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Find link is a tool written by Edward Betts.searching for K-1 505 found (14413 total)
alternate case: k-1
Standard deviation
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k − 1 + k − 1 k ( x k − A k − 1 ) 2 = Q k − 1 + ( x k − A k − 1 ) ( x k − A k ) {\displaystyle {\begin{aligned}Q_{0}&=0\\Q_{k}&=Q_{k-1}+{\frac {k-1Fibonacci sequence (13,044 words) [view diff] no match in snippet view article find links to article
k = 1 ∞ q k 1 − q k , {\displaystyle \textstyle L(q):=\sum _{k=1}^{\infty }{\frac {q^{k}}{1-q^{k}}},} since 1 F 2 k = 5 ( ψ 2 k 1 − ψ 2 k − ψ 4 k 1 −Poisson distribution (11,203 words) [view diff] no match in snippet view article find links to article
distribution is Pr ( X 1 = k 1 , X 2 = k 2 ) = exp ( − λ 1 − λ 2 − λ 3 ) λ 1 k 1 k 1 ! λ 2 k 2 k 2 ! ∑ k = 0 min ( k 1 , k 2 ) ( k 1 k ) ( k 2 k ) k ! ( λP-adic number (7,711 words) [view diff] no match in snippet view article find links to article
i p i = a k p k + a k + 1 p k + 1 + a k + 2 p k + 2 + ⋯ {\displaystyle s=\sum _{i=k}^{\infty }a_{i}p^{i}=a_{k}p^{k}+a_{k+1}p^{k+1}+a_{k+2}p^{k+2}+\cdotsBinomial distribution (7,554 words) [view diff] no match in snippet view article find links to article
calculating f ( k + 1 , n , p ) f ( k , n , p ) = ( n − k ) p ( k + 1 ) ( 1 − p ) {\displaystyle {\frac {f(k+1,n,p)}{f(k,n,p)}}={\frac {(n-k)p}{(k+1)(1-p)}}}Kalman filter (20,932 words) [view diff] no match in snippet view article find links to article
k − 1 ] T Y k − 1 ∣ k − 1 F k − 1 C k = M k [ M k + Q k − 1 ] − 1 L k = I − C k Y k ∣ k − 1 = L k M k + C k Q k − 1 C k T y ^ k ∣ k − 1 = L k [ F k −Permutation (11,667 words) [view diff] exact match in snippet view article find links to article
λ k − 1 ( p k − 1 k ) λ k − 1 ( p k − 2 k ) λ k − 1 ⋯ λ k − 1 ( p 1 k ) λ k − 1 {\displaystyle \lambda _{k}=\lambda _{k-1}(p_{k-1}k)\lambda _{k-1}(p_{k-2}k)\lambdaBinomial coefficient (10,733 words) [view diff] exact match in snippet view article find links to article
× ⋯ × ( n − k + 1 ) k × ( k − 1 ) × ⋯ × 1 , {\displaystyle {\binom {n}{k}}={\frac {n\times (n-1)\times \cdots \times (n-k+1)}{k\times (k-1)\times \cdotsMichaelis–Menten kinetics (6,227 words) [view diff] no match in snippet view article find links to article
K_{\mathrm {m} }} is equal to k + 2 / k + 1 {\displaystyle k_{+2}/k_{+1}} or to k − 1 / k + 1 {\displaystyle k_{-1}/k_{+1}} or to something else. G. E. BriggsList of trigonometric identities (12,421 words) [view diff] exact match in snippet view article find links to article
identity can be proved: ∏ k = 1 n sin ( 2 k − 1 ) π 4 n = ∏ k = 1 n cos ( 2 k − 1 ) π 4 n = 2 2 n {\displaystyle \prod _{k=1}^{n}\sin {\frac {\left(2k-1\right)\piLogistic regression (20,641 words) [view diff] no match in snippet view article find links to article
case of a perfect prediction (i.e., when p k = 1 {\displaystyle p_{k}=1} and y k = 1 {\displaystyle y_{k}=1} , or p k = 0 {\displaystyle p_{k}=0} and yBinomial theorem (6,735 words) [view diff] exact match in snippet view article find links to article
( n − k + 1 ) k ( k − 1 ) ( k − 2 ) ⋯ 2 ⋅ 1 . {\displaystyle {\binom {n}{k}}={\frac {n!}{k!\,(n-k)!}}={\frac {n(n-1)(n-2)\cdots (n-k+1)}{k(k-1)(k-2)\cdotsBoltzmann constant (2,946 words) [view diff] no match in snippet view article find links to article
constants defining the International System of Units, the SI, with k = 1.380649×10−23 J K−1. The Boltzmann constant is a proportionality constant between theSpecific heat capacity (8,537 words) [view diff] no match in snippet view article find links to article
among common substances, about 4184 J⋅kg−1⋅K−1 at 20 °C; but that of ice, just below 0 °C, is only 2093 J⋅kg−1⋅K−1. The specific heat capacities of iron,NACA airfoil (2,605 words) [view diff] no match in snippet view article find links to article
0.3 - the value of r {\displaystyle r} , k 1 {\displaystyle k_{1}} and k 2 / k 1 {\displaystyle k_{2}/k_{1}} must be linearly scaled for a differentGas constant (1,997 words) [view diff] no match in snippet view article find links to article
{\displaystyle R=N_{\rm {A}}k} = 6.02214076×1023 mol−1 × 1.380649×10−23 J⋅K−1 = 8.31446261815324 J⋅K−1⋅mol−1 Since the 2019 revision of the SI, both NA and k are definedNatural logarithm (5,882 words) [view diff] exact match in snippet view article find links to article
( 1 + x ) = ∑ k = 1 ∞ ( − 1 ) k − 1 k x k = x − x 2 2 + x 3 3 − ⋯ , {\displaystyle \ln(1+x)=\sum _{k=1}^{\infty }{\frac {(-1)^{k-1}}{k}}x^{k}=x-{\fracMoment of inertia (17,301 words) [view diff] no match in snippet view article find links to article
∑ k = 1 N m k ( y k 2 + z k 2 ) − ∑ k = 1 N m k x k y k − ∑ k = 1 N m k x k z k − ∑ k = 1 N m k x k y k ∑ k = 1 N m k ( x k 2 + z k 2 ) − ∑ k = 1 N mMathematical induction (6,914 words) [view diff] no match in snippet view article find links to article
+k)+(k+1)={\frac {k(k+1)}{2}}+(k+1).} Algebraically, the right hand side simplifies as: k ( k + 1 ) 2 + ( k + 1 ) = k ( k + 1 ) + 2 ( k + 1 ) 2 = ( k + 1 )Finite element method (7,946 words) [view diff] no match in snippet view article find links to article
e., v k ( x ) = { x − x k − 1 x k − x k − 1 if x ∈ [ x k − 1 , x k ] , x k + 1 − x x k + 1 − x k if x ∈ [ x k , x k + 1 ] , 0 otherwise , {\displaystyleTaylor's theorem (9,632 words) [view diff] no match in snippet view article find links to article
| x − a | k + 1 ( k + 1 ) ! ≤ M r k + 1 ( k + 1 ) ! {\displaystyle |R_{k}(x)|\leq M{\frac {|x-a|^{k+1}}{(k+1)!}}\leq M{\frac {r^{k+1}}{(k+1)!}}} for allEnzyme kinetics (9,539 words) [view diff] no match in snippet view article find links to article
M S = ( k − 1 + k 2 ) / k 1 {\displaystyle K_{M}^{S}=(k_{-1}+k_{2})/k_{1}} and K M P = ( k − 1 + k 2 ) / k − 2 {\displaystyle K_{M}^{P}=(k_{-1}+k_{2})/k_{-2}}Taylor series (8,229 words) [view diff] no match in snippet view article find links to article
α n ) = ∏ k = 1 n α − k + 1 k = α ( α − 1 ) ⋯ ( α − n + 1 ) n ! . {\displaystyle {\binom {\alpha }{n}}=\prod _{k=1}^{n}{\frac {\alpha -k+1}{k}}={\fracGamma function (13,526 words) [view diff] no match in snippet view article find links to article
x 2 ) x − 1 ∏ k = 1 n k + 1 k + x {\displaystyle x!=\lim _{n\to \infty }\left(n+1+{\frac {x}{2}}\right)^{x-1}\prod _{k=1}^{n}{\frac {k+1}{k+x}}} whichWeibull distribution (5,823 words) [view diff] exact match in snippet view article find links to article
k − 1 e − ( x / λ ) k , x ≥ 0 , 0 , x < 0 , {\displaystyle f(x;\lambda ,k)={\begin{cases}{\frac {k}{\lambda }}\left({\frac {x}{\lambda }}\right)^{k-1}e^{-(x/\lambdaEuler's totient function (6,519 words) [view diff] exact match in snippet view article find links to article
and k ≥ 1, then φ ( p k ) = p k − p k − 1 = p k − 1 ( p − 1 ) = p k ( 1 − 1 p ) . {\displaystyle \varphi \left(p^{k}\right)=p^{k}-p^{k-1}=p^{k-1Geometric distribution (5,151 words) [view diff] exact match in snippet view article find links to article
trial is the first success is Pr ( X = k ) = ( 1 − p ) k − 1 p {\displaystyle \Pr(X=k)=(1-p)^{k-1}p} for k = 1 , 2 , 3 , 4 , … {\displaystyle k=1,2,3Triangular number (3,543 words) [view diff] no match in snippet view article find links to article
k = 1 n k = 1 + 2 + ⋯ + n = n 2 + n ( n + 1 ) 2 = n ( n + 1 ) 2 = ( n + 1 2 ) {\displaystyle \displaystyle {\begin{aligned}T_{n}&=\sum _{k=1}^{n}k=1+2+\dotsbEigenvalues and eigenvectors (13,582 words) [view diff] exact match in snippet view article find links to article
d t k + a k − 1 d k − 1 x d t k − 1 + ⋯ + a 1 d x d t + a 0 x = 0. {\displaystyle {\frac {d^{k}x}{dt^{k}}}+a_{k-1}{\frac {d^{k-1}x}{dt^{k-1}}}+\cdotsPascal's triangle (7,606 words) [view diff] no match in snippet view article find links to article
∑ k = 1 n + 1 a k − 1 x k + ∑ k = 0 n a k x k = ∑ k = 1 n a k − 1 x k + a n x n + 1 + a 0 x 0 + ∑ k = 1 n a k x k = a 0 x 0 + ∑ k = 1 n ( a k − 1 + aSummation (4,576 words) [view diff] no match in snippet view article find links to article
{\displaystyle p>1} ∑ k = 1 n k p = n p + 1 p + 1 + 1 2 n p + ∑ k = 2 p ( p k ) B k p − k + 1 n p − k + 1 , {\displaystyle \sum _{k=1}^{n}k^{p}={\fracAcid (5,957 words) [view diff] no match in snippet view article find links to article
[ H + ] 2 + [ H + ] K 1 + K 1 K 2 = [ H 2 A ] [ H 2 A ] + [ H A − ] + [ A 2 − ] α HA − = [ H + ] K 1 [ H + ] 2 + [ H + ] K 1 + K 1 K 2 = [ HA − ] [ H 2Negative binomial distribution (8,217 words) [view diff] no match in snippet view article find links to article
binomial": ( k + r − 1 ) ⋯ ( r ) k ! = ( − 1 ) k ( − r ) ( − r − 1 ) ( − r − 2 ) ⋯ ( − r − k + 1 ) ⏞ k factors k ! = ( − 1 ) k ( − r − k ) . {\displaystyleGini coefficient (10,898 words) [view diff] exact match in snippet view article find links to article
trapezoids and: G 1 = 1 − ∑ k = 1 n ( X k − X k − 1 ) ( Y k + Y k − 1 ) {\displaystyle G_{1}=1-\sum _{k=1}^{n}(X_{k}-X_{k-1})(Y_{k}+Y_{k-1})} is the resultingQuadrilateral (6,989 words) [view diff] no match in snippet view article find links to article
q: K = 1 2 ( m + n + p ) ( m + n − p ) ( m + n + q ) ( m + n − q ) , {\displaystyle K={\tfrac {1}{2}}{\sqrt {(m+n+p)(m+n-p)(m+n+q)(m+n-q)}},} K = 1 2 pBernoulli distribution (2,196 words) [view diff] no match in snippet view article find links to article
) = p k ( 1 − p ) 1 − k for k ∈ { 0 , 1 } {\displaystyle f(k;p)=p^{k}(1-p)^{1-k}\quad {\text{for }}k\in \{0,1\}} or as f ( k ; p ) = p k + ( 1 − p )Quantization (signal processing) (6,359 words) [view diff] no match in snippet view article
values of { b k } k = 1 M − 1 {\displaystyle \{b_{k}\}_{k=1}^{M-1}} , { c k } k = 1 M {\displaystyle \{c_{k}\}_{k=1}^{M}} and { y k } k = 1 M {\displaystyleFeynman diagram (15,967 words) [view diff] no match in snippet view article find links to article
k 1 ) ϕ ( k 2 ) ϕ ( k 3 ) ϕ ( k 4 ) ⟩ = δ ( k 1 − k 2 ) k 1 2 δ ( k 3 − k 4 ) k 3 2 + δ ( k 1 − k 3 ) k 3 2 δ ( k 2 − k 4 ) k 2 2 + δ ( k 1 − k 4 ) kCombination (3,806 words) [view diff] exact match in snippet view article find links to article
n k ) = n ( n − 1 ) ⋯ ( n − k + 1 ) k ( k − 1 ) ⋯ 1 , {\displaystyle {\binom {n}{k}}={\frac {n(n-1)\dotsb (n-k+1)}{k(k-1)\dotsb 1}},} which can be writtenSimplex (7,866 words) [view diff] case mismatch in snippet view article find links to article
k-dimensional polytope that is the convex hull of its k + 1 vertices. More formally, suppose the k + 1 points u 0 , … , u k {\displaystyle u_{0},\dots ,u_{k}}Runge–Kutta methods (7,392 words) [view diff] no match in snippet view article find links to article
_{i=1}^{s}b_{i}k_{i},} where k 1 = f ( t n , y n ) , k 2 = f ( t n + c 2 h , y n + ( a 21 k 1 ) h ) , k 3 = f ( t n + c 3 h , y n + ( a 31 k 1 + a 32 k 2 ) h )Euler's constant (9,582 words) [view diff] no match in snippet view article find links to article
n + ∑ k = 1 n 1 k ) = ∫ 1 ∞ ( − 1 x + 1 ⌊ x ⌋ ) d x . {\displaystyle {\begin{aligned}\gamma &=\lim _{n\to \infty }\left(-\log n+\sum _{k=1}^{n}{\fracRunge–Kutta methods (7,392 words) [view diff] no match in snippet view article find links to article
_{i=1}^{s}b_{i}k_{i},} where k 1 = f ( t n , y n ) , k 2 = f ( t n + c 2 h , y n + ( a 21 k 1 ) h ) , k 3 = f ( t n + c 3 h , y n + ( a 31 k 1 + a 32 k 2 ) h )Euler's constant (9,582 words) [view diff] no match in snippet view article find links to article
n + ∑ k = 1 n 1 k ) = ∫ 1 ∞ ( − 1 x + 1 ⌊ x ⌋ ) d x . {\displaystyle {\begin{aligned}\gamma &=\lim _{n\to \infty }\left(-\log n+\sum _{k=1}^{n}{\fracLagrangian mechanics (14,691 words) [view diff] no match in snippet view article find links to article
− V , {\displaystyle L=T-V,} where T = 1 2 ∑ k = 1 N m k v k 2 {\displaystyle T={\frac {1}{2}}\sum _{k=1}^{N}m_{k}v_{k}^{2}} is the total kinetic energyRiemann zeta function (10,428 words) [view diff] no match in snippet view article find links to article
k 1 > k 2 > ⋯ > k n > 0 k 1 − s 1 k 2 − s 2 ⋯ k n − s n . {\displaystyle \zeta (s_{1},s_{2},\ldots ,s_{n})=\sum _{k_{1}>k_{2}>\cdots >k_{n}>0}{k_{1Lisa Carrington (1,930 words) [view diff] no match in snippet view article find links to article
and one bronze medal. She won three consecutive gold medals in the Women's K‑1 200 metres at the 2012 Summer Olympics, 2016 Summer Olympics and 2020 SummerBernoulli number (13,028 words) [view diff] no match in snippet view article find links to article
0 n ( n k ) 2 n − k + 1 n − k + 1 B k ( 1 ) = 2 n {\displaystyle -1+\sum _{k=0}^{n}{\binom {n}{k}}{\frac {2^{n-k+1}}{n-k+1}}B_{k}(1)=2^{n}} and − 1 +Discrete cosine transform (11,983 words) [view diff] no match in snippet view article find links to article
around k = − 1 / 2 {\displaystyle k=-1/2} and even around k = N − 1 / 2. {\displaystyle k=N-1/2.} X k = ∑ n = 0 N − 1 x n cos [ π N ( n + 1 2 ) ( k + 1 2Transcendental number (6,764 words) [view diff] no match in snippet view article find links to article
sufficient to prove that k + 1 {\displaystyle k+1} does not divide P {\displaystyle P} . To that end, let k + 1 {\displaystyle k+1} be any prime larger thanCentral limit theorem (9,169 words) [view diff] exact match in snippet view article find links to article
∑ k = 1 n E [ ( M k − M k − 1 ) 2 ∣ M 1 , … , M k − 1 ] → 1 {\displaystyle {\frac {1}{n}}\sum _{k=1}^{n}\operatorname {E} \left[\left(M_{k}-M_{k-1}\right)^{2}\midSequence (6,158 words) [view diff] exact match in snippet view article find links to article
a_{k}=k^{2}} ( a 2 k − 1 ) k = 1 ∞ , a k = k 2 {\displaystyle {(a_{2k-1})}_{k=1}^{\infty },\qquad a_{k}=k^{2}} ( a k ) k = 1 ∞ , a k = ( 2 k − 1 ) 2 {\displaystyleInteger (3,935 words) [view diff] no match in snippet view article find links to article
= ⋯ = [ ( k , k ) ] 1 = [ ( 1 , 0 ) ] = [ ( 2 , 1 ) ] = ⋯ = [ ( k + 1 , k ) ] − 1 = [ ( 0 , 1 ) ] = [ ( 1 , 2 ) ] = ⋯ = [ ( k , k + 1 ) ] 2 = [ ( 2Rate equation (7,576 words) [view diff] no match in snippet view article find links to article
0 1 k 1 + k − 1 ( k − 1 + k 1 e − ( k 1 + k − 1 ) t ) + [ P ] 0 k − 1 k 1 + k − 1 ( 1 − e − ( k 1 + k − 1 ) t ) [ P ] = [ A ] 0 k 1 k 1 + k − 1 ( 1 −Chi-squared distribution (6,811 words) [view diff] no match in snippet view article find links to article
{\displaystyle k} with a width k 1 / 2 + α {\displaystyle k^{1/2+\alpha }} : P r ( ‖ Z ‖ 2 ∈ [ k − 2 k 1 / 2 + α , k + 2 k 1 / 2 + α + 2 k α ] ) ≥ 1 − eReal number (8,223 words) [view diff] exact match in snippet view article find links to article
infinite series x = b k 10 k + b k − 1 10 k − 1 + ⋯ + b 0 + a 1 10 + a 2 10 2 + ⋯ . {\displaystyle x=b_{k}10^{k}+b_{k-1}10^{k-1}+\cdots +b_{0}+{\frac {a_{1}}{10}}+{\fracAdam van Koeverden (1,539 words) [view diff] exact match in snippet view article find links to article
is an Olympic gold medallist in the K-1 500m category (2004) and a two-time world champion in K-1 500 (2007) and K-1 1000 (2011), winning four Olympic andReed–Solomon error correction (12,677 words) [view diff] no match in snippet view article find links to article
k + 1 … g 1 , n 0 1 0 … 0 g 2 , k + 1 … g 2 , n 0 0 1 … 0 g 3 , k + 1 … g 3 , n ⋮ ⋮ ⋮ ⋮ ⋮ ⋮ 0 … 0 … 1 g k , k + 1 … g k , n ] [ m 0 m 1 ⋮ m k − 1 ]List of Olympic medalists in canoeing (men) (16 words) [view diff] no match in snippet view article
This is the complete list of men's Olympic medalists in canoeing. International Olympic Committee results databaseMoving average (3,168 words) [view diff] no match in snippet view article find links to article
k = p n − k + 1 + p n − k + 2 + ⋯ + p n k = 1 k ∑ i = n − k + 1 n p i {\displaystyle {\begin{aligned}{\textit {SMA}}_{k}&={\frac {p_{n-k+1}+p_{n-k+2}+\cdotsLogarithm (11,635 words) [view diff] no match in snippet view article find links to article
1 + 1 2 + 1 3 + ⋯ + 1 n = ∑ k = 1 n 1 k , {\displaystyle 1+{\frac {1}{2}}+{\frac {1}{3}}+\cdots +{\frac {1}{n}}=\sum _{k=1}^{n}{\frac {1}{k}},} is calledDissociation constant (3,119 words) [view diff] no match in snippet view article find links to article
K 1 ′ = [ L ] [ M ] [ L M ] [ LM ] = [ L ] [ M ] K 1 ′ [ L ] + [ LM ] ↽ − − ⇀ [ L 2 M ] K 2 ′ = [ L ] [ LM ] [ L 2 M ] [ L 2 M ] = [ L ] 2 [ M ] K 1 ′Russian roulette (2,825 words) [view diff] no match in snippet view article find links to article
