in snippet view article find links to article
with Alan Thompson, Ian Ferguson and Paul MacDonald. Bramwell also won a K-1 10000 m bronze at the 1985 ICF Canoe Sprint World Championships in MechelenPolylogarithm (10,139 words) [view diff] no match in snippet view article find links to article
series in s: Li s ( z ) = ∑ k = 1 ∞ z k k s = z + z 2 2 s + z 3 3 s + ⋯ {\displaystyle \operatorname {Li} _{s}(z)=\sum _{k=1}^{\infty }{z^{k} \over k^{s}}=z+{z^{2}Eric Murray (rower) (1,275 words) [view diff] exact match in snippet view article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanApéry's constant (3,021 words) [view diff] no match in snippet view article find links to article
= 1 4 ∑ k = 1 ∞ ( − 1 ) k − 1 ( k − 1 ) ! 3 ( 56 k 2 − 32 k + 5 ) ( 2 k − 1 ) 2 ( 3 k ) ! . {\displaystyle \zeta (3)={\frac {1}{4}}\sum _{k=1}^{\inftyCantor set (6,941 words) [view diff] no match in snippet view article find links to article
k + 0 3 n , k + 1 3 n ] {\textstyle \left[{\frac {3k+0}{3^{n+1}}},{\frac {3k+3}{3^{n+1}}}\right]=\left[{\frac {k+0}{3^{n}}},{\frac {k+1}{3^{n}}}\right]}Dornier Do 217 (16,743 words) [view diff] exact match in snippet view article find links to article
(62 ft 4 in) for the K-1) to give better high-altitude performance when carrying the heavy Fritz-X bombs. 50 were converted from K-1 airframes. The wingAndré Wohllebe (240 words) [view diff] exact match in snippet view article find links to article
he won three medals with a gold (1992: K-4 1000 m) and two bronzes (1988: K-1 1000 m, K-4 1000 m). He was born in Berlin. Wohllebe also won eighteen medals