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Find link is a tool written by Edward Betts.searching for K-1 505 found (14416 total)
alternate case: k-1
Standard deviation
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k − 1 + k − 1 k ( x k − A k − 1 ) 2 = Q k − 1 + ( x k − A k − 1 ) ( x k − A k ) {\displaystyle {\begin{aligned}Q_{0}&=0\\Q_{k}&=Q_{k-1}+{\frac {k-1Fibonacci sequence (13,044 words) [view diff] no match in snippet view article find links to article
k = 1 ∞ q k 1 − q k , {\displaystyle \textstyle L(q):=\sum _{k=1}^{\infty }{\frac {q^{k}}{1-q^{k}}},} since 1 F 2 k = 5 ( ψ 2 k 1 − ψ 2 k − ψ 4 k 1 −Poisson distribution (11,203 words) [view diff] no match in snippet view article find links to article
distribution is Pr ( X 1 = k 1 , X 2 = k 2 ) = exp ( − λ 1 − λ 2 − λ 3 ) λ 1 k 1 k 1 ! λ 2 k 2 k 2 ! ∑ k = 0 min ( k 1 , k 2 ) ( k 1 k ) ( k 2 k ) k ! ( λBinomial distribution (7,554 words) [view diff] no match in snippet view article find links to article
calculating f ( k + 1 , n , p ) f ( k , n , p ) = ( n − k ) p ( k + 1 ) ( 1 − p ) {\displaystyle {\frac {f(k+1,n,p)}{f(k,n,p)}}={\frac {(n-k)p}{(k+1)(1-p)}}}P-adic number (7,711 words) [view diff] no match in snippet view article find links to article
i p i = a k p k + a k + 1 p k + 1 + a k + 2 p k + 2 + ⋯ {\displaystyle s=\sum _{i=k}^{\infty }a_{i}p^{i}=a_{k}p^{k}+a_{k+1}p^{k+1}+a_{k+2}p^{k+2}+\cdotsKalman filter (20,932 words) [view diff] no match in snippet view article find links to article
k − 1 ] T Y k − 1 ∣ k − 1 F k − 1 C k = M k [ M k + Q k − 1 ] − 1 L k = I − C k Y k ∣ k − 1 = L k M k + C k Q k − 1 C k T y ^ k ∣ k − 1 = L k [ F k −Permutation (11,667 words) [view diff] exact match in snippet view article find links to article
λ k − 1 ( p k − 1 k ) λ k − 1 ( p k − 2 k ) λ k − 1 ⋯ λ k − 1 ( p 1 k ) λ k − 1 {\displaystyle \lambda _{k}=\lambda _{k-1}(p_{k-1}k)\lambda _{k-1}(p_{k-2}k)\lambdaBinomial coefficient (10,733 words) [view diff] exact match in snippet view article find links to article
× ⋯ × ( n − k + 1 ) k × ( k − 1 ) × ⋯ × 1 , {\displaystyle {\binom {n}{k}}={\frac {n\times (n-1)\times \cdots \times (n-k+1)}{k\times (k-1)\times \cdotsMichaelis–Menten kinetics (6,227 words) [view diff] no match in snippet view article find links to article
K_{\mathrm {m} }} is equal to k + 2 / k + 1 {\displaystyle k_{+2}/k_{+1}} or to k − 1 / k + 1 {\displaystyle k_{-1}/k_{+1}} or to something else. G. E. BriggsList of trigonometric identities (12,421 words) [view diff] exact match in snippet view article find links to article
identity can be proved: ∏ k = 1 n sin ( 2 k − 1 ) π 4 n = ∏ k = 1 n cos ( 2 k − 1 ) π 4 n = 2 2 n {\displaystyle \prod _{k=1}^{n}\sin {\frac {\left(2k-1\right)\piLogistic regression (20,641 words) [view diff] no match in snippet view article find links to article
case of a perfect prediction (i.e., when p k = 1 {\displaystyle p_{k}=1} and y k = 1 {\displaystyle y_{k}=1} , or p k = 0 {\displaystyle p_{k}=0} and yBinomial theorem (6,735 words) [view diff] exact match in snippet view article find links to article
( n − k + 1 ) k ( k − 1 ) ( k − 2 ) ⋯ 2 ⋅ 1 . {\displaystyle {\binom {n}{k}}={\frac {n!}{k!\,(n-k)!}}={\frac {n(n-1)(n-2)\cdots (n-k+1)}{k(k-1)(k-2)\cdotsBoltzmann constant (2,946 words) [view diff] no match in snippet view article find links to article
constants defining the International System of Units, the SI, with k = 1.380649×10−23 J K−1. The Boltzmann constant is a proportionality constant between theSpecific heat capacity (8,537 words) [view diff] no match in snippet view article find links to article
among common substances, about 4184 J⋅kg−1⋅K−1 at 20 °C; but that of ice, just below 0 °C, is only 2093 J⋅kg−1⋅K−1. The specific heat capacities of iron,Gas constant (1,997 words) [view diff] no match in snippet view article find links to article
{\displaystyle R=N_{\rm {A}}k} = 6.02214076×1023 mol−1 × 1.380649×10−23 J⋅K−1 = 8.31446261815324 J⋅K−1⋅mol−1 Since the 2019 revision of the SI, both NA and k are definedNatural logarithm (5,882 words) [view diff] exact match in snippet view article find links to article
( 1 + x ) = ∑ k = 1 ∞ ( − 1 ) k − 1 k x k = x − x 2 2 + x 3 3 − ⋯ , {\displaystyle \ln(1+x)=\sum _{k=1}^{\infty }{\frac {(-1)^{k-1}}{k}}x^{k}=x-{\fracNACA airfoil (2,605 words) [view diff] no match in snippet view article find links to article
0.3 - the value of r {\displaystyle r} , k 1 {\displaystyle k_{1}} and k 2 / k 1 {\displaystyle k_{2}/k_{1}} must be linearly scaled for a differentMoment of inertia (17,301 words) [view diff] no match in snippet view article find links to article
∑ k = 1 N m k ( y k 2 + z k 2 ) − ∑ k = 1 N m k x k y k − ∑ k = 1 N m k x k z k − ∑ k = 1 N m k x k y k ∑ k = 1 N m k ( x k 2 + z k 2 ) − ∑ k = 1 N mMathematical induction (6,914 words) [view diff] no match in snippet view article find links to article
+k)+(k+1)={\frac {k(k+1)}{2}}+(k+1).} Algebraically, the right hand side simplifies as: k ( k + 1 ) 2 + ( k + 1 ) = k ( k + 1 ) + 2 ( k + 1 ) 2 = ( k + 1 )Finite element method (7,946 words) [view diff] no match in snippet view article find links to article
e., v k ( x ) = { x − x k − 1 x k − x k − 1 if x ∈ [ x k − 1 , x k ] , x k + 1 − x x k + 1 − x k if x ∈ [ x k , x k + 1 ] , 0 otherwise , {\displaystyleTaylor's theorem (9,632 words) [view diff] no match in snippet view article find links to article
| x − a | k + 1 ( k + 1 ) ! ≤ M r k + 1 ( k + 1 ) ! {\displaystyle |R_{k}(x)|\leq M{\frac {|x-a|^{k+1}}{(k+1)!}}\leq M{\frac {r^{k+1}}{(k+1)!}}} for allTaylor series (8,229 words) [view diff] no match in snippet view article find links to article
α n ) = ∏ k = 1 n α − k + 1 k = α ( α − 1 ) ⋯ ( α − n + 1 ) n ! . {\displaystyle {\binom {\alpha }{n}}=\prod _{k=1}^{n}{\frac {\alpha -k+1}{k}}={\fracGamma function (13,524 words) [view diff] no match in snippet view article find links to article
x 2 ) x − 1 ∏ k = 1 n k + 1 k + x {\displaystyle x!=\lim _{n\to \infty }\left(n+1+{\frac {x}{2}}\right)^{x-1}\prod _{k=1}^{n}{\frac {k+1}{k+x}}} whichEnzyme kinetics (9,539 words) [view diff] no match in snippet view article find links to article
M S = ( k − 1 + k 2 ) / k 1 {\displaystyle K_{M}^{S}=(k_{-1}+k_{2})/k_{1}} and K M P = ( k − 1 + k 2 ) / k − 2 {\displaystyle K_{M}^{P}=(k_{-1}+k_{2})/k_{-2}}Euler's totient function (6,519 words) [view diff] exact match in snippet view article find links to article
and k ≥ 1, then φ ( p k ) = p k − p k − 1 = p k − 1 ( p − 1 ) = p k ( 1 − 1 p ) . {\displaystyle \varphi \left(p^{k}\right)=p^{k}-p^{k-1}=p^{k-1Weibull distribution (5,823 words) [view diff] exact match in snippet view article find links to article
k − 1 e − ( x / λ ) k , x ≥ 0 , 0 , x < 0 , {\displaystyle f(x;\lambda ,k)={\begin{cases}{\frac {k}{\lambda }}\left({\frac {x}{\lambda }}\right)^{k-1}e^{-(x/\lambdaTriangular number (3,543 words) [view diff] no match in snippet view article find links to article
k = 1 n k = 1 + 2 + ⋯ + n = n 2 + n ( n + 1 ) 2 = n ( n + 1 ) 2 = ( n + 1 2 ) {\displaystyle \displaystyle {\begin{aligned}T_{n}&=\sum _{k=1}^{n}k=1+2+\dotsbEigenvalues and eigenvectors (13,582 words) [view diff] exact match in snippet view article find links to article
d t k + a k − 1 d k − 1 x d t k − 1 + ⋯ + a 1 d x d t + a 0 x = 0. {\displaystyle {\frac {d^{k}x}{dt^{k}}}+a_{k-1}{\frac {d^{k-1}x}{dt^{k-1}}}+\cdotsPascal's triangle (7,606 words) [view diff] no match in snippet view article find links to article
∑ k = 1 n + 1 a k − 1 x k + ∑ k = 0 n a k x k = ∑ k = 1 n a k − 1 x k + a n x n + 1 + a 0 x 0 + ∑ k = 1 n a k x k = a 0 x 0 + ∑ k = 1 n ( a k − 1 + aGeometric distribution (5,151 words) [view diff] exact match in snippet view article find links to article
trial is the first success is Pr ( X = k ) = ( 1 − p ) k − 1 p {\displaystyle \Pr(X=k)=(1-p)^{k-1}p} for k = 1 , 2 , 3 , 4 , … {\displaystyle k=1,2,3Acid (5,957 words) [view diff] no match in snippet view article find links to article
[ H + ] 2 + [ H + ] K 1 + K 1 K 2 = [ H 2 A ] [ H 2 A ] + [ H A − ] + [ A 2 − ] α HA − = [ H + ] K 1 [ H + ] 2 + [ H + ] K 1 + K 1 K 2 = [ HA − ] [ H 2Summation (4,576 words) [view diff] no match in snippet view article find links to article
{\displaystyle p>1} ∑ k = 1 n k p = n p + 1 p + 1 + 1 2 n p + ∑ k = 2 p ( p k ) B k p − k + 1 n p − k + 1 , {\displaystyle \sum _{k=1}^{n}k^{p}={\fracQuantization (signal processing) (6,359 words) [view diff] no match in snippet view article
values of { b k } k = 1 M − 1 {\displaystyle \{b_{k}\}_{k=1}^{M-1}} , { c k } k = 1 M {\displaystyle \{c_{k}\}_{k=1}^{M}} and { y k } k = 1 M {\displaystyleGini coefficient (10,898 words) [view diff] exact match in snippet view article find links to article
trapezoids and: G 1 = 1 − ∑ k = 1 n ( X k − X k − 1 ) ( Y k + Y k − 1 ) {\displaystyle G_{1}=1-\sum _{k=1}^{n}(X_{k}-X_{k-1})(Y_{k}+Y_{k-1})} is the resultingNegative binomial distribution (8,217 words) [view diff] no match in snippet view article find links to article
binomial": ( k + r − 1 ) ⋯ ( r ) k ! = ( − 1 ) k ( − r ) ( − r − 1 ) ( − r − 2 ) ⋯ ( − r − k + 1 ) ⏞ k factors k ! = ( − 1 ) k ( − r − k ) . {\displaystyleBernoulli distribution (2,196 words) [view diff] no match in snippet view article find links to article
) = p k ( 1 − p ) 1 − k for k ∈ { 0 , 1 } {\displaystyle f(k;p)=p^{k}(1-p)^{1-k}\quad {\text{for }}k\in \{0,1\}} or as f ( k ; p ) = p k + ( 1 − p )Quadrilateral (6,989 words) [view diff] no match in snippet view article find links to article
q: K = 1 2 ( m + n + p ) ( m + n − p ) ( m + n + q ) ( m + n − q ) , {\displaystyle K={\tfrac {1}{2}}{\sqrt {(m+n+p)(m+n-p)(m+n+q)(m+n-q)}},} K = 1 2 pFeynman diagram (15,967 words) [view diff] no match in snippet view article find links to article
k 1 ) ϕ ( k 2 ) ϕ ( k 3 ) ϕ ( k 4 ) ⟩ = δ ( k 1 − k 2 ) k 1 2 δ ( k 3 − k 4 ) k 3 2 + δ ( k 1 − k 3 ) k 3 2 δ ( k 2 − k 4 ) k 2 2 + δ ( k 1 − k 4 ) kSimplex (7,866 words) [view diff] case mismatch in snippet view article find links to article
k-dimensional polytope that is the convex hull of its k + 1 vertices. More formally, suppose the k + 1 points u 0 , … , u k {\displaystyle u_{0},\dots ,u_{k}}Combination (3,806 words) [view diff] exact match in snippet view article find links to article
n k ) = n ( n − 1 ) ⋯ ( n − k + 1 ) k ( k − 1 ) ⋯ 1 , {\displaystyle {\binom {n}{k}}={\frac {n(n-1)\dotsb (n-k+1)}{k(k-1)\dotsb 1}},} which can be writtenPerturbation theory (quantum mechanics) (15,990 words) [view diff] no match in snippet view article
k 1 n E n k 1 | k 1 ( 0 ) ⟩ | n ( 2 ) ⟩ = ( V k 1 k 2 V k 2 n E n k 1 E n k 2 − V n n V k 1 n E n k 1 2 ) | k 1 ( 0 ) ⟩ − 1 2 V n k 1 V k 1 n E k 1 nLagrangian mechanics (14,691 words) [view diff] no match in snippet view article find links to article
− V , {\displaystyle L=T-V,} where T = 1 2 ∑ k = 1 N m k v k 2 {\displaystyle T={\frac {1}{2}}\sum _{k=1}^{N}m_{k}v_{k}^{2}} is the total kinetic energyLagrangian mechanics (14,691 words) [view diff] no match in snippet view article find links to article
− V , {\displaystyle L=T-V,} where T = 1 2 ∑ k = 1 N m k v k 2 {\displaystyle T={\frac {1}{2}}\sum _{k=1}^{N}m_{k}v_{k}^{2}} is the total kinetic energyEuler's constant (9,582 words) [view diff] no match in snippet view article find links to article
n + ∑ k = 1 n 1 k ) = ∫ 1 ∞ ( − 1 x + 1 ⌊ x ⌋ ) d x . {\displaystyle {\begin{aligned}\gamma &=\lim _{n\to \infty }\left(-\log n+\sum _{k=1}^{n}{\fracDiscrete cosine transform (11,983 words) [view diff] no match in snippet view article find links to article
around k = − 1 / 2 {\displaystyle k=-1/2} and even around k = N − 1 / 2. {\displaystyle k=N-1/2.} X k = ∑ n = 0 N − 1 x n cos [ π N ( n + 1 2 ) ( k + 1 2Central limit theorem (9,169 words) [view diff] exact match in snippet view article find links to article
∑ k = 1 n E [ ( M k − M k − 1 ) 2 ∣ M 1 , … , M k − 1 ] → 1 {\displaystyle {\frac {1}{n}}\sum _{k=1}^{n}\operatorname {E} \left[\left(M_{k}-M_{k-1}\right)^{2}\midDirichlet distribution (6,666 words) [view diff] exact match in snippet view article find links to article
_{i}-1}} where { x k } k = 1 k = K {\displaystyle \{x_{k}\}_{k=1}^{k=K}} belong to the standard K − 1 {\displaystyle K-1} simplex, or in other words:Integer (3,935 words) [view diff] no match in snippet view article find links to article
= ⋯ = [ ( k , k ) ] 1 = [ ( 1 , 0 ) ] = [ ( 2 , 1 ) ] = ⋯ = [ ( k + 1 , k ) ] − 1 = [ ( 0 , 1 ) ] = [ ( 1 , 2 ) ] = ⋯ = [ ( k , k + 1 ) ] 2 = [ ( 2Bernoulli number (13,028 words) [view diff] no match in snippet view article find links to article
0 n ( n k ) 2 n − k + 1 n − k + 1 B k ( 1 ) = 2 n {\displaystyle -1+\sum _{k=0}^{n}{\binom {n}{k}}{\frac {2^{n-k+1}}{n-k+1}}B_{k}(1)=2^{n}} and − 1 +Real number (8,223 words) [view diff] exact match in snippet view article find links to article
infinite series x = b k 10 k + b k − 1 10 k − 1 + ⋯ + b 0 + a 1 10 + a 2 10 2 + ⋯ . {\displaystyle x=b_{k}10^{k}+b_{k-1}10^{k-1}+\cdots +b_{0}+{\frac {a_{1}}{10}}+{\fracTranscendental number (6,738 words) [view diff] no match in snippet view article find links to article
sufficient to prove that k + 1 {\displaystyle k+1} does not divide P {\displaystyle P} . To that end, let k + 1 {\displaystyle k+1} be any prime larger thanRiemann zeta function (10,382 words) [view diff] no match in snippet view article find links to article
k 1 > k 2 > ⋯ > k n > 0 k 1 − s 1 k 2 − s 2 ⋯ k n − s n . {\displaystyle \zeta (s_{1},s_{2},\ldots ,s_{n})=\sum _{k_{1}>k_{2}>\cdots >k_{n}>0}{k_{1Sequence (6,158 words) [view diff] exact match in snippet view article find links to article
a_{k}=k^{2}} ( a 2 k − 1 ) k = 1 ∞ , a k = k 2 {\displaystyle {(a_{2k-1})}_{k=1}^{\infty },\qquad a_{k}=k^{2}} ( a k ) k = 1 ∞ , a k = ( 2 k − 1 ) 2 {\displaystyleChi-squared distribution (6,811 words) [view diff] no match in snippet view article find links to article
{\displaystyle k} with a width k 1 / 2 + α {\displaystyle k^{1/2+\alpha }} : P r ( ‖ Z ‖ 2 ∈ [ k − 2 k 1 / 2 + α , k + 2 k 1 / 2 + α + 2 k α ] ) ≥ 1 − eLisa Carrington (1,930 words) [view diff] no match in snippet view article find links to article
and one bronze medal. She won three consecutive gold medals in the Women's K‑1 200 metres at the 2012 Summer Olympics, 2016 Summer Olympics and 2020 SummerRate equation (7,576 words) [view diff] no match in snippet view article find links to article
0 1 k 1 + k − 1 ( k − 1 + k 1 e − ( k 1 + k − 1 ) t ) + [ P ] 0 k − 1 k 1 + k − 1 ( 1 − e − ( k 1 + k − 1 ) t ) [ P ] = [ A ] 0 k 1 k 1 + k − 1 ( 1 −Logarithm (11,635 words) [view diff] no match in snippet view article find links to article
1 + 1 2 + 1 3 + ⋯ + 1 n = ∑ k = 1 n 1 k , {\displaystyle 1+{\frac {1}{2}}+{\frac {1}{3}}+\cdots +{\frac {1}{n}}=\sum _{k=1}^{n}{\frac {1}{k}},} is calledAdam van Koeverden (1,539 words) [view diff] exact match in snippet view article find links to article
is an Olympic gold medallist in the K-1 500m category (2004) and a two-time world champion in K-1 500 (2007) and K-1 1000 (2011), winning four Olympic andMoving average (3,168 words) [view diff] no match in snippet view article find links to article
k = p n − k + 1 + p n − k + 2 + ⋯ + p n k = 1 k ∑ i = n − k + 1 n p i {\displaystyle {\begin{aligned}{\textit {SMA}}_{k}&={\frac {p_{n-k+1}+p_{n-k+2}+\cdotsList of Olympic medalists in canoeing (men) (16 words) [view diff] no match in snippet view article
This is the complete list of men's Olympic medalists in canoeing. International Olympic Committee results databaseICF Canoe Sprint World Championships (734 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200 metres (660 ft), 500Reed–Solomon error correction (12,677 words) [view diff] no match in snippet view article find links to article