{\displaystyle k} is 1 n − k ⋅ ∏ i = 0 k − 1 n − i − 1 n − i = n − 1 n ⋅ n − 2 n − 1 ⋅ . . . ⋅ n − k n − k − 1 ⋅ 1 n − k = 1 6 ≈ 16.7 % {\displaystyle {\tfracBirthday problem (7,114 words) [view diff] no match in snippet view article find links to article
p ¯ ( n ) = ∏ k = 1 n − 1 ( 1 − k 365 ) < ∏ k = 1 n − 1 ( e − k 365 ) = e − n ( n − 1 ) 730 . {\displaystyle {\bar {p}}(n)=\prod _{k=1}^{n-1}\left(1-{\fracICF Canoe Sprint World Championships (734 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200 metres (660 ft), 500Lehmer mean (837 words) [view diff] no match in snippet view article find links to article
as: L p ( x ) = ∑ k = 1 n x k p ∑ k = 1 n x k p − 1 . {\displaystyle L_{p}(\mathbf {x} )={\frac {\sum _{k=1}^{n}x_{k}^{p}}{\sum _{k=1}^{n}x_{k}^{p-1}}}Standard molar entropy (788 words) [view diff] no match in snippet view article find links to article
= ∑ k = 1 N Δ S k = ∑ k = 1 N d Q k T → ∫ 0 T 2 d S d T d T = ∫ 0 T 2 C p k T d T {\displaystyle S^{\circ }=\sum _{k=1}^{N}\Delta S_{k}=\sum _{k=1}^{N}{\fracPartial autocorrelation function (1,129 words) [view diff] exact match in snippet view article find links to article
k − 1 + ⋯ + β k − 1 z t + 1 and z ^ t = β 1 z t + 1 + ⋯ + β k − 1 z t + k − 1 . {\displaystyle {\hat {z}}_{t+k}=\beta _{1}z_{t+k-1}+\cdots +\beta _{k-1}z_{t+1}\qquadTrapezoidal rule (3,483 words) [view diff] exact match in snippet view article find links to article
(that is, Δ x k = x k − x k − 1 {\displaystyle \Delta x_{k}=x_{k}-x_{k-1}} ), then ∫ a b f ( x ) d x ≈ ∑ k = 1 N f ( x k − 1 ) + f ( x k ) 2 Δ x k . {\displaystyleExterior algebra (12,098 words) [view diff] exact match in snippet view article find links to article
k − 1 {\displaystyle k-1} elements of V ∗ {\displaystyle V^{*}} , then define ( ι α w ) ( u 1 , u 2 , … , u k − 1 ) = w ( α , u 1 , u 2 , … , u k −Chaos theory (13,440 words) [view diff] no match in snippet view article find links to article
non-linear differential equations of the second order, I: The equation y" + k(1−y2)y' + y = bλkcos(λt + a), k large". Journal of the London MathematicalErlang distribution (1,969 words) [view diff] no match in snippet view article find links to article
of time until the occurrence of a fixed number of events. When k = 1 {\displaystyle k=1} , the distribution simplifies to the exponential distributionPhase-shift keying (6,226 words) [view diff] exact match in snippet view article find links to article
number: r k r k − 1 ∗ = E s e j ( φ k − φ k − 1 ) + E s e j φ k n k − 1 ∗ + E s e − j φ k − 1 n k + n k n k − 1 ∗ {\displaystyle r_{k}r_{k-1}^{*}=E_{s}e^{j\left(\varphiFloor and ceiling functions (5,879 words) [view diff] no match in snippet view article find links to article
integer k is ⌊ log b k ⌋ + 1 = ⌈ log b ( k + 1 ) ⌉ . {\displaystyle \lfloor \log _{b}{k}\rfloor +1=\lceil \log _{b}{(k+1)}\rceil .} The number ofExterior derivative (3,307 words) [view diff] no match in snippet view article find links to article
can be thought of as measuring the net flux through the boundary of a (k + 1)-parallelotope at each point. The exterior derivative of a differentialVariance (10,207 words) [view diff] no match in snippet view article find links to article
∑ k = 1 n Y k ] = 1 n ∑ i = 1 n ( E [ Y i 2 ] − 2 n ( ∑ j ≠ i E [ Y i Y j ] + E [ Y i 2 ] ) + 1 n 2 ∑ j = 1 n ∑ k ≠ j n E [ Y j Y k ] + 1 n 2Entropy (14,024 words) [view diff] no match in snippet view article find links to article
temperature, which has a unit of joules per kelvin (J⋅K−1) in the International System of Units (or kg⋅m2⋅s−2⋅K−1 in terms of base units). The entropy of a substanceOrder statistic (4,933 words) [view diff] exact match in snippet view article find links to article
U ( k ) ( u ) = n ! ( k − 1 ) ! ( n − k ) ! u k − 1 ( 1 − u ) n − k {\displaystyle f_{U_{(k)}}(u)={n! \over (k-1)!(n-k)!}u^{k-1}(1-u)^{n-k}} that is,Sobolev space (6,658 words) [view diff] exact match in snippet view article find links to article
it is enough to assume that the ( k − 1 ) {\displaystyle (k{-}1)} -th derivative f ( k − 1 ) {\displaystyle f^{(k-1)}} is differentiable almost everywhereSmoothness (3,923 words) [view diff] exact match in snippet view article find links to article
at least in the class C k − 1 {\displaystyle C^{k-1}} since f ′ , f ″ , … , f ( k − 1 ) {\displaystyle f',f'',\dots ,f^{(k-1)}} are continuous on U .Exponential family (11,203 words) [view diff] exact match in snippet view article find links to article
{\displaystyle \sum _{i=1}^{k}p_{i}=1\,.} Thus, there are only k − 1 {\displaystyle k-1} independent parameters. Variant 1 uses k {\displaystyle k} naturalThermal conductivity and resistivity (8,365 words) [view diff] no match in snippet view article find links to article
{\displaystyle \lambda } , or κ {\displaystyle \kappa } and is measured in W·m−1·K−1. Heat transfer occurs at a lower rate in materials of low thermal conductivityProportional–integral–derivative controller (12,059 words) [view diff] no match in snippet view article find links to article
u ( t k ) − u ( t k − 1 ) Δ t = K p e ( t k ) − e ( t k − 1 ) Δ t + K i e ( t k ) + K d e ( t k ) − e ( t k − 1 ) Δ t − e ( t k − 1 ) − e ( t k − 2 )Recurrence relation (4,166 words) [view diff] exact match in snippet view article find links to article
uni-dimensional recurrence: ( n k ) = ( n k − 1 ) ( n − k + 1 ) / k , {\displaystyle {\binom {n}{k}}={\binom {n}{k-1}}(n-k+1)/k,} with the initial value ( n 0Generating function (14,464 words) [view diff] no match in snippet view article find links to article
, 1 k 1 , 1 0 0 ⋯ k 0 , 2 k 1 , 2 k 2 , 2 0 ⋯ k 0 , 3 k 1 , 3 k 2 , 3 k 3 , 3 ⋯ ⋮ ⋮ ⋮ ⋮ ] = [ k 0 , 0 0 0 0 ⋯ k 0 , 1 k 1 , 1 0 0 ⋯ k 0 , 2 k 1 , 2 kInvertible matrix (6,996 words) [view diff] exact match in snippet view article find links to article
A k − 1 A k ) − 1 = A k − 1 A k − 1 − 1 ⋯ A 2 − 1 A 1 − 1 . {\displaystyle (\mathbf {A} _{1}\mathbf {A} _{2}\cdots \mathbf {A} _{k-1}\mathbf {A} _{k})^{-1}=\mathbfCompetitive inhibition (2,864 words) [view diff] no match in snippet view article find links to article
rearranging to k 1 [ E ] [ S ] = ( k − 1 + k 2 ) [ ES ] {\displaystyle k_{1}[{\ce {E}}][{\ce {S}}]=(k_{-1}+k_{2})[{\ce {ES}}]} Dividing by k 1 [ S ] {\displaystyleFinite difference (5,863 words) [view diff] exact match in snippet view article find links to article
k − 1 ∑ i 2 = 0 k − 1 ⋯ ∑ i n = 0 k − 1 Δ h n ( f , x + i 1 h + i 2 h + ⋯ + i n h ) . {\displaystyle \Delta _{kh}^{n}(f,x)=\sum \limits _{i_{1}=0}^{k-1}\sumConvergent series (1,966 words) [view diff] no match in snippet view article find links to article
that is denoted S = a 1 + a 2 + a 3 + ⋯ = ∑ k = 1 ∞ a k . {\displaystyle S=a_{1}+a_{2}+a_{3}+\cdots =\sum _{k=1}^{\infty }a_{k}.} The nth partial sum SnStirling numbers of the second kind (4,313 words) [view diff] exact match in snippet view article find links to article
n k − 1 } {\displaystyle \left\{{n \atop k-1}\right\}} since we must partition the remaining n objects into the available k − 1 {\displaystyle k-1} Finite difference (5,863 words) [view diff] exact match in snippet view article find links to article
k − 1 ∑ i 2 = 0 k − 1 ⋯ ∑ i n = 0 k − 1 Δ h n ( f , x + i 1 h + i 2 h + ⋯ + i n h ) . {\displaystyle \Delta _{kh}^{n}(f,x)=\sum \limits _{i_{1}=0}^{k-1}\sumSmoothness (3,923 words) [view diff] exact match in snippet view article find links to article
at least in the class C k − 1 {\displaystyle C^{k-1}} since f ′ , f ″ , … , f ( k − 1 ) {\displaystyle f',f'',\dots ,f^{(k-1)}} are continuous on U .Gram–Schmidt process (4,423 words) [view diff] no match in snippet view article find links to article
( k − 1 ) = u k ( k − 2 ) − proj u k − 1 ( u k ( k − 2 ) ) , e k = u k ( k − 1 ) ‖ u k ( k − 1 ) ‖ {\displaystyle {\begin{aligned}\mathbf {u} _{k}^{(1)}&=\mathbfMoment (mathematics) (3,066 words) [view diff] no match in snippet view article
X 1 k 1 ⋯ X n k n ] {\displaystyle E[{X_{1}}^{k_{1}}\cdots {X_{n}}^{k_{n}}]} is called a mixed moment of order k {\displaystyle k} (where k = k 1 + .Min-max theorem (4,542 words) [view diff] exact match in snippet view article find links to article
to pick a ( i k − 1 − ( i 1 − 1 ) ) {\textstyle (i_{k-1}-(i_{1}-1))} -dimensional subspace W k − 1 ′ ⊂ W k ∩ V i k − 1 {\textstyle W_{k-1}'\subset W_{k}\capList of Olympic medalists in canoeing (women) (16 words) [view diff] no match in snippet view article
This is the complete list of women's Olympic medalists in kayaking. International Olympic Committee results databaseCanoeing at the 2016 Summer Olympics (685 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 200 m men C-1 1000 m men C-2 1000 m men K-1 200 m men women K-1 500 m women K-1 1000 m men K-2 200 m menExtrapolation (1,869 words) [view diff] exact match in snippet view article find links to article
= y k − 1 + x ∗ − x k − 1 x k − x k − 1 ( y k − y k − 1 ) . {\displaystyle y(x_{*})=y_{k-1}+{\frac {x_{*}-x_{k-1}}{x_{k}-x_{k-1}}}(y_{k}-y_{k-1}).} (whichProbability density function (4,940 words) [view diff] no match in snippet view article find links to article
for y is ∑ k = 1 n ( y ) | d d y g k − 1 ( y ) | ⋅ f X ( g k − 1 ( y ) ) , {\displaystyle \sum _{k=1}^{n(y)}\left|{\frac {d}{dy}}g_{k}^{-1}(y)\right|\cdotError function (7,304 words) [view diff] exact match in snippet view article find links to article
) k − 1 π H k − 1 ( z ) e − z 2 = 2 π d k − 1 d z k − 1 ( e − z 2 ) , k = 1 , 2 , … {\displaystyle \operatorname {erf} ^{(k)}z={\frac {2(-1)^{k-1}}{\sqrtKosambi–Karhunen–Loève theorem (10,711 words) [view diff] no match in snippet view article find links to article
∑ k = 1 N p k ≥ ∑ k = 1 N q k {\displaystyle \sum _{k=1}^{N}p_{k}\geq \sum _{k=1}^{N}q_{k}} This implies that: − ∑ k = 1 ∞ p k log ( p k ) ≤ − ∑ k =Canoeing at the 2020 Summer Olympics (435 words) [view diff] exact match in snippet view article find links to article
C-1 men women K-1 men women Sprint C-1 200 m women C-1 1000 m men C-2 500 m women C-2 1000 m men K-1 200 m men women K-1 500 m women K-1 1000 m men K-2Arithmetic progression (2,297 words) [view diff] no match in snippet view article find links to article
n , k ) = 1 2 ( k − 1 ) ( n 2 − ( k − 1 ) n + ( k − 2 ) + ϕ ( n + 1 , k − 1 ) ) = 1 2 ( k − 1 ) ( ( n − 1 ) ( n − ( k − 2 ) ) + ϕ ( n + 1 , k − 1 ) )Kronecker delta (3,740 words) [view diff] exact match in snippet view article find links to article
_{p-1}}-\sum _{k=1}^{p-1}\delta _{\nu _{k}}^{\mu _{p}}\delta _{\nu _{1}\dots \nu _{k-1}\,\nu _{p}\,\nu _{k+1}\dots \nu _{p-1}}^{\mu _{1}\dots \mu _{k-1}\,\mu _{k}\Softmax function (5,286 words) [view diff] no match in snippet view article find links to article
{\displaystyle \sigma \colon \mathbb {R} ^{K}\to (0,1)^{K}} , where K > 1 {\displaystyle K>1} , takes a vector z = ( z 1 , … , z K ) ∈ R K {\displaystyle \mathbfPrincipal component analysis (14,450 words) [view diff] no match in snippet view article find links to article
of the normalization constraints: α k ′ α k = 1 , k = 1 , … , p {\displaystyle \alpha _{k}'\alpha _{k}=1,k=1,\dots ,p} . As noted above, the results ofHypergeometric distribution (4,115 words) [view diff] no match in snippet view article find links to article
hypergeometric distribution: Pr ( X 1 = k 1 , … , X c = k c ) = ∏ i = 1 c ( K i k i ) ( N n ) {\displaystyle \Pr(X_{1}=k_{1},\ldots ,X_{c}=k_{c})={\frac {\prod1000 (number) (24,094 words) [view diff] no match in snippet view article
k = 1 46 σ ( k ) {\displaystyle \sum _{k=1}^{46}\sigma (k)} 1759 = de Polignac prime 1760 = the number of yards in a mile 1761 = k such that k, k+1 andMax Hoff (canoeist) (198 words) [view diff] exact match in snippet view article
Championships with five golds (K-1 1000 m: 2009, 2010, 2013; K-1 5000 m: 2011 and K-4 1000 m: 2011 ) and three silvers (K-1 5000 m: 2010, 2014, 2015). AtQuaternion (12,634 words) [view diff] no match in snippet view article find links to article
quaternions, i 2 = j 2 = k 2 = i j k = − 1 {\displaystyle \mathbf {i} ^{2}=\mathbf {j} ^{2}=\mathbf {k} ^{2}=\mathbf {i\,j\,k} =-1} into the stone of BroughamLagrange polynomial (3,973 words) [view diff] no match in snippet view article find links to article
F^{(k+1)}(\xi )} : F ( k + 1 ) ( ξ ) = f ( k + 1 ) ( ξ ) − L ( k + 1 ) ( ξ ) − R ~ ( k + 1 ) ( ξ ) {\displaystyle F^{(k+1)}(\xi )=f^{(k+1)}(\xi )-L^{(k+1)}(\xiCanoeing at the Summer Olympics (333 words) [view diff] exact match in snippet view article find links to article
200 m events with one of them being K-1 200 m for the women. The other events for men at 200 m will be C-1, K-1, and K-2. This was confirmed at theirIdeal gas law (4,622 words) [view diff] no match in snippet view article find links to article
−273.15 °C, the lowest possible temperature). R has for value 8.314 J/(mol·K) = 1.989 ≈ 2 cal/(mol·K), or 0.0821 L⋅atm/(mol⋅K). How much gas is present couldEuler–Maclaurin formula (3,779 words) [view diff] exact match in snippet view article find links to article
∑ k = 1 p B k k ! ( f ( k − 1 ) ( n ) − f ( k − 1 ) ( m ) ) + R p , {\displaystyle S-I=\sum _{k=1}^{p}{{\frac {B_{k}}{k!}}\left(f^{(k-1)}(n)-f^{(k-1)}(m)\right)}+R_{p}Handley Page Victor (9,400 words) [view diff] no match in snippet view article find links to article
tanker (renamed K.1 after bombing capability removed), 11 converted. Victor BK.1A 3-point in-flight refuelling tanker (renamed K.1A as for K.1), 14 convertedElliptic integral (7,832 words) [view diff] no match in snippet view article find links to article
}})={\tfrac {1}{2}}\pi } For example: 4 3 K ( 1 3 ) E ( 1 2 ) + 3 2 E ( 1 3 ) K ( 1 2 ) − 2 K ( 1 3 ) K ( 1 2 ) = 1 2 π {\displaystyle {\tfrac {4}{3}}K({\colorRatio test (5,987 words) [view diff] no match in snippet view article find links to article
a subsequence ( a n k ) k = 1 ∞ {\displaystyle \left(a_{n_{k}}\right)_{k=1}^{\infty }} satisfying lim sup n → ∞ | a n k + 1 a n k | ≤ ℓ < r {\displaystyleOzone (18,196 words) [view diff] no match in snippet view article find links to article
intermediate can be determined as follows: K 1 = K 1 K − 1 = [ O 2 ] ⋅ [ O ] [ O 3 ] {\displaystyle K_{1}={\frac {K_{1}}{K_{-1}}}={\frac {[{\ce {O2}}]\cdot [{\ceHölder's inequality (7,917 words) [view diff] no match in snippet view article find links to article
functions for k = 1 , . . . , m {\displaystyle k=1,...,m} . Then ‖ ∏ k = 1 m f k ‖ 1 ≥ ∏ k = 1 m ‖ f k ‖ p k . {\displaystyle \left\|\prod _{k=1}^{m}f_{k}\right\|_{1}\geqLogistic function (8,029 words) [view diff] no match in snippet view article find links to article
standard logistic function, depicted at right, where L = 1 , k = 1 , x 0 = 0 {\displaystyle L=1,k=1,x_{0}=0} , has the equation f ( x ) = 1 1 + e − x {\displaystyleList of ICF Canoe Sprint World Championships medalists in men's kayak (269 words) [view diff] no match in snippet view article find links to article
This is a list of medalists from the ICF Canoe Sprint World Championships in men's kayak. Debuted: 1994. Debuted: 1948. Debuted: 1938. Not held: 1948.Canoeing at the 2012 Summer Olympics (574 words) [view diff] exact match in snippet view article find links to article
by a 200m race; in addition, the men's C-2 500m was replaced by a women's K-1 200m sprint. This was confirmed at an International Canoe Federation boardHarmonic series (mathematics) (6,219 words) [view diff] no match in snippet view article
{1}{k(k+1)}}=\sum _{k=1}^{\infty }\sum _{n=1}^{k}{\frac {1}{k(k+1)}}} = ∑ k = 1 ∞ k k ( k + 1 ) = ∑ k = 1 ∞ 1 k + 1 = S − 1 {\displaystyle =\sum _{k=1}^{\inftyApproximations of π (12,280 words) [view diff] no match in snippet view article find links to article
{2}}} and y k + 1 = ( 1 − f ( y k ) ) / ( 1 + f ( y k ) ) , a k + 1 = a k ( 1 + y k + 1 ) 4 − 2 2 k + 3 y k + 1 ( 1 + y k + 1 + y k + 1 2 ) {\displaystyleConjugate gradient method (7,493 words) [view diff] no match in snippet view article find links to article
_{k}} is rewritten as r k + 1 T A p k = 1 α k r k + 1 T ( r k − r k + 1 ) = − 1 α k r k + 1 T r k + 1 {\displaystyle \mathbf {r} _{k+1}^{\mathsf {T}}\mathbfDiscrete Fourier transform (12,311 words) [view diff] no match in snippet view article find links to article
case above: X k 1 , k 2 , … , k d = X N 1 − k 1 , N 2 − k 2 , … , N d − k d ∗ , {\displaystyle X_{k_{1},k_{2},\dots ,k_{d}}=X_{N_{1}-k_{1},N_{2}-k_{2}Paul MacDonald (canoeist) (352 words) [view diff] exact match in snippet view article
1988; K-4 1000 m: 1984), one silver (K-2 1000 m: 1988), and one bronze (K-1 500 m: 1988). His five Olympic medals is the record for the second most OlympicDifferential form (10,058 words) [view diff] case mismatch in snippet view article find links to article
differential forms that, given a k-form φ {\displaystyle \varphi } , produces a (k+1)-form d φ . {\displaystyle d\varphi .} This operation extends the differentialICF Canoe Marathon World Championships (371 words) [view diff] no match in snippet view article find links to article
ICF Canoe Marathon World Championships is an International Canoe Federation competition in canoe marathon in which athletes compete over long distancesNewton's method in optimization (1,857 words) [view diff] no match in snippet view article find links to article
obtains the iterative scheme x k + 1 = x k − [ f ″ ( x k ) ] − 1 f ′ ( x k ) , k ≥ 0. {\displaystyle x_{k+1}=x_{k}-[f''(x_{k})]^{-1}f'(x_{k}),\qquad k\geq 0Maximum likelihood estimation (9,703 words) [view diff] no match in snippet view article find links to article
functions: f n ( y ; θ ) = ∏ k = 1 n f k u n i v a r ( y k ; θ ) . {\displaystyle f_{n}(\mathbf {y} ;\theta )=\prod _{k=1}^{n}\,f_{k}^{\mathsf {univar}}(y_{k};\thetaMolar heat capacity (5,707 words) [view diff] no match in snippet view article find links to article
mass. The SI unit of molar heat capacity is joule per kelvin per mole, J⋅K−1⋅mol−1. Like the specific heat, the measured molar heat capacity of a substanceTetrahedral number (1,343 words) [view diff] no match in snippet view article find links to article
n = ∑ k = 1 n T k = ∑ k = 1 n k ( k + 1 ) 2 = ∑ k = 1 n ( ∑ i = 1 k i ) {\displaystyle Te_{n}=\sum _{k=1}^{n}T_{k}=\sum _{k=1}^{n}{\frac {k(k+1)}{2}}=\sumEuler numbers (2,049 words) [view diff] no match in snippet view article find links to article
}{q}}(2q-\ell )^{2n},} E 2 n = ∑ k = 1 2 n ( − 1 ) k 1 2 k ∑ ℓ = 0 2 k ( − 1 ) ℓ ( 2 k ℓ ) ( k − ℓ ) 2 n . {\displaystyle E_{2n}=\sum _{k=1}^{2n}(-1)^{k}{\frac {1}{2^{k}}}\sumBinomial series (1,904 words) [view diff] no match in snippet view article find links to article
) ( α − 2 ) ⋯ ( α − k + 1 ) k ! . {\displaystyle {\binom {\alpha }{k}}:={\frac {\alpha (\alpha -1)(\alpha -2)\cdots (\alpha -k+1)}{k!}}.} Note that ifGert Fredriksson (427 words) [view diff] exact match in snippet view article find links to article
(1948: K-1 1000 m, K-1 10000 m; 1952: K-1 1000 m, 1956: K-1 1000 m, K-1 10000 m; 1960: K-2 1000 m), one silver (1952: K-1 10000 m), and one bronze (K-1 1000Kaprekar's routine (3,143 words) [view diff] no match in snippet view article find links to article
) = α − β = ( ( 2 k − 1 ) − ( k − 1 ) ) b 2 n + 2 ( ∑ i = 0 n b i ) + ( k − k ) b n + 1 ( ∑ i = 0 n b i ) + ( ( k − 1 ) − ( 2 k − 1 ) ) ( ∑ i = 0 n bLogarithmic distribution (377 words) [view diff] no match in snippet view article find links to article
the identity ∑ k = 1 ∞ − 1 ln ( 1 − p ) p k k = 1. {\displaystyle \sum _{k=1}^{\infty }{\frac {-1}{\ln(1-p)}}\;{\frac {p^{k}}{k}}=1.} This leads directlyBinomial series (1,904 words) [view diff] no match in snippet view article find links to article
) ( α − 2 ) ⋯ ( α − k + 1 ) k ! . {\displaystyle {\binom {\alpha }{k}}:={\frac {\alpha (\alpha -1)(\alpha -2)\cdots (\alpha -k+1)}{k!}}.} Note that ifEuler numbers (2,049 words) [view diff] no match in snippet view article find links to article
}{q}}(2q-\ell )^{2n},} E 2 n = ∑ k = 1 2 n ( − 1 ) k 1 2 k ∑ ℓ = 0 2 k ( − 1 ) ℓ ( 2 k ℓ ) ( k − ℓ ) 2 n . {\displaystyle E_{2n}=\sum _{k=1}^{2n}(-1)^{k}{\frac {1}{2^{k}}}\sumStirling numbers of the first kind (7,262 words) [view diff] no match in snippet view article find links to article
1 ) z Γ ( z + 1 ) ( k − 1 ) ! ∑ r = 1 k − 1 s ( k − 1 , r ) ∑ m = 0 r ( r m ) ( k − 2 ) r − m ζ ( z + 1 − m ) , ℜ ( z ) > k − 1 , k = 3 , 4 , 5 , … {\displaystyleChi distribution (1,726 words) [view diff] exact match in snippet view article find links to article
( x ; k ) = { x k − 1 e − x 2 / 2 2 k / 2 − 1 Γ ( k 2 ) , x ≥ 0 ; 0 , otherwise . {\displaystyle f(x;k)={\begin{cases}{\dfrac {x^{k-1}e^{-x^{2}/2}}{2^{k/2-1}\GammaStirling's approximation (4,758 words) [view diff] no match in snippet view article find links to article
) + 1 2 ln n = n ln n − n + 1 + ∑ k = 2 m ( − 1 ) k B k k ( k − 1 ) ( 1 n k − 1 − 1 ) + R m , n , {\displaystyle {\begin{aligned}\ln(n!)-{\tfracExact sequence (2,577 words) [view diff] exact match in snippet view article find links to article
A k + 1 {\displaystyle A_{k+1}} and morphism A k → A k + 1 {\displaystyle A_{k}\to A_{k+1}} such that A k − 1 → A k → A k + 1 {\displaystyle A_{k-1}\toAnalytic continuation (3,886 words) [view diff] no match in snippet view article find links to article
π ∑ n = k ∞ ( − 1 ) n ( n k ) ( a − 1 ) n − k ∫ 0 2 π d θ = ∑ n = k ∞ ( − 1 ) n ( n k ) ( a − 1 ) n − k = ( − 1 ) k ∑ m = 0 ∞ ( m + k k ) ( 1 − a ) mAlan Thompson (canoeist) (528 words) [view diff] exact match in snippet view article
silvers (K-1 1000 m and K-2 500 m: both 1982), and a bronze (K-1 1000 m: 1983). He won both of his Olympic gold medals at Los Angeles in 1984, in the K-1 1000Multiset (4,955 words) [view diff] exact match in snippet view article find links to article
+ k − 1 k ) = ( n + k − 1 ) ! k ! ( n − 1 ) ! = n ( n + 1 ) ( n + 2 ) ⋯ ( n + k − 1 ) k ! , {\displaystyle \left(\!\!{n \choose k}\!\!\right)={n+k-1 \chooseOscillation (3,045 words) [view diff] no match in snippet view article find links to article
1 x ¨ 1 = − ( k 1 + k 2 ) x 1 + k 2 x 2 m 2 x ¨ 2 = k 2 x 1 − ( k 2 + k 3 ) x 2 {\displaystyle {\begin{cases}m_{1}{\ddot {x}}_{1}=-(k_{1Rademacher distribution (1,065 words) [view diff] no match in snippet view article find links to article
( k ) = { 1 / 2 if k = − 1 , 1 / 2 if k = + 1 , 0 otherwise. {\displaystyle f(k)=\left\{{\begin{matrix}1/2&{\text{if }}k=-1,\\1/2&{\text{if }}k=+1,\\0&{\text{otherwiseNumeral system (3,494 words) [view diff] no match in snippet view article find links to article
k b k + ∑ k = 1 ∞ c k b − k . {\displaystyle (a_{n}a_{n-1}\cdots a_{1}a_{0}.c_{1}c_{2}c_{3}\cdots )_{b}=\sum _{k=0}^{n}a_{k}b^{k}+\sum _{k=1}^{\infty }c_{k}b^{-k}Lebesgue measure (2,678 words) [view diff] no match in snippet view article find links to article
as an infimum λ ∗ ( E ) = inf { ∑ k = 1 ∞ ℓ ( I k ) : ( I k ) k ∈ N is a sequence of open intervals with E ⊂ ⋃ k = 1 ∞ I k } . {\displaystyle \lambdaFlory–Schulz distribution (288 words) [view diff] exact match in snippet view article find links to article
length k {\displaystyle k} is: w a ( k ) = a 2 k ( 1 − a ) k − 1 . {\displaystyle w_{a}(k)=a^{2}k(1-a)^{k-1}{\text{.}}} In this equation, k is the numberTopological sorting (3,170 words) [view diff] exact match in snippet view article find links to article
indices a k − 1 + ∑ i = 0 j − 1 | Q i k | , … , a k − 1 + ( ∑ i = 0 j | Q i k | ) − 1 {\textstyle a_{k-1}+\sum _{i=0}^{j-1}|Q_{i}^{k}|,\dots ,a_{k-1}+\left(\sumAlgebra over a field (3,122 words) [view diff] no match in snippet view article find links to article
k 1 , k 2 ∈ K {\displaystyle k_{1},k_{2}\in K} and v 1 , v 2 ∈ V {\displaystyle v_{1},v_{2}\in V} , one has ( k 1 + v 1 ) ( k 2 + v 2 ) = k 1 kAC power (4,388 words) [view diff] no match in snippet view article find links to article
result. A cos ( ω 1 t + k 1 ) cos ( ω 2 t + k 2 ) = A 2 cos [ ( ω 1 t + k 1 ) + ( ω 2 t + k 2 ) ] + A 2 cos [ ( ω 1 t + k 1 ) − ( ω 2 t + k 2 ) ]Asymptotic analysis (2,774 words) [view diff] exact match in snippet view article find links to article
1 − ⋯ − g k − 1 ∼ g k {\displaystyle f-g_{1}-\cdots -g_{k-1}\sim g_{k}} takes its full meaning if g k + 1 = o ( g k ) {\displaystyle g_{k+1}=o(g_{k})}Kaprekar number (4,058 words) [view diff] no match in snippet view article find links to article
= 2 k + 1 + ∑ i = 1 n ( 2 k + 1 ) b 2 i + ( 2 k + 1 ) b 2 i − 1 = 2 k + 1 + ∑ i = 1 2 n ( 2 k + 1 ) b i = ∑ i = 0 2 n ( 2 k + 1 ) b i = ( 2 k + 1 ) ∑Generalized Dirichlet distribution (1,861 words) [view diff] exact match in snippet view article find links to article
function of p 1 , … , p k − 1 {\displaystyle p_{1},\ldots ,p_{k-1}} is [ ∏ i = 1 k − 1 B ( a i , b i ) ] − 1 p k b k − 1 − 1 ∏ i = 1 k − 1 [ p i a i − 1 ( ∑Trapezoid (4,042 words) [view diff] exact match in snippet view article find links to article
≈ ∑ k = 1 N 1 2 ( f ( x k − 1 ) + f ( x k ) ) Δ x , {\displaystyle \int _{a}^{b}f(x)\,dx\approx \sum _{k=1}^{N}{\tfrac {1}{2}}{\bigl (}f(x_{k-1})+f(x_{k}){\bigrRational function (2,421 words) [view diff] exact match in snippet view article find links to article
− 2 x k − ∑ k = 1 ∞ a k − 1 x k + 2 ∑ k = 0 ∞ a k x k . {\displaystyle 1=\sum _{k=2}^{\infty }a_{k-2}x^{k}-\sum _{k=1}^{\infty }a_{k-1}x^{k}+2\sum _{k=0}^{\inftyMeasure (mathematics) (5,550 words) [view diff] no match in snippet view article
collections { E k } k = 1 ∞ {\displaystyle \{E_{k}\}_{k=1}^{\infty }} of pairwise disjoint sets in Σ, μ ( ⋃ k = 1 ∞ E k ) = ∑ k = 1 ∞ μ ( E k ) . {\displaystyle2017 ICF Canoe Sprint World Championships (567 words) [view diff] exact match in snippet view article find links to article
Women's C–2 500 m results Women's K-1 200 m results Women's K-1 500 m results Women's K-1 1000 m results Women's K-1 5000 m results Women's K-2 200 m resultsCanoeing at the 2008 Summer Olympics (70 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menFactorization (7,851 words) [view diff] no match in snippet view article find links to article
E 2 n + F 2 n = ∏ k = 1 n ( E 2 + 2 E F cos ( 2 k − 1 ) π 2 n + F 2 ) = ∏ k = 1 n ( E 2 − 2 E F cos ( 2 k − 1 ) π 2 n + F 2 ) {\displaystyle2010 ICF Canoe Sprint World Championships (1,990 words) [view diff] exact match in snippet view article find links to article
winningest medalist in men's kayak with his 21st career medal, earning that in a K-1 200 m silver. Rauhe eclipsed that record he had tied at the previous championshipsRoot test (1,926 words) [view diff] exact match in snippet view article find links to article
K − 1 1 ∏ k = 1 i ln ( k ) ( n ) − ρ n ∏ k = 1 K ln ( k ) ( n ) + O ( 1 n ) . {\displaystyle \ln a_{n}=-1-\sum _{i=1}^{K-1}{\frac {1}{\prod _{k=1}^{i}\lnFloyd–Warshall algorithm (3,071 words) [view diff] exact match in snippet view article find links to article
t h ( i , j , k − 1 ) , {\displaystyle \mathrm {min} {\Big (}\mathrm {shortestPath} (i,j,k-1),} s h o r t e s t P a t h ( i , k , k − 1 ) + s h o r tDirichlet's test (999 words) [view diff] no match in snippet view article find links to article
k = 1 n M | a k − a k + 1 | = ∑ k = 1 n M ( a k − a k + 1 ) = M ∑ k = 1 n ( a k − a k + 1 ) , {\displaystyle \sum _{k=1}^{n}M|a_{k}-a_{k+1}|=\sum _{kSpline (mathematics) (3,784 words) [view diff] no match in snippet view article
0 , … , k − 1 [ a , b ] = [ t 0 , t 1 ) ∪ [ t 1 , t 2 ) ∪ ⋯ ∪ [ t k − 2 , t k − 1 ) ∪ [ t k − 1 , t k ) ∪ [ t k ] a = t 0 ≤ t 1 ≤ ⋯ ≤ t k − 1 ≤ t k =Canoeing at the 2004 Summer Olympics (96 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menBurr distribution (604 words) [view diff] no match in snippet view article find links to article
k + 1 f ( x ; c , k , λ ) = c k λ ( x λ ) c − 1 [ 1 + ( x λ ) c ] − k − 1 {\displaystyle {\begin{aligned}f(x;c,k)&=ck{\frac {x^{c-1}}{(1+x^{c})^{k+1}}}\\[6pt]f(x;cHexagonal number (1,028 words) [view diff] no match in snippet view article find links to article
∑ k = 1 ∞ 1 k ( 2 k − 1 ) = lim n → ∞ 2 ∑ k = 1 n ( 1 2 k − 1 − 1 2 k ) = lim n → ∞ 2 ∑ k = 1 n ( 1 2 k − 1 + 1 2 k − 1 k ) = 2 lim n → ∞ ( ∑ k = 1 2Myanmar kyat (3,449 words) [view diff] no match in snippet view article find links to article
(plural), placed before the numerals followed by "/-". Amounts less than K. 1/- are typically denoted with the number of pyas following "-/" (e.g. -/50Bose–Einstein statistics (6,024 words) [view diff] no match in snippet view article find links to article
following formula w ( n , g ) = ∑ k 1 = 0 n ∑ k 2 = 0 n − k 1 w ( n − k 1 − k 2 , g − 2 ) = ∑ k 1 = 0 n ∑ k 2 = 0 n − k 1 ⋯ ∑ k g = 0 n − ∑ j = 1 g − 1 kInductance (8,763 words) [view diff] no match in snippet view article find links to article
authors define the range as 0 ≤ k < 1 {\displaystyle 0\leq k<1} , but some define it as − 1 < k < 1 {\displaystyle -1<k<1\,} . Allowing negative valuesParticle filter (16,882 words) [view diff] no match in snippet view article find links to article
k − 1 ) ) = p ( y k − 1 | x k − 1 ) p ( x k | x k − 1 ) p ( x k − 1 | y 0 , ⋯ , y k − 2 ) ∫ p ( y k − 1 | x k − 1 ′ ) p ( x k | x k − 1 ′ ) p ( x k −Integral test for convergence (1,727 words) [view diff] exact match in snippet view article find links to article
( x ) for k = 1 , ln ( ln k − 1 ( x ) ) for k ≥ 2. {\displaystyle \ln _{k}(x)={\begin{cases}\ln(x)&{\text{for }}k=1,\\\ln(\ln _{k-1}(x))&{\text{forPhase velocity (1,075 words) [view diff] no match in snippet view article find links to article
x , t ) = cos ( k 1 x − ω 1 t ) + cos ( k 2 x − ω 2 t ) = 2 cos ( ( k 2 − k 1 ) x − ( ω 2 − ω 1 ) t 2 ) cos ( ( k 2 + k 1 ) x − ( ω 2 + ω 1 )Integer partition (3,396 words) [view diff] no match in snippet view article find links to article
= ∏ k = 1 ∞ ( 1 + x k ) = ∏ k = 1 ∞ 1 1 − x 2 k − 1 . {\displaystyle \sum _{n=0}^{\infty }q(n)x^{n}=\prod _{k=1}^{\infty }(1+x^{k})=\prod _{k=1}^{\inftyPink noise (6,607 words) [view diff] no match in snippet view article find links to article
the interval [ k τ , ( k + 1 ) τ ] {\displaystyle [k\tau ,(k+1)\tau ]} as y k = 1 τ ∫ k τ ( k + 1 ) τ x ˙ ( t ) d t = x ( ( k + 1 ) τ ) − x ( k τ ) τ {\displaystyle2019 K-1 Air Base attack (1,303 words) [view diff] exact match in snippet view article find links to article
A rocket attack was carried out on the K-1 Air Base in Kirkuk province in Iraq on 27 December 2019. The air base was one of many Iraqi military basesThermal expansion (6,133 words) [view diff] no match in snippet view article find links to article
K − 1 {\displaystyle \alpha \approx {\frac {0.038}{T_{m}}}-7.0\cdot 10^{-6}\,\mathrm {K} ^{-1}} In the table below, the range for α is from 10−7 K−1 forRoot test (1,926 words) [view diff] exact match in snippet view article find links to article
K − 1 1 ∏ k = 1 i ln ( k ) ( n ) − ρ n ∏ k = 1 K ln ( k ) ( n ) + O ( 1 n ) . {\displaystyle \ln a_{n}=-1-\sum _{i=1}^{K-1}{\frac {1}{\prod _{k=1}^{i}\lnBroyden–Fletcher–Goldfarb–Shanno algorithm (2,987 words) [view diff] no match in snippet view article find links to article
B k + 1 ( x k + 1 − x k ) = ∇ f ( x k + 1 ) − ∇ f ( x k ) . {\displaystyle B_{k+1}(\mathbf {x} _{k+1}-\mathbf {x} _{k})=\nabla f(\mathbf {x} _{k+1})-\nabla2019 K-1 Air Base attack (1,303 words) [view diff] exact match in snippet view article find links to article
A rocket attack was carried out on the K-1 Air Base in Kirkuk province in Iraq on 27 December 2019. The air base was one of many Iraqi military basesDirichlet's test (999 words) [view diff] no match in snippet view article find links to article
k = 1 n M | a k − a k + 1 | = ∑ k = 1 n M ( a k − a k + 1 ) = M ∑ k = 1 n ( a k − a k + 1 ) , {\displaystyle \sum _{k=1}^{n}M|a_{k}-a_{k+1}|=\sum _{kGoodness of fit (1,150 words) [view diff] no match in snippet view article find links to article
any k − 1 are known, the remaining one is uniquely determined. Basically, one can say, there are only k − 1 freely determined binn counts, thus k − 1 degreesHome advantage (7,714 words) [view diff] no match in snippet view article find links to article