k + 1 … g 1 , n 0 1 0 … 0 g 2 , k + 1 … g 2 , n 0 0 1 … 0 g 3 , k + 1 … g 3 , n ⋮ ⋮ ⋮ ⋮ ⋮ ⋮ 0 … 0 … 1 g k , k + 1 … g k , n ] [ m 0 m 1 ⋮ m k − 1 ]Russian roulette (2,825 words) [view diff] no match in snippet view article find links to article
{\displaystyle k} is 1 n − k ⋅ ∏ i = 0 k − 1 n − i − 1 n − i = n − 1 n ⋅ n − 2 n − 1 ⋅ . . . ⋅ n − k n − k − 1 ⋅ 1 n − k = 1 6 ≈ 16.7 % {\displaystyle {\tfracBirthday problem (7,114 words) [view diff] no match in snippet view article find links to article
p ¯ ( n ) = ∏ k = 1 n − 1 ( 1 − k 365 ) < ∏ k = 1 n − 1 ( e − k 365 ) = e − n ( n − 1 ) 730 . {\displaystyle {\bar {p}}(n)=\prod _{k=1}^{n-1}\left(1-{\fracDissociation constant (3,119 words) [view diff] no match in snippet view article find links to article
K 1 ′ = [ L ] [ M ] [ L M ] [ LM ] = [ L ] [ M ] K 1 ′ [ L ] + [ LM ] ↽ − − ⇀ [ L 2 M ] K 2 ′ = [ L ] [ LM ] [ L 2 M ] [ L 2 M ] = [ L ] 2 [ M ] K 1 ′Standard molar entropy (788 words) [view diff] no match in snippet view article find links to article
= ∑ k = 1 N Δ S k = ∑ k = 1 N d Q k T → ∫ 0 T 2 d S d T d T = ∫ 0 T 2 C p k T d T {\displaystyle S^{\circ }=\sum _{k=1}^{N}\Delta S_{k}=\sum _{k=1}^{N}{\fracChaos theory (13,439 words) [view diff] no match in snippet view article find links to article
non-linear differential equations of the second order, I: The equation y" + k(1−y2)y' + y = bλkcos(λt + a), k large". Journal of the London MathematicalPartial autocorrelation function (1,129 words) [view diff] exact match in snippet view article find links to article
k − 1 + ⋯ + β k − 1 z t + 1 and z ^ t = β 1 z t + 1 + ⋯ + β k − 1 z t + k − 1 . {\displaystyle {\hat {z}}_{t+k}=\beta _{1}z_{t+k-1}+\cdots +\beta _{k-1}z_{t+1}\qquadExterior algebra (12,098 words) [view diff] exact match in snippet view article find links to article
k − 1 {\displaystyle k-1} elements of V ∗ {\displaystyle V^{*}} , then define ( ι α w ) ( u 1 , u 2 , … , u k − 1 ) = w ( α , u 1 , u 2 , … , u k −Entropy (14,024 words) [view diff] no match in snippet view article find links to article
temperature, which has a unit of joules per kelvin (J⋅K−1) in the International System of Units (or kg⋅m2⋅s−2⋅K−1 in terms of base units). The entropy of a substanceVariance (10,207 words) [view diff] no match in snippet view article find links to article
∑ k = 1 n Y k ] = 1 n ∑ i = 1 n ( E [ Y i 2 ] − 2 n ( ∑ j ≠ i E [ Y i Y j ] + E [ Y i 2 ] ) + 1 n 2 ∑ j = 1 n ∑ k ≠ j n E [ Y j Y k ] + 1 n 2Lehmer mean (837 words) [view diff] no match in snippet view article find links to article
as: L p ( x ) = ∑ k = 1 n x k p ∑ k = 1 n x k p − 1 . {\displaystyle L_{p}(\mathbf {x} )={\frac {\sum _{k=1}^{n}x_{k}^{p}}{\sum _{k=1}^{n}x_{k}^{p-1}}}Phase-shift keying (6,226 words) [view diff] exact match in snippet view article find links to article
number: r k r k − 1 ∗ = E s e j ( φ k − φ k − 1 ) + E s e j φ k n k − 1 ∗ + E s e − j φ k − 1 n k + n k n k − 1 ∗ {\displaystyle r_{k}r_{k-1}^{*}=E_{s}e^{j\left(\varphiTrapezoidal rule (3,483 words) [view diff] exact match in snippet view article find links to article
(that is, Δ x k = x k − x k − 1 {\displaystyle \Delta x_{k}=x_{k}-x_{k-1}} ), then ∫ a b f ( x ) d x ≈ ∑ k = 1 N f ( x k − 1 ) + f ( x k ) 2 Δ x k . {\displaystyleExterior derivative (3,307 words) [view diff] no match in snippet view article find links to article
can be thought of as measuring the net flux through the boundary of a (k + 1)-parallelotope at each point. The exterior derivative of a differentialFloor and ceiling functions (5,879 words) [view diff] no match in snippet view article find links to article
integer k is ⌊ log b k ⌋ + 1 = ⌈ log b ( k + 1 ) ⌉ . {\displaystyle \lfloor \log _{b}{k}\rfloor +1=\lceil \log _{b}{(k+1)}\rceil .} The number ofErlang distribution (1,969 words) [view diff] no match in snippet view article find links to article
of time until the occurrence of a fixed number of events. When k = 1 {\displaystyle k=1} , the distribution simplifies to the exponential distributionThermal conductivity and resistivity (8,365 words) [view diff] no match in snippet view article find links to article
{\displaystyle \lambda } , or κ {\displaystyle \kappa } and is measured in W·m−1·K−1. Heat transfer occurs at a lower rate in materials of low thermal conductivitySobolev space (6,658 words) [view diff] exact match in snippet view article find links to article
it is enough to assume that the ( k − 1 ) {\displaystyle (k{-}1)} -th derivative f ( k − 1 ) {\displaystyle f^{(k-1)}} is differentiable almost everywhereExponential family (11,203 words) [view diff] exact match in snippet view article find links to article
{\displaystyle \sum _{i=1}^{k}p_{i}=1\,.} Thus, there are only k − 1 {\displaystyle k-1} independent parameters. Variant 1 uses k {\displaystyle k} naturalOrder statistic (4,933 words) [view diff] exact match in snippet view article find links to article
U ( k ) ( u ) = n ! ( k − 1 ) ! ( n − k ) ! u k − 1 ( 1 − u ) n − k {\displaystyle f_{U_{(k)}}(u)={n! \over (k-1)!(n-k)!}u^{k-1}(1-u)^{n-k}} that is,Invertible matrix (6,996 words) [view diff] exact match in snippet view article find links to article
A k − 1 A k ) − 1 = A k − 1 A k − 1 − 1 ⋯ A 2 − 1 A 1 − 1 . {\displaystyle (\mathbf {A} _{1}\mathbf {A} _{2}\cdots \mathbf {A} _{k-1}\mathbf {A} _{k})^{-1}=\mathbfRecurrence relation (4,166 words) [view diff] exact match in snippet view article find links to article
uni-dimensional recurrence: ( n k ) = ( n k − 1 ) ( n − k + 1 ) / k , {\displaystyle {\binom {n}{k}}={\binom {n}{k-1}}(n-k+1)/k,} with the initial value ( n 0Proportional–integral–derivative controller (12,059 words) [view diff] no match in snippet view article find links to article
u ( t k ) − u ( t k − 1 ) Δ t = K p e ( t k ) − e ( t k − 1 ) Δ t + K i e ( t k ) + K d e ( t k ) − e ( t k − 1 ) Δ t − e ( t k − 1 ) − e ( t k − 2 )Generating function (14,464 words) [view diff] no match in snippet view article find links to article
, 1 k 1 , 1 0 0 ⋯ k 0 , 2 k 1 , 2 k 2 , 2 0 ⋯ k 0 , 3 k 1 , 3 k 2 , 3 k 3 , 3 ⋯ ⋮ ⋮ ⋮ ⋮ ] = [ k 0 , 0 0 0 0 ⋯ k 0 , 1 k 1 , 1 0 0 ⋯ k 0 , 2 k 1 , 2 kSmoothness (3,923 words) [view diff] exact match in snippet view article find links to article
at least in the class C k − 1 {\displaystyle C^{k-1}} since f ′ , f ″ , … , f ( k − 1 ) {\displaystyle f',f'',\dots ,f^{(k-1)}} are continuous on U .Euclidean algorithm (15,336 words) [view diff] exact match in snippet view article find links to article
m k = q k m k − 1 + m k − 2 n k = q k n k − 1 + n k − 2 , {\displaystyle {\begin{aligned}m_{k}&=q_{k}m_{k-1}+m_{k-2}\\n_{k}&=q_{k}n_{k-1}+n_{k-2},\end{aligned}}}Finite difference (5,863 words) [view diff] exact match in snippet view article find links to article
k − 1 ∑ i 2 = 0 k − 1 ⋯ ∑ i n = 0 k − 1 Δ h n ( f , x + i 1 h + i 2 h + ⋯ + i n h ) . {\displaystyle \Delta _{kh}^{n}(f,x)=\sum \limits _{i_{1}=0}^{k-1}\sumMoment (mathematics) (3,066 words) [view diff] no match in snippet view article
X 1 k 1 ⋯ X n k n ] {\displaystyle E[{X_{1}}^{k_{1}}\cdots {X_{n}}^{k_{n}}]} is called a mixed moment of order k {\displaystyle k} (where k = k 1 + .Moment (mathematics) (3,066 words) [view diff] no match in snippet view article
X 1 k 1 ⋯ X n k n ] {\displaystyle E[{X_{1}}^{k_{1}}\cdots {X_{n}}^{k_{n}}]} is called a mixed moment of order k {\displaystyle k} (where k = k 1 + .Convergent series (1,966 words) [view diff] no match in snippet view article find links to article
that is denoted S = a 1 + a 2 + a 3 + ⋯ = ∑ k = 1 ∞ a k . {\displaystyle S=a_{1}+a_{2}+a_{3}+\cdots =\sum _{k=1}^{\infty }a_{k}.} The nth partial sum SnStirling numbers of the second kind (4,313 words) [view diff] exact match in snippet view article find links to article
n k − 1 } {\displaystyle \left\{{n \atop k-1}\right\}} since we must partition the remaining n objects into the available k − 1 {\displaystyle k-1} Gram–Schmidt process (4,423 words) [view diff] no match in snippet view article find links to article
( k − 1 ) = u k ( k − 2 ) − proj u k − 1 ( u k ( k − 2 ) ) , e k = u k ( k − 1 ) ‖ u k ( k − 1 ) ‖ {\displaystyle {\begin{aligned}\mathbf {u} _{k}^{(1)}&=\mathbfPrincipal component analysis (14,450 words) [view diff] no match in snippet view article find links to article
of the normalization constraints: α k ′ α k = 1 , k = 1 , … , p {\displaystyle \alpha _{k}'\alpha _{k}=1,k=1,\dots ,p} . As noted above, the results ofArithmetic progression (2,297 words) [view diff] no match in snippet view article find links to article
n , k ) = 1 2 ( k − 1 ) ( n 2 − ( k − 1 ) n + ( k − 2 ) + ϕ ( n + 1 , k − 1 ) ) = 1 2 ( k − 1 ) ( ( n − 1 ) ( n − ( k − 2 ) ) + ϕ ( n + 1 , k − 1 ) )Softmax function (5,286 words) [view diff] no match in snippet view article find links to article
{\displaystyle \sigma \colon \mathbb {R} ^{K}\to (0,1)^{K}} , where K > 1 {\displaystyle K>1} , takes a vector z = ( z 1 , … , z K ) ∈ R K {\displaystyle \mathbfProbability density function (4,940 words) [view diff] no match in snippet view article find links to article
for y is ∑ k = 1 n ( y ) | d d y g k − 1 ( y ) | ⋅ f X ( g k − 1 ( y ) ) , {\displaystyle \sum _{k=1}^{n(y)}\left|{\frac {d}{dy}}g_{k}^{-1}(y)\right|\cdotList of Olympic medalists in canoeing (women) (16 words) [view diff] no match in snippet view article
This is the complete list of women's Olympic medalists in kayaking. International Olympic Committee results database1000 (number) (24,094 words) [view diff] no match in snippet view article
k = 1 46 σ ( k ) {\displaystyle \sum _{k=1}^{46}\sigma (k)} 1759 = de Polignac prime 1760 = the number of yards in a mile 1761 = k such that k, k+1 andGalois group (3,232 words) [view diff] no match in snippet view article find links to article
G_{2}.} The field K 1 K 2 {\displaystyle K_{1}K_{2}} with Galois group G = Gal ( K 1 K 2 / k ) {\displaystyle G=\operatorname {Gal} (K_{1}K_{2}/k)} hasHypergeometric distribution (4,115 words) [view diff] no match in snippet view article find links to article
hypergeometric distribution: Pr ( X 1 = k 1 , … , X c = k c ) = ∏ i = 1 c ( K i k i ) ( N n ) {\displaystyle \Pr(X_{1}=k_{1},\ldots ,X_{c}=k_{c})={\frac {\prodExtrapolation (1,869 words) [view diff] exact match in snippet view article find links to article
= y k − 1 + x ∗ − x k − 1 x k − x k − 1 ( y k − y k − 1 ) . {\displaystyle y(x_{*})=y_{k-1}+{\frac {x_{*}-x_{k-1}}{x_{k}-x_{k-1}}}(y_{k}-y_{k-1}).} (whichError function (7,304 words) [view diff] exact match in snippet view article find links to article
) k − 1 π H k − 1 ( z ) e − z 2 = 2 π d k − 1 d z k − 1 ( e − z 2 ) , k = 1 , 2 , … {\displaystyle \operatorname {erf} ^{(k)}z={\frac {2(-1)^{k-1}}{\sqrtKronecker delta (3,740 words) [view diff] exact match in snippet view article find links to article
_{p-1}}-\sum _{k=1}^{p-1}\delta _{\nu _{k}}^{\mu _{p}}\delta _{\nu _{1}\dots \nu _{k-1}\,\nu _{p}\,\nu _{k+1}\dots \nu _{p-1}}^{\mu _{1}\dots \mu _{k-1}\,\mu _{k}\Min-max theorem (4,542 words) [view diff] exact match in snippet view article find links to article
to pick a ( i k − 1 − ( i 1 − 1 ) ) {\textstyle (i_{k-1}-(i_{1}-1))} -dimensional subspace W k − 1 ′ ⊂ W k ∩ V i k − 1 {\textstyle W_{k-1}'\subset W_{k}\capCanoeing at the 2016 Summer Olympics (685 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 200 m men C-1 1000 m men C-2 1000 m men K-1 200 m men women K-1 500 m women K-1 1000 m men K-2 200 m menQuaternion (12,634 words) [view diff] no match in snippet view article find links to article
quaternions, i 2 = j 2 = k 2 = i j k = − 1 {\displaystyle \mathbf {i} ^{2}=\mathbf {j} ^{2}=\mathbf {k} ^{2}=\mathbf {i\,j\,k} =-1} into the stone of BroughamIdeal gas law (4,622 words) [view diff] no match in snippet view article find links to article
−273.15 °C, the lowest possible temperature). R has for value 8.314 J/(mol·K) = 1.989 ≈ 2 cal/(mol·K), or 0.0821 L⋅atm/(mol⋅K). How much gas is present couldMax Hoff (canoeist) (198 words) [view diff] exact match in snippet view article
Championships with five golds (K-1 1000 m: 2009, 2010, 2013; K-1 5000 m: 2011 and K-4 1000 m: 2011 ) and three silvers (K-1 5000 m: 2010, 2014, 2015). AtCanoeing at the 2020 Summer Olympics (435 words) [view diff] exact match in snippet view article find links to article
C-1 men women K-1 men women Sprint C-1 200 m women C-1 1000 m men C-2 500 m women C-2 1000 m men K-1 200 m men women K-1 500 m women K-1 1000 m men K-2Ozone (18,196 words) [view diff] no match in snippet view article find links to article
intermediate can be determined as follows: K 1 = K 1 K − 1 = [ O 2 ] ⋅ [ O ] [ O 3 ] {\displaystyle K_{1}={\frac {K_{1}}{K_{-1}}}={\frac {[{\ce {O2}}]\cdot [{\ceKosambi–Karhunen–Loève theorem (10,711 words) [view diff] no match in snippet view article find links to article
∑ k = 1 N p k ≥ ∑ k = 1 N q k {\displaystyle \sum _{k=1}^{N}p_{k}\geq \sum _{k=1}^{N}q_{k}} This implies that: − ∑ k = 1 ∞ p k log ( p k ) ≤ − ∑ k =Canoeing at the Summer Olympics (333 words) [view diff] exact match in snippet view article find links to article
200 m events with one of them being K-1 200 m for the women. The other events for men at 200 m will be C-1, K-1, and K-2. This was confirmed at theirHandley Page Victor (9,400 words) [view diff] no match in snippet view article find links to article
tanker (renamed K.1 after bombing capability removed), 11 converted. Victor BK.1A 3-point in-flight refuelling tanker (renamed K.1A as for K.1), 14 convertedLagrange polynomial (3,973 words) [view diff] no match in snippet view article find links to article
F^{(k+1)}(\xi )} : F ( k + 1 ) ( ξ ) = f ( k + 1 ) ( ξ ) − L ( k + 1 ) ( ξ ) − R ~ ( k + 1 ) ( ξ ) {\displaystyle F^{(k+1)}(\xi )=f^{(k+1)}(\xi )-L^{(k+1)}(\xiElliptic integral (7,832 words) [view diff] no match in snippet view article find links to article
}})={\tfrac {1}{2}}\pi } For example: 4 3 K ( 1 3 ) E ( 1 2 ) + 3 2 E ( 1 3 ) K ( 1 2 ) − 2 K ( 1 3 ) K ( 1 2 ) = 1 2 π {\displaystyle {\tfrac {4}{3}}K({\colorEuler–Maclaurin formula (3,779 words) [view diff] exact match in snippet view article find links to article
∑ k = 1 p B k k ! ( f ( k − 1 ) ( n ) − f ( k − 1 ) ( m ) ) + R p , {\displaystyle S-I=\sum _{k=1}^{p}{{\frac {B_{k}}{k!}}\left(f^{(k-1)}(n)-f^{(k-1)}(m)\right)}+R_{p}Maximum likelihood estimation (9,703 words) [view diff] no match in snippet view article find links to article
functions: f n ( y ; θ ) = ∏ k = 1 n f k u n i v a r ( y k ; θ ) . {\displaystyle f_{n}(\mathbf {y} ;\theta )=\prod _{k=1}^{n}\,f_{k}^{\mathsf {univar}}(y_{k};\thetaApproximations of π (12,280 words) [view diff] no match in snippet view article find links to article
{2}}} and y k + 1 = ( 1 − f ( y k ) ) / ( 1 + f ( y k ) ) , a k + 1 = a k ( 1 + y k + 1 ) 4 − 2 2 k + 3 y k + 1 ( 1 + y k + 1 + y k + 1 2 ) {\displaystyleLogistic function (8,031 words) [view diff] no match in snippet view article find links to article
standard logistic function, depicted at right, where L = 1 , k = 1 , x 0 = 0 {\displaystyle L=1,k=1,x_{0}=0} , has the equation f ( x ) = 1 1 + e − x {\displaystyleDiscrete Fourier transform (12,311 words) [view diff] no match in snippet view article find links to article
case above: X k 1 , k 2 , … , k d = X N 1 − k 1 , N 2 − k 2 , … , N d − k d ∗ , {\displaystyle X_{k_{1},k_{2},\dots ,k_{d}}=X_{N_{1}-k_{1},N_{2}-k_{2}List of ICF Canoe Sprint World Championships medalists in men's kayak (269 words) [view diff] no match in snippet view article find links to article