season to obtain k 1 {\displaystyle k_{1}} , k 0 {\displaystyle k_{0}} , and k − 1 {\displaystyle k_{-1}} . Values of k 1 {\displaystyle k_{1}} , k 0 {\displaystyleChain rule (7,087 words) [view diff] no match in snippet view article find links to article
( D f 2 ∘ f 3 . . n ) ⋯ ( D f n − 1 ∘ f n . . n ) D f n = ∏ k = 1 n [ D f k ∘ f ( k + 1 ) . . n ] {\displaystyle {\begin{aligned}Df_{1\,.\,.\,n}&=(Df_{1}\circDanuta Kozák (615 words) [view diff] exact match in snippet view article find links to article
fourteen golds (K-1 500 m: 2013, 2014, 2018; K-2 200 m: 2011; K-2 500 m: 2009, 2010, 2015, 2018; K-4 500 m: 2009, 2011, 2013, 2014, 2018 and K-1 200 m relay:Katalin Kovács (500 words) [view diff] exact match in snippet view article find links to article
seven silvers (K-1 1000 m: 2010, K-2 500 m: 2013, K-4 200 m: 2007, 2009, K-4 500 m: 1997, 1998, 2007), and three bronzes (K-1 500 m: 2001, K-1 1000 m: 1999Phase velocity (1,075 words) [view diff] no match in snippet view article find links to article
x , t ) = cos ( k 1 x − ω 1 t ) + cos ( k 2 x − ω 2 t ) = 2 cos ( ( k 2 − k 1 ) x − ( ω 2 − ω 1 ) t 2 ) cos ( ( k 2 + k 1 ) x − ( ω 2 + ω 1 )Negative hypergeometric distribution (1,911 words) [view diff] no match in snippet view article find links to article
− 1 k ) ( N − r − k K − k ) ( N K ) = 1 ( N K ) ∑ k = 0 K ( k + r − 1 k ) ( N − r − k K − k ) = 1 ( N K ) ( N K ) = 1 , {\displaystyle \sum _{k=0}^{K}\Pr(X=k)=\sumGreen's theorem (4,074 words) [view diff] no match in snippet view article find links to article
\varepsilon } . We have | ∑ i = k + 1 s ∫ Γ i A d x + B d y | ≤ 1 2 ε ∑ i = k + 1 s Λ i . {\displaystyle \left\vert \sum _{i=k+1}^{s}\int _{\Gamma _{i}}A\,dx+B\S-matrix (9,208 words) [view diff] no match in snippet view article find links to article
, k 1 … k n ⟩ = a i † ( k 1 ) ⋯ a i † ( k n ) | i , 0 ⟩ } , {\displaystyle {\mathcal {H}}_{\rm {i}}=\operatorname {span} \{\left|\mathrm {i} ,k_{1}\ldotsElliptic Curve Digital Signature Algorithm (2,833 words) [view diff] no match in snippet view article find links to article
{\displaystyle r=0} , go back to step 3. Calculate s = k − 1 ( z + r d A ) mod n {\displaystyle s=k^{-1}(z+rd_{A})\,{\bmod {\,}}n} . If s = 0 {\displaystyle2021 ICF Canoe Sprint World Championships (447 words) [view diff] exact match in snippet view article find links to article
September 2021. "Men's K-1 200" (PDF). Retrieved 19 September 2021. "Men's K-1 500" (PDF). Retrieved 19 September 2021. "Men's K-1 1000" (PDF). RetrievedPigeonhole principle (4,155 words) [view diff] no match in snippet view article find links to article
contain at least k + 1 objects. For arbitrary n and m, this generalizes to k + 1 = ⌊ ( n − 1 ) / m ⌋ + 1 = ⌈ n / m ⌉ {\displaystyle k+1=\lfloor (n-1)/m\rfloorIan Ferguson (canoeist) (638 words) [view diff] exact match in snippet view article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four Ian2013 ICF Canoe Sprint World Championships (710 words) [view diff] exact match in snippet view article find links to article
Men's C–1 200 m Relay Results Men's K–1 200 m Results Men's K–1 500 m Results Men's K–1 1000 m Results Men's K–1 5000 m Results Men's K–2 200 m ResultsNoncentral chi-squared distribution (3,719 words) [view diff] no match in snippet view article find links to article
variable is developed as V 1 / k 1 V 2 / k 2 ∼ F k 1 , k 2 ′ ( λ ) {\displaystyle {\frac {V_{1}/k_{1}}{V_{2}/k_{2}}}\sim F'_{k_{1},k_{2}}(\lambda )} If J ∼Substitution reaction (1,456 words) [view diff] no match in snippet view article find links to article
described with k1, k−1 and k2, which are the rate constants of their corresponding intermediate reaction steps: L n M − L ⇌ + L , k − 1 − L , k 1 L n M − ◻ →Levi-Civita symbol (5,174 words) [view diff] no match in snippet view article find links to article
2-spinors. In three dimensions, the Levi-Civita symbol is defined by: ε i j k = { + 1 if ( i , j , k ) is ( 1 , 2 , 3 ) , ( 2 , 3 , 1 ) , or ( 3 , 1 ,Interest (9,217 words) [view diff] exact match in snippet view article find links to article
k − 1 r = k [ 1 + ( k − 1 ) r 2 + ⋯ ] {\displaystyle \lambda _{k}={\frac {p_{k}}{p}}={\frac {r_{k}}{r}}={\frac {(1+r)^{k}-1}{r}}=k\left[1+{\frac {(k-1)r}{2}}+\cdotsExtended Euclidean algorithm (4,467 words) [view diff] no match in snippet view article find links to article
k + 1 {\displaystyle s_{k+1}} and t k + 1 {\displaystyle t_{k+1}} are coprime. The relation a s k + 1 + b t k + 1 = 0 {\displaystyle as_{k+1}+bt_{k+1}=0}Discretization (2,400 words) [view diff] no match in snippet view article find links to article
− τ ) B u ( τ ) d τ x [ k + 1 ] = e A ( k + 1 ) T x ( 0 ) + ∫ 0 ( k + 1 ) T e A [ ( k + 1 ) T − τ ] B u ( τ ) d τ x [ k + 1 ] = e A T [ e A k T x ( 0Rate of convergence (5,628 words) [view diff] no match in snippet view article find links to article
x k + 1 − x k x k − x k − 1 | log | x k − x k − 1 x k − 1 − x k − 2 | . {\displaystyle q\approx {\frac {\log \left|\displaystyle {\frac {x_{k+1List of ICF Canoe Sprint World Championships medalists in women's kayak (222 words) [view diff] no match in snippet view article find links to article
This is a list of medalists from the ICF Canoe Sprint World Championships in women's kayak. Debuted: 1994. Debuted: 1938. Not held: 1948. Resumed: 1950Abelian group (5,284 words) [view diff] no match in snippet view article find links to article
numbers k 1 , k 2 , … , k u {\displaystyle k_{1},k_{2},\dots ,k_{u}} are powers of (not necessarily distinct) primes, or k 1 {\displaystyle k_{1}} dividesEulerian number (2,460 words) [view diff] no match in snippet view article find links to article
( n , k ) = ∑ i = 0 k ( − 1 ) i ( n + 1 i ) ( k + 1 − i ) n . {\displaystyle A(n,k)=\sum _{i=0}^{k}(-1)^{i}{\binom {n+1}{i}}(k+1-i)^{n}.} For fixed nJosefa Idem (966 words) [view diff] exact match in snippet view article find links to article
Schüttpelz. The next year, Idem switched to the K-1 events. At the 1988 Olympics in Seoul, she finished ninth in the K-1 500 m and fifth with the West German quartetGreatest common divisor (4,717 words) [view diff] exact match in snippet view article find links to article
d 1 − k ζ ( k ) − 1 = ζ ( k − 1 ) ζ ( k ) . {\displaystyle \mathrm {E} (k)=\sum _{d=1}^{\infty }d^{1-k}\zeta (k)^{-1}={\frac {\zeta (k-1)}{\zeta (k)}}K-nearest neighbors algorithm (4,316 words) [view diff] no match in snippet view article find links to article
its k nearest neighbors (k is a positive integer, typically small). If k = 1, then the object is simply assigned to the class of that single nearestCanoeing at the 1996 Summer Olympics (81 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menKolmogorov–Smirnov test (3,912 words) [view diff] no match in snippet view article find links to article
k = 1 ∞ ( − 1 ) k − 1 e − 2 k 2 x 2 = 2 π x ∑ k = 1 ∞ e − ( 2 k − 1 ) 2 π 2 / ( 8 x 2 ) , {\displaystyle \operatorname {Pr} (K\leq x)=1-2\sum _{k=1}^{\inftyExpectation–maximization algorithm (7,512 words) [view diff] no match in snippet view article find links to article
via F ^ = ∑ k = 1 N ( x ^ k + 1 − F ^ x ^ k ) 2 ∑ k = 1 N x ^ k 2 . {\displaystyle {\widehat {F}}={\frac {\sum _{k=1}^{N}{({\widehat {x}}_{k+1}-{\widehatFermat number (4,717 words) [view diff] no match in snippet view article find links to article
( 2 k + 1 ) . {\displaystyle (2^{r}+1)\mid (2^{k}+1).} Because 1 < 2 r + 1 < 2 k + 1 {\displaystyle 1<2^{r}+1<2^{k}+1} , it follows that 2 k + 1 {\displaystyleDirichlet-multinomial distribution (6,950 words) [view diff] exact match in snippet view article find links to article
^{k}|n_{1}+\cdots +n_{k}=n\}.\,} Its number of elements is ( n + k − 1 k − 1 ) . {\displaystyle {n+k-1 \choose k-1}.} In matrix notation, E ( X ) = n p , {\displaystyleYule–Simon distribution (1,312 words) [view diff] exact match in snippet view article find links to article
is an integer, f ( k ; ρ ) = ρ ρ ! ( k − 1 ) ! ( k + ρ ) ! . {\displaystyle f(k;\rho )={\frac {\rho \,\rho !\,(k-1)!}{(k+\rho )!}}.} The parameter ρ {\displaystyleCapacitance (4,187 words) [view diff] no match in snippet view article find links to article
with a Z/1 − K impedance between the first node and ground and a KZ/K − 1 impedance between the second node and ground. Since impedance varies inverselyCohen's kappa (3,698 words) [view diff] no match in snippet view article find links to article
following construction: p e = ∑ k p k 12 ^ = ind. ∑ k p k 1 ^ p k 2 ^ = ∑ k n k 1 N n k 2 N = 1 N 2 ∑ k n k 1 n k 2 {\displaystyle p_{e}=\sum _{k}{\widehat {p_{k12}}}{\oversetRonald Rauhe (647 words) [view diff] exact match in snippet view article find links to article
years older he won two medals – gold in the K-4 500 m and silver in the K-1 500 m, an unprecedented achievement for a fifteen-year-old. After winningLagrange multiplier (7,987 words) [view diff] no match in snippet view article find links to article
∇ f ( x ) = ∑ k = 1 M λ k ∇ g k ( x ) ⟺ ∇ f ( x ) − ∑ k = 1 M λ k ∇ g k ( x ) = 0 . {\displaystyle \nabla f(\mathbf {x} )=\sum _{k=1}^{M}\lambda _{k}\Hodge star operator (6,501 words) [view diff] no match in snippet view article find links to article
i k + 1 , … , i n d x i k + 1 ∧ ⋯ ∧ d x i n . {\displaystyle {\star }\alpha ={\frac {1}{(n-k)!}}({\star }\alpha )_{i_{k+1},\dots ,i_{n}}dx^{i_{k+1}}\wedgeList of fighting games (2,012 words) [view diff] exact match in snippet view article find links to article
Fu Factory K-1 World GP K-1 World GP 2006 K-1 Premium 2005 Dynamite!! K-1 World GP 2005 K-1 World Max 2005 K-1 Premium 2004 Dynamite!! K-1 World GrandPolytope (3,119 words) [view diff] case mismatch in snippet view article find links to article
context, "flat sides" means that the sides of a (k + 1)-polytope consist of k-polytopes that may have (k – 1)-polytopes in common. Some theories further generalizeInternational System of Units (6,146 words) [view diff] no match in snippet view article find links to article
the fixed numerical value of the Boltzmann constant k to 1.380649×10−23 J⋅K−1, (J = kg⋅m2⋅s−2), given the definition of the kilogram, the metre, and theAleksandr Shaparenko (208 words) [view diff] exact match in snippet view article find links to article
1972: K-1 1000 m) and one silver (1968: K-1 1000 m). Shaparenko also won 13 medals at the ICF Canoe Sprint World Championships with seven golds (K-1 1000List of fighting games (2,012 words) [view diff] exact match in snippet view article find links to article
Fu Factory K-1 World GP K-1 World GP 2006 K-1 Premium 2005 Dynamite!! K-1 World GP 2005 K-1 World Max 2005 K-1 Premium 2004 Dynamite!! K-1 World GrandZipf's law (4,591 words) [view diff] no match in snippet view article find links to article
&\ {\mbox{ if }}\ k<1\ {\mbox{ or }}\ N<k~.\end{cases}}} where HN is a normalization constant: The Nth harmonic number: H N ≡ ∑ k = 1 N 1 k . {\displaystylePolytope (3,119 words) [view diff] case mismatch in snippet view article find links to article
context, "flat sides" means that the sides of a (k + 1)-polytope consist of k-polytopes that may have (k – 1)-polytopes in common. Some theories further generalizeExpectation–maximization algorithm (7,512 words) [view diff] no match in snippet view article find links to article
via F ^ = ∑ k = 1 N ( x ^ k + 1 − F ^ x ^ k ) 2 ∑ k = 1 N x ^ k 2 . {\displaystyle {\widehat {F}}={\frac {\sum _{k=1}^{N}{({\widehat {x}}_{k+1}-{\widehatRonald Rauhe (647 words) [view diff] exact match in snippet view article find links to article
years older he won two medals – gold in the K-4 500 m and silver in the K-1 500 m, an unprecedented achievement for a fifteen-year-old. After winningHypoexponential distribution (1,758 words) [view diff] no match in snippet view article find links to article
finite state Markov process. If we have a k+1 state process, where the first k states are transient and the state k+1 is an absorbing state, then the distributionSquare wave (waveform) (1,295 words) [view diff] no match in snippet view article
an infinite sum of sinusoidal waves: x ( t ) = 4 π ∑ k = 1 ∞ sin ( 2 π ( 2 k − 1 ) f t ) 2 k − 1 = 4 π ( sin ( ω t ) + 1 3 sin ( 3 ω t ) + 1 5 sinLah number (1,812 words) [view diff] exact match in snippet view article find links to article
, k − 1 ) = k ( k + 1 ) L ( n , k + 1 ) + 2 k L ( n , k ) + L ( n , k − 1 ) {\displaystyle {\begin{aligned}L(n+1,k)&=(n+k)L(n,k)+L(n,k-1)\\&=k(k+1)L(nLebesgue integral (5,919 words) [view diff] no match in snippet view article find links to article
positive, we set ∫ ( ∑ k a k 1 S k ) d μ = ∑ k a k ∫ 1 S k d μ = ∑ k a k μ ( S k ) {\displaystyle \int \left(\sum _{k}a_{k}1_{S_{k}}\right)\,d\mu =\sumReversible reaction (894 words) [view diff] no match in snippet view article find links to article
at the final kinetic expression: [ A ] = k -1 [ A ] 0 k 1 + k -1 + k 1 [ A ] 0 k 1 + k -1 exp ( − k 1 + k -1 ) t {\displaystyle [A]={\fracHermite polynomials (12,119 words) [view diff] exact match in snippet view article find links to article
k + 1 ) a n , k + 1 k = 0 , a n , k − 1 − ( k + 1 ) a n , k + 1 k > 0 , {\displaystyle a_{n+1,k}={\begin{cases}-(k+1)a_{n,k+1}&k=0,\\a_{n,k-1}-(k+1)a_{nRita Kőbán (398 words) [view diff] exact match in snippet view article find links to article
(K-1 200 m: 1994, 1995; K-1 500 m: 1995, K-2 200 m: 1994, K-4 200 m: 1994, 1998, 1999; K-4 500 m: 1986, 1999), ten silvers (K-1 500 m: 1991, 1994; K-1Square triangular number (1,478 words) [view diff] exact match in snippet view article find links to article
x k + 1 = 2 x k x 1 − x k − 1 , y k + 1 = 2 y k x 1 − y k − 1 . {\displaystyle \displaystyle {\begin{aligned}x_{k+1}&=2x_{k}x_{1}-x_{k-1},\\y_{k+1}&=2y_{k}x_{1}-y_{k-1}1 + 2 + 3 + 4 + ⋯ (4,221 words) [view diff] no match in snippet view article find links to article
partial sum of the series is the triangular number ∑ k = 1 n k = n ( n + 1 ) 2 , {\displaystyle \sum _{k=1}^{n}k={\frac {n(n+1)}{2}},} which increases withoutPartial fraction decomposition (7,008 words) [view diff] exact match in snippet view article find links to article
\deg H_{k}<\deg G.} Setting F k − 1 = F C + Q , {\displaystyle F_{k-1}=FC+Q,} one gets F G k = H k G k + F k − 1 G k − 1 , {\displaystyle {\frac {F}{G^{k}}}={\frac(a,b,0) class of distributions (797 words) [view diff] exact match in snippet view article
satisfies the recurrence formula p k p k − 1 = a + b k , k = 1 , 2 , 3 , … {\displaystyle {\frac {p_{k}}{p_{k-1}}}=a+{\frac {b}{k}},\qquad k=1,2,3,\dotsYule–Simon distribution (1,312 words) [view diff] exact match in snippet view article find links to article
is an integer, f ( k ; ρ ) = ρ ρ ! ( k − 1 ) ! ( k + ρ ) ! . {\displaystyle f(k;\rho )={\frac {\rho \,\rho !\,(k-1)!}{(k+\rho )!}}.} The parameter ρ {\displaystylePercentile (2,647 words) [view diff] no match in snippet view article find links to article
C} , and v = v k + P − p k p k + 1 − p k ( v k + 1 − v k ) . {\displaystyle v=v_{k}+{\frac {P-p_{k}}{p_{k+1}-p_{k}}}(v_{k+1}-v_{k}).} The 50% weighted percentileFerenc Csipes (356 words) [view diff] exact match in snippet view article find links to article
with eight golds (K-1 1000 m: 1985, K-1 10000 m: 1986, K-2 500 m: 1987, K-4 1000 m: 1986, 1987, 1989, 1990, 1991), four silvers (K-1 1000 m: 1986, 1987Characteristic polynomial (3,040 words) [view diff] exact match in snippet view article find links to article
A^{k}} because A k v = A k − 1 A v = λ A k − 1 v = ⋯ = λ k v . {\displaystyle A^{k}{\textbf {v}}=A^{k-1}A{\textbf {v}}=\lambda A^{k-1}{\textbf {v}}=\dots =\lambdaSquared triangular number (1,867 words) [view diff] no match in snippet view article find links to article
mathematical notation for summation: ∑ k = 1 n k 3 = ( ∑ k = 1 n k ) 2 . {\displaystyle \sum _{k=1}^{n}k^{3}=\left(\sum _{k=1}^{n}k\right)^{2}.} This identityTensor algebra (4,161 words) [view diff] no match in snippet view article find links to article
one has scalar multiplication on the field: k 1 ⊗ k 2 = k 1 k 2 . {\displaystyle k_{1}\otimes k_{2}=k_{1}k_{2}.} The most difficult to verify is the compatibilityFundamental theorem of algebra (7,621 words) [view diff] no match in snippet view article find links to article
( z − z 0 ) k + c k + 1 ( z − z 0 ) k + 1 + ⋯ + c n ( z − z 0 ) n . {\displaystyle p(z)=a+c_{k}(z-z_{0})^{k}+c_{k+1}(z-z_{0})^{k+1}+\cdots +c_{n}(z-z_{0})^{n}2022 ICF Canoe Sprint World Championships (70 words) [view diff] exact match in snippet view article find links to article
C-2 1000m men C-4 500m men women Kayak events K-1 200m men women K-1 500m men women K-1 1000m men women K-1 5000m men women K-2 200m women K-2 500m menGeneral Leibniz rule (1,247 words) [view diff] no match in snippet view article find links to article
_{t=1}^{m}k_{t}=n,} and ( n k 1 , k 2 , … , k m ) = n ! k 1 ! k 2 ! ⋯ k m ! {\displaystyle {n \choose k_{1},k_{2},\ldots ,k_{m}}={\frac {n!}{k_{1}!\,k_{2}!\cdotsChebyshev polynomials (11,475 words) [view diff] no match in snippet view article find links to article
k ) ( 1 − x − 2 ) k = n 2 ∑ k = 0 ⌊ n 2 ⌋ ( − 1 ) k ( n − k − 1 ) ! k ! ( n − 2 k ) ! ( 2 x ) n − 2 k for n > 0 = n ∑ k = 0 n ( − 2 ) k ( n + kHalf-logistic distribution (247 words) [view diff] no match in snippet view article find links to article
2F(k) − 1 is the cdf of a half-logistic distribution. Specifically, G ( k ) = 1 − e − k 1 + e − k for k ≥ 0. {\displaystyle G(k)={\frac {1-e^{-k}}{1+e^{-k}}}{\text{Kelvin (4,784 words) [view diff] no match in snippet view article find links to article
adopted at the 26th CGPM in late 2018, with a value of kB = 1.380649×10−23 J⋅K−1. In fundamental physics, the mapping E=kBT which converts between the characteristicFriedman test (1,169 words) [view diff] no match in snippet view article find links to article
12 n k ( k + 1 ) ∑ j = 1 k ( r ¯ ⋅ j − k + 1 2 ) 2 {\displaystyle Q={\frac {12n}{k(k+1)}}\sum _{j=1}^{k}\left({\bar {r}}_{\cdot j}-{\frac {k+1}{2}}\right)^{2}}Faà di Bruno's formula (3,788 words) [view diff] no match in snippet view article find links to article
noticing that m j {\displaystyle m_{j}} has to be zero for j > n − k + 1 {\displaystyle j>n-k+1} leads to a somewhat simpler formula expressed in terms of partial2005 ICF Canoe Sprint World Championships (330 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Carlos Pérez (ESP) 35.289 Tomasz Mendelski (POL) 35.697 Anton Ryakhov (RUS) 35.733 K-1 500 m Nathan Baggaley (AUS)Color index (1,031 words) [view diff] no match in snippet view article find links to article
formula (also implemented in the PyAstronomy package for Python): T = 4600 K ( 1 0.92 ( B - V ) + 1.7 + 1 0.92 ( B - V ) + 0.62 ) . {\displaystyle T=4600\Moiré pattern (4,166 words) [view diff] no match in snippet view article find links to article
= k 1 + k 2 2 {\displaystyle A={\frac {k_{1}+k_{2}}{2}}} and B = k 1 − k 2 2 . {\displaystyle B={\frac {k_{1}-k_{2}}{2}}.} This function average, f3Cross-polytope (1,106 words) [view diff] no match in snippet view article find links to article
is thus given by (see binomial coefficient): 2 k + 1 ( n k + 1 ) {\displaystyle 2^{k+1}{n \choose {k+1}}} The extended f-vector for an n-orthoplex can2019 ICF Canoe Sprint World Championships (1,279 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200, 500, 1000 or 5000 metresCanoeing at the 1976 Summer Olympics (76 words) [view diff] exact match in snippet view article find links to article
in the Montreal program though four 500 m events for men were (C-1, C-2, K-1, and K-2). 1976 Summer Olympics official report Volume 3. pp. 167–85. (inSawtooth wave (1,102 words) [view diff] no match in snippet view article find links to article
sawtooth ( t ) = − 2 a π ∑ k = 1 ∞ ( − 1 ) k sin ( 2 π k f t ) k {\displaystyle x_{\text{sawtooth}}(t)=-{\frac {2a}{\pi }}\sum _{k=1}^{\infty }{(-1)}^{k}{\fracCanoeing at the 1992 Summer Olympics (88 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m men2006 ICF Canoe Sprint World Championships (337 words) [view diff] exact match in snippet view article find links to article
final, giving Mexico their first-ever world championship gold medal. The K-1 1000 m, the Blue Riband event, was won by Markus Oscarsson of Sweden. Germany'sMaximum entropy probability distribution (4,530 words) [view diff] no match in snippet view article find links to article
x k } = p k for k = 1 , 2 , … {\displaystyle \operatorname {Pr} \{\ X=x_{k}\}=p_{k}\qquad ~{\mbox{ for }}~\quad k=1,\ 2,\ \ldots ~} then theBorosilicate glass (3,691 words) [view diff] no match in snippet view article find links to article
are known for having very low coefficients of thermal expansion (≈3 × 10−6 K−1 at 20 °C), making them more resistant to thermal shock than any other commonAbel's test (1,047 words) [view diff] no match in snippet view article find links to article
absolutely: ∑ k = 1 ∞ | ( a k − a k − 1 ) z k | = ∑ k = 1 ∞ | a k − a k − 1 | ⋅ | z | k ≤ ∑ k = 1 ∞ ( a k − 1 − a k ) {\displaystyle \sum _{k=1}^{\inftyPerfect digital invariant (5,240 words) [view diff] no match in snippet view article find links to article
1 ) ( 3 k + 1 ) − k ( 3 k + 1 ) = ( k + 1 ) ( 3 k + 1 ) ( 3 k + 1 ) − k ( 3 k + 1 ) = k ( 3 k + 1 ) ( 3 k + 1 ) + ( 3 k + 1 ) ( 3 k + 1 ) − k ( 3 k +Vampire number (730 words) [view diff] exact match in snippet view article find links to article
digits: A = a k a k − 1 . . . a 1 {\displaystyle A={a_{k}}{a_{k-1}}...{a_{1}}} B = b k b k − 1 . . . b 1 {\displaystyle B={b_{k}}{b_{k-1}}...{b_{1}}} suchAutoregressive model (5,421 words) [view diff] no match in snippet view article find links to article
expressed as [citation needed] ρ ( τ ) = ∑ k = 1 p a k y k − | τ | , {\displaystyle \rho (\tau )=\sum _{k=1}^{p}a_{k}y_{k}^{-|\tau |},} where y k {\displaystyleFalling and rising factorials (3,377 words) [view diff] no match in snippet view article find links to article
= x n _ = x ( x − 1 ) ( x − 2 ) ⋯ ( x − n + 1 ) ⏞ n factors = ∏ k = 1 n ( x − k + 1 ) = ∏ k = 0 n − 1 ( x − k ) . {\displaystyle {\begin{aligned}(x)_{n}=x^{\underlineKnot theory (6,292 words) [view diff] no match in snippet view article find links to article
{R} ^{3}} , with the only "non-injectivity" being K ( 0 ) = K ( 1 ) {\displaystyle K(0)=K(1)} . Topologists consider knots and other entanglements such2019 ICF Canoe Sprint World Championships (1,279 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200, 500, 1000 or 5000 metresDroop quota (2,336 words) [view diff] no match in snippet view article find links to article
and truncate: ⌈ total votes k + 1 ⌉ ≈ ⌊ total votes k + 1 + 1 ⌋ {\displaystyle \left\lceil {\frac {\text{total votes}}{k+1}}\right\rceil \approx \left\lfloorZsolt Gyulay (337 words) [view diff] exact match in snippet view article find links to article
(1988: K-1 500 m, K-4 1000 m) and two silver (1992: K-1 500 m, K-4 1000 m). He also won fourteen medals at the world championships: six golds (K-1 1000Zeta distribution (1,030 words) [view diff] no match in snippet view article find links to article
defined for positive integers k ≥ 1 {\displaystyle k\geq 1} , and its probability mass function is given by P ( x = k ) = 1 ζ ( s ) k − s , {\displaystyleKnot theory (6,292 words) [view diff] no match in snippet view article find links to article
{R} ^{3}} , with the only "non-injectivity" being K ( 0 ) = K ( 1 ) {\displaystyle K(0)=K(1)} . Topologists consider knots and other entanglements suchCube (algebra) (3,026 words) [view diff] exact match in snippet view article
well-known identity: n 2 = ∑ k = 1 n ( 2 k − 1 ) , {\displaystyle n^{2}=\sum _{k=1}^{n}(2k-1),} we obtain the following derivation: ∑ k = 1 n k 3 = 1 + 8 + 27 +Factorion (1,282 words) [view diff] exact match in snippet view article find links to article
the following: SFD b ( n ) = ∑ i = 0 k − 1 d i ! . {\displaystyle \operatorname {SFD} _{b}(n)=\sum _{i=0}^{k-1}d_{i}!.} where k = ⌊ log b n ⌋ + 1 {\displaystyleMathematical economics (13,624 words) [view diff] no match in snippet view article find links to article
) k / ( 1 − τ ) {\textstyle dw/d\tau =-f'(k)k/(1-\tau )} , we have that: d w d x = − f ′ ( k ) k 1 − τ f ′ ( k ) 1 − τ [ τ f ′ ( k ) f ″ ( k ) + k ] =Natasa Dusev-Janics (717 words) [view diff] exact match in snippet view article find links to article
won 26 medals at the ICF Canoe Sprint World Championships with 20 golds (K-1 200 m: 2007, 2009, 2010; K-2 200 m: 2005, 2006, 2009, 2010; K-2 500 m: 2005Least squares (5,702 words) [view diff] no match in snippet view article find links to article
are obtained by successive approximation: β j k + 1 = β j k + Δ β j , {\displaystyle {\beta _{j}}^{k+1}={\beta _{j}}^{k}+\Delta \beta _{j},} where a superscriptDiscrete phase-type distribution (596 words) [view diff] no match in snippet view article find links to article
distribution function is F ( k ) = 1 − τ T k 1 , {\displaystyle F(k)=1-{\boldsymbol {\tau }}{T}^{k}\mathbf {1} ,} for k = 1 , 2 , . . . {\displaystyle k=1Caroline Brunet (212 words) [view diff] exact match in snippet view article find links to article
(K-1 200 m: 1997, 1998, 1999, 2003; K-1 500 m: 1997, 1998, 1999; K-1 1000 m: 1997, 1999; K-4 200 m: 1995), seven silvers (K-1 200 m: 1995, 2002; K-1 500Lewandowski-Kurowicka-Joe distribution (425 words) [view diff] no match in snippet view article find links to article
k = 1 d − 1 ( 2 η − 2 + d − k ) ( d − k ) ∏ k = 1 d − 1 [ B ( η + ( d − k − 1 ) / 2 , η + ( d − k − 1 ) / 2 ) ] d − k {\displaystyle C=2^{\sum _{k=1}^{d-1}(2\etaBirth–death process (3,948 words) [view diff] exact match in snippet view article find links to article
= λ k − 1 p k − 1 ( t ) + μ k + 1 p k + 1 ( t ) − ( λ k + μ k ) p k ( t ) , k = 1 , 2 , … , {\displaystyle p_{k}^{\prime }(t)=\lambda _{k-1}p_{k-1}(t)+\mu2007 ICF Canoe Sprint World Championships (267 words) [view diff] exact match in snippet view article find links to article
K-2 races were ruled by the German paddlers. However, Katalin Kovács won K-1 1000 m and 500 m, and gained two silvers in the K-4 events, while former1998 ICF Canoe Sprint World Championships (77 words) [view diff] exact match in snippet view article find links to article
K-1 200 m Caroline Brunet (CAN) Josefa Idem (ITA) Éva Dónusz (HUN) K-1 500 m Caroline Brunet (CAN) Katrin Borchert (AUS) Josefa Idem (ITA) K-1 1000Gauss–Kuzmin distribution (569 words) [view diff] no match in snippet view article find links to article
_{2}\left(1-{\frac {1}{(1+k)^{2}}}\right)~.} Let x = 1 k 1 + 1 k 2 + ⋯ {\displaystyle x={\cfrac {1}{k_{1}+{\cfrac {1}{k_{2}+\cdots }}}}} be the continued fractionCumulant (8,867 words) [view diff] exact match in snippet view article find links to article
∑ k = 1 n ( − 1 ) k − 1 ( k − 1 ) ! B n , k ( μ 1 ′ , … , μ n − k + 1 ′ ) , {\displaystyle \kappa _{n}=\sum _{k=1}^{n}(-1)^{k-1}(k-1)!B_{n,k}(\mu '_{1}Distortion (optics) (2,784 words) [view diff] no match in snippet view article
given by x d = x c + x u − x c 2 K 1 r u 2 ( 1 − 1 − 4 K 1 r u 2 ) y d = y c + y u − y c 2 K 1 r u 2 ( 1 − 1 − 4 K 1 r u 2 ) , {\displaystyle {\begin{aligned}x_{\mathrmPhytomenadione (1,333 words) [view diff] no match in snippet view article find links to article
Phytomenadione, also known as vitamin K1 or phylloquinone, is a vitamin found in food and used as a dietary supplement. It is on the World Health Organization'sProbability mass function (1,539 words) [view diff] exact match in snippet view article find links to article
success. Its probability mass function is p X ( k ) = ( 1 − p ) k − 1 p {\textstyle p_{X}(k)=(1-p)^{k-1}p} . An example is tossing a coin until the firstRaman Piatrushenka (603 words) [view diff] exact match in snippet view article find links to article
m bronze. In the K-1 1000m however, he could only finish 17th. At the 2002 European under-23 Championships in Zagreb, he won the K-1 1000 m gold medalArithmetic function (7,550 words) [view diff] no match in snippet view article find links to article
k 1 , n ) = 1 1 ≤ k 1 , k 2 , … , k s ≤ n gcd ( k 1 − 1 , k 2 , … , k s , n ) = φ ( n ) σ s − 1 ( n ) . {\displaystyle \sum _{\stackrel {1\leq k_{1}Regular polygon (3,223 words) [view diff] no match in snippet view article find links to article
{1}{n}}\sum _{i=1}^{n}d_{i}^{2m}} , then S n ( 2 m ) = ( S n ( 2 ) ) m + ∑ k = 1 ⌊ m / 2 ⌋ ( m 2 k ) ( 2 k k ) R 2 k ( S n ( 2 ) − R 2 ) k ( S n ( 2 ) )Initial condition (1,362 words) [view diff] exact match in snippet view article find links to article
d t k + a k − 1 d k − 1 x d t k − 1 + ⋯ + a 1 d x d t + a 0 x = 0. {\displaystyle {\frac {d^{k}x}{dt^{k}}}+a_{k-1}{\frac {d^{k-1}x}{dt^{k-1}}}+\cdotsQuasi-Newton method (2,264 words) [view diff] no match in snippet view article find links to article
approximate Hessian B k + 1 {\displaystyle B_{k+1}} , or directly its inverse H k + 1 = B k + 1 − 1 {\displaystyle H_{k+1}=B_{k+1}^{-1}} using the Sherman–MorrisonRoot of unity (5,939 words) [view diff] no match in snippet view article find links to article
of unity, as ( z k ) n = z k n = ( z n ) k = 1 k = 1. {\displaystyle (z^{k})^{n}=z^{kn}=(z^{n})^{k}=1^{k}=1.} This is also true for negative exponentsCholesky decomposition (8,335 words) [view diff] no match in snippet view article find links to article
for k = 1:n r = sqrt(L(k, k)^2 + x(k)^2); c = r / L(k, k); s = x(k) / L(k, k); L(k, k) = r; if k < n L((k+1):n, k) = (L((k+1):n, k) + s * x((k+1):n))Proof that 22/7 exceeds π (2,814 words) [view diff] no match in snippet view article find links to article
≥ 0 and ℓ ≥ 2 we have x k ( 1 − x ) ℓ = ( 1 − 2 x + x 2 ) x k ( 1 − x ) ℓ − 2 = ( 1 + x 2 ) x k ( 1 − x ) ℓ − 2 − 2 x k + 1 ( 1 − x ) ℓ − 2 . {\displaystyle2009 ICF Canoe Sprint World Championships (3,937 words) [view diff] exact match in snippet view article find links to article
men's 500 m events (C-1, C-2, K-1 and K-2) at the Summer Olympics with the 200 m events (men's C-1, K-1 and K-2; and women's K-1) for the upcoming Summer OlympicsMerit order (2,602 words) [view diff] no match in snippet view article find links to article
total welfare is then W = ∑ k = 1 n V k ( D k ) − ∑ k = 1 n C k ( S k ) {\displaystyle W=\sum _{k=1}^{n}V_{k}(D_{k})-\sum _{k=1}^{n}C_{k}(S_{k})} The economicCanoeing at the 1984 Summer Olympics (66 words) [view diff] exact match in snippet view article find links to article
Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m men women K-2 1000 m men K-4 500 m women K-4Characteristic function (probability theory) (5,208 words) [view diff] no match in snippet view article
) − k 1 ( 1 − θ i t ) − k 2 = ( 1 − θ i t ) − ( k 1 + k 2 ) . {\displaystyle \varphi _{X+Y}(t)=\varphi _{X}(t)\varphi _{Y}(t)=(1-\theta it)^{-k_{1}}(1-\thetaPower rule (2,631 words) [view diff] exact match in snippet view article find links to article
i.e. d d x x k = k x k − 1 . {\displaystyle {\frac {d}{dx}}x^{k}=kx^{k-1}.} When n = k + 1 {\displaystyle n=k+1} , d d x x k + 1 = d d x ( x k ⋅ x ) =Markov chain (12,894 words) [view diff] no match in snippet view article find links to article
X_{0}=i)>0\}} The state is periodic if k > 1 {\displaystyle k>1} ; otherwise k = 1 {\displaystyle k=1} and the state is aperiodic. A state i is saidPopulation model (734 words) [view diff] no match in snippet view article find links to article
equations: d N 1 d t = r 1 N 1 K 1 − N 1 − α N 2 K 1 {\displaystyle {\frac {dN_{1}}{dt}}=r_{1}N_{1}{\frac {K_{1}-N_{1}-\alpha N_{2}}{K_{1}}}\,} Island biogeography:Lists of integrals (5,611 words) [view diff] no match in snippet view article find links to article
( x ) − ( − 1 ) n d n f ( x ) d x n ) d x = e x ∑ k = 1 n ( − 1 ) k − 1 d k − 1 f ( x ) d x k − 1 + C {\displaystyle \int {e^{x}\left(f\left(x\rightIterative method (1,546 words) [view diff] no match in snippet view article find links to article
defined as M x k + 1 = N x k + b , k ≥ 0 , {\displaystyle M\mathbf {x} ^{k+1}=N\mathbf {x} ^{k}+b,\quad k\geq 0,} or, equivalently, x k + 1 = x k + M − 1Cyclic permutation (2,039 words) [view diff] no match in snippet view article find links to article
= ( k k + 1 ) ⋅ ( k + 1 k + 2 ) ⋯ ( l − 1 l ) ⋅ ( l − 2 l − 1 ) ⋯ ( k k + 1 ) . {\displaystyle (k~~l)=(k~~k+1)\cdot (k+1~~k+2)\cdotsInterior product (1,587 words) [view diff] no match in snippet view article find links to article
i = k + 1 n ( ∂ i a ) d ξ i ∧ d ξ 2 ∧ ⋯ ∧ d ξ k , d α = ∑ i = k + 1 n ( ∂ i a ) d ξ i ∧ d ξ 1 ∧ d ξ 2 ∧ ⋯ ∧ d ξ k , ι X ( d α ) = − ∑ i = k + 1 n ( ∂2003 ICF Canoe Sprint World Championships (217 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Ronald Rauhe (GER) 35.798 Vince Fehérvári (AUS) 36.411 Anton Ryakhov (UZB) 36.417 K-1 500 m Nathan Baggaley (AUS)Vibration (7,235 words) [view diff] no match in snippet view article find links to article
defined by the following formula. X = F 0 k 1 ( 1 − r 2 ) 2 + ( 2 ζ r ) 2 . {\displaystyle X={F_{0} \over k}{1 \over {\sqrt {(1-r^{2})^{2}+(2\zeta r)^{2}}}}Geometric process (858 words) [view diff] no match in snippet view article find links to article
k = 1 , 2 , … } {\displaystyle \{X_{k},k=1,2,\dots \}} , if they are independent and the cdf of X k {\displaystyle X_{k}} is given by F ( a k − 1 xGaussian elimination (4,368 words) [view diff] exact match in snippet view article find links to article
R_{i}} with r k , k R i − r i , k R k r k − 1 , k − 1 . {\textstyle {\frac {r_{k,k}R_{i}-r_{i,k}R_{k}}{r_{k-1,k-1}}}.} This produces a row echelon formNewton's identities (7,644 words) [view diff] case mismatch in snippet view article find links to article
including general relativity. Let x1, ..., xn be variables, denote for k ≥ 1 by pk(x1, ..., xn) the k-th power sum: p k ( x 1 , … , x n ) = ∑ i = 1 nGauss–Markov theorem (4,717 words) [view diff] no match in snippet view article find links to article
variable β K + 1 {\displaystyle \beta _{K+1}} with a newly introduced last column of X being unity i.e., X i ( K + 1 ) = 1 {\displaystyle X_{i(K+1)}=1} for2014 ICF Canoe Sprint World Championships (442 words) [view diff] exact match in snippet view article find links to article
Men's C–1 200 m Relay Results Men's K–1 200 m Results Men's K–1 500 m Results Men's K–1 1000 m Results Men's K–1 5000 m Results Men's K–2 200 m ResultsProjection (linear algebra) (5,806 words) [view diff] no match in snippet view article
i 2 1 ≤ i ≤ k 1 k + 1 ≤ i ≤ n − k 0 otherwise {\displaystyle \sigma _{i}={\begin{cases}{\sqrt {1+\gamma _{i}^{2}}}&1\leq i\leq k\\1&k+1\leq i\leqCanoeing at the 2000 Summer Olympics (131 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menTriple DES (2,946 words) [view diff] no match in snippet view article find links to article
would be to use two keys ( K 1 , K 2 ) {\displaystyle (K1,K2)} instead of one, and encrypt each block twice: E K 2 ( E K 1 ( plaintext ) ) {\displaystyleFunction of several complex variables (17,688 words) [view diff] no match in snippet view article find links to article
∂ k 1 + ⋯ + k n f ( ζ 1 , ζ 2 , … , ζ n ) ∂ z 1 k 1 ⋯ ∂ z n k n | ≤ M k 1 ! ⋯ k n ! r 1 k 1 ⋯ r n k n {\displaystyle \left|{\frac {\partial ^{k_{1}+\cdotsBen Fouhy (485 words) [view diff] exact match in snippet view article find links to article
2000s. He competed in three Summer Olympics, winning a silver medal in the K-1 1000 m event at Athens in 2004. He also finished fourth in the 2008 OlympicsProjection (linear algebra) (5,806 words) [view diff] no match in snippet view article
i 2 1 ≤ i ≤ k 1 k + 1 ≤ i ≤ n − k 0 otherwise {\displaystyle \sigma _{i}={\begin{cases}{\sqrt {1+\gamma _{i}^{2}}}&1\leq i\leq k\\1&k+1\leq i\leqSchröder–Bernstein theorem (2,374 words) [view diff] no match in snippet view article find links to article
x = ∑ k = 1 ∞ a k ⋅ 10 − k {\displaystyle x=\sum _{k=1}^{\infty }a_{k}\cdot 10^{-k}} and y = ∑ k = 1 ∞ b k ⋅ 10 − k {\displaystyle y=\sum _{k=1}^{\inftyNeighbor joining (2,881 words) [view diff] no match in snippet view article find links to article
) d ( a , b ) − ∑ k = 1 5 d ( a , k ) − ∑ k = 1 5 d ( b , k ) {\displaystyle Q_{1}(a,b)=(n-2)d(a,b)-\sum _{k=1}^{5}d(a,k)-\sum _{k=1}^{5}d(b,k)} = ( 5List of ICF Canoe Sprint World Championships medalists in paracanoe (365 words) [view diff] exact match in snippet view article find links to article
2010. Classed as K-1 A before 2015. First contested in 2010. Classed as K-1 TA before 2015. First contested in 2010. Classed as K-1 LTA before 2015. Was2014 ICF Canoe Sprint World Championships (442 words) [view diff] exact match in snippet view article find links to article
Men's C–1 200 m Relay Results Men's K–1 200 m Results Men's K–1 500 m Results Men's K–1 1000 m Results Men's K–1 5000 m Results Men's K–2 200 m ResultsCauchy–Schwarz inequality (5,175 words) [view diff] no match in snippet view article find links to article
⟩ | 2 = | ∑ k = 1 n u k v ¯ k | 2 ≤ ⟨ u , u ⟩ ⟨ v , v ⟩ = ( ∑ k = 1 n u k u ¯ k ) ( ∑ k = 1 n v k v ¯ k ) = ∑ j = 1 n | u j | 2 ∑ k = 1 n | v k | 2Arithmetico-geometric sequence (2,160 words) [view diff] no match in snippet view article find links to article
arithmetico-geometric series has the form S n = ∑ k = 1 n A k G k = ∑ k = 1 n ( a + ( k − 1 ) d ) b r k − 1 = b ∑ k = 0 n − 1 ( a + k d ) r k = a b + ( aMonotone convergence theorem (5,489 words) [view diff] no match in snippet view article find links to article
k ( x ) ≤ f k + 1 ( x ) {\displaystyle (1-\varepsilon )s(x)\leq f_{k}(x)\leq f_{k+1}(x)} so x ∈ B k + 1 s , ε . {\displaystyle x\in B_{k+1}^{s,\varepsilonGreg Barton (415 words) [view diff] exact match in snippet view article find links to article
Championships with four golds (K-1 1000 m: 1987, K-1 10000 m: 1985, 1987, 1991), a silver (K-1 10000 m: 1990), and a bronze (K-1 1000 m: 1991). He receivedRandom forest (6,483 words) [view diff] no match in snippet view article find links to article
function, or connection function is K k c c ( x , z ) = ∑ k 1 , … , k d , ∑ j = 1 d k j = k k ! k 1 ! ⋯ k d ! ( 1 d ) k ∏ j = 1 d 1 ⌈ 2 k j x j ⌉ = ⌈ 2 k2018 ICF Canoe Sprint World Championships (1,178 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200, 500, 1000 or 5000 metresBotond Storcz (378 words) [view diff] exact match in snippet view article find links to article
medals at the ICF Canoe Sprint World Championships with four golds (K-1 500 m: 1997, K-1 1000 m: 1997, K-4 500 m: 1997, K-4 1000 m: 1999), five silvers (K-2Dick Joyce (rower) (511 words) [view diff] exact match in snippet view article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanDiagonalizable matrix (4,692 words) [view diff] no match in snippet view article find links to article
1 k 0 0 0 1 k 0 0 0 2 k ] [ 1 0 1 1 2 0 0 1 − 1 ] − 1 = [ 2 − 2 k − 1 + 2 k 2 − 2 k + 1 0 1 0 − 1 + 2 k 1 − 2 k − 1 + 2 k + 1 ] . {\displaystyleList of integrals of exponential functions (3,291 words) [view diff] exact match in snippet view article find links to article
_{k=1}^{n}{\left(-1\right)^{k-1}{\frac {d^{k-1}f\left(x\right)}{dx^{k-1}}}}+C} ∫ e − x ( f ( x ) − d n f ( x ) d x n ) d x = − e − x ∑ k = 1 n d k − 1 fMultiplicative digital root (965 words) [view diff] exact match in snippet view article find links to article
k − 1 d i b i {\displaystyle n=\sum _{i=0}^{k-1}d_{i}b^{i}} and therefore F b ( n ) = ∏ i = 0 k − 1 d i = d k − 1 ∏ i = 0 k − 2 d i < d k − 1 b k − 1Wrapped normal distribution (1,707 words) [view diff] no match in snippet view article find links to article
expansion for the logarithm: ln ( 1 + x ) = − ∑ k = 1 ∞ ( − 1 ) k k x k {\displaystyle \ln(1+x)=-\sum _{k=1}^{\infty }{\frac {(-1)^{k}}{k}}\,x^{k}} the logarithmicHSL and HSV (10,785 words) [view diff] case mismatch in snippet view article find links to article
f ( n ) = L − a max ( − 1 , min ( k − 3 , 9 − k , 1 ) ) {\displaystyle f(n)=L-a\max(-1,\min(k-3,9-k,1))} where k , n ∈ R ≥ 0 {\displaystyle k,n\in \mathbbAlternating series test (1,825 words) [view diff] no match in snippet view article find links to article
S k − L | ≤ | S k − S k + 1 | = a k + 1 . {\displaystyle \left|S_{k}-L\right\vert \leq \left|S_{k}-S_{k+1}\right\vert =a_{k+1}.\!} Suppose we are givenKatrin Wagner-Augustin (325 words) [view diff] exact match in snippet view article find links to article
bronze (K-1 500 m: 2008). Wagner-Augustin also won 26 medals at the ICF Canoe Sprint World Championships with ten golds (K-1 1000 m: 2005, K-1 4 × 200Saúl Craviotto (553 words) [view diff] exact match in snippet view article find links to article
the K-1 200 m event at the 2012 Summer Olympics in London, a gold medal (with Cristian Toro) in the K-2 200 m event and a bronze medal in the K-1 200Heat exchanger (9,485 words) [view diff] no match in snippet view article find links to article
where k 1 = γ / J 1 {\displaystyle k_{1}=\gamma /J_{1}} , k 2 = γ / J 2 {\displaystyle k_{2}=\gamma /J_{2}} , k = k 1 + k 2 {\displaystyle k=k_{1}+k_{2}}Haralambie Ivanov (233 words) [view diff] exact match in snippet view article find links to article
with four golds (K-1 4 x 500 m: 1963, K-2 500 m: 1963, K-2 1000 m: 1963, K-4 1000 m: 1966), a silver (K-4 1000 m: 1963), and a bronze (K-1 4 x 500 m: 1966)Arnaud Hybois (177 words) [view diff] exact match in snippet view article find links to article
m in 2011), a silver (K-1 4 x 200 m, 2014) and two bronze (K-1 4 x 200 m: 2009, K-1 500 m 2013). Hybois also competed in the K-1 500 m event at the 2008Convergence tests (2,222 words) [view diff] no match in snippet view article find links to article
case of p = 1 , k = 1 {\displaystyle p=1,k=1} yields the harmonic series, which diverges. The case of p = 2 , k = 1 {\displaystyle p=2,k=1} is the Basel1997 ICF Canoe Sprint World Championships (97 words) [view diff] exact match in snippet view article find links to article
kayak events. Eight events were held for the women, all in kayak. Women's K-1 1000 m and K-2 1000 m events were added. This was the 28th championshipsFourier series (11,131 words) [view diff] no match in snippet view article find links to article
1 1 φ ( y ) cos ( 2 k + 1 ) π y 2 d y = ∫ − 1 1 ( a cos π y 2 cos ( 2 k + 1 ) π y 2 + a ′ cos 3 π y 2 cos ( 2 k + 1 ) π y 2 + ⋯ ) d y {\displaystyleSinc function (3,074 words) [view diff] exact match in snippet view article find links to article
k − 1 ∑ n = 1 2 k − 1 cos ( n − 1 / 2 2 k − 1 x ) , ∀ k ≥ 1 , {\displaystyle \prod _{n=1}^{k}\cos \left({\frac {x}{2^{n}}}\right)={\frac {1}{2^{k-1}}}\sumSI derived unit (387 words) [view diff] no match in snippet view article find links to article
conductivity m⋅kg⋅s−3⋅K−1 kelvin per watt K/W thermal resistance m−2⋅kg−1⋅s3⋅K reciprocal kelvin K−1 thermal expansion coefficient K−1 kelvin per metre K/mYokosuka MXY-7 Ohka (3,234 words) [view diff] exact match in snippet view article find links to article
had the engine of the Model 11 and the airframe of the Model 22. The Ohka K-1 was an unpowered trainer version with water ballast instead of warhead andStandard RAID levels (4,551 words) [view diff] exact match in snippet view article find links to article
{\displaystyle D} as polynomials D = d k − 1 x k − 1 + d k − 2 x k − 2 + . . . + d 1 x + d 0 {\displaystyle \mathbf {D} =d_{k-1}x^{k-1}+d_{k-2}x^{k-2}+...+d_{1}x+d_{0}}Lennart Klingström (144 words) [view diff] exact match in snippet view article find links to article
Sprint World Championships with three golds (K-1 4×500 m: 1948, 1950; K-4 1000 m: 1948) and a silver (K-1 500 m: 1950). Lennart Klingström. Sports-referenceHomothety (2,065 words) [view diff] no match in snippet view article find links to article
for k {\displaystyle k} : for k = 1 {\displaystyle k=1} one gets the identity mapping, for k = − 1 {\displaystyle k=-1} one gets the reflection at theBirgit Fischer (480 words) [view diff] exact match in snippet view article find links to article
Germany 1980 Moscow K-1 500 m 1988 Seoul K-2 500 m 1988 Seoul K-4 500 m 1988 Seoul K-1 500 m Representing Germany 1992 Barcelona K-1 500 m 1996 AtlantaGroup velocity (3,504 words) [view diff] no match in snippet view article find links to article
x , t ) = cos ( k 1 x − ω 1 t ) + cos ( k 2 x − ω 2 t ) = 2 cos ( ( k 2 − k 1 ) x − ( ω 2 − ω 1 ) t 2 ) cos ( ( k 2 + k 1 ) x − ( ω 2 + ω 1 )Beta function (4,110 words) [view diff] no match in snippet view article find links to article
adjusting indices: ( n k ) = 1 ( n + 1 ) B ( n − k + 1 , k + 1 ) . {\displaystyle {\binom {n}{k}}={\frac {1}{(n+1)\,\mathrm {B} (n-k+1,k+1)}}.} Moreover, forJosef Dostál (canoeist) (328 words) [view diff] exact match in snippet view article
Summer Olympics in the K-4 1000 m event. He won the silver medal in the K-1 1000 metres event at the 2016 Summer Olympics in Rio de Janeiro. He was alsoCzech Republic at the Olympics (269 words) [view diff] exact match in snippet view article find links to article
Dostál Canoeing Men's K-1 1000 m Silver Jaroslav Kulhavý Cycling Men's cross-country Bronze Jiří Prskavec Canoeing Men's slalom K-1 Bronze Ondřej SynekChain reaction (2,580 words) [view diff] no match in snippet view article find links to article
obtain k 1 [ CH 3 CHO ] − 2 k 4 [ CH 3 ] 2 = 0 {\displaystyle k_{1}{\ce {[CH3CHO]}}-2k_{4}{\ce {[CH3]}}^{2}=0} so that ( 4 ) . . . [ CH 3 ] = k 1 2 k 41st Army (German Empire) (625 words) [view diff] no match in snippet view article
The 1st Army (German: 1. Armee / Armeeoberkommando 1 / A.O.K. 1) was an army level command of the German Army in World War I. It was formed on mobilizationF-test (2,188 words) [view diff] exact match in snippet view article find links to article
1 K n i ( Y ¯ i ⋅ − Y ¯ ) 2 / ( K − 1 ) {\displaystyle \sum _{i=1}^{K}n_{i}({\bar {Y}}_{i\cdot }-{\bar {Y}})^{2}/(K-1)} where Y ¯ i ⋅ {\displaystyle {\bar1994 ICF Canoe Sprint World Championships (211 words) [view diff] exact match in snippet view article find links to article
and men's and women's K-1) resumed at the 2010 championships.) and the 200 m events for C-1, C-2, and C-4 (men only), and K-1, K-2, and K-4 (both menSolenoid (mathematics) (1,488 words) [view diff] no match in snippet view article
θ = ∑ k = 1 ∞ r k e 2 π i ω k t {\displaystyle \zeta =2\pi t,\quad re^{i\theta }=\sum _{k=1}^{\infty }r_{k}e^{2\pi i\omega _{k}t}} where ω k = 1 n 1 ⋯Czech Republic at the Olympics (269 words) [view diff] exact match in snippet view article find links to article
Dostál Canoeing Men's K-1 1000 m Silver Jaroslav Kulhavý Cycling Men's cross-country Bronze Jiří Prskavec Canoeing Men's slalom K-1 Bronze Ondřej SynekNarcissistic number (1,082 words) [view diff] exact match in snippet view article find links to article
{N} } to be the following: F b ( n ) = ∑ i = 0 k − 1 d i k . {\displaystyle F_{b}(n)=\sum _{i=0}^{k-1}d_{i}^{k}.} where k = ⌊ log b n ⌋ + 1 {\displaystyleHarmonic number (5,594 words) [view diff] no match in snippet view article find links to article
u d u = ∫ 0 1 [ ∑ k = 1 n ( n k ) ( − u ) k − 1 ] d u = ∑ k = 1 n ( n k ) ∫ 0 1 ( − u ) k − 1 d u = ∑ k = 1 n ( n k ) ( − 1 ) k − 1 k . {\displaystyleBasel problem (8,692 words) [view diff] no match in snippet view article find links to article
be defined by S n ( x ) x := ∏ k = 1 n ( 1 − x 2 k 2 ⋅ π 2 ) {\displaystyle {\frac {S_{n}(x)}{x}}:=\prod \limits _{k=1}^{n}\left(1-{\frac {x^{2}}{k^{2}\cdotRecursion (3,677 words) [view diff] no match in snippet view article find links to article
{\displaystyle k\in \mathbb {N} } . Then F(k + 1) = f(F(k)) = f(G(k)) = G(k + 1). Hence F(k) = G(k) implies F(k + 1) = G(k + 1). By induction, F(n) = G(n) for allChain reaction (2,580 words) [view diff] no match in snippet view article find links to article
obtain k 1 [ CH 3 CHO ] − 2 k 4 [ CH 3 ] 2 = 0 {\displaystyle k_{1}{\ce {[CH3CHO]}}-2k_{4}{\ce {[CH3]}}^{2}=0} so that ( 4 ) . . . [ CH 3 ] = k 1 2 k 4Square root (6,182 words) [view diff] no match in snippet view article find links to article
e k + 1 p k + 1 2 e k + 1 … p n 2 e n = p 1 e 1 … p n e n p 1 … p k . {\displaystyle {\sqrt {p_{1}^{2e_{1}+1}\cdots p_{k}^{2e_{k}+1}p_{k+1}^{2e_{k+1}}\dotsSpectral radius (3,196 words) [view diff] no match in snippet view article find links to article
formula states that ρ ( A ) = lim k → ∞ ‖ A k ‖ 1 / k {\displaystyle \rho (A)=\lim _{k\to \infty }\|A^{k}\|^{1/k}} . Both of these results are shown belowNumerical methods for ordinary differential equations (3,916 words) [view diff] no match in snippet view article find links to article
form α k y n + k + α k − 1 y n + k − 1 + ⋯ + α 0 y n = h [ β k f ( t n + k , y n + k ) + β k − 1 f ( t n + k − 1 , y n + k − 1 ) + ⋯ + β 0 f ( t n ,Differential operator (3,693 words) [view diff] no match in snippet view article find links to article
Laplacian operator, defined by Δ = ∇ 2 = ∑ k = 1 n ∂ 2 ∂ x k 2 . {\displaystyle \Delta =\nabla ^{2}=\sum _{k=1}^{n}{\frac {\partial ^{2}}{\partial x_{k}^{2}}}Steven Ferguson (253 words) [view diff] exact match in snippet view article find links to article
finished eighth in the K-2 1000 m event, but was eliminated in the heats of the K-1 500 m event. He competed again in the K-2 1000 m at the 2008 Summer OlympicsLatent Dirichlet allocation (7,614 words) [view diff] no match in snippet view article find links to article
we get: A = ∑ k = 1 K α β C k ¬ n + V β {\displaystyle A=\sum _{k=1}^{K}{\frac {\alpha \beta }{C_{k}^{\neg n}+V\beta }}} B = ∑ k = 1 K C k d β C k ¬Yoshihiro Akiyama (3,777 words) [view diff] exact match in snippet view article find links to article
for South Korea and for Japan at the 2002 Asian Games. He is the former K-1 HERO's Light Heavyweight Grand Prix Tournament Champion. Before his professionalCompound Poisson distribution (2,307 words) [view diff] no match in snippet view article find links to article
( ∑ k = 1 ∞ α k λ ( z k − 1 ) ) , ( | z | ≤ 1 ) {\displaystyle P_{Y}(z)=\sum \limits _{i=0}^{\infty }P(Y=i)z^{i}=\exp \left(\sum \limits _{k=1}^{\inftyMaryna Litvinchuk (272 words) [view diff] exact match in snippet view article find links to article
K-1 5000 m 2014 Moscow K-1 5000 m 2018 Montemor-o-Velho K-1 5000 m 2019 Szeged K-4 500 m 2021 Copenhagen K-2 500 m 2011 Szeged K-1 5000 m 2011 Szeged K-4Newton polynomial (5,843 words) [view diff] no match in snippet view article find links to article
are calculated using Newton's divided differences method. Given a set of k + 1 data points ( x 0 , y 0 ) , … , ( x j , y j ) , … , ( x k , y k ) {\displaystyleLinear independence (4,286 words) [view diff] no match in snippet view article find links to article
{v} _{k},} if k > 1 , {\displaystyle k>1,} and v 1 = 0 {\displaystyle \mathbf {v} _{1}=\mathbf {0} } if k = 1. {\displaystyle k=1.} Thus, a set ofB-spline (5,717 words) [view diff] exact match in snippet view article find links to article
, k − 1 ( x ) + t i + k + 1 − x t i + k + 1 − t i + 1 B i + 1 , k − 1 ( x ) . {\displaystyle B_{i,k}(x):={\frac {x-t_{i}}{t_{i+k}-t_{i}}}B_{i,k-1}(x)+{\fracQuadratic variation (1,539 words) [view diff] exact match in snippet view article find links to article
‖ P ‖ → 0 ∑ k = 1 n ( X t k − X t k − 1 ) 2 {\displaystyle [X]_{t}=\lim _{\Vert P\Vert \rightarrow 0}\sum _{k=1}^{n}(X_{t_{k}}-X_{t_{k-1}})^{2}} whereMultivariate normal distribution (9,619 words) [view diff] no match in snippet view article find links to article
k 1 {\displaystyle k_{1}} and k 2 {\displaystyle k_{2}} dimensional marginal distributions X {\displaystyle X} and Y {\displaystyle Y} , such that k 1East Germany at the 1980 Summer Olympics (2,024 words) [view diff] exact match in snippet view article find links to article
Men's K-1 1000m Gold Rüdiger Helm Bernd Olbricht Harald Marg Bernd Duvigneau Canoeing Men's K-4 1000m Gold Birgit Fischer Canoeing Women's K-1 500m GoldInterpolation attack (2,288 words) [view diff] no match in snippet view article find links to article
+ k 1 ) 3 = ( x 2 + k 1 2 ) ( x + k 1 ) = x 3 + k 1 2 x + x 2 k 1 + k 1 3 , {\displaystyle c_{1}=(x+k_{1})^{3}=(x^{2}+k_{1}^{2})(x+k_{1})=x^{3}+k_{1Ernesto Hoost (1,810 words) [view diff] exact match in snippet view article find links to article
kickboxer. A four-time K-1 World Champion, Hoost is considered to be one of the greatest kickboxers of all time. Debuting in 1993 at the K-1 World Grand PrixList of airships of the United States Navy (553 words) [view diff] exact match in snippet view article find links to article
airship) (ZNN-G) (ZGT) H class blimp (observation) J class blimp (trainer) K-1 blimp (experimental) K class blimp (anti-submarine patrol) (ZNP-K) (ZSG-2Narayana number (1,088 words) [view diff] exact match in snippet view article find links to article
coefficients: N ( n , k ) = 1 n ( n k ) ( n k − 1 ) {\displaystyle \operatorname {N} (n,k)={\frac {1}{n}}{n \choose k}{n \choose k-1}} The first eight rows1995 ICF Canoe Sprint World Championships (102 words) [view diff] exact match in snippet view article find links to article
Gold Time Silver Time Bronze Time K-1 200 m Piotr Markiewicz (POL) Sergey Kalesnik (BLR) Renn Crichlow (CAN) K-1 500 m Piotr Markiewicz (POL) KnutMass–energy equivalence (11,628 words) [view diff] no match in snippet view article find links to article
energy K by an additive constant, which gives K 0 − K 1 = E ( 1 1 − v 2 c 2 − 1 ) {\displaystyle K_{0}-K_{1}=E\left({\frac {1}{\sqrt {1-{\frac {v^{2}}{c^{2}}}}}}-1\right)}Antonio Rossi (270 words) [view diff] exact match in snippet view article find links to article
in five Summer Olympics, he won five medals which included three golds (K-1 500 m: 1996, K-2 1000 m: 1996, 2000), one silver (K-2 1000 m: 2004), andPerfect digit-to-digit invariant (1,095 words) [view diff] exact match in snippet view article find links to article
base b {\displaystyle b} as the k-digit number d k − 1 d k − 2 . . . d 1 d 0 {\displaystyle d_{k-1}d_{k-2}...d_{1}d_{0}} where each digit d i {\displaystyleShellsort (3,436 words) [view diff] exact match in snippet view article find links to article
of passes p {\displaystyle p} to Ω ( N ∑ k = 1 p h k − 1 / h k ) {\displaystyle \Omega (N\sum _{k=1}^{p}h_{k-1}/h_{k})} where h 0 = N {\displaystyle h_{0}=N}Box spread (1,710 words) [view diff] no match in snippet view article find links to article
consider the put/call parity equation at two different strike prices K 1 {\displaystyle K_{1}} and K 2 {\displaystyle K_{2}} . The stock price S will disappearNewton's method (8,748 words) [view diff] no match in snippet view article find links to article
x_{2}-3~\end{bmatrix}}_{k}\end{aligned}}} and X k + 1 = X k − C k + 1 {\displaystyle X_{k+1}~=~X_{k}-C_{k+1}} The iterations should be repeated until [Tom Liebscher (84 words) [view diff] exact match in snippet view article find links to article
96 kg (212 lb) Sport Country Germany Sport Sprint kayak Event(s) K-1 200 m, K-1 500 m, K-1 1000 m, K-2 200 m, K-4 500 m, K-4 1000 m Club Kanu Club DresdenTamara Csipes (244 words) [view diff] exact match in snippet view article find links to article
gold medal in Women's K-4 500 metres, and a silver medal in the Women's K-1 500 metres At the 2010 ICF Canoe Sprint World Championships in Poznań, sheButterworth filter (4,135 words) [view diff] no match in snippet view article find links to article
recursion formula a k + 1 a k = cos ( k γ ) sin ( ( k + 1 ) γ ) {\displaystyle {\frac {a_{k+1}}{a_{k}}}={\frac {\cos(k\gamma )}{\sin((k+1)\gamma )}}} andExtended Kalman filter (3,823 words) [view diff] exact match in snippet view article find links to article
become P k | k − 1 = F k − 1 P k − 1 | k − 1 F k − 1 T + L k − 1 Q k − 1 L k − 1 T {\displaystyle {\boldsymbol {P}}_{k|k-1}={{\boldsymbol {F}}_{k-1}}{{\boldsymbolTriple point (1,328 words) [view diff] no match in snippet view article find links to article
was redefined so that the Boltzmann constant is exactly 1.380649×10−23 J⋅K−1, and the triple point of water became an experimentally measured constantInclusion–exclusion principle (6,851 words) [view diff] no match in snippet view article find links to article
k = 1 n ( − 1 ) k + 1 ( ∑ 1 ⩽ i 1 < ⋯ < i k ⩽ n | A i 1 ∩ ⋯ ∩ A i k | ) {\displaystyle \left|\bigcup _{i=1}^{n}A_{i}\right|=\sum _{k=1}^{n}(-1)^{k+1}\left(\sumTechnology (10,447 words) [view diff] no match in snippet view article find links to article
Yael; Chazan, Michael; Arnold, M.; Aumaître, G.; Bourlès, D.; Keddadouche, K. (1 May 2021). "Magnetostratigraphy and cosmogenic dating of Wonderwerk Cave:Multinomial theorem (2,059 words) [view diff] no match in snippet view article find links to article
power: ( x 1 + x 2 + ⋯ + x m ) n = ∑ k 1 + k 2 + ⋯ + k m = n k 1 , k 2 , ⋯ , k m ≥ 0 ( n k 1 , k 2 , … , k m ) x 1 k 1 ⋅ x 2 k 2 ⋯ x m k m {\displaystyleScale (map) (5,382 words) [view diff] no match in snippet view article
should be within 4 parts in 10,000, or 0.04%, corresponding to k = 1.0004 {\displaystyle k=1.0004} . Since sec φ {\displaystyle \sec \varphi } attainsJapanese submarine I-15 (2,880 words) [view diff] exact match in snippet view article find links to article
Harbor, operated off the United States West Coast, and took part in Operation K-1, the Aleutian Islands campaign, and the Guadalcanal campaign, including theNarayana number (1,088 words) [view diff] exact match in snippet view article find links to article
coefficients: N ( n , k ) = 1 n ( n k ) ( n k − 1 ) {\displaystyle \operatorname {N} (n,k)={\frac {1}{n}}{n \choose k}{n \choose k-1}} The first eight rowsExtended Kalman filter (3,823 words) [view diff] exact match in snippet view article find links to article
become P k | k − 1 = F k − 1 P k − 1 | k − 1 F k − 1 T + L k − 1 Q k − 1 L k − 1 T {\displaystyle {\boldsymbol {P}}_{k|k-1}={{\boldsymbol {F}}_{k-1}}{{\boldsymbolSemiprime (866 words) [view diff] no match in snippet view article find links to article
than or equal to n. Then π 2 ( n ) = ∑ k = 1 π ( n ) [ π ( n p k ) − k + 1 ] {\displaystyle \pi _{2}(n)=\sum _{k=1}^{\pi \left({\sqrt {n}}\right)}\left[\piLazdijai District Municipality (142 words) [view diff] no match in snippet view article find links to article
K 1 0 1 Paulenka K 0 0 0 Paveisininkai K 7 3 4 Pertakas K 5 3 2 Purviniai K 3 2 1 Semoškai K 26 13 13 Simaniškė K 1 0 1 Sirguškė K 6 4 2 Stalai K 1 1Quartile (2,225 words) [view diff] no match in snippet view article find links to article
{\displaystyle x_{k}} and x k + 1 {\displaystyle x_{k+1}} . q ( p / 4 ) = x k + α ( x k + 1 − x k ) {\displaystyle q(p/4)=x_{k}+\alpha (x_{k+1}-x_{k})} , where kFriedmann–Lemaître–Robertson–Walker metric (3,622 words) [view diff] no match in snippet view article find links to article
r ) = { k − 1 sin ( r k ) , k > 0 r , k = 0 | k | − 1 sinh ( r | k | ) , k < 0. {\displaystyle S_{k}(r)={\begin{cases}{\sqrt {k}}^{\,-1}\sin(r{\sqrtHungary at the 1956 Summer Olympics (256 words) [view diff] exact match in snippet view article find links to article
Farkas József Hunics C-2 10000 m — 55:15.6 Lajos Kiss K-1 1000 m 4:35.8 2 Q 4:16.2 Ferenc Hatlaczky K-1 10000 m — 47:53.3 Imre Vágyóczky Zoltán Szigeti K-2Trigonometric functions (10,611 words) [view diff] no match in snippet view article find links to article
square ( t ) = 4 π ∑ k = 1 ∞ sin ( ( 2 k − 1 ) t ) 2 k − 1 . {\displaystyle f_{\text{square}}(t)={\frac {4}{\pi }}\sum _{k=1}^{\infty }{\sin {\bigEMER-K1 (724 words) [view diff] exact match in snippet view article find links to article
The EMER K-1, sometimes known as the EMER K1 or EMERK-1, was a prototype bullpup assault rifle made in Myanmar by the Electrical Mechanical and EngineeringReflexive space (6,409 words) [view diff] no match in snippet view article find links to article
{\displaystyle x_{\varnothing },} the root of the tree, followed, for k = 1 , … , n , {\displaystyle k=1,\ldots ,n,} by a family of s k {\displaystyle s^{k}} 2 vectorsBates distribution (695 words) [view diff] no match in snippet view article find links to article
variables on the unit interval, Uk: X = 1 n ∑ k = 1 n U k . {\displaystyle X={\frac {1}{n}}\sum _{k=1}^{n}U_{k}.} The equation defining the probabilityEuclid's theorem (3,429 words) [view diff] no match in snippet view article find links to article
integers) is equivalent to the statement that we have ∏ p ∈ P k 1 1 − 1 p = ∑ n ∈ N k 1 n , {\displaystyle \prod _{p\in P_{k}}{\frac {1}{1-{\frac {1}{p}}}}=\sum2011 ICF Canoe Sprint World Championships (3,160 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200 metres (660 ft), 500Polynomial interpolation (9,051 words) [view diff] no match in snippet view article find links to article
C ( u − k , 1 ) Δ y k − 1 + C ( u − k + 1 , 2 ) Δ 2 y k − 2 + C ( u − k + 2 , 3 ) Δ 3 y k − 3 + ⋯ = y k + ( u − k ) Δ y k − 1 + ( u − k + 1 ) ( u − kDecimal representation (1,815 words) [view diff] exact match in snippet view article find links to article
traditionally written with a single separator: r = b k b k − 1 ⋯ b 0 . a 1 a 2 ⋯ {\displaystyle r=b_{k}b_{k-1}\cdots b_{0}.a_{1}a_{2}\cdots } Here . is the decimalCanoeing at the 1988 Summer Olympics (51 words) [view diff] exact match in snippet view article find links to article
Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m men women K-2 1000 m men K-4 500 m women K-4Irwin–Hall distribution (1,358 words) [view diff] no match in snippet view article find links to article
identically distributed U(0, 1) random variables: X = ∑ k = 1 n U k . {\displaystyle X=\sum _{k=1}^{n}U_{k}.} The probability density function (pdf) forMark and recapture (3,122 words) [view diff] no match in snippet view article find links to article
K + 1 ) k + 1 − 1 {\displaystyle {\hat {N}}_{C}={\frac {(n+1)(K+1)}{k+1}}-1} The example (n, K, k) = (10, 15, 5) gives N ^ C = ( n + 1 ) ( K + 1 ) k +SN1 reaction (1,970 words) [view diff] no match in snippet view article find links to article
= k 1 [ tBuBr ] − k − 1 [ tBu + ] [ Br − ] − k 2 [ tBu + ] [ H 2 O ] {\displaystyle {\frac {d[{\text{tBu}}^{+}]}{dt}}=0=k_{1}[{\text{tBuBr}}]-k_{-1Ball (mathematics) (1,840 words) [view diff] no match in snippet view article
r ) = π k k ! r 2 k , V 2 k + 1 ( r ) = 2 k + 1 π k ( 2 k + 1 ) ! ! r 2 k + 1 = 2 ( k ! ) ( 4 π ) k ( 2 k + 1 ) ! r 2 k + 1 . {\displaystyleSatisfaction equilibrium (3,856 words) [view diff] exact match in snippet view article find links to article
× A k − 1 × A k + 1 × … , × A K → 2 A k {\displaystyle f_{k}:{\mathcal {A}}_{1}\times \ldots \times {\mathcal {A}}_{k-1}\times {\mathcal {A}}_{k+1}\timesOuter product (2,942 words) [view diff] no match in snippet view article find links to article
{\displaystyle \mathbf {u} ,\mathbf {v} } with dimensions ( k 1 , k 2 , … , k m ) {\displaystyle (k_{1},k_{2},\dots ,k_{m})} and ( l 1 , l 2 , … , l n ) {\displaystyleGéza Csapó (309 words) [view diff] exact match in snippet view article find links to article
with six golds (K-1 500 m: 1973, 1975; K-1 1000 m: 1973, 1974; K-1 4 x 500 m: 1971, K-2 10000 m: 1973), two silvers (K-1 500 m: 1973, K-1 4 x 500 m: 1973)Deficient number (560 words) [view diff] exact match in snippet view article find links to article
, p k − 1 {\displaystyle 1,p,p^{2},\dots ,p^{k-1}} which sum to p k − 1 p − 1 {\displaystyle {\frac {p^{k}-1}{p-1}}} , which is at most p k − 1 {\displaystyleEinar Rasmussen (200 words) [view diff] exact match in snippet view article find links to article
golds (K-1 10000 m: 1981, 1983; K-2 1000 m: 1979, K-4 10000 m: 1975), three silvers (K-1 10000 m: 1979, 1982; K-2 1000 m: 1978), and three bronzes (K-1 1000Togo at the 2008 Summer Olympics (164 words) [view diff] exact match in snippet view article find links to article
in Beijing, China from August 8 to August 24, 2008. At the men's slalom K-1 event, Benjamin Boukpeti won a bronze medal in canoeing, the first OlympicLine integral (3,183 words) [view diff] no match in snippet view article find links to article
considering the expression ∑ k = 1 n f ( γ ( t k ) ) [ γ ( t k ) − γ ( t k − 1 ) ] = ∑ k = 1 n f ( γ k ) Δ γ k . {\displaystyle \sum _{k=1}^{n}f(\gamma (t_{k}))\Apéry's constant (3,021 words) [view diff] no match in snippet view article find links to article
= 1 4 ∑ k = 1 ∞ ( − 1 ) k − 1 ( k − 1 ) ! 3 ( 56 k 2 − 32 k + 5 ) ( 2 k − 1 ) 2 ( 3 k ) ! . {\displaystyle \zeta (3)={\frac {1}{4}}\sum _{k=1}^{\inftyColossally abundant number (1,635 words) [view diff] no match in snippet view article find links to article
that for all k > 1, σ ( n ) n 1 + ε ≥ σ ( k ) k 1 + ε {\displaystyle {\frac {\sigma (n)}{n^{1+\varepsilon }}}\geq {\frac {\sigma (k)}{k^{1+\varepsilonMotzkin number (846 words) [view diff] exact match in snippet view article find links to article
This gives ∑ k = 0 n C k = 1 + ∑ k = 1 n ( n k ) M k − 1 . {\displaystyle \sum _{k=0}^{n}C_{k}=1+\sum _{k=1}^{n}{\binom {n}{k}}M_{k-1}.} The generating functionJoule per mole (467 words) [view diff] no match in snippet view article find links to article
particle, 0.239 kcal·mol−1, or 83.6 cm−1. At room temperature (25 °C, or 298.15 K) 1 kJ·mol−1 is approximately equal to 0.4034 k B T {\displaystyle k_{B}T}Katrin Borchert (641 words) [view diff] exact match in snippet view article find links to article
500 m for Germany) and two bronzes (both Australia, 1996: K-2 500 m, 2000: K-1 500 m). During her career, she has represented four countries: East GermanyHouseholder transformation (3,241 words) [view diff] no match in snippet view article find links to article
− sgn ( a k + 1 , k k ) ∑ j = k + 1 n ( a j k k ) 2 r = 1 2 ( α 2 − a k + 1 , k k α ) v 1 k = v 2 k = ⋯ = v k k = 0 v k + 1 k = a k + 1 , k k − α 2Integral transform (1,278 words) [view diff] no match in snippet view article find links to article
kernel K − 1 ( u , t ) {\displaystyle K^{-1}(u,t)} which (roughly speaking) yields an inverse transform: f ( t ) = ∫ u 1 u 2 ( T f ) ( u ) K − 1 ( u ,N-sphere (7,312 words) [view diff] exact match in snippet view article find links to article
r 2 + ∑ k = 1 n − 1 r 2 ( ∏ m = 1 k − 1 sin 2 ( φ m ) ) d φ k 2 {\displaystyle ds^{2}=dr^{2}+\sum _{k=1}^{n-1}r^{2}\left(\prod _{m=1}^{k-1}\sin ^{2}\left(\varphiEast Germany at the 1976 Summer Olympics (932 words) [view diff] exact match in snippet view article find links to article
Helm Canoeing men's K-1 1000 m Gold Joachim Mattern Bernd Olbricht Canoeing men's K-2 500 m Gold Carola Zirzow Canoeing women's K-1 500 m Gold Klaus-JürgenDeterminant (13,785 words) [view diff] no match in snippet view article find links to article
c n − m = − 1 m ∑ k = 1 m c n − m + k tr ( A k ) ( 1 ≤ m ≤ n ) . {\displaystyle c_{n}=1;~~~c_{n-m}=-{\frac {1}{m}}\sum _{k=1}^{m}c_{n-m+k}\operatornameOreste Perri (200 words) [view diff] exact match in snippet view article find links to article
Championships with four golds (K-1 1000 m: 1975 (tied with Poland's Grzegorz Śledziewski, K-1 10000 m: 1974, 1975, 1977) and two bronzes (K-1 1000 m: 1974, 1977)Laurent series (2,675 words) [view diff] exact match in snippet view article find links to article
) n − k − 1 d z = ∮ γ ∑ n = − ∞ ∞ b n ( z − c ) n − k − 1 d z . {\displaystyle \oint _{\gamma }\,\sum _{n=-\infty }^{\infty }a_{n}(z-c)^{n-k-1}\,dz=\ointNicole Reinhardt (276 words) [view diff] exact match in snippet view article find links to article
ICF Canoe Sprint World Championships with eight golds (K-1 500 m: 2005, 2011, K-2 200 m: 2007, K-1 4 × 200 m: 2009, 2010, 2011, K-2 500 m: 2007, K-4 200Pentax K-1 (522 words) [view diff] exact match in snippet view article find links to article
The Pentax K-1 is the first production Pentax full-frame digital SLR camera. As the flagship model of the Pentax K-mount system, it includes several newBessel function (12,179 words) [view diff] no match in snippet view article find links to article
π ∑ k = 0 n − 1 ( n − k − 1 ) ! k ! ( z 2 4 ) k + 2 π J n ( z ) ln z 2 − ( z 2 ) n π ∑ k = 0 ∞ ( ψ ( k + 1 ) + ψ ( n + k + 1 ) ) ( − z 2 4 ) k k ! (Fock state (5,644 words) [view diff] no match in snippet view article find links to article
| n k 1 , n k 2 . . . ⟩ = ( b k 1 † ) n k 1 n k 1 ! ( b k 2 † ) n k 2 n k 2 ! . . . | 0 k 1 , 0 k 2 , . . . ⟩ {\displaystyle |n_{\mathbf {k} _{1}},n_{\mathbfSimon Dickie (722 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanMatrix-exponential distribution (379 words) [view diff] no match in snippet view article find links to article
given by E ( X k ) = ( − 1 ) k + 1 k ! α T − ( k + 1 ) s . {\displaystyle \operatorname {E} (X^{k})=(-1)^{k+1}k!\mathbf {\alpha } T^{-(k+1)}\mathbf {s}Deficient number (560 words) [view diff] exact match in snippet view article find links to article
, p k − 1 {\displaystyle 1,p,p^{2},\dots ,p^{k-1}} which sum to p k − 1 p − 1 {\displaystyle {\frac {p^{k}-1}{p-1}}} , which is at most p k − 1 {\displaystyleCoxeter group (3,763 words) [view diff] no match in snippet view article find links to article
a 3-cycle : ( k k + 1 ) ⋅ ( k + 1 k + 2 ) = ( k k + 2 k + 1 ) {\displaystyle (k~~k+1)\cdot (k+1~~k+2)=(k~~k+2~~k+1)} . Therefore S n +Polynomial interpolation (9,051 words) [view diff] no match in snippet view article find links to article
C ( u − k , 1 ) Δ y k − 1 + C ( u − k + 1 , 2 ) Δ 2 y k − 2 + C ( u − k + 2 , 3 ) Δ 3 y k − 3 + ⋯ = y k + ( u − k ) Δ y k − 1 + ( u − k + 1 ) ( u − kHamiltonian mechanics (9,287 words) [view diff] no match in snippet view article find links to article
2 ∑ k = 1 N ( m k r ˙ k ( q , q ˙ ) ⋅ r ˙ k ( q , q ˙ ) ) {\displaystyle T({\boldsymbol {q}},{\boldsymbol {\dot {q}}})={\frac {1}{2}}\sum _{k=1}^{N}{\bigglB+ tree (3,417 words) [view diff] no match in snippet view article find links to article
K + 1 ) / 2 ⌉ {\displaystyle \lceil (K+1)/2\rceil } items new node has ⌊ ( K + 1 ) / 2 ⌋ {\displaystyle \lfloor (K+1)/2\rfloor } items Copy ⌈ ( K + 1Big O notation (8,444 words) [view diff] no match in snippet view article find links to article
below (with constant factor k 1 {\displaystyle k_{1}} ) ∃ k 1 > 0 ∃ k 2 > 0 ∃ n 0 ∀ n > n 0 : {\displaystyle \exists k_{1}>0\,\exists k_{2}>0\,\existsAcid dissociation constant (11,513 words) [view diff] no match in snippet view article find links to article
A−, so [ H + ] 2 = K 1 K 2 {\displaystyle [{\ce {H+}}]^{2}=K_{1}K_{2}} Therefore, taking cologarithms, the pH is given by p I = p K 1 + p K 2 2 {\displaystyleBanach space (17,005 words) [view diff] no match in snippet view article find links to article
proved that if c − 2 ∑ k = 1 n ‖ x k ‖ 2 ≤ Ave ± ‖ ∑ k = 1 n ± x k ‖ 2 ≤ c 2 ∑ k = 1 n ‖ x k ‖ 2 {\displaystyle c^{-2}\sum _{k=1}^{n}\|x_{k}\|^{2}\leqList of mathematical constants (3,561 words) [view diff] no match in snippet view article find links to article
root of x k + 1 = 2 k + 1 ( x − 1 ) , β k = 2 − α k k + 1 − k α k {\displaystyle x^{k+1}=2^{k+1}(x-1),\beta _{k}={\frac {2-\alpha _{k}}{k+1-k\alpha _{k}}}}Householder transformation (3,241 words) [view diff] no match in snippet view article find links to article
− sgn ( a k + 1 , k k ) ∑ j = k + 1 n ( a j k k ) 2 r = 1 2 ( α 2 − a k + 1 , k k α ) v 1 k = v 2 k = ⋯ = v k k = 0 v k + 1 k = a k + 1 , k k − α 2Decimal representation (1,815 words) [view diff] exact match in snippet view article find links to article
traditionally written with a single separator: r = b k b k − 1 ⋯ b 0 . a 1 a 2 ⋯ {\displaystyle r=b_{k}b_{k-1}\cdots b_{0}.a_{1}a_{2}\cdots } Here . is the decimalPolylogarithm (10,139 words) [view diff] no match in snippet view article find links to article
series in s: Li s ( z ) = ∑ k = 1 ∞ z k k s = z + z 2 2 s + z 3 3 s + ⋯ {\displaystyle \operatorname {Li} _{s}(z)=\sum _{k=1}^{\infty }{z^{k} \over k^{s}}=z+{z^{2}Saitama Super Arena (1,366 words) [view diff] exact match in snippet view article find links to article
2008 featured Dream and K-1 fights Dynamite!! 2009 featured fights by Dream, Sengoku and K-1 Dynamite!! 2010 featured Dream and K-1 fights. Fight For Japan:Appell's equation of motion (1,565 words) [view diff] no match in snippet view article find links to article
the particle accelerations squared, S = 1 2 ∑ k = 1 N m k a k 2 , {\displaystyle S={\frac {1}{2}}\sum _{k=1}^{N}m_{k}\mathbf {a} _{k}^{2}\,,} where thePythagorean theorem (12,704 words) [view diff] no match in snippet view article find links to article
equation ‖ ∑ k = 1 n v k ‖ 2 = ∑ k = 1 n ‖ v k ‖ 2 {\displaystyle {\biggl \|}\sum _{k=1}^{n}\mathbf {v} _{k}{\biggr \|}^{2}=\sum _{k=1}^{n}\|\mathbfCaroline Evers-Swindell (555 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanAbsolute convergence (5,193 words) [view diff] no match in snippet view article find links to article
have 0 ≤ ∑ k = 1 n ( a k + | a k | ) ≤ ∑ k = 1 n 2 | a k | . {\displaystyle 0\leq \sum _{k=1}^{n}(a_{k}+\left|a_{k}\right|)\leq \sum _{k=1}^{n}2\left|a_{k}\right|Polar decomposition (4,254 words) [view diff] no match in snippet view article find links to article
= ‖ U k − 1 ‖ 1 ‖ U k − 1 ‖ ∞ ‖ U k ‖ 1 ‖ U k ‖ ∞ 4 {\displaystyle \gamma _{k}={\sqrt[{4}]{\frac {\left\|U_{k}^{-1}\right\|_{1}\left\|U_{k}^{-1}\right\|_{\inftyCompressor (6,856 words) [view diff] exact match in snippet view article find links to article
− T 1 ) k − 1 = k R T 1 k − 1 [ ( P 2 P 1 ) ( k − 1 ) / k − 1 ] {\displaystyle W_{comp,in}={\frac {kR(T_{2}-T_{1})}{k-1}}={\frac {kRT_{1}}{k-1}}\left[\left({\fracDirichlet process (4,861 words) [view diff] no match in snippet view article find links to article
k = 1 ∞ β k δ x k ( x ) {\displaystyle f(x)=\sum _{k=1}^{\infty }\beta _{k}\delta _{x_{k}}(x)} , where { x k } k = 1 ∞ {\displaystyle \{x_{k}\}_{k=1}^{\inftyMatrix-exponential distribution (379 words) [view diff] no match in snippet view article find links to article
given by E ( X k ) = ( − 1 ) k + 1 k ! α T − ( k + 1 ) s . {\displaystyle \operatorname {E} (X^{k})=(-1)^{k+1}k!\mathbf {\alpha } T^{-(k+1)}\mathbf {s}Georgina Evers-Swindell (552 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanTogo at the 2008 Summer Olympics (164 words) [view diff] exact match in snippet view article find links to article
in Beijing, China from August 8 to August 24, 2008. At the men's slalom K-1 event, Benjamin Boukpeti won a bronze medal in canoeing, the first OlympicDanyon Loader (359 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanArithmetic coding (5,380 words) [view diff] no match in snippet view article find links to article
the computation of the product ∏ k = 1 n f k = ∏ k = 1 A f k f k . {\displaystyle \prod _{k=1}^{n}f_{k}=\prod _{k=1}^{A}f_{k}^{f_{k}}.} Applying log2Discrete uniform distribution (772 words) [view diff] no match in snippet view article find links to article
k, the sample size, is N ^ = k + 1 k m − 1 = m + m k − 1 {\displaystyle {\hat {N}}={\frac {k+1}{k}}m-1=m+{\frac {m}{k}}-1} . This can be seen as a veryPentax K-1 (522 words) [view diff] exact match in snippet view article find links to article
The Pentax K-1 is the first production Pentax full-frame digital SLR camera. As the flagship model of the Pentax K-mount system, it includes several newVladimir Parfenovich (446 words) [view diff] exact match in snippet view article find links to article
he entered: K-1 500 m, K-2 500 m and K-2 1000 m. He also won twelve medals at the ICF Canoe Sprint World Championships, with nine golds (K-1 500 m: 1979Fock state (5,644 words) [view diff] no match in snippet view article find links to article
| n k 1 , n k 2 . . . ⟩ = ( b k 1 † ) n k 1 n k 1 ! ( b k 2 † ) n k 2 n k 2 ! . . . | 0 k 1 , 0 k 2 , . . . ⟩ {\displaystyle |n_{\mathbf {k} _{1}},n_{\mathbfVandermonde matrix (5,263 words) [view diff] no match in snippet view article find links to article
v o l ( F ) = 1 k ! ∏ 1 ≤ m < n ≤ k + 1 ( t i n − t i m ) . {\displaystyle \mathrm {nvol} (F)={\frac {1}{k!}}\prod _{1\leq m<n\leq k+1}{(t_{i_{n}}-t_{i_{m}})}Operation K (1,326 words) [view diff] no match in snippet view article find links to article
Operation K (K作戦, Kē-Sakusen) was a Japanese naval operation in World War II, intended as reconnaissance of Pearl Harbor and disruption of repair and salvageAnalysis of variance (7,645 words) [view diff] no match in snippet view article find links to article
{\displaystyle b} . Thus, v k = [ g 1 ( Z k , 1 ) , g 2 ( Z k , 2 ) , … , g B ( Z k , B ) ] {\displaystyle v_{k}=[g_{1}(Z_{k,1}),g_{2}(Z_{k,2}),\ldots ,g_{B}(Z_{kBeta negative binomial distribution (1,541 words) [view diff] no match in snippet view article find links to article
+ r − 1 k ) ( 1 − q ) k q r ⋅ q α − 1 ( 1 − q ) β − 1 B ( α , β ) d q = 1 B ( α , β ) ( k + r − 1 k ) ∫ 0 1 q α + r − 1 ( 1 − q ) β + k − 1 d q {\displaystyleHadamard matrix (3,698 words) [view diff] exact match in snippet view article find links to article
k − 1 H 2 k − 1 H 2 k − 1 − H 2 k − 1 ] = H 2 ⊗ H 2 k − 1 , {\displaystyle H_{2^{k}}={\begin{bmatrix}H_{2^{k-1}}&H_{2^{k-1}}\\H_{2^{k-1}}&-H_{2^{k-1Lars Glassér (305 words) [view diff] exact match in snippet view article find links to article
five golds (K-1 4 x 500 m: 1948, 1950, 1954; K-2 500 m: 1950, K-2 1000 m: 1950) and one silver (K-1 500 m: 1948). Note that the K-1 500 m, K-1 4 x 500 mBijective numeration (2,021 words) [view diff] exact match in snippet view article find links to article
− 1 d k − 1 d k − 1 = d k − 1 ¯ {\displaystyle \ldots d_{k-1}d_{k-1}d_{k-1}={\overline {d_{k-1}}}} . This is because the Euler summation g ( d k − 1 ¯Géza Csapó (309 words) [view diff] exact match in snippet view article find links to article
with six golds (K-1 500 m: 1973, 1975; K-1 1000 m: 1973, 1974; K-1 4 x 500 m: 1971, K-2 10000 m: 1973), two silvers (K-1 500 m: 1973, K-1 4 x 500 m: 1973)Heat capacity (2,775 words) [view diff] no match in snippet view article find links to article
The SI unit for heat capacity of an object is joule per kelvin (J/K or J⋅K−1). Since an increment of temperature of one degree Celsius is the same asMoran process (4,769 words) [view diff] no match in snippet view article find links to article
k 1 j y 2 j = y 1 j − δ 1 j q 1 = k 1 j − δ 1 j q 1 y 3 j = k 1 j − δ 1 j q 1 − δ 2 j q 2 ⋮ y i j = k 1 j − ∑ r = 1 i − 1 δ r j q r = { k 1 j j ≥ i kShell integration (549 words) [view diff] no match in snippet view article find links to article
rectangle, its made by obtaining a cylinder of radius a + ( k + 1 ) Δ x {\displaystyle a+(k+1)\Delta x} with height f ( a + k Δ x ) {\displaystyle f(a+k\DeltaInverse trigonometric functions (10,605 words) [view diff] no match in snippet view article find links to article
2 ∑ n = 0 ∞ ∏ k = 1 n 2 k z 2 ( 2 k + 1 ) ( 1 + z 2 ) . {\displaystyle \arctan(z)={\frac {z}{1+z^{2}}}\sum _{n=0}^{\infty }\prod _{k=1}^{n}{\fracPerfect number (5,168 words) [view diff] exact match in snippet view article find links to article
is at most k − 1 2 . {\displaystyle {\frac {k-1}{2}}.} At least one of the prime powers dividing N exceeds 1062. N < 2 ( 4 k + 1 − 2 k + 1 ) {\displaystyleGrzegorz Śledziewski (201 words) [view diff] exact match in snippet view article find links to article
with three golds (K-1 1000 m: 1971, 1975 (tied with Italy's Oreste Perri); K-2 500 m: 1974), five silvers (K-1 500 m: 1970, 1977; K-1 1000 m: 1973, 1974;Grant Bramwell (231 words) [view diff] exact match in snippet view article find links to article
with Alan Thompson, Ian Ferguson and Paul MacDonald. Bramwell also won a K-1 10000 m bronze at the 1985 ICF Canoe Sprint World Championships in MechelenAbsolute magnitude (5,779 words) [view diff] no match in snippet view article find links to article
approximated as m 1 = M 1 + 2.5 ⋅ K 1 log 10 ( d B S d 0 ) + 5 log 10 ( d B O d 0 ) {\displaystyle m_{1}=M_{1}+2.5\cdot K_{1}\log _{10}{\left({\fracRegular expression (8,860 words) [view diff] exact match in snippet view article find links to article
) ( a ∣ b ) ⋯ ( a ∣ b ) ⏟ k − 1 times . {\displaystyle (a\mid b)^{*}a\underbrace {(a\mid b)(a\mid b)\cdots (a\mid b)} _{k-1{\text{ times}}}.\,} On theLjung–Box test (870 words) [view diff] no match in snippet view article find links to article
correlation. The test statistic is: Q = n ( n + 2 ) ∑ k = 1 h ρ ^ k 2 n − k {\displaystyle Q=n(n+2)\sum _{k=1}^{h}{\frac {{\hat {\rho }}_{k}^{2}}{n-k}}} whereGrassmannian (8,401 words) [view diff] exact match in snippet view article find links to article
1 k + 1 ( − 1 ) ℓ w i 1 , … , i k − 1 , j l w j 1 , … , j l ^ , … j k + 1 = 0 , {\displaystyle \sum _{l=1}^{k+1}(-1)^{\ell }w_{i_{1},\dots ,i_{k-1},j_{l}}w_{j_{1}