This is a list of medalists from the ICF Canoe Sprint World Championships in men's kayak. Debuted: 1994. Debuted: 1948. Debuted: 1938. Not held: 1948.Molar heat capacity (5,707 words) [view diff] no match in snippet view article find links to article
mass. The SI unit of molar heat capacity is joule per kelvin per mole, J⋅K−1⋅mol−1. Like the specific heat, the measured molar heat capacity of a substanceDifferential form (10,058 words) [view diff] case mismatch in snippet view article find links to article
differential forms that, given a k-form φ {\displaystyle \varphi } , produces a (k+1)-form d φ . {\displaystyle d\varphi .} This operation extends the differentialHarmonic series (mathematics) (6,219 words) [view diff] no match in snippet view article
{1}{k(k+1)}}=\sum _{k=1}^{\infty }\sum _{n=1}^{k}{\frac {1}{k(k+1)}}} = ∑ k = 1 ∞ k k ( k + 1 ) = ∑ k = 1 ∞ 1 k + 1 = S − 1 {\displaystyle =\sum _{k=1}^{\inftyRatio test (5,987 words) [view diff] no match in snippet view article find links to article
a subsequence ( a n k ) k = 1 ∞ {\displaystyle \left(a_{n_{k}}\right)_{k=1}^{\infty }} satisfying lim sup n → ∞ | a n k + 1 a n k | ≤ ℓ < r {\displaystyleHölder's inequality (7,917 words) [view diff] no match in snippet view article find links to article
functions for k = 1 , . . . , m {\displaystyle k=1,...,m} . Then ‖ ∏ k = 1 m f k ‖ 1 ≥ ∏ k = 1 m ‖ f k ‖ p k . {\displaystyle \left\|\prod _{k=1}^{m}f_{k}\right\|_{1}\geqContinuous uniform distribution (4,219 words) [view diff] case mismatch in snippet view article find links to article
{a^{2}+ab+b^{2}}{3}},} m k = ∑ i = 0 k a i b k − i k + 1 . {\displaystyle m_{k}={\frac {\sum _{i=0}^{k}a^{i}b^{k-i}}{k+1}}.} For a random variable following theEuler numbers (2,049 words) [view diff] no match in snippet view article find links to article
}{q}}(2q-\ell )^{2n},} E 2 n = ∑ k = 1 2 n ( − 1 ) k 1 2 k ∑ ℓ = 0 2 k ( − 1 ) ℓ ( 2 k ℓ ) ( k − ℓ ) 2 n . {\displaystyle E_{2n}=\sum _{k=1}^{2n}(-1)^{k}{\frac {1}{2^{k}}}\sumStirling's approximation (4,758 words) [view diff] no match in snippet view article find links to article
) + 1 2 ln n = n ln n − n + 1 + ∑ k = 2 m ( − 1 ) k B k k ( k − 1 ) ( 1 n k − 1 − 1 ) + R m , n , {\displaystyle {\begin{aligned}\ln(n!)-{\tfracMultinomial logistic regression (5,245 words) [view diff] no match in snippet view article find links to article
= ∑ k = 1 K Pr ( Y i = k ) = ∑ k = 1 K 1 Z e β k ⋅ X i = 1 Z ∑ k = 1 K e β k ⋅ X i . {\displaystyle 1=\sum _{k=1}^{K}\Pr(Y_{i}=k)\;=\;\sum _{k=1}^{K}{\fracNewton's method in optimization (1,857 words) [view diff] no match in snippet view article find links to article
obtains the iterative scheme x k + 1 = x k − [ f ″ ( x k ) ] − 1 f ′ ( x k ) , k ≥ 0. {\displaystyle x_{k+1}=x_{k}-[f''(x_{k})]^{-1}f'(x_{k}),\qquad k\geq 0Binomial series (1,904 words) [view diff] no match in snippet view article find links to article
) ( α − 2 ) ⋯ ( α − k + 1 ) k ! . {\displaystyle {\binom {\alpha }{k}}:={\frac {\alpha (\alpha -1)(\alpha -2)\cdots (\alpha -k+1)}{k!}}.} Note that ifPaul MacDonald (canoeist) (352 words) [view diff] exact match in snippet view article
1988; K-4 1000 m: 1984), one silver (K-2 1000 m: 1988), and one bronze (K-1 500 m: 1988). His five Olympic medals is the record for the second most OlympicChi distribution (1,726 words) [view diff] exact match in snippet view article find links to article
( x ; k ) = { x k − 1 e − x 2 / 2 2 k / 2 − 1 Γ ( k 2 ) , x ≥ 0 ; 0 , otherwise . {\displaystyle f(x;k)={\begin{cases}{\dfrac {x^{k-1}e^{-x^{2}/2}}{2^{k/2-1}\GammaKaprekar's routine (3,143 words) [view diff] no match in snippet view article find links to article
) = α − β = ( ( 2 k − 1 ) − ( k − 1 ) ) b 2 n + 2 ( ∑ i = 0 n b i ) + ( k − k ) b n + 1 ( ∑ i = 0 n b i ) + ( ( k − 1 ) − ( 2 k − 1 ) ) ( ∑ i = 0 n bEuler numbers (2,049 words) [view diff] no match in snippet view article find links to article
}{q}}(2q-\ell )^{2n},} E 2 n = ∑ k = 1 2 n ( − 1 ) k 1 2 k ∑ ℓ = 0 2 k ( − 1 ) ℓ ( 2 k ℓ ) ( k − ℓ ) 2 n . {\displaystyle E_{2n}=\sum _{k=1}^{2n}(-1)^{k}{\frac {1}{2^{k}}}\sumOscillation (3,045 words) [view diff] no match in snippet view article find links to article
1 x ¨ 1 = − ( k 1 + k 2 ) x 1 + k 2 x 2 m 2 x ¨ 2 = k 2 x 1 − ( k 2 + k 3 ) x 2 {\displaystyle {\begin{cases}m_{1}{\ddot {x}}_{1}=-(k_{1Stirling numbers of the first kind (7,262 words) [view diff] no match in snippet view article find links to article
1 ) z Γ ( z + 1 ) ( k − 1 ) ! ∑ r = 1 k − 1 s ( k − 1 , r ) ∑ m = 0 r ( r m ) ( k − 2 ) r − m ζ ( z + 1 − m ) , ℜ ( z ) > k − 1 , k = 3 , 4 , 5 , … {\displaystyleTetrahedral number (1,343 words) [view diff] no match in snippet view article find links to article
n = ∑ k = 1 n T k = ∑ k = 1 n k ( k + 1 ) 2 = ∑ k = 1 n ( ∑ i = 1 k i ) {\displaystyle Te_{n}=\sum _{k=1}^{n}T_{k}=\sum _{k=1}^{n}{\frac {k(k+1)}{2}}=\sumBinomial series (1,904 words) [view diff] no match in snippet view article find links to article
) ( α − 2 ) ⋯ ( α − k + 1 ) k ! . {\displaystyle {\binom {\alpha }{k}}:={\frac {\alpha (\alpha -1)(\alpha -2)\cdots (\alpha -k+1)}{k!}}.} Note that ifLebesgue measure (2,678 words) [view diff] no match in snippet view article find links to article
as an infimum λ ∗ ( E ) = inf { ∑ k = 1 ∞ ℓ ( I k ) : ( I k ) k ∈ N is a sequence of open intervals with E ⊂ ⋃ k = 1 ∞ I k } . {\displaystyle \lambdaNumeral system (3,494 words) [view diff] no match in snippet view article find links to article
k b k + ∑ k = 1 ∞ c k b − k . {\displaystyle (a_{n}a_{n-1}\cdots a_{1}a_{0}.c_{1}c_{2}c_{3}\cdots )_{b}=\sum _{k=0}^{n}a_{k}b^{k}+\sum _{k=1}^{\infty }c_{k}b^{-k}Chi distribution (1,726 words) [view diff] exact match in snippet view article find links to article
( x ; k ) = { x k − 1 e − x 2 / 2 2 k / 2 − 1 Γ ( k 2 ) , x ≥ 0 ; 0 , otherwise . {\displaystyle f(x;k)={\begin{cases}{\dfrac {x^{k-1}e^{-x^{2}/2}}{2^{k/2-1}\GammaExact sequence (2,577 words) [view diff] exact match in snippet view article find links to article
A k + 1 {\displaystyle A_{k+1}} and morphism A k → A k + 1 {\displaystyle A_{k}\to A_{k+1}} such that A k − 1 → A k → A k + 1 {\displaystyle A_{k-1}\toGert Fredriksson (427 words) [view diff] exact match in snippet view article find links to article
(1948: K-1 1000 m, K-1 10000 m; 1952: K-1 1000 m, 1956: K-1 1000 m, K-1 10000 m; 1960: K-2 1000 m), one silver (1952: K-1 10000 m), and one bronze (K-1 1000Algebra over a field (3,122 words) [view diff] no match in snippet view article find links to article
k 1 , k 2 ∈ K {\displaystyle k_{1},k_{2}\in K} and v 1 , v 2 ∈ V {\displaystyle v_{1},v_{2}\in V} , one has ( k 1 + v 1 ) ( k 2 + v 2 ) = k 1 kMeasure (mathematics) (5,550 words) [view diff] no match in snippet view article
collections { E k } k = 1 ∞ {\displaystyle \{E_{k}\}_{k=1}^{\infty }} of pairwise disjoint sets in Σ, μ ( ⋃ k = 1 ∞ E k ) = ∑ k = 1 ∞ μ ( E k ) . {\displaystyleTrapezoid (4,042 words) [view diff] exact match in snippet view article find links to article
≈ ∑ k = 1 N 1 2 ( f ( x k − 1 ) + f ( x k ) ) Δ x , {\displaystyle \int _{a}^{b}f(x)\,dx\approx \sum _{k=1}^{N}{\tfrac {1}{2}}{\bigl (}f(x_{k-1})+f(x_{k}){\bigrAC power (4,388 words) [view diff] no match in snippet view article find links to article
result. A cos ( ω 1 t + k 1 ) cos ( ω 2 t + k 2 ) = A 2 cos [ ( ω 1 t + k 1 ) + ( ω 2 t + k 2 ) ] + A 2 cos [ ( ω 1 t + k 1 ) − ( ω 2 t + k 2 ) ]Multiset (4,955 words) [view diff] exact match in snippet view article find links to article
+ k − 1 k ) = ( n + k − 1 ) ! k ! ( n − 1 ) ! = n ( n + 1 ) ( n + 2 ) ⋯ ( n + k − 1 ) k ! , {\displaystyle \left(\!\!{n \choose k}\!\!\right)={n+k-1 \chooseLogarithmic distribution (377 words) [view diff] no match in snippet view article find links to article
the identity ∑ k = 1 ∞ − 1 ln ( 1 − p ) p k k = 1. {\displaystyle \sum _{k=1}^{\infty }{\frac {-1}{\ln(1-p)}}\;{\frac {p^{k}}{k}}=1.} This leads directlyAnalytic continuation (3,886 words) [view diff] no match in snippet view article find links to article
π ∑ n = k ∞ ( − 1 ) n ( n k ) ( a − 1 ) n − k ∫ 0 2 π d θ = ∑ n = k ∞ ( − 1 ) n ( n k ) ( a − 1 ) n − k = ( − 1 ) k ∑ m = 0 ∞ ( m + k k ) ( 1 − a ) mRademacher distribution (1,065 words) [view diff] no match in snippet view article find links to article
( k ) = { 1 / 2 if k = − 1 , 1 / 2 if k = + 1 , 0 otherwise. {\displaystyle f(k)=\left\{{\begin{matrix}1/2&{\text{if }}k=-1,\\1/2&{\text{if }}k=+1,\\0&{\text{otherwiseAsymptotic analysis (2,774 words) [view diff] exact match in snippet view article find links to article
1 − ⋯ − g k − 1 ∼ g k {\displaystyle f-g_{1}-\cdots -g_{k-1}\sim g_{k}} takes its full meaning if g k + 1 = o ( g k ) {\displaystyle g_{k+1}=o(g_{k})}Topological sorting (3,170 words) [view diff] exact match in snippet view article find links to article
indices a k − 1 + ∑ i = 0 j − 1 | Q i k | , … , a k − 1 + ( ∑ i = 0 j | Q i k | ) − 1 {\textstyle a_{k-1}+\sum _{i=0}^{j-1}|Q_{i}^{k}|,\dots ,a_{k-1}+\left(\sumAlan Thompson (canoeist) (528 words) [view diff] exact match in snippet view article
silvers (K-1 1000 m and K-2 500 m: both 1982), and a bronze (K-1 1000 m: 1983). He won both of his Olympic gold medals at Los Angeles in 1984, in the K-1 1000Rational function (2,421 words) [view diff] exact match in snippet view article find links to article
− 2 x k − ∑ k = 1 ∞ a k − 1 x k + 2 ∑ k = 0 ∞ a k x k . {\displaystyle 1=\sum _{k=2}^{\infty }a_{k-2}x^{k}-\sum _{k=1}^{\infty }a_{k-1}x^{k}+2\sum _{k=0}^{\inftyFlory–Schulz distribution (288 words) [view diff] exact match in snippet view article find links to article
length k {\displaystyle k} is: w a ( k ) = a 2 k ( 1 − a ) k − 1 . {\displaystyle w_{a}(k)=a^{2}k(1-a)^{k-1}{\text{.}}} In this equation, k is the numberFactorization (7,851 words) [view diff] no match in snippet view article find links to article
E 2 n + F 2 n = ∏ k = 1 n ( E 2 + 2 E F cos ( 2 k − 1 ) π 2 n + F 2 ) = ∏ k = 1 n ( E 2 − 2 E F cos ( 2 k − 1 ) π 2 n + F 2 ) {\displaystyleGeneralized Dirichlet distribution (1,861 words) [view diff] exact match in snippet view article find links to article
function of p 1 , … , p k − 1 {\displaystyle p_{1},\ldots ,p_{k-1}} is [ ∏ i = 1 k − 1 B ( a i , b i ) ] − 1 p k b k − 1 − 1 ∏ i = 1 k − 1 [ p i a i − 1 ( ∑2017 ICF Canoe Sprint World Championships (567 words) [view diff] exact match in snippet view article find links to article
Women's C–2 500 m results Women's K-1 200 m results Women's K-1 500 m results Women's K-1 1000 m results Women's K-1 5000 m results Women's K-2 200 m resultsKaprekar number (4,058 words) [view diff] no match in snippet view article find links to article
= 2 k + 1 + ∑ i = 1 n ( 2 k + 1 ) b 2 i + ( 2 k + 1 ) b 2 i − 1 = 2 k + 1 + ∑ i = 1 2 n ( 2 k + 1 ) b i = ∑ i = 0 2 n ( 2 k + 1 ) b i = ( 2 k + 1 ) ∑Inductance (8,763 words) [view diff] no match in snippet view article find links to article
authors define the range as 0 ≤ k < 1 {\displaystyle 0\leq k<1} , but some define it as − 1 < k < 1 {\displaystyle -1<k<1\,} . Allowing negative valuesThermal expansion (6,133 words) [view diff] no match in snippet view article find links to article
K − 1 {\displaystyle \alpha \approx {\frac {0.038}{T_{m}}}-7.0\cdot 10^{-6}\,\mathrm {K} ^{-1}} In the table below, the range for α is from 10−7 K−1 forBose–Einstein statistics (6,024 words) [view diff] no match in snippet view article find links to article
following formula w ( n , g ) = ∑ k 1 = 0 n ∑ k 2 = 0 n − k 1 w ( n − k 1 − k 2 , g − 2 ) = ∑ k 1 = 0 n ∑ k 2 = 0 n − k 1 ⋯ ∑ k g = 0 n − ∑ j = 1 g − 1 kFloyd–Warshall algorithm (3,071 words) [view diff] exact match in snippet view article find links to article
t h ( i , j , k − 1 ) , {\displaystyle \mathrm {min} {\Big (}\mathrm {shortestPath} (i,j,k-1),} s h o r t e s t P a t h ( i , k , k − 1 ) + s h o r tCanoeing at the 2008 Summer Olympics (70 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menSpline (mathematics) (3,784 words) [view diff] no match in snippet view article
0 , … , k − 1 [ a , b ] = [ t 0 , t 1 ) ∪ [ t 1 , t 2 ) ∪ ⋯ ∪ [ t k − 2 , t k − 1 ) ∪ [ t k − 1 , t k ) ∪ [ t k ] a = t 0 ≤ t 1 ≤ ⋯ ≤ t k − 1 ≤ t k =Myanmar kyat (3,449 words) [view diff] no match in snippet view article find links to article
(plural), placed before the numerals followed by "/-". Amounts less than K. 1/- are typically denoted with the number of pyas following "-/" (e.g. -/502010 ICF Canoe Sprint World Championships (1,990 words) [view diff] exact match in snippet view article find links to article
winningest medalist in men's kayak with his 21st career medal, earning that in a K-1 200 m silver. Rauhe eclipsed that record he had tied at the previous championshipsInteger partition (3,396 words) [view diff] no match in snippet view article find links to article
= ∏ k = 1 ∞ ( 1 + x k ) = ∏ k = 1 ∞ 1 1 − x 2 k − 1 . {\displaystyle \sum _{n=0}^{\infty }q(n)x^{n}=\prod _{k=1}^{\infty }(1+x^{k})=\prod _{k=1}^{\inftyChain rule (7,087 words) [view diff] no match in snippet view article find links to article
( D f 2 ∘ f 3 . . n ) ⋯ ( D f n − 1 ∘ f n . . n ) D f n = ∏ k = 1 n [ D f k ∘ f ( k + 1 ) . . n ] {\displaystyle {\begin{aligned}Df_{1\,.\,.\,n}&=(Df_{1}\circPhase velocity (1,075 words) [view diff] no match in snippet view article find links to article
x , t ) = cos ( k 1 x − ω 1 t ) + cos ( k 2 x − ω 2 t ) = 2 cos ( ( k 2 − k 1 ) x − ( ω 2 − ω 1 ) t 2 ) cos ( ( k 2 + k 1 ) x − ( ω 2 + ω 1 )Multinomial distribution (6,412 words) [view diff] exact match in snippet view article find links to article
n_{1}+\cdots +n_{k}=n\}.\,} Its number of elements is ( n + k − 1 k − 1 ) . {\displaystyle {n+k-1 \choose k-1}.} In matrix notation, E ( X ) = n p , {\displaystyleCanoeing at the 2004 Summer Olympics (96 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menPink noise (6,607 words) [view diff] no match in snippet view article find links to article
the interval [ k τ , ( k + 1 ) τ ] {\displaystyle [k\tau ,(k+1)\tau ]} as y k = 1 τ ∫ k τ ( k + 1 ) τ x ˙ ( t ) d t = x ( ( k + 1 ) τ ) − x ( k τ ) τ {\displaystyleHome advantage (7,714 words) [view diff] no match in snippet view article find links to article
season to obtain k 1 {\displaystyle k_{1}} , k 0 {\displaystyle k_{0}} , and k − 1 {\displaystyle k_{-1}} . Values of k 1 {\displaystyle k_{1}} , k 0 {\displaystyleHexagonal number (1,028 words) [view diff] no match in snippet view article find links to article
∑ k = 1 ∞ 1 k ( 2 k − 1 ) = lim n → ∞ 2 ∑ k = 1 n ( 1 2 k − 1 − 1 2 k ) = lim n → ∞ 2 ∑ k = 1 n ( 1 2 k − 1 + 1 2 k − 1 k ) = 2 lim n → ∞ ( ∑ k = 1 2Burr distribution (604 words) [view diff] no match in snippet view article find links to article
k + 1 f ( x ; c , k , λ ) = c k λ ( x λ ) c − 1 [ 1 + ( x λ ) c ] − k − 1 {\displaystyle {\begin{aligned}f(x;c,k)&=ck{\frac {x^{c-1}}{(1+x^{c})^{k+1}}}\\[6pt]f(x;cDivisor function (3,781 words) [view diff] no match in snippet view article find links to article
k + 1 ) n k {\displaystyle \zeta (k+1)n^{k}} : σ k ( n ) = ζ ( k + 1 ) n k [ 1 + ( − 1 ) n 2 k + 1 + 2 cos 2 π n 3 3 k + 1 + 2 cos π n 2 4 k + 1 +Phase velocity (1,075 words) [view diff] no match in snippet view article find links to article
x , t ) = cos ( k 1 x − ω 1 t ) + cos ( k 2 x − ω 2 t ) = 2 cos ( ( k 2 − k 1 ) x − ( ω 2 − ω 1 ) t 2 ) cos ( ( k 2 + k 1 ) x − ( ω 2 + ω 1 )Divisor function (3,781 words) [view diff] no match in snippet view article find links to article
k + 1 ) n k {\displaystyle \zeta (k+1)n^{k}} : σ k ( n ) = ζ ( k + 1 ) n k [ 1 + ( − 1 ) n 2 k + 1 + 2 cos 2 π n 3 3 k + 1 + 2 cos π n 2 4 k + 1 +Canoeing at the 2008 Summer Olympics (70 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menGoodness of fit (1,150 words) [view diff] no match in snippet view article find links to article
any k − 1 are known, the remaining one is uniquely determined. Basically, one can say, there are only k − 1 freely determined binn counts, thus k − 1 degreesGreen's theorem (4,074 words) [view diff] no match in snippet view article find links to article
\varepsilon } . We have | ∑ i = k + 1 s ∫ Γ i A d x + B d y | ≤ 1 2 ε ∑ i = k + 1 s Λ i . {\displaystyle \left\vert \sum _{i=k+1}^{s}\int _{\Gamma _{i}}A\,dx+B\S-matrix (9,208 words) [view diff] no match in snippet view article find links to article
, k 1 … k n ⟩ = a i † ( k 1 ) ⋯ a i † ( k n ) | i , 0 ⟩ } , {\displaystyle {\mathcal {H}}_{\rm {i}}=\operatorname {span} \{\left|\mathrm {i} ,k_{1}\ldotsDanuta Kozák (615 words) [view diff] exact match in snippet view article find links to article
fourteen golds (K-1 500 m: 2013, 2014, 2018; K-2 200 m: 2011; K-2 500 m: 2009, 2010, 2015, 2018; K-4 500 m: 2009, 2011, 2013, 2014, 2018 and K-1 200 m relay:Interest (9,217 words) [view diff] exact match in snippet view article find links to article
k − 1 r = k [ 1 + ( k − 1 ) r 2 + ⋯ ] {\displaystyle \lambda _{k}={\frac {p_{k}}{p}}={\frac {r_{k}}{r}}={\frac {(1+r)^{k}-1}{r}}=k\left[1+{\frac {(k-1)r}{2}}+\cdotsElliptic Curve Digital Signature Algorithm (2,833 words) [view diff] no match in snippet view article find links to article
{\displaystyle r=0} , go back to step 3. Calculate s = k − 1 ( z + r d A ) mod n {\displaystyle s=k^{-1}(z+rd_{A})\,{\bmod {\,}}n} . If s = 0 {\displaystyleSubstitution reaction (1,456 words) [view diff] no match in snippet view article find links to article
described with k1, k−1 and k2, which are the rate constants of their corresponding intermediate reaction steps: L n M − L ⇌ + L , k − 1 − L , k 1 L n M − ◻ →Abelian group (5,284 words) [view diff] no match in snippet view article find links to article
numbers k 1 , k 2 , … , k u {\displaystyle k_{1},k_{2},\dots ,k_{u}} are powers of (not necessarily distinct) primes, or k 1 {\displaystyle k_{1}} dividesPigeonhole principle (4,155 words) [view diff] no match in snippet view article find links to article
contain at least k + 1 objects. For arbitrary n and m, this generalizes to k + 1 = ⌊ ( n − 1 ) / m ⌋ + 1 = ⌈ n / m ⌉ {\displaystyle k+1=\lfloor (n-1)/m\rfloorNoncentral chi-squared distribution (3,719 words) [view diff] no match in snippet view article find links to article
variable is developed as V 1 / k 1 V 2 / k 2 ∼ F k 1 , k 2 ′ ( λ ) {\displaystyle {\frac {V_{1}/k_{1}}{V_{2}/k_{2}}}\sim F'_{k_{1},k_{2}}(\lambda )} If J ∼Home advantage (7,714 words) [view diff] no match in snippet view article find links to article
season to obtain k 1 {\displaystyle k_{1}} , k 0 {\displaystyle k_{0}} , and k − 1 {\displaystyle k_{-1}} . Values of k 1 {\displaystyle k_{1}} , k 0 {\displaystyleVirial theorem (7,675 words) [view diff] no match in snippet view article find links to article
virial is − 1 2 ∑ k = 1 N F k ⋅ r k = 1 2 ∑ k = 1 N ∑ j < k d V j k d r j k r j k = 1 2 ∑ k = 1 N ∑ j < k n α r j k n − 1 r j k = 1 2 ∑ k = 1 N ∑ j < k n VBroyden–Fletcher–Goldfarb–Shanno algorithm (2,987 words) [view diff] no match in snippet view article find links to article
B k + 1 ( x k + 1 − x k ) = ∇ f ( x k + 1 ) − ∇ f ( x k ) . {\displaystyle B_{k+1}(\mathbf {x} _{k+1}-\mathbf {x} _{k})=\nabla f(\mathbf {x} _{k+1})-\nablaInternational System of Units (6,146 words) [view diff] no match in snippet view article find links to article
the fixed numerical value of the Boltzmann constant k to 1.380649×10−23 J⋅K−1, (J = kg⋅m2⋅s−2), given the definition of the kilogram, the metre, and theKatalin Kovács (500 words) [view diff] exact match in snippet view article find links to article
seven silvers (K-1 1000 m: 2010, K-2 500 m: 2013, K-4 200 m: 2007, 2009, K-4 500 m: 1997, 1998, 2007), and three bronzes (K-1 500 m: 2001, K-1 1000 m: 1999Extended Euclidean algorithm (4,467 words) [view diff] no match in snippet view article find links to article
k + 1 {\displaystyle s_{k+1}} and t k + 1 {\displaystyle t_{k+1}} are coprime. The relation a s k + 1 + b t k + 1 = 0 {\displaystyle as_{k+1}+bt_{k+1}=0}Greatest common divisor (4,717 words) [view diff] exact match in snippet view article find links to article
d 1 − k ζ ( k ) − 1 = ζ ( k − 1 ) ζ ( k ) . {\displaystyle \mathrm {E} (k)=\sum _{d=1}^{\infty }d^{1-k}\zeta (k)^{-1}={\frac {\zeta (k-1)}{\zeta (k)}}Kolmogorov–Smirnov test (3,912 words) [view diff] no match in snippet view article find links to article
k = 1 ∞ ( − 1 ) k − 1 e − 2 k 2 x 2 = 2 π x ∑ k = 1 ∞ e − ( 2 k − 1 ) 2 π 2 / ( 8 x 2 ) , {\displaystyle \operatorname {Pr} (K\leq x)=1-2\sum _{k=1}^{\inftyK-nearest neighbors algorithm (4,316 words) [view diff] no match in snippet view article find links to article
its k nearest neighbors (k is a positive integer, typically small). If k = 1, then the object is simply assigned to the class of that single nearestIan Ferguson (canoeist) (638 words) [view diff] exact match in snippet view article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanCapacitance (4,187 words) [view diff] no match in snippet view article find links to article
with a Z/1 − K impedance between the first node and ground and a KZ/K − 1 impedance between the second node and ground. Since impedance varies inverselyNegative hypergeometric distribution (1,911 words) [view diff] no match in snippet view article find links to article
− 1 k ) ( N − r − k K − k ) ( N K ) = 1 ( N K ) ∑ k = 0 K ( k + r − 1 k ) ( N − r − k K − k ) = 1 ( N K ) ( N K ) = 1 , {\displaystyle \sum _{k=0}^{K}\Pr(X=k)=\sumHodge star operator (6,501 words) [view diff] no match in snippet view article find links to article
i k + 1 , … , i n d x i k + 1 ∧ ⋯ ∧ d x i n . {\displaystyle {\star }\alpha ={\frac {1}{(n-k)!}}({\star }\alpha )_{i_{k+1},\dots ,i_{n}}dx^{i_{k+1}}\wedgeEulerian number (2,460 words) [view diff] no match in snippet view article find links to article
( n , k ) = ∑ i = 0 k ( − 1 ) i ( n + 1 i ) ( k + 1 − i ) n . {\displaystyle A(n,k)=\sum _{i=0}^{k}(-1)^{i}{\binom {n+1}{i}}(k+1-i)^{n}.} For fixed nRate of convergence (5,628 words) [view diff] no match in snippet view article find links to article
x k + 1 − x k x k − x k − 1 | log | x k − x k − 1 x k − 1 − x k − 2 | . {\displaystyle q\approx {\frac {\log \left|\displaystyle {\frac {x_{k+12021 ICF Canoe Sprint World Championships (447 words) [view diff] exact match in snippet view article find links to article
September 2021. "Men's K-1 200" (PDF). Retrieved 19 September 2021. "Men's K-1 500" (PDF). Retrieved 19 September 2021. "Men's K-1 1000" (PDF). RetrievedChebyshev polynomials (11,177 words) [view diff] no match in snippet view article find links to article
k ) ( 1 − x − 2 ) k = n 2 ∑ k = 0 ⌊ n 2 ⌋ ( − 1 ) k ( n − k − 1 ) ! k ! ( n − 2 k ) ! ( 2 x ) n − 2 k for n > 0 = n ∑ k = 0 n ( − 2 ) k ( n + k −Cohen's kappa (3,698 words) [view diff] no match in snippet view article find links to article
following construction: p e = ∑ k p k 12 ^ = ind. ∑ k p k 1 ^ p k 2 ^ = ∑ k n k 1 N n k 2 N = 1 N 2 ∑ k n k 1 n k 2 {\displaystyle p_{e}=\sum _{k}{\widehat {p_{k12}}}{\oversetList of ICF Canoe Sprint World Championships medalists in women's kayak (222 words) [view diff] no match in snippet view article find links to article
This is a list of medalists from the ICF Canoe Sprint World Championships in women's kayak. Debuted: 1994. Debuted: 1938. Not held: 1948. Resumed: 1950Dispersion (water waves) (3,434 words) [view diff] no match in snippet view article
c g = lim k 1 → k 2 ω 1 − ω 2 k 1 − k 2 = lim k 1 → k 2 Ω ( k 1 ) − Ω ( k 2 ) k 1 − k 2 = d Ω ( k ) d k . {\displaystyle c_{g}=\lim _{k_{1}\,\to \,k_{2}}{\frac2019 K-1 Air Base attack (1,303 words) [view diff] exact match in snippet view article find links to article
A rocket attack was carried out on the K-1 Air Base in Kirkuk province in Iraq on 27 December 2019. The air base was one of many Iraqi military bases1999 ICF Canoe Sprint World Championships (79 words) [view diff] exact match in snippet view article find links to article
Time K-1 200 m Caroline Brunet (CAN) Josefa Idem (ITA) Rita Kőbán (HUN) K-1 500 m Caroline Brunet (CAN) Josefa Idem (ITA) Rita Kőbán (HUN) K-1 10002013 ICF Canoe Sprint World Championships (710 words) [view diff] exact match in snippet view article find links to article
Men's C–1 200 m Relay Results Men's K–1 200 m Results Men's K–1 500 m Results Men's K–1 1000 m Results Men's K–1 5000 m Results Men's K–2 200 m ResultsCanoeing at the 1996 Summer Olympics (81 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m men2001 ICF Canoe Sprint World Championships (143 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Ronald Rauhe (GER) Oleksiy Slivinskiy (UKR) Anton Ryakhov (UZB) K-1 500 m Ákos Verecki (HUN) Anton Ryakhov (UZB)Lagrange multiplier (7,987 words) [view diff] no match in snippet view article find links to article
∇ f ( x ) = ∑ k = 1 M λ k ∇ g k ( x ) ⟺ ∇ f ( x ) − ∑ k = 1 M λ k ∇ g k ( x ) = 0 . {\displaystyle \nabla f(\mathbf {x} )=\sum _{k=1}^{M}\lambda _{k}\Fermat number (4,717 words) [view diff] no match in snippet view article find links to article
( 2 k + 1 ) . {\displaystyle (2^{r}+1)\mid (2^{k}+1).} Because 1 < 2 r + 1 < 2 k + 1 {\displaystyle 1<2^{r}+1<2^{k}+1} , it follows that 2 k + 1 {\displaystyleZipf's law (4,638 words) [view diff] no match in snippet view article find links to article
&\ {\mbox{ if }}\ k<1\ {\mbox{ or }}\ N<k~.\end{cases}}} where HN is a normalization constant: The Nth harmonic number: H N ≡ ∑ k = 1 N 1 k . {\displaystyleList of fighting games (2,012 words) [view diff] exact match in snippet view article find links to article
Fu Factory K-1 World GP K-1 World GP 2006 K-1 Premium 2005 Dynamite!! K-1 World GP 2005 K-1 World Max 2005 K-1 Premium 2004 Dynamite!! K-1 World GrandDirichlet-multinomial distribution (6,950 words) [view diff] exact match in snippet view article find links to article
^{k}|n_{1}+\cdots +n_{k}=n\}.\,} Its number of elements is ( n + k − 1 k − 1 ) . {\displaystyle {n+k-1 \choose k-1}.} In matrix notation, E ( X ) = n p , {\displaystyleDiscretization (2,400 words) [view diff] no match in snippet view article find links to article
− τ ) B u ( τ ) d τ x [ k + 1 ] = e A ( k + 1 ) T x ( 0 ) + ∫ 0 ( k + 1 ) T e A [ ( k + 1 ) T − τ ] B u ( τ ) d τ x [ k + 1 ] = e A T [ e A k T x ( 0Polytope (3,119 words) [view diff] case mismatch in snippet view article find links to article
context, "flat sides" means that the sides of a (k + 1)-polytope consist of k-polytopes that may have (k – 1)-polytopes in common. Some theories further generalizeLevi-Civita symbol (5,174 words) [view diff] no match in snippet view article find links to article
2-spinors. In three dimensions, the Levi-Civita symbol is defined by: ε i j k = { + 1 if ( i , j , k ) is ( 1 , 2 , 3 ) , ( 2 , 3 , 1 ) , or ( 3 , 1 ,Aleksandr Shaparenko (208 words) [view diff] exact match in snippet view article find links to article
1972: K-1 1000 m) and one silver (1968: K-1 1000 m). Shaparenko also won 13 medals at the ICF Canoe Sprint World Championships with seven golds (K-1 1000Rita Kőbán (398 words) [view diff] exact match in snippet view article find links to article
(K-1 200 m: 1994, 1995; K-1 500 m: 1995, K-2 200 m: 1994, K-4 200 m: 1994, 1998, 1999; K-4 500 m: 1986, 1999), ten silvers (K-1 500 m: 1991, 1994; K-1Kelvin (4,784 words) [view diff] no match in snippet view article find links to article
adopted at the 26th CGPM in late 2018, with a value of kB = 1.380649×10−23 J⋅K−1. In fundamental physics, the mapping E=kBT which converts between the characteristic1999 ICF Canoe Sprint World Championships (79 words) [view diff] exact match in snippet view article find links to article
Time K-1 200 m Caroline Brunet (CAN) Josefa Idem (ITA) Rita Kőbán (HUN) K-1 500 m Caroline Brunet (CAN) Josefa Idem (ITA) Rita Kőbán (HUN) K-1 10002001 ICF Canoe Sprint World Championships (143 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Ronald Rauhe (GER) Oleksiy Slivinskiy (UKR) Anton Ryakhov (UZB) K-1 500 m Ákos Verecki (HUN) Anton Ryakhov (UZB)Lebesgue integral (5,919 words) [view diff] no match in snippet view article find links to article
positive, we set ∫ ( ∑ k a k 1 S k ) d μ = ∑ k a k ∫ 1 S k d μ = ∑ k a k μ ( S k ) {\displaystyle \int \left(\sum _{k}a_{k}1_{S_{k}}\right)\,d\mu =\sumPercentile (2,647 words) [view diff] no match in snippet view article find links to article
C} , and v = v k + P − p k p k + 1 − p k ( v k + 1 − v k ) . {\displaystyle v=v_{k}+{\frac {P-p_{k}}{p_{k+1}-p_{k}}}(v_{k+1}-v_{k}).} The 50% weighted percentileFundamental theorem of algebra (7,621 words) [view diff] no match in snippet view article find links to article
( z − z 0 ) k + c k + 1 ( z − z 0 ) k + 1 + ⋯ + c n ( z − z 0 ) n . {\displaystyle p(z)=a+c_{k}(z-z_{0})^{k}+c_{k+1}(z-z_{0})^{k+1}+\cdots +c_{n}(z-z_{0})^{n}General Leibniz rule (1,247 words) [view diff] no match in snippet view article find links to article
_{t=1}^{m}k_{t}=n,} and ( n k 1 , k 2 , … , k m ) = n ! k 1 ! k 2 ! ⋯ k m ! {\displaystyle {n \choose k_{1},k_{2},\ldots ,k_{m}}={\frac {n!}{k_{1}!\,k_{2}!\cdots1 + 2 + 3 + 4 + ⋯ (4,221 words) [view diff] no match in snippet view article find links to article
partial sum of the series is the triangular number ∑ k = 1 n k = n ( n + 1 ) 2 , {\displaystyle \sum _{k=1}^{n}k={\frac {n(n+1)}{2}},} which increases without(a,b,0) class of distributions (797 words) [view diff] exact match in snippet view article
satisfies the recurrence formula p k p k − 1 = a + b k , k = 1 , 2 , 3 , … {\displaystyle {\frac {p_{k}}{p_{k-1}}}=a+{\frac {b}{k}},\qquad k=1,2,3,\dotsPartial fraction decomposition (7,008 words) [view diff] exact match in snippet view article find links to article
\deg H_{k}<\deg G.} Setting F k − 1 = F C + Q , {\displaystyle F_{k-1}=FC+Q,} one gets F G k = H k G k + F k − 1 G k − 1 , {\displaystyle {\frac {F}{G^{k}}}={\fracAlmost prime (402 words) [view diff] exact match in snippet view article find links to article
log log n ) k − 1 ( k − 1 ) ! , {\displaystyle \pi _{k}(n)\sim \left({\frac {n}{\log n}}\right){\frac {(\log \log n)^{k-1}}{(k-1)!}},} a result ofRonald Rauhe (647 words) [view diff] exact match in snippet view article find links to article
years older he won two medals – gold in the K-4 500 m and silver in the K-1 500 m, an unprecedented achievement for a fifteen-year-old. After winningColor index (1,031 words) [view diff] no match in snippet view article find links to article
formula (also implemented in the PyAstronomy package for Python): T = 4600 K ( 1 0.92 ( B - V ) + 1.7 + 1 0.92 ( B - V ) + 0.62 ) . {\displaystyle T=4600\Lah number (1,812 words) [view diff] exact match in snippet view article find links to article
, k − 1 ) = k ( k + 1 ) L ( n , k + 1 ) + 2 k L ( n , k ) + L ( n , k − 1 ) {\displaystyle {\begin{aligned}L(n+1,k)&=(n+k)L(n,k)+L(n,k-1)\\&=k(k+1)L(nSquare wave (waveform) (1,295 words) [view diff] no match in snippet view article
an infinite sum of sinusoidal waves: x ( t ) = 4 π ∑ k = 1 ∞ sin ( 2 π ( 2 k − 1 ) f t ) 2 k − 1 = 4 π ( sin ( ω t ) + 1 3 sin ( 3 ω t ) + 1 5 sinHermite polynomials (12,119 words) [view diff] exact match in snippet view article find links to article
k + 1 ) a n , k + 1 k = 0 , a n , k − 1 − ( k + 1 ) a n , k + 1 k > 0 , {\displaystyle a_{n+1,k}={\begin{cases}-(k+1)a_{n,k+1}&k=0,\\a_{n,k-1}-(k+1)a_{nTensor algebra (4,161 words) [view diff] no match in snippet view article find links to article
one has scalar multiplication on the field: k 1 ⊗ k 2 = k 1 k 2 . {\displaystyle k_{1}\otimes k_{2}=k_{1}k_{2}.} The most difficult to verify is the compatibilityMie scattering (9,207 words) [view diff] no match in snippet view article find links to article
{M} _{o1n}^{(1)}(k_{1},\mathbf {r} )\right),} H 1 = − k 1 ω μ 1 ∑ n = 1 ∞ E n ( d n M e 1 n ( 1 ) ( k 1 , r ) + i c n N o 1 n ( 1 ) ( k 1 , r ) ) . {\displaystyleCanoeing at the 1992 Summer Olympics (88 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menMoiré pattern (4,166 words) [view diff] no match in snippet view article find links to article
= k 1 + k 2 2 {\displaystyle A={\frac {k_{1}+k_{2}}{2}}} and B = k 1 − k 2 2 . {\displaystyle B={\frac {k_{1}-k_{2}}{2}}.} This function average, f32022 ICF Canoe Sprint World Championships (70 words) [view diff] exact match in snippet view article find links to article
C-2 1000m men C-4 500m men women Kayak events K-1 200m men women K-1 500m men women K-1 1000m men women K-1 5000m men women K-2 200m women K-2 500m menCharacteristic polynomial (3,040 words) [view diff] exact match in snippet view article find links to article
A^{k}} because A k v = A k − 1 A v = λ A k − 1 v = ⋯ = λ k v . {\displaystyle A^{k}{\textbf {v}}=A^{k-1}A{\textbf {v}}=\lambda A^{k-1}{\textbf {v}}=\dots =\lambdaHypoexponential distribution (1,758 words) [view diff] no match in snippet view article find links to article
finite state Markov process. If we have a k+1 state process, where the first k states are transient and the state k+1 is an absorbing state, then the distributionSquare triangular number (1,478 words) [view diff] exact match in snippet view article find links to article
x k + 1 = 2 x k x 1 − x k − 1 , y k + 1 = 2 y k x 1 − y k − 1 . {\displaystyle \displaystyle {\begin{aligned}x_{k+1}&=2x_{k}x_{1}-x_{k-1},\\y_{k+1}&=2y_{k}x_{1}-y_{k-1}Borosilicate glass (3,691 words) [view diff] no match in snippet view article find links to article
are known for having very low coefficients of thermal expansion (≈3 × 10−6 K−1 at 20 °C), making them more resistant to thermal shock than any other commonMaximum entropy probability distribution (4,530 words) [view diff] no match in snippet view article find links to article
x k } = p k for k = 1 , 2 , … {\displaystyle \operatorname {Pr} \{\ X=x_{k}\}=p_{k}\qquad ~{\mbox{ for }}~\quad k=1,\ 2,\ \ldots ~} then theFerenc Csipes (356 words) [view diff] exact match in snippet view article find links to article
with eight golds (K-1 1000 m: 1985, K-1 10000 m: 1986, K-2 500 m: 1987, K-4 1000 m: 1986, 1987, 1989, 1990, 1991), four silvers (K-1 1000 m: 1986, 1987Reversible reaction (894 words) [view diff] no match in snippet view article find links to article
at the final kinetic expression: [ A ] = k -1 [ A ] 0 k 1 + k -1 + k 1 [ A ] 0 k 1 + k -1 exp ( − k 1 + k -1 ) t {\displaystyle [A]={\fracSquared triangular number (1,867 words) [view diff] no match in snippet view article find links to article
mathematical notation for summation: ∑ k = 1 n k 3 = ( ∑ k = 1 n k ) 2 . {\displaystyle \sum _{k=1}^{n}k^{3}=\left(\sum _{k=1}^{n}k\right)^{2}.} This identityFriedman test (1,169 words) [view diff] no match in snippet view article find links to article
12 n k ( k + 1 ) ∑ j = 1 k ( r ¯ ⋅ j − k + 1 2 ) 2 {\displaystyle Q={\frac {12n}{k(k+1)}}\sum _{j=1}^{k}\left({\bar {r}}_{\cdot j}-{\frac {k+1}{2}}\right)^{2}}Yule–Simon distribution (1,312 words) [view diff] exact match in snippet view article find links to article
is an integer, f ( k ; ρ ) = ρ ρ ! ( k − 1 ) ! ( k + ρ ) ! . {\displaystyle f(k;\rho )={\frac {\rho \,\rho !\,(k-1)!}{(k+\rho )!}}.} The parameter ρ {\displaystylePerfect digital invariant (5,240 words) [view diff] no match in snippet view article find links to article
1 ) ( 3 k + 1 ) − k ( 3 k + 1 ) = ( k + 1 ) ( 3 k + 1 ) ( 3 k + 1 ) − k ( 3 k + 1 ) = k ( 3 k + 1 ) ( 3 k + 1 ) + ( 3 k + 1 ) ( 3 k + 1 ) − k ( 3 k +Faà di Bruno's formula (3,788 words) [view diff] no match in snippet view article find links to article
noticing that m j {\displaystyle m_{j}} has to be zero for j > n − k + 1 {\displaystyle j>n-k+1} leads to a somewhat simpler formula expressed in terms of partialCross-polytope (1,106 words) [view diff] no match in snippet view article find links to article
is thus given by (see binomial coefficient): 2 k + 1 ( n k + 1 ) {\displaystyle 2^{k+1}{n \choose {k+1}}} The extended f-vector for an n-orthoplex canMathematical economics (13,624 words) [view diff] no match in snippet view article find links to article
) k / ( 1 − τ ) {\textstyle dw/d\tau =-f'(k)k/(1-\tau )} , we have that: d w d x = − f ′ ( k ) k 1 − τ f ′ ( k ) 1 − τ [ τ f ′ ( k ) f ″ ( k ) + k ] =Half-logistic distribution (247 words) [view diff] no match in snippet view article find links to article
2F(k) − 1 is the cdf of a half-logistic distribution. Specifically, G ( k ) = 1 − e − k 1 + e − k for k ≥ 0. {\displaystyle G(k)={\frac {1-e^{-k}}{1+e^{-k}}}{\text{Vampire number (730 words) [view diff] exact match in snippet view article find links to article
digits: A = a k a k − 1 . . . a 1 {\displaystyle A={a_{k}}{a_{k-1}}...{a_{1}}} B = b k b k − 1 . . . b 1 {\displaystyle B={b_{k}}{b_{k-1}}...{b_{1}}} suchLeast squares (5,702 words) [view diff] no match in snippet view article find links to article
are obtained by successive approximation: β j k + 1 = β j k + Δ β j , {\displaystyle {\beta _{j}}^{k+1}={\beta _{j}}^{k}+\Delta \beta _{j},} where a superscriptKnot theory (6,292 words) [view diff] no match in snippet view article find links to article
{R} ^{3}} , with the only "non-injectivity" being K ( 0 ) = K ( 1 ) {\displaystyle K(0)=K(1)} . Topologists consider knots and other entanglements suchAutoregressive model (5,421 words) [view diff] no match in snippet view article find links to article
expressed as [citation needed] ρ ( τ ) = ∑ k = 1 p a k y k − | τ | , {\displaystyle \rho (\tau )=\sum _{k=1}^{p}a_{k}y_{k}^{-|\tau |},} where y k {\displaystyleSawtooth wave (1,102 words) [view diff] no match in snippet view article find links to article
sawtooth ( t ) = − 2 a π ∑ k = 1 ∞ ( − 1 ) k sin ( 2 π k f t ) k {\displaystyle x_{\text{sawtooth}}(t)=-{\frac {2a}{\pi }}\sum _{k=1}^{\infty }{(-1)}^{k}{\frac2019 ICF Canoe Sprint World Championships (1,279 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200, 500, 1000 or 5000 metres2005 ICF Canoe Sprint World Championships (330 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Carlos Pérez (ESP) 35.289 Tomasz Mendelski (POL) 35.697 Anton Ryakhov (RUS) 35.733 K-1 500 m Nathan Baggaley (AUS)Canoeing at the 1976 Summer Olympics (76 words) [view diff] exact match in snippet view article find links to article
in the Montreal program though four 500 m events for men were (C-1, C-2, K-1, and K-2). 1976 Summer Olympics official report Volume 3. pp. 167–85. (inCube (algebra) (3,026 words) [view diff] exact match in snippet view article
well-known identity: n 2 = ∑ k = 1 n ( 2 k − 1 ) , {\displaystyle n^{2}=\sum _{k=1}^{n}(2k-1),} we obtain the following derivation: ∑ k = 1 n k 3 = 1 + 8 + 27 +2019 ICF Canoe Sprint World Championships (1,279 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200, 500, 1000 or 5000 metresCube (algebra) (3,026 words) [view diff] exact match in snippet view article
well-known identity: n 2 = ∑ k = 1 n ( 2 k − 1 ) , {\displaystyle n^{2}=\sum _{k=1}^{n}(2k-1),} we obtain the following derivation: ∑ k = 1 n k 3 = 1 + 8 + 27 +2006 ICF Canoe Sprint World Championships (337 words) [view diff] exact match in snippet view article find links to article
final, giving Mexico their first-ever world championship gold medal. The K-1 1000 m, the Blue Riband event, was won by Markus Oscarsson of Sweden. Germany'sZeta distribution (1,030 words) [view diff] no match in snippet view article find links to article
defined for positive integers k ≥ 1 {\displaystyle k\geq 1} , and its probability mass function is given by P ( x = k ) = 1 ζ ( s ) k − s , {\displaystyleZsolt Gyulay (337 words) [view diff] exact match in snippet view article find links to article
(1988: K-1 500 m, K-4 1000 m) and two silver (1992: K-1 500 m, K-4 1000 m). He also won fourteen medals at the world championships: six golds (K-1 1000Droop quota (2,336 words) [view diff] no match in snippet view article find links to article
and truncate: ⌈ total votes k + 1 ⌉ ≈ ⌊ total votes k + 1 + 1 ⌋ {\displaystyle \left\lceil {\frac {\text{total votes}}{k+1}}\right\rceil \approx \left\lfloorDistortion (optics) (2,784 words) [view diff] no match in snippet view article
given by x d = x c + x u − x c 2 K 1 r u 2 ( 1 − 1 − 4 K 1 r u 2 ) y d = y c + y u − y c 2 K 1 r u 2 ( 1 − 1 − 4 K 1 r u 2 ) , {\displaystyle {\begin{aligned}x_{\mathrmPerfect digital invariant (5,240 words) [view diff] no match in snippet view article find links to article
1 ) ( 3 k + 1 ) − k ( 3 k + 1 ) = ( k + 1 ) ( 3 k + 1 ) ( 3 k + 1 ) − k ( 3 k + 1 ) = k ( 3 k + 1 ) ( 3 k + 1 ) + ( 3 k + 1 ) ( 3 k + 1 ) − k ( 3 k +Markov chain (12,894 words) [view diff] no match in snippet view article find links to article
X_{0}=i)>0\}} The state is periodic if k > 1 {\displaystyle k>1} ; otherwise k = 1 {\displaystyle k=1} and the state is aperiodic. A state i is saidRoot of unity (5,939 words) [view diff] no match in snippet view article find links to article
of unity, as ( z k ) n = z k n = ( z n ) k = 1 k = 1. {\displaystyle (z^{k})^{n}=z^{kn}=(z^{n})^{k}=1^{k}=1.} This is also true for negative exponentsKen Wallace (canoeist) (270 words) [view diff] exact match in snippet view article
gold in the K-1 500 m and bronze in the K-1 1000 m events. He also won two medals at the ICF Canoe Sprint World Championships with a gold (K-1 5000 m: 2010)Gauss–Kuzmin distribution (569 words) [view diff] no match in snippet view article find links to article
_{2}\left(1-{\frac {1}{(1+k)^{2}}}\right)~.} Let x = 1 k 1 + 1 k 2 + ⋯ {\displaystyle x={\cfrac {1}{k_{1}+{\cfrac {1}{k_{2}+\cdots }}}}} be the continued fractionRegular polygon (3,223 words) [view diff] no match in snippet view article find links to article
{1}{n}}\sum _{i=1}^{n}d_{i}^{2m}} , then S n ( 2 m ) = ( S n ( 2 ) ) m + ∑ k = 1 ⌊ m / 2 ⌋ ( m 2 k ) ( 2 k k ) R 2 k ( S n ( 2 ) − R 2 ) k ( S n ( 2 ) )Abel's test (1,047 words) [view diff] no match in snippet view article find links to article
absolutely: ∑ k = 1 ∞ | ( a k − a k − 1 ) z k | = ∑ k = 1 ∞ | a k − a k − 1 | ⋅ | z | k ≤ ∑ k = 1 ∞ ( a k − 1 − a k ) {\displaystyle \sum _{k=1}^{\inftyDiscrete phase-type distribution (596 words) [view diff] no match in snippet view article find links to article
distribution function is F ( k ) = 1 − τ T k 1 , {\displaystyle F(k)=1-{\boldsymbol {\tau }}{T}^{k}\mathbf {1} ,} for k = 1 , 2 , . . . {\displaystyle k=1Lewandowski-Kurowicka-Joe distribution (425 words) [view diff] no match in snippet view article find links to article
k = 1 d − 1 ( 2 η − 2 + d − k ) ( d − k ) ∏ k = 1 d − 1 [ B ( η + ( d − k − 1 ) / 2 , η + ( d − k − 1 ) / 2 ) ] d − k {\displaystyle C=2^{\sum _{k=1}^{d-1}(2\eta2007 ICF Canoe Sprint World Championships (267 words) [view diff] exact match in snippet view article find links to article
K-2 races were ruled by the German paddlers. However, Katalin Kovács won K-1 1000 m and 500 m, and gained two silvers in the K-4 events, while formerCaroline Brunet (212 words) [view diff] exact match in snippet view article find links to article
(K-1 200 m: 1997, 1998, 1999, 2003; K-1 500 m: 1997, 1998, 1999; K-1 1000 m: 1997, 1999; K-4 200 m: 1995), seven silvers (K-1 200 m: 1995, 2002; K-1 500Natasa Dusev-Janics (717 words) [view diff] exact match in snippet view article find links to article
won 26 medals at the ICF Canoe Sprint World Championships with 20 golds (K-1 200 m: 2007, 2009, 2010; K-2 200 m: 2005, 2006, 2009, 2010; K-2 500 m: 2005Phytomenadione (1,334 words) [view diff] no match in snippet view article find links to article
Phytomenadione, also known as vitamin K1, phylloquinone, or phytonadione, is a vitamin found in food and used as a dietary supplement. It is on the WorldLists of integrals (5,611 words) [view diff] no match in snippet view article find links to article
( x ) − ( − 1 ) n d n f ( x ) d x n ) d x = e x ∑ k = 1 n ( − 1 ) k − 1 d k − 1 f ( x ) d x k − 1 + C {\displaystyle \int {e^{x}\left(f\left(x\rightCumulant (8,867 words) [view diff] exact match in snippet view article find links to article
∑ k = 1 n ( − 1 ) k − 1 ( k − 1 ) ! B n , k ( μ 1 ′ , … , μ n − k + 1 ′ ) , {\displaystyle \kappa _{n}=\sum _{k=1}^{n}(-1)^{k-1}(k-1)!B_{n,k}(\mu '_{1}Proof that 22/7 exceeds π (2,814 words) [view diff] no match in snippet view article find links to article
≥ 0 and ℓ ≥ 2 we have x k ( 1 − x ) ℓ = ( 1 − 2 x + x 2 ) x k ( 1 − x ) ℓ − 2 = ( 1 + x 2 ) x k ( 1 − x ) ℓ − 2 − 2 x k + 1 ( 1 − x ) ℓ − 2 . {\displaystyleInitial condition (1,362 words) [view diff] exact match in snippet view article find links to article
d t k + a k − 1 d k − 1 x d t k − 1 + ⋯ + a 1 d x d t + a 0 x = 0. {\displaystyle {\frac {d^{k}x}{dt^{k}}}+a_{k-1}{\frac {d^{k-1}x}{dt^{k-1}}}+\cdotsArithmetic function (7,550 words) [view diff] no match in snippet view article find links to article
k 1 , n ) = 1 1 ≤ k 1 , k 2 , … , k s ≤ n gcd ( k 1 − 1 , k 2 , … , k s , n ) = φ ( n ) σ s − 1 ( n ) . {\displaystyle \sum _{\stackrel {1\leq k_{1}Iterative method (1,546 words) [view diff] no match in snippet view article find links to article
defined as M x k + 1 = N x k + b , k ≥ 0 , {\displaystyle M\mathbf {x} ^{k+1}=N\mathbf {x} ^{k}+b,\quad k\geq 0,} or, equivalently, x k + 1 = x k + M − 1Factorion (1,282 words) [view diff] exact match in snippet view article find links to article
the following: SFD b ( n ) = ∑ i = 0 k − 1 d i ! . {\displaystyle \operatorname {SFD} _{b}(n)=\sum _{i=0}^{k-1}d_{i}!.} where k = ⌊ log b n ⌋ + 1 {\displaystyleQuasi-Newton method (2,264 words) [view diff] no match in snippet view article find links to article
approximate Hessian B k + 1 {\displaystyle B_{k+1}} , or directly its inverse H k + 1 = B k + 1 − 1 {\displaystyle H_{k+1}=B_{k+1}^{-1}} using the Sherman–MorrisonPower rule (2,631 words) [view diff] exact match in snippet view article find links to article
i.e. d d x x k = k x k − 1 . {\displaystyle {\frac {d}{dx}}x^{k}=kx^{k-1}.} When n = k + 1 {\displaystyle n=k+1} , d d x x k + 1 = d d x ( x k ⋅ x ) =Characteristic function (probability theory) (5,208 words) [view diff] no match in snippet view article
) − k 1 ( 1 − θ i t ) − k 2 = ( 1 − θ i t ) − ( k 1 + k 2 ) . {\displaystyle \varphi _{X+Y}(t)=\varphi _{X}(t)\varphi _{Y}(t)=(1-\theta it)^{-k_{1}}(1-\thetaBirth–death process (3,948 words) [view diff] exact match in snippet view article find links to article
= λ k − 1 p k − 1 ( t ) + μ k + 1 p k + 1 ( t ) − ( λ k + μ k ) p k ( t ) , k = 1 , 2 , … , {\displaystyle p_{k}^{\prime }(t)=\lambda _{k-1}p_{k-1}(t)+\muCanoeing at the 1984 Summer Olympics (66 words) [view diff] exact match in snippet view article find links to article
Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m men women K-2 1000 m men K-4 500 m women K-4Probability mass function (1,539 words) [view diff] exact match in snippet view article find links to article
success. Its probability mass function is p X ( k ) = ( 1 − p ) k − 1 p {\textstyle p_{X}(k)=(1-p)^{k-1}p} . An example is tossing a coin until the firstPopulation model (734 words) [view diff] no match in snippet view article find links to article
equations: d N 1 d t = r 1 N 1 K 1 − N 1 − α N 2 K 1 {\displaystyle {\frac {dN_{1}}{dt}}=r_{1}N_{1}{\frac {K_{1}-N_{1}-\alpha N_{2}}{K_{1}}}\,} Island biogeography:2009 ICF Canoe Sprint World Championships (3,937 words) [view diff] exact match in snippet view article find links to article
men's 500 m events (C-1, C-2, K-1 and K-2) at the Summer Olympics with the 200 m events (men's C-1, K-1 and K-2; and women's K-1) for the upcoming Summer OlympicsCholesky decomposition (8,335 words) [view diff] no match in snippet view article find links to article
for k = 1:n r = sqrt(L(k, k)^2 + x(k)^2); c = r / L(k, k); s = x(k) / L(k, k); L(k, k) = r; if k < n L((k+1):n, k) = (L((k+1):n, k) + s * x((k+1):n))Raman Piatrushenka (603 words) [view diff] exact match in snippet view article find links to article
m bronze. In the K-1 1000m however, he could only finish 17th. At the 2002 European under-23 Championships in Zagreb, he won the K-1 1000 m gold medalMerit order (2,602 words) [view diff] no match in snippet view article find links to article
total welfare is then W = ∑ k = 1 n V k ( D k ) − ∑ k = 1 n C k ( S k ) {\displaystyle W=\sum _{k=1}^{n}V_{k}(D_{k})-\sum _{k=1}^{n}C_{k}(S_{k})} The economicGaussian elimination (4,368 words) [view diff] exact match in snippet view article find links to article
R_{i}} with r k , k R i − r i , k R k r k − 1 , k − 1 . {\textstyle {\frac {r_{k,k}R_{i}-r_{i,k}R_{k}}{r_{k-1,k-1}}}.} This produces a row echelon formInterior product (1,587 words) [view diff] no match in snippet view article find links to article
i = k + 1 n ( ∂ i a ) d ξ i ∧ d ξ 2 ∧ ⋯ ∧ d ξ k , d α = ∑ i = k + 1 n ( ∂ i a ) d ξ i ∧ d ξ 1 ∧ d ξ 2 ∧ ⋯ ∧ d ξ k , ι X ( d α ) = − ∑ i = k + 1 n ( ∂1998 ICF Canoe Sprint World Championships (77 words) [view diff] exact match in snippet view article find links to article
K-1 200 m Caroline Brunet (CAN) Josefa Idem (ITA) Éva Dónusz (HUN) K-1 500 m Caroline Brunet (CAN) Katrin Borchert (AUS) Josefa Idem (ITA) K-1 1000Vibration (7,235 words) [view diff] no match in snippet view article find links to article
defined by the following formula. X = F 0 k 1 ( 1 − r 2 ) 2 + ( 2 ζ r ) 2 . {\displaystyle X={F_{0} \over k}{1 \over {\sqrt {(1-r^{2})^{2}+(2\zeta r)^{2}}}}Projection (linear algebra) (5,806 words) [view diff] no match in snippet view article
i 2 1 ≤ i ≤ k 1 k + 1 ≤ i ≤ n − k 0 otherwise {\displaystyle \sigma _{i}={\begin{cases}{\sqrt {1+\gamma _{i}^{2}}}&1\leq i\leq k\\1&k+1\leq i\leqCauchy–Schwarz inequality (5,175 words) [view diff] no match in snippet view article find links to article
⟩ | 2 = | ∑ k = 1 n u k v ¯ k | 2 ≤ ⟨ u , u ⟩ ⟨ v , v ⟩ = ( ∑ k = 1 n u k u ¯ k ) ( ∑ k = 1 n v k v ¯ k ) = ∑ j = 1 n | u j | 2 ∑ k = 1 n | v k | 2Random forest (6,483 words) [view diff] no match in snippet view article find links to article
function, or connection function is K k c c ( x , z ) = ∑ k 1 , … , k d , ∑ j = 1 d k j = k k ! k 1 ! ⋯ k d ! ( 1 d ) k ∏ j = 1 d 1 ⌈ 2 k j x j ⌉ = ⌈ 2 kCyclic permutation (2,039 words) [view diff] no match in snippet view article find links to article
= ( k k + 1 ) ⋅ ( k + 1 k + 2 ) ⋯ ( l − 1 l ) ⋅ ( l − 2 l − 1 ) ⋯ ( k k + 1 ) . {\displaystyle (k~~l)=(k~~k+1)\cdot (k+1~~k+2)\cdots2003 ICF Canoe Sprint World Championships (217 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Ronald Rauhe (GER) 35.798 Vince Fehérvári (AUS) 36.411 Anton Ryakhov (UZB) 36.417 K-1 500 m Nathan Baggaley (AUS)Schröder–Bernstein theorem (2,374 words) [view diff] no match in snippet view article find links to article
x = ∑ k = 1 ∞ a k ⋅ 10 − k {\displaystyle x=\sum _{k=1}^{\infty }a_{k}\cdot 10^{-k}} and y = ∑ k = 1 ∞ b k ⋅ 10 − k {\displaystyle y=\sum _{k=1}^{\inftyNewton's identities (7,644 words) [view diff] case mismatch in snippet view article find links to article
including general relativity. Let x1, ..., xn be variables, denote for k ≥ 1 by pk(x1, ..., xn) the k-th power sum: p k ( x 1 , … , x n ) = ∑ i = 1 nNewton's identities (7,644 words) [view diff] case mismatch in snippet view article find links to article
including general relativity. Let x1, ..., xn be variables, denote for k ≥ 1 by pk(x1, ..., xn) the k-th power sum: p k ( x 1 , … , x n ) = ∑ i = 1 nHSL and HSV (10,785 words) [view diff] case mismatch in snippet view article find links to article
f ( n ) = L − a max ( − 1 , min ( k − 3 , 9 − k , 1 ) ) {\displaystyle f(n)=L-a\max(-1,\min(k-3,9-k,1))} where k , n ∈ R ≥ 0 {\displaystyle k,n\in \mathbbHeat exchanger (9,485 words) [view diff] no match in snippet view article find links to article
where k 1 = γ / J 1 {\displaystyle k_{1}=\gamma /J_{1}} , k 2 = γ / J 2 {\displaystyle k_{2}=\gamma /J_{2}} , k = k 1 + k 2 {\displaystyle k=k_{1}+k_{2}}Canoeing at the 2000 Summer Olympics (131 words) [view diff] exact match in snippet view article find links to article
Slalom C-1 men C-2 men K-1 men women Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m menGauss–Markov theorem (4,717 words) [view diff] no match in snippet view article find links to article
variable β K + 1 {\displaystyle \beta _{K+1}} with a newly introduced last column of X being unity i.e., X i ( K + 1 ) = 1 {\displaystyle X_{i(K+1)}=1} forFunction of several complex variables (17,688 words) [view diff] no match in snippet view article find links to article
∂ k 1 + ⋯ + k n f ( ζ 1 , ζ 2 , … , ζ n ) ∂ z 1 k 1 ⋯ ∂ z n k n | ≤ M k 1 ! ⋯ k n ! r 1 k 1 ⋯ r n k n {\displaystyle \left|{\frac {\partial ^{k_{1}+\cdotsTriple DES (2,946 words) [view diff] no match in snippet view article find links to article
would be to use two keys ( K 1 , K 2 ) {\displaystyle (K1,K2)} instead of one, and encrypt each block twice: E K 2 ( E K 1 ( plaintext ) ) {\displaystyleFourier series (11,131 words) [view diff] no match in snippet view article find links to article
1 1 φ ( y ) cos ( 2 k + 1 ) π y 2 d y = ∫ − 1 1 ( a cos π y 2 cos ( 2 k + 1 ) π y 2 + a ′ cos 3 π y 2 cos ( 2 k + 1 ) π y 2 + ⋯ ) d y {\displaystyleBotond Storcz (378 words) [view diff] exact match in snippet view article find links to article
medals at the ICF Canoe Sprint World Championships with four golds (K-1 500 m: 1997, K-1 1000 m: 1997, K-4 500 m: 1997, K-4 1000 m: 1999), five silvers (K-2Hypocycloid (1,350 words) [view diff] exact match in snippet view article find links to article
( k − 1 ) cos θ + r cos ( ( k − 1 ) θ ) y ( θ ) = r ( k − 1 ) sin θ − r sin ( ( k − 1 ) θ ) {\displaystyle {\begin{aligned}&x(\theta )=r(k-1)\cos2002 ICF Canoe Sprint World Championships (136 words) [view diff] exact match in snippet view article find links to article
Event Gold Silver Bronze K-1 200 m Ronald Rauhe (GER) Anton Ryakhov (UZB) Roman Petrukanecas (LTU) K-1 500 m Nathan Baggaley (AUS) Petar Merkov (BUL)Monotone convergence theorem (5,489 words) [view diff] no match in snippet view article find links to article
k ( x ) ≤ f k + 1 ( x ) {\displaystyle (1-\varepsilon )s(x)\leq f_{k}(x)\leq f_{k+1}(x)} so x ∈ B k + 1 s , ε . {\displaystyle x\in B_{k+1}^{s,\varepsilonArithmetico-geometric sequence (2,160 words) [view diff] no match in snippet view article find links to article
arithmetico-geometric series has the form S n = ∑ k = 1 n A k G k = ∑ k = 1 n ( a + ( k − 1 ) d ) b r k − 1 = b ∑ k = 0 n − 1 ( a + k d ) r k = a b + ( aStandard RAID levels (4,551 words) [view diff] exact match in snippet view article find links to article
{\displaystyle D} as polynomials D = d k − 1 x k − 1 + d k − 2 x k − 2 + . . . + d 1 x + d 0 {\displaystyle \mathbf {D} =d_{k-1}x^{k-1}+d_{k-2}x^{k-2}+...+d_{1}x+d_{0}}Diagonalizable matrix (4,692 words) [view diff] no match in snippet view article find links to article
1 k 0 0 0 1 k 0 0 0 2 k ] [ 1 0 1 1 2 0 0 1 − 1 ] − 1 = [ 2 − 2 k − 1 + 2 k 2 − 2 k + 1 0 1 0 − 1 + 2 k 1 − 2 k − 1 + 2 k + 1 ] . {\displaystyleYokosuka MXY-7 Ohka (3,234 words) [view diff] exact match in snippet view article find links to article
had the engine of the Model 11 and the airframe of the Model 22. The Ohka K-1 was an unpowered trainer version with water ballast instead of warhead andDick Joyce (rower) (511 words) [view diff] exact match in snippet view article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanNeighbor joining (2,881 words) [view diff] no match in snippet view article find links to article
) d ( a , b ) − ∑ k = 1 5 d ( a , k ) − ∑ k = 1 5 d ( b , k ) {\displaystyle Q_{1}(a,b)=(n-2)d(a,b)-\sum _{k=1}^{5}d(a,k)-\sum _{k=1}^{5}d(b,k)} = ( 5Chain reaction (2,580 words) [view diff] no match in snippet view article find links to article
obtain k 1 [ CH 3 CHO ] − 2 k 4 [ CH 3 ] 2 = 0 {\displaystyle k_{1}{\ce {[CH3CHO]}}-2k_{4}{\ce {[CH3]}}^{2}=0} so that ( 4 ) . . . [ CH 3 ] = k 1 2 k 4Alternating series test (1,828 words) [view diff] no match in snippet view article find links to article
S k − L | ≤ | S k − S k + 1 | = a k + 1 . {\displaystyle \left|S_{k}-L\right\vert \leq \left|S_{k}-S_{k+1}\right\vert =a_{k+1}.\!} Suppose we are givenMaryna Litvinchuk (272 words) [view diff] exact match in snippet view article find links to article
K-1 5000 m 2014 Moscow K-1 5000 m 2018 Montemor-o-Velho K-1 5000 m 2019 Szeged K-4 500 m 2021 Copenhagen K-2 500 m 2011 Szeged K-1 5000 m 2011 Szeged K-42018 ICF Canoe Sprint World Championships (1,178 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200, 500, 1000 or 5000 metresNewton polynomial (5,843 words) [view diff] no match in snippet view article find links to article
are calculated using Newton's divided differences method. Given a set of k + 1 data points ( x 0 , y 0 ) , … , ( x j , y j ) , … , ( x k , y k ) {\displaystyleWrapped normal distribution (1,707 words) [view diff] no match in snippet view article find links to article
expansion for the logarithm: ln ( 1 + x ) = − ∑ k = 1 ∞ ( − 1 ) k k x k {\displaystyle \ln(1+x)=-\sum _{k=1}^{\infty }{\frac {(-1)^{k}}{k}}\,x^{k}} the logarithmic2014 ICF Canoe Sprint World Championships (442 words) [view diff] exact match in snippet view article find links to article
Men's C–1 200 m Relay Results Men's K–1 200 m Results Men's K–1 500 m Results Men's K–1 1000 m Results Men's K–1 5000 m Results Men's K–2 200 m ResultsMultiplicative digital root (965 words) [view diff] exact match in snippet view article find links to article
k − 1 d i b i {\displaystyle n=\sum _{i=0}^{k-1}d_{i}b^{i}} and therefore F b ( n ) = ∏ i = 0 k − 1 d i = d k − 1 ∏ i = 0 k − 2 d i < d k − 1 b k − 1List of ICF Canoe Sprint World Championships medalists in paracanoe (365 words) [view diff] exact match in snippet view article find links to article
2010. Classed as K-1 A before 2015. First contested in 2010. Classed as K-1 TA before 2015. First contested in 2010. Classed as K-1 LTA before 2015. WasRecursion (3,677 words) [view diff] no match in snippet view article find links to article
{\displaystyle k\in \mathbb {N} } . Then F(k + 1) = f(F(k)) = f(G(k)) = G(k + 1). Hence F(k) = G(k) implies F(k + 1) = G(k + 1). By induction, F(n) = G(n) for allGreg Barton (415 words) [view diff] exact match in snippet view article find links to article
Championships with four golds (K-1 1000 m: 1987, K-1 10000 m: 1985, 1987, 1991), a silver (K-1 10000 m: 1990), and a bronze (K-1 1000 m: 1991). He receivedF-test (2,188 words) [view diff] exact match in snippet view article find links to article
1 K n i ( Y ¯ i ⋅ − Y ¯ ) 2 / ( K − 1 ) {\displaystyle \sum _{i=1}^{K}n_{i}({\bar {Y}}_{i\cdot }-{\bar {Y}})^{2}/(K-1)} where Y ¯ i ⋅ {\displaystyle {\barSI derived unit (387 words) [view diff] no match in snippet view article find links to article
conductivity m⋅kg⋅s−3⋅K−1 kelvin per watt K/W thermal resistance m−2⋅kg−1⋅s3⋅K reciprocal kelvin K−1 thermal expansion coefficient K−1 kelvin per metre K/mJosef Dostál (canoeist) (328 words) [view diff] exact match in snippet view article
Summer Olympics in the K-4 1000 m event. He won the silver medal in the K-1 1000 metres event at the 2016 Summer Olympics in Rio de Janeiro. He was alsoGeometric process (858 words) [view diff] no match in snippet view article find links to article
k = 1 , 2 , … } {\displaystyle \{X_{k},k=1,2,\dots \}} , if they are independent and the cdf of X k {\displaystyle X_{k}} is given by F ( a k − 1 xHaralambie Ivanov (233 words) [view diff] exact match in snippet view article find links to article
with four golds (K-1 4 x 500 m: 1963, K-2 500 m: 1963, K-2 1000 m: 1963, K-4 1000 m: 1966), a silver (K-4 1000 m: 1963), and a bronze (K-1 4 x 500 m: 1966)Square root (6,182 words) [view diff] no match in snippet view article find links to article
e k + 1 p k + 1 2 e k + 1 … p n 2 e n = p 1 e 1 … p n e n p 1 … p k . {\displaystyle {\sqrt {p_{1}^{2e_{1}+1}\cdots p_{k}^{2e_{k}+1}p_{k+1}^{2e_{k+1}}\dotsSaúl Craviotto (553 words) [view diff] exact match in snippet view article find links to article
the K-1 200 m event at the 2012 Summer Olympics in London, a gold medal (with Cristian Toro) in the K-2 200 m event and a bronze medal in the K-1 200Sinc function (3,074 words) [view diff] exact match in snippet view article find links to article
k − 1 ∑ n = 1 2 k − 1 cos ( n − 1 / 2 2 k − 1 x ) , ∀ k ≥ 1 , {\displaystyle \prod _{n=1}^{k}\cos \left({\frac {x}{2^{n}}}\right)={\frac {1}{2^{k-1}}}\sumAntonio Rossi (270 words) [view diff] exact match in snippet view article find links to article
in five Summer Olympics, he won five medals which included three golds (K-1 500 m: 1996, K-2 1000 m: 1996, 2000), one silver (K-2 1000 m: 2004), andDivergent series (5,028 words) [view diff] exact match in snippet view article find links to article
if we define the sequence pk by p n k = ( n + k − 1 k − 1 ) {\displaystyle p_{n}^{k}={n+k-1 \choose k-1}} then the Cesàro sum Ck is defined by Ck(s) =List of integrals of exponential functions (3,291 words) [view diff] exact match in snippet view article find links to article
_{k=1}^{n}{\left(-1\right)^{k-1}{\frac {d^{k-1}f\left(x\right)}{dx^{k-1}}}}+C} ∫ e − x ( f ( x ) − d n f ( x ) d x n ) d x = − e − x ∑ k = 1 n d k − 1 fKatrin Wagner-Augustin (325 words) [view diff] exact match in snippet view article find links to article
bronze (K-1 500 m: 2008). Wagner-Augustin also won 26 medals at the ICF Canoe Sprint World Championships with ten golds (K-1 1000 m: 2005, K-1 4 × 200Czech Republic at the Olympics (269 words) [view diff] exact match in snippet view article find links to article
Dostál Canoeing Men's K-1 1000 m Silver Jaroslav Kulhavý Cycling Men's cross-country Bronze Jiří Prskavec Canoeing Men's slalom K-1 Bronze Ondřej SynekConvergence tests (2,228 words) [view diff] no match in snippet view article find links to article
case of p = 1 , k = 1 {\displaystyle p=1,k=1} yields the harmonic series, which diverges. The case of p = 2 , k = 1 {\displaystyle p=2,k=1} is the BaselBirgit Fischer (480 words) [view diff] exact match in snippet view article find links to article
Germany 1980 Moscow K-1 500 m 1988 Seoul K-2 500 m 1988 Seoul K-4 500 m 1988 Seoul K-1 500 m Representing Germany 1992 Barcelona K-1 500 m 1996 AtlantaGroup velocity (3,504 words) [view diff] no match in snippet view article find links to article
x , t ) = cos ( k 1 x − ω 1 t ) + cos ( k 2 x − ω 2 t ) = 2 cos ( ( k 2 − k 1 ) x − ( ω 2 − ω 1 ) t 2 ) cos ( ( k 2 + k 1 ) x − ( ω 2 + ω 1 )Multivariate normal distribution (9,619 words) [view diff] no match in snippet view article find links to article
k 1 {\displaystyle k_{1}} and k 2 {\displaystyle k_{2}} dimensional marginal distributions X {\displaystyle X} and Y {\displaystyle Y} , such that k 1Arnaud Hybois (177 words) [view diff] exact match in snippet view article find links to article
m in 2011), a silver (K-1 4 x 200 m, 2014) and two bronze (K-1 4 x 200 m: 2009, K-1 500 m 2013). Hybois also competed in the K-1 500 m event at the 2008Differential operator (3,693 words) [view diff] no match in snippet view article find links to article
Laplacian operator, defined by Δ = ∇ 2 = ∑ k = 1 n ∂ 2 ∂ x k 2 . {\displaystyle \Delta =\nabla ^{2}=\sum _{k=1}^{n}{\frac {\partial ^{2}}{\partial x_{k}^{2}}}Chain reaction (2,580 words) [view diff] no match in snippet view article find links to article
obtain k 1 [ CH 3 CHO ] − 2 k 4 [ CH 3 ] 2 = 0 {\displaystyle k_{1}{\ce {[CH3CHO]}}-2k_{4}{\ce {[CH3]}}^{2}=0} so that ( 4 ) . . . [ CH 3 ] = k 1 2 k 4Mass–energy equivalence (11,628 words) [view diff] no match in snippet view article find links to article
energy K by an additive constant, which gives K 0 − K 1 = E ( 1 1 − v 2 c 2 − 1 ) {\displaystyle K_{0}-K_{1}=E\left({\frac {1}{\sqrt {1-{\frac {v^{2}}{c^{2}}}}}}-1\right)}Narcissistic number (1,082 words) [view diff] exact match in snippet view article find links to article
{N} } to be the following: F b ( n ) = ∑ i = 0 k − 1 d i k . {\displaystyle F_{b}(n)=\sum _{i=0}^{k-1}d_{i}^{k}.} where k = ⌊ log b n ⌋ + 1 {\displaystyle1st Army (German Empire) (625 words) [view diff] no match in snippet view article
The 1st Army (German: 1. Armee / Armeeoberkommando 1 / A.O.K. 1) was an army level command of the German Army in World War I. It was formed on mobilizationLatent Dirichlet allocation (7,614 words) [view diff] no match in snippet view article find links to article
we get: A = ∑ k = 1 K α β C k ¬ n + V β {\displaystyle A=\sum _{k=1}^{K}{\frac {\alpha \beta }{C_{k}^{\neg n}+V\beta }}} B = ∑ k = 1 K C k d β C k ¬Homothety (2,065 words) [view diff] no match in snippet view article find links to article
for k {\displaystyle k} : for k = 1 {\displaystyle k=1} one gets the identity mapping, for k = − 1 {\displaystyle k=-1} one gets the reflection at theLennart Klingström (144 words) [view diff] exact match in snippet view article find links to article
Sprint World Championships with three golds (K-1 4×500 m: 1948, 1950; K-4 1000 m: 1948) and a silver (K-1 500 m: 1950). Lennart Klingström. Sports-referenceBasel problem (8,692 words) [view diff] no match in snippet view article find links to article
be defined by S n ( x ) x := ∏ k = 1 n ( 1 − x 2 k 2 ⋅ π 2 ) {\displaystyle {\frac {S_{n}(x)}{x}}:=\prod \limits _{k=1}^{n}\left(1-{\frac {x^{2}}{k^{2}\cdotTechnology (10,447 words) [view diff] no match in snippet view article find links to article
Yael; Chazan, Michael; Arnold, M.; Aumaître, G.; Bourlès, D.; Keddadouche, K. (1 May 2021). "Magnetostratigraphy and cosmogenic dating of Wonderwerk Cave:Newton's method (8,748 words) [view diff] no match in snippet view article find links to article
x_{2}-3~\end{bmatrix}}_{k}\end{aligned}}} and X k + 1 = X k − C k + 1 {\displaystyle X_{k+1}~=~X_{k}-C_{k+1}} The iterations should be repeated until [Steven Ferguson (253 words) [view diff] exact match in snippet view article find links to article
finished eighth in the K-2 1000 m event, but was eliminated in the heats of the K-1 500 m event. He competed again in the K-2 1000 m at the 2008 Summer OlympicsEast Germany at the 1980 Summer Olympics (2,024 words) [view diff] exact match in snippet view article find links to article
Men's K-1 1000m Gold Rüdiger Helm Bernd Olbricht Harald Marg Bernd Duvigneau Canoeing Men's K-4 1000m Gold Birgit Fischer Canoeing Women's K-1 500m GoldLinear independence (4,286 words) [view diff] no match in snippet view article find links to article
{v} _{k},} if k > 1 , {\displaystyle k>1,} and v 1 = 0 {\displaystyle \mathbf {v} _{1}=\mathbf {0} } if k = 1. {\displaystyle k=1.} Thus, a set ofList of airships of the United States Navy (553 words) [view diff] exact match in snippet view article find links to article
airship) (ZNN-G) (ZGT) H class blimp (observation) J class blimp (trainer) K-1 blimp (experimental) K class blimp (anti-submarine patrol) (ZNP-K) (ZSG-2Quadratic variation (1,539 words) [view diff] exact match in snippet view article find links to article
‖ P ‖ → 0 ∑ k = 1 n ( X t k − X t k − 1 ) 2 {\displaystyle [X]_{t}=\lim _{\Vert P\Vert \rightarrow 0}\sum _{k=1}^{n}(X_{t_{k}}-X_{t_{k-1}})^{2}} whereSum-product number (973 words) [view diff] exact match in snippet view article find links to article
) k + 1 . {\displaystyle F_{b}(n)=k(b-1)^{k+1}.} This suggests that k ( b − 1 ) k + 1 ≥ n ≥ b k − 1 , {\displaystyle k(b-1)^{k+1}\geq n\geq b^{k-1},}Yoshihiro Akiyama (3,776 words) [view diff] exact match in snippet view article find links to article
for South Korea and for Japan at the 2002 Asian Games. He is the former K-1 HERO's Light Heavyweight Grand Prix Tournament Champion. Before his professionalNewton polynomial (5,843 words) [view diff] no match in snippet view article find links to article
are calculated using Newton's divided differences method. Given a set of k + 1 data points ( x 0 , y 0 ) , … , ( x j , y j ) , … , ( x k , y k ) {\displaystyleInterpolation attack (2,288 words) [view diff] no match in snippet view article find links to article
+ k 1 ) 3 = ( x 2 + k 1 2 ) ( x + k 1 ) = x 3 + k 1 2 x + x 2 k 1 + k 1 3 , {\displaystyle c_{1}=(x+k_{1})^{3}=(x^{2}+k_{1}^{2})(x+k_{1})=x^{3}+k_{1Trigonometric functions (10,715 words) [view diff] no match in snippet view article find links to article
square ( t ) = 4 π ∑ k = 1 ∞ sin ( ( 2 k − 1 ) t ) 2 k − 1 . {\displaystyle f_{\text{square}}(t)={\frac {4}{\pi }}\sum _{k=1}^{\infty }{\sin {\bigNumerical methods for ordinary differential equations (3,916 words) [view diff] no match in snippet view article find links to article
form α k y n + k + α k − 1 y n + k − 1 + ⋯ + α 0 y n = h [ β k f ( t n + k , y n + k ) + β k − 1 f ( t n + k − 1 , y n + k − 1 ) + ⋯ + β 0 f ( t n ,Triple point (1,328 words) [view diff] no match in snippet view article find links to article
was redefined so that the Boltzmann constant is exactly 1.380649×10−23 J⋅K−1, and the triple point of water became an experimentally measured constantMaryna Litvinchuk (272 words) [view diff] exact match in snippet view article find links to article
K-1 5000 m 2014 Moscow K-1 5000 m 2018 Montemor-o-Velho K-1 5000 m 2019 Szeged K-4 500 m 2021 Copenhagen K-2 500 m 2011 Szeged K-1 5000 m 2011 Szeged K-4Spectral radius (3,197 words) [view diff] no match in snippet view article find links to article
formula states that ρ ( A ) = lim k → ∞ ‖ A k ‖ 1 / k {\displaystyle \rho (A)=\lim _{k\to \infty }\|A^{k}\|^{1/k}} . Both of these results are shown belowBox spread (1,710 words) [view diff] no match in snippet view article find links to article
consider the put/call parity equation at two different strike prices K 1 {\displaystyle K_{1}} and K 2 {\displaystyle K_{2}} . The stock price S will disappearHarmonic number (5,594 words) [view diff] no match in snippet view article find links to article
u d u = ∫ 0 1 [ ∑ k = 1 n ( n k ) ( − u ) k − 1 ] d u = ∑ k = 1 n ( n k ) ∫ 0 1 ( − u ) k − 1 d u = ∑ k = 1 n ( n k ) ( − 1 ) k − 1 k . {\displaystyleInclusion–exclusion principle (6,851 words) [view diff] no match in snippet view article find links to article
k = 1 n ( − 1 ) k + 1 ( ∑ 1 ⩽ i 1 < ⋯ < i k ⩽ n | A i 1 ∩ ⋯ ∩ A i k | ) {\displaystyle \left|\bigcup _{i=1}^{n}A_{i}\right|=\sum _{k=1}^{n}(-1)^{k+1}\left(\sumQuaternion group (3,716 words) [view diff] no match in snippet view article find links to article
isomorphic to the eight-element subset { 1 , i , j , k , − 1 , − i , − j , − k } {\displaystyle \{1,i,j,k,-1,-i,-j,-k\}} of the quaternions under multiplication1994 ICF Canoe Sprint World Championships (211 words) [view diff] exact match in snippet view article find links to article
and men's and women's K-1) resumed at the 2010 championships.) and the 200 m events for C-1, C-2, and C-4 (men only), and K-1, K-2, and K-4 (both menAntonio Rossi (270 words) [view diff] exact match in snippet view article find links to article
in five Summer Olympics, he won five medals which included three golds (K-1 500 m: 1996, K-2 1000 m: 1996, 2000), one silver (K-2 1000 m: 2004), andJapanese submarine I-15 (2,880 words) [view diff] exact match in snippet view article find links to article
Harbor, operated off the United States West Coast, and took part in Operation K-1, the Aleutian Islands campaign, and the Guadalcanal campaign, including theCompound Poisson distribution (2,307 words) [view diff] no match in snippet view article find links to article
( ∑ k = 1 ∞ α k λ ( z k − 1 ) ) , ( | z | ≤ 1 ) {\displaystyle P_{Y}(z)=\sum \limits _{i=0}^{\infty }P(Y=i)z^{i}=\exp \left(\sum \limits _{k=1}^{\inftyScale (map) (5,382 words) [view diff] no match in snippet view article
should be within 4 parts in 10,000, or 0.04%, corresponding to k = 1.0004 {\displaystyle k=1.0004} . Since sec φ {\displaystyle \sec \varphi } attainsButterworth filter (4,135 words) [view diff] no match in snippet view article find links to article
recursion formula a k + 1 a k = cos ( k γ ) sin ( ( k + 1 ) γ ) {\displaystyle {\frac {a_{k+1}}{a_{k}}}={\frac {\cos(k\gamma )}{\sin((k+1)\gamma )}}} andB-spline (5,717 words) [view diff] exact match in snippet view article find links to article
, k − 1 ( x ) + t i + k + 1 − x t i + k + 1 − t i + 1 B i + 1 , k − 1 ( x ) . {\displaystyle B_{i,k}(x):={\frac {x-t_{i}}{t_{i+k}-t_{i}}}B_{i,k-1}(x)+{\fracErnesto Hoost (1,810 words) [view diff] exact match in snippet view article find links to article
kickboxer. A four-time K-1 World Champion, Hoost is considered to be one of the greatest kickboxers of all time. Debuting in 1993 at the K-1 World Grand PrixSemiprime (866 words) [view diff] no match in snippet view article find links to article
than or equal to n. Then π 2 ( n ) = ∑ k = 1 π ( n ) [ π ( n p k ) − k + 1 ] {\displaystyle \pi _{2}(n)=\sum _{k=1}^{\pi \left({\sqrt {n}}\right)}\left[\piTom Liebscher (84 words) [view diff] exact match in snippet view article find links to article
96 kg (212 lb) Sport Country Germany Sport Sprint kayak Event(s) K-1 200 m, K-1 500 m, K-1 1000 m, K-2 200 m, K-4 500 m, K-4 1000 m Club Kanu Club DresdenPerfect digit-to-digit invariant (1,095 words) [view diff] exact match in snippet view article find links to article
base b {\displaystyle b} as the k-digit number d k − 1 d k − 2 . . . d 1 d 0 {\displaystyle d_{k-1}d_{k-2}...d_{1}d_{0}} where each digit d i {\displaystyleLazdijai District Municipality (142 words) [view diff] no match in snippet view article find links to article
K 1 0 1 Paulenka K 0 0 0 Paveisininkai K 7 3 4 Pertakas K 5 3 2 Purviniai K 3 2 1 Semoškai K 26 13 13 Simaniškė K 1 0 1 Sirguškė K 6 4 2 Stalai K 1 1Multinomial theorem (2,059 words) [view diff] no match in snippet view article find links to article
power: ( x 1 + x 2 + ⋯ + x m ) n = ∑ k 1 + k 2 + ⋯ + k m = n k 1 , k 2 , ⋯ , k m ≥ 0 ( n k 1 , k 2 , … , k m ) x 1 k 1 ⋅ x 2 k 2 ⋯ x m k m {\displaystyleHungary at the 1956 Summer Olympics (256 words) [view diff] exact match in snippet view article find links to article
Farkas József Hunics C-2 10000 m — 55:15.6 Lajos Kiss K-1 1000 m 4:35.8 2 Q 4:16.2 Ferenc Hatlaczky K-1 10000 m — 47:53.3 Imre Vágyóczky Zoltán Szigeti K-2Tamara Csipes (244 words) [view diff] exact match in snippet view article find links to article
gold medal in Women's K-4 500 metres, and a silver medal in the Women's K-1 500 metres At the 2010 ICF Canoe Sprint World Championships in Poznań, sheDeterminant (13,785 words) [view diff] no match in snippet view article find links to article
c n − m = − 1 m ∑ k = 1 m c n − m + k tr ( A k ) ( 1 ≤ m ≤ n ) . {\displaystyle c_{n}=1;~~~c_{n-m}=-{\frac {1}{m}}\sum _{k=1}^{m}c_{n-m+k}\operatornameIntegral transform (1,278 words) [view diff] no match in snippet view article find links to article
kernel K − 1 ( u , t ) {\displaystyle K^{-1}(u,t)} which (roughly speaking) yields an inverse transform: f ( t ) = ∫ u 1 u 2 ( T f ) ( u ) K − 1 ( u ,Butterworth filter (4,135 words) [view diff] no match in snippet view article find links to article
recursion formula a k + 1 a k = cos ( k γ ) sin ( ( k + 1 ) γ ) {\displaystyle {\frac {a_{k+1}}{a_{k}}}={\frac {\cos(k\gamma )}{\sin((k+1)\gamma )}}} andHungary at the 1956 Summer Olympics (256 words) [view diff] exact match in snippet view article find links to article
Farkas József Hunics C-2 10000 m — 55:15.6 Lajos Kiss K-1 1000 m 4:35.8 2 Q 4:16.2 Ferenc Hatlaczky K-1 10000 m — 47:53.3 Imre Vágyóczky Zoltán Szigeti K-2Ball (mathematics) (1,840 words) [view diff] no match in snippet view article
r ) = π k k ! r 2 k , V 2 k + 1 ( r ) = 2 k + 1 π k ( 2 k + 1 ) ! ! r 2 k + 1 = 2 ( k ! ) ( 4 π ) k ( 2 k + 1 ) ! r 2 k + 1 . {\displaystyleReflexive space (6,409 words) [view diff] no match in snippet view article find links to article
{\displaystyle x_{\varnothing },} the root of the tree, followed, for k = 1 , … , n , {\displaystyle k=1,\ldots ,n,} by a family of s k {\displaystyle s^{k}} 2 vectorsIrwin–Hall distribution (1,358 words) [view diff] no match in snippet view article find links to article
identically distributed U(0, 1) random variables: X = ∑ k = 1 n U k . {\displaystyle X=\sum _{k=1}^{n}U_{k}.} The probability density function (pdf) forBessel function (12,179 words) [view diff] no match in snippet view article find links to article
π ∑ k = 0 n − 1 ( n − k − 1 ) ! k ! ( z 2 4 ) k + 2 π J n ( z ) ln z 2 − ( z 2 ) n π ∑ k = 0 ∞ ( ψ ( k + 1 ) + ψ ( n + k + 1 ) ) ( − z 2 4 ) k k ! (Extended Kalman filter (3,823 words) [view diff] exact match in snippet view article find links to article
become P k | k − 1 = F k − 1 P k − 1 | k − 1 F k − 1 T + L k − 1 Q k − 1 L k − 1 T {\displaystyle {\boldsymbol {P}}_{k|k-1}={{\boldsymbol {F}}_{k-1}}{{\boldsymbolLazdijai District Municipality (142 words) [view diff] no match in snippet view article find links to article
K 1 0 1 Paulenka K 0 0 0 Paveisininkai K 7 3 4 Pertakas K 5 3 2 Purviniai K 3 2 1 Semoškai K 26 13 13 Simaniškė K 1 0 1 Sirguškė K 6 4 2 Stalai K 1 1Dynamic programming (9,282 words) [view diff] no match in snippet view article find links to article
equation: J k ∗ ( x n − k ) = min u n − k { f ^ ( x n − k , u n − k ) + J k − 1 ∗ ( g ^ ( x n − k , u n − k ) ) } {\displaystyle J_{k}^{\ast }\left(\mathbfN-sphere (7,312 words) [view diff] exact match in snippet view article find links to article
r 2 + ∑ k = 1 n − 1 r 2 ( ∏ m = 1 k − 1 sin 2 ( φ m ) ) d φ k 2 {\displaystyle ds^{2}=dr^{2}+\sum _{k=1}^{n-1}r^{2}\left(\prod _{m=1}^{k-1}\sin ^{2}\left(\varphiBates distribution (695 words) [view diff] no match in snippet view article find links to article
variables on the unit interval, Uk: X = 1 n ∑ k = 1 n U k . {\displaystyle X={\frac {1}{n}}\sum _{k=1}^{n}U_{k}.} The equation defining the probabilityErnesto Hoost (1,810 words) [view diff] exact match in snippet view article find links to article
kickboxer. A four-time K-1 World Champion, Hoost is considered to be one of the greatest kickboxers of all time. Debuting in 1993 at the K-1 World Grand PrixMultinomial theorem (2,059 words) [view diff] no match in snippet view article find links to article
power: ( x 1 + x 2 + ⋯ + x m ) n = ∑ k 1 + k 2 + ⋯ + k m = n k 1 , k 2 , ⋯ , k m ≥ 0 ( n k 1 , k 2 , … , k m ) x 1 k 1 ⋅ x 2 k 2 ⋯ x m k m {\displaystyleBig O notation (8,444 words) [view diff] no match in snippet view article find links to article
below (with constant factor k 1 {\displaystyle k_{1}} ) ∃ k 1 > 0 ∃ k 2 > 0 ∃ n 0 ∀ n > n 0 : {\displaystyle \exists k_{1}>0\,\exists k_{2}>0\,\existsLine integral (3,183 words) [view diff] no match in snippet view article find links to article
considering the expression ∑ k = 1 n f ( γ ( t k ) ) [ γ ( t k ) − γ ( t k − 1 ) ] = ∑ k = 1 n f ( γ k ) Δ γ k . {\displaystyle \sum _{k=1}^{n}f(\gamma (t_{k}))\Pythagorean theorem (12,704 words) [view diff] no match in snippet view article find links to article
equation ‖ ∑ k = 1 n v k ‖ 2 = ∑ k = 1 n ‖ v k ‖ 2 {\displaystyle {\biggl \|}\sum _{k=1}^{n}\mathbf {v} _{k}{\biggr \|}^{2}=\sum _{k=1}^{n}\|\mathbfEuclid's theorem (3,429 words) [view diff] no match in snippet view article find links to article
integers) is equivalent to the statement that we have ∏ p ∈ P k 1 1 − 1 p = ∑ n ∈ N k 1 n , {\displaystyle \prod _{p\in P_{k}}{\frac {1}{1-{\frac {1}{p}}}}=\sumHamiltonian mechanics (9,286 words) [view diff] no match in snippet view article find links to article
2 ∑ k = 1 N ( m k r ˙ k ( q , q ˙ ) ⋅ r ˙ k ( q , q ˙ ) ) {\displaystyle T({\boldsymbol {q}},{\boldsymbol {\dot {q}}})={\frac {1}{2}}\sum _{k=1}^{N}{\bigglEast Germany at the 1976 Summer Olympics (932 words) [view diff] exact match in snippet view article find links to article
Helm Canoeing men's K-1 1000 m Gold Joachim Mattern Bernd Olbricht Canoeing men's K-2 500 m Gold Carola Zirzow Canoeing women's K-1 500 m Gold Klaus-JürgenB+ tree (3,417 words) [view diff] no match in snippet view article find links to article
K + 1 ) / 2 ⌉ {\displaystyle \lceil (K+1)/2\rceil } items new node has ⌊ ( K + 1 ) / 2 ⌋ {\displaystyle \lfloor (K+1)/2\rfloor } items Copy ⌈ ( K + 1Banach space (17,005 words) [view diff] no match in snippet view article find links to article
proved that if c − 2 ∑ k = 1 n ‖ x k ‖ 2 ≤ Ave ± ‖ ∑ k = 1 n ± x k ‖ 2 ≤ c 2 ∑ k = 1 n ‖ x k ‖ 2 {\displaystyle c^{-2}\sum _{k=1}^{n}\|x_{k}\|^{2}\leqAcid dissociation constant (11,513 words) [view diff] no match in snippet view article find links to article
A−, so [ H + ] 2 = K 1 K 2 {\displaystyle [{\ce {H+}}]^{2}=K_{1}K_{2}} Therefore, taking cologarithms, the pH is given by p I = p K 1 + p K 2 2 {\displaystyleCoxeter group (3,763 words) [view diff] no match in snippet view article find links to article
a 3-cycle : ( k k + 1 ) ⋅ ( k + 1 k + 2 ) = ( k k + 2 k + 1 ) {\displaystyle (k~~k+1)\cdot (k+1~~k+2)=(k~~k+2~~k+1)} . Therefore S n +Satisfaction equilibrium (3,856 words) [view diff] exact match in snippet view article find links to article
× A k − 1 × A k + 1 × … , × A K → 2 A k {\displaystyle f_{k}:{\mathcal {A}}_{1}\times \ldots \times {\mathcal {A}}_{k-1}\times {\mathcal {A}}_{k+1}\timesOuter product (2,942 words) [view diff] no match in snippet view article find links to article
{\displaystyle \mathbf {u} ,\mathbf {v} } with dimensions ( k 1 , k 2 , … , k m ) {\displaystyle (k_{1},k_{2},\dots ,k_{m})} and ( l 1 , l 2 , … , l n ) {\displaystyleMotzkin number (846 words) [view diff] exact match in snippet view article find links to article
This gives ∑ k = 0 n C k = 1 + ∑ k = 1 n ( n k ) M k − 1 . {\displaystyle \sum _{k=0}^{n}C_{k}=1+\sum _{k=1}^{n}{\binom {n}{k}}M_{k-1}.} The generating functionSaitama Super Arena (1,366 words) [view diff] exact match in snippet view article find links to article
2008 featured Dream and K-1 fights Dynamite!! 2009 featured fights by Dream, Sengoku and K-1 Dynamite!! 2010 featured Dream and K-1 fights. Fight For Japan:Apéry's constant (3,021 words) [view diff] no match in snippet view article find links to article
= 1 4 ∑ k = 1 ∞ ( − 1 ) k − 1 ( k − 1 ) ! 3 ( 56 k 2 − 32 k + 5 ) ( 2 k − 1 ) 2 ( 3 k ) ! . {\displaystyle \zeta (3)={\frac {1}{4}}\sum _{k=1}^{\inftyKatrin Borchert (641 words) [view diff] exact match in snippet view article find links to article
500 m for Germany) and two bronzes (both Australia, 1996: K-2 500 m, 2000: K-1 500 m). During her career, she has represented four countries: East GermanyInterspecific competition (3,334 words) [view diff] no match in snippet view article find links to article
respectively: d N 1 d t = r 1 N 1 K 1 − N 1 − α N 2 K 1 {\displaystyle {dN_{1} \over dt}=r_{1}N_{1}{K_{1}-N_{1}-\alpha N_{2} \over K_{1}}} d N 2 d t = r 2 N 2 KPolynomial interpolation (9,051 words) [view diff] no match in snippet view article find links to article
C ( u − k , 1 ) Δ y k − 1 + C ( u − k + 1 , 2 ) Δ 2 y k − 2 + C ( u − k + 2 , 3 ) Δ 3 y k − 3 + ⋯ = y k + ( u − k ) Δ y k − 1 + ( u − k + 1 ) ( u − kColossally abundant number (1,635 words) [view diff] no match in snippet view article find links to article
that for all k > 1, σ ( n ) n 1 + ε ≥ σ ( k ) k 1 + ε {\displaystyle {\frac {\sigma (n)}{n^{1+\varepsilon }}}\geq {\frac {\sigma (k)}{k^{1+\varepsilonCompressor (6,856 words) [view diff] exact match in snippet view article find links to article
− T 1 ) k − 1 = k R T 1 k − 1 [ ( P 2 P 1 ) ( k − 1 ) / k − 1 ] {\displaystyle W_{comp,in}={\frac {kR(T_{2}-T_{1})}{k-1}}={\frac {kRT_{1}}{k-1}}\left[\left({\fracJoule per mole (467 words) [view diff] no match in snippet view article find links to article
particle, 0.239 kcal·mol−1, or 83.6 cm−1. At room temperature (25 °C, or 298.15 K) 1 kJ·mol−1 is approximately equal to 0.4034 k B T {\displaystyle k_{B}T}Laurent series (2,675 words) [view diff] exact match in snippet view article find links to article
) n − k − 1 d z = ∮ γ ∑ n = − ∞ ∞ b n ( z − c ) n − k − 1 d z . {\displaystyle \oint _{\gamma }\,\sum _{n=-\infty }^{\infty }a_{n}(z-c)^{n-k-1}\,dz=\ointEMER-K1 (724 words) [view diff] exact match in snippet view article find links to article
The EMER K-1, sometimes known as the EMER K1 or EMERK-1, was a prototype bullpup assault rifle made in Myanmar by the Electrical Mechanical and EngineeringCanoeing at the 1988 Summer Olympics (51 words) [view diff] exact match in snippet view article find links to article
Sprint C-1 500 m men C-1 1000 m men C-2 500 m men C-2 1000 m men K-1 500 m men women K-1 1000 m men K-2 500 m men women K-2 1000 m men K-4 500 m women K-4Nicole Reinhardt (276 words) [view diff] exact match in snippet view article find links to article
ICF Canoe Sprint World Championships with eight golds (K-1 500 m: 2005, 2011, K-2 200 m: 2007, K-1 4 × 200 m: 2009, 2010, 2011, K-2 500 m: 2007, K-4 200Simon Dickie (722 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanDarcy's law (3,524 words) [view diff] no match in snippet view article find links to article
linear with the velocity we may write: − ( k − 1 ) i j μ φ u j − ∂ i p = 0 , {\displaystyle -\left(k^{-1}\right)_{ij}\mu \varphi u_{j}-\partial _{i}p=0\2011 ICF Canoe Sprint World Championships (3,160 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200 metres (660 ft), 500Einar Rasmussen (200 words) [view diff] exact match in snippet view article find links to article
golds (K-1 10000 m: 1981, 1983; K-2 1000 m: 1979, K-4 10000 m: 1975), three silvers (K-1 10000 m: 1979, 1982; K-2 1000 m: 1978), and three bronzes (K-1 1000Quasinorm (936 words) [view diff] no match in snippet view article find links to article
+ ‖ y ‖ ) {\displaystyle \|x+y\|\leq K(\|x\|+\|y\|)} for some K > 1. {\displaystyle K>1.} A quasi-seminorm on a vector space X {\displaystyle X} is aB+ tree (3,417 words) [view diff] no match in snippet view article find links to article
K + 1 ) / 2 ⌉ {\displaystyle \lceil (K+1)/2\rceil } items new node has ⌊ ( K + 1 ) / 2 ⌋ {\displaystyle \lfloor (K+1)/2\rfloor } items Copy ⌈ ( K + 12011 ICF Canoe Sprint World Championships (3,160 words) [view diff] exact match in snippet view article find links to article
or four people (4). For each of the specific canoes or kayaks, such as a K-1 (kayak single), the competition distances can be 200 metres (660 ft), 500Cubic Hermite spline (3,102 words) [view diff] exact match in snippet view article find links to article
m k = ( 1 − c ) p k + 1 − p k − 1 x k + 1 − x k − 1 {\displaystyle {\boldsymbol {m}}_{k}=(1-c){\frac {{\boldsymbol {p}}_{k+1}-{\boldsymbol {p}}_{k-1}}{x_{k+1}-x_{k-1}}}}Danyon Loader (359 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanDeficient number (560 words) [view diff] exact match in snippet view article find links to article
, p k − 1 {\displaystyle 1,p,p^{2},\dots ,p^{k-1}} which sum to p k − 1 p − 1 {\displaystyle {\frac {p^{k}-1}{p-1}}} , which is at most p k − 1 {\displaystylePerfect power (1,027 words) [view diff] no match in snippet view article find links to article
formally, n is a perfect power if there exist natural numbers m > 1, and k > 1 such that mk = n. In this case, n may be called a perfect kth power. IfSN1 reaction (1,970 words) [view diff] no match in snippet view article find links to article
= k 1 [ tBuBr ] − k − 1 [ tBu + ] [ Br − ] − k 2 [ tBu + ] [ H 2 O ] {\displaystyle {\frac {d[{\text{tBu}}^{+}]}{dt}}=0=k_{1}[{\text{tBuBr}}]-k_{-1Ljung–Box test (870 words) [view diff] no match in snippet view article find links to article
correlation. The test statistic is: Q = n ( n + 2 ) ∑ k = 1 h ρ ^ k 2 n − k {\displaystyle Q=n(n+2)\sum _{k=1}^{h}{\frac {{\hat {\rho }}_{k}^{2}}{n-k}}} whereInverse trigonometric functions (10,605 words) [view diff] no match in snippet view article find links to article
2 ∑ n = 0 ∞ ∏ k = 1 n 2 k z 2 ( 2 k + 1 ) ( 1 + z 2 ) . {\displaystyle \arctan(z)={\frac {z}{1+z^{2}}}\sum _{n=0}^{\infty }\prod _{k=1}^{n}{\fracHouseholder transformation (3,241 words) [view diff] no match in snippet view article find links to article
− sgn ( a k + 1 , k k ) ∑ j = k + 1 n ( a j k k ) 2 r = 1 2 ( α 2 − a k + 1 , k k α ) v 1 k = v 2 k = ⋯ = v k k = 0 v k + 1 k = a k + 1 , k k − α 2Interspecific competition (3,334 words) [view diff] no match in snippet view article find links to article
respectively: d N 1 d t = r 1 N 1 K 1 − N 1 − α N 2 K 1 {\displaystyle {dN_{1} \over dt}=r_{1}N_{1}{K_{1}-N_{1}-\alpha N_{2} \over K_{1}}} d N 2 d t = r 2 N 2 KHeat capacity (2,775 words) [view diff] no match in snippet view article find links to article
The SI unit for heat capacity of an object is joule per kelvin (J/K or J⋅K−1). Since an increment of temperature of one degree Celsius is the same asVladimir Parfenovich (446 words) [view diff] exact match in snippet view article find links to article
he entered: K-1 500 m, K-2 500 m and K-2 1000 m. He also won twelve medals at the ICF Canoe Sprint World Championships, with nine golds (K-1 500 m: 1979Polylogarithm (10,139 words) [view diff] no match in snippet view article find links to article
series in s: Li s ( z ) = ∑ k = 1 ∞ z k k s = z + z 2 2 s + z 3 3 s + ⋯ {\displaystyle \operatorname {Li} _{s}(z)=\sum _{k=1}^{\infty }{z^{k} \over k^{s}}=z+{z^{2}Arithmetic coding (5,380 words) [view diff] no match in snippet view article find links to article
the computation of the product ∏ k = 1 n f k = ∏ k = 1 A f k f k . {\displaystyle \prod _{k=1}^{n}f_{k}=\prod _{k=1}^{A}f_{k}^{f_{k}}.} Applying log2Regular expression (8,860 words) [view diff] exact match in snippet view article find links to article
) ( a ∣ b ) ⋯ ( a ∣ b ) ⏟ k − 1 times . {\displaystyle (a\mid b)^{*}a\underbrace {(a\mid b)(a\mid b)\cdots (a\mid b)} _{k-1{\text{ times}}}.\,} On theBálint Kopasz (79 words) [view diff] exact match in snippet view article find links to article
(born 20 June 1997) is a Hungarian sprint canoeist. He competed in the men's K-1 1000 metres event at the 2016 Summer Olympics. He won the same event in theDiscrete uniform distribution (772 words) [view diff] no match in snippet view article find links to article
k, the sample size, is N ^ = k + 1 k m − 1 = m + m k − 1 {\displaystyle {\hat {N}}={\frac {k+1}{k}}m-1=m+{\frac {m}{k}}-1} . This can be seen as a veryAbsolute convergence (5,193 words) [view diff] no match in snippet view article find links to article
have 0 ≤ ∑ k = 1 n ( a k + | a k | ) ≤ ∑ k = 1 n 2 | a k | . {\displaystyle 0\leq \sum _{k=1}^{n}(a_{k}+\left|a_{k}\right|)\leq \sum _{k=1}^{n}2\left|a_{k}\right|Georgina Evers-Swindell (552 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanDirichlet process (4,861 words) [view diff] no match in snippet view article find links to article
k = 1 ∞ β k δ x k ( x ) {\displaystyle f(x)=\sum _{k=1}^{\infty }\beta _{k}\delta _{x_{k}}(x)} , where { x k } k = 1 ∞ {\displaystyle \{x_{k}\}_{k=1}^{\inftyPerfect number (5,168 words) [view diff] exact match in snippet view article find links to article
is at most k − 1 2 . {\displaystyle {\frac {k-1}{2}}.} At least one of the prime powers dividing N exceeds 1062. N < 2 ( 4 k + 1 − 2 k + 1 ) {\displaystyleAbsolute magnitude (5,779 words) [view diff] no match in snippet view article find links to article
approximated as m 1 = M 1 + 2.5 ⋅ K 1 log 10 ( d B S d 0 ) + 5 log 10 ( d B O d 0 ) {\displaystyle m_{1}=M_{1}+2.5\cdot K_{1}\log _{10}{\left({\fracKatrin Borchert (641 words) [view diff] exact match in snippet view article find links to article
500 m for Germany) and two bronzes (both Australia, 1996: K-2 500 m, 2000: K-1 500 m). During her career, she has represented four countries: East GermanyVandermonde matrix (5,263 words) [view diff] no match in snippet view article find links to article
v o l ( F ) = 1 k ! ∏ 1 ≤ m < n ≤ k + 1 ( t i n − t i m ) . {\displaystyle \mathrm {nvol} (F)={\frac {1}{k!}}\prod _{1\leq m<n\leq k+1}{(t_{i_{n}}-t_{i_{m}})}Darcy's law (3,524 words) [view diff] no match in snippet view article find links to article
linear with the velocity we may write: − ( k − 1 ) i j μ φ u j − ∂ i p = 0 , {\displaystyle -\left(k^{-1}\right)_{ij}\mu \varphi u_{j}-\partial _{i}p=0\Second-order logic (4,387 words) [view diff] no match in snippet view article find links to article
{\displaystyle \phi } is a Π k 1 {\displaystyle \Pi _{k}^{1}} formula, and similar, Π k + 1 1 {\displaystyle \Pi _{k+1}^{1}} has the form ∀ R 0 … ∀ RPolar decomposition (4,254 words) [view diff] no match in snippet view article find links to article
= ‖ U k − 1 ‖ 1 ‖ U k − 1 ‖ ∞ ‖ U k ‖ 1 ‖ U k ‖ ∞ 4 {\displaystyle \gamma _{k}={\sqrt[{4}]{\frac {\left\|U_{k}^{-1}\right\|_{1}\left\|U_{k}^{-1}\right\|_{\inftyOreste Perri (200 words) [view diff] exact match in snippet view article find links to article
Championships with four golds (K-1 1000 m: 1975 (tied with Poland's Grzegorz Śledziewski, K-1 10000 m: 1974, 1975, 1977) and two bronzes (K-1 1000 m: 1974, 1977)Appell's equation of motion (1,565 words) [view diff] no match in snippet view article find links to article
the particle accelerations squared, S = 1 2 ∑ k = 1 N m k a k 2 , {\displaystyle S={\frac {1}{2}}\sum _{k=1}^{N}m_{k}\mathbf {a} _{k}^{2}\,,} where theHadamard matrix (3,698 words) [view diff] exact match in snippet view article find links to article
k − 1 H 2 k − 1 H 2 k − 1 − H 2 k − 1 ] = H 2 ⊗ H 2 k − 1 , {\displaystyle H_{2^{k}}={\begin{bmatrix}H_{2^{k-1}}&H_{2^{k-1}}\\H_{2^{k-1}}&-H_{2^{k-1List of mathematical constants (3,561 words) [view diff] no match in snippet view article find links to article
root of x k + 1 = 2 k + 1 ( x − 1 ) , β k = 2 − α k k + 1 − k α k {\displaystyle x^{k+1}=2^{k+1}(x-1),\beta _{k}={\frac {2-\alpha _{k}}{k+1-k\alpha _{k}}}}Matrix-exponential distribution (379 words) [view diff] no match in snippet view article find links to article
given by E ( X k ) = ( − 1 ) k + 1 k ! α T − ( k + 1 ) s . {\displaystyle \operatorname {E} (X^{k})=(-1)^{k+1}k!\mathbf {\alpha } T^{-(k+1)}\mathbf {s}Grzegorz Śledziewski (201 words) [view diff] exact match in snippet view article find links to article
with three golds (K-1 1000 m: 1971, 1975 (tied with Italy's Oreste Perri); K-2 500 m: 1974), five silvers (K-1 500 m: 1970, 1977; K-1 1000 m: 1973, 1974;Pauli matrices (7,411 words) [view diff] no match in snippet view article find links to article
operator, P j k = 1 2 ( σ → j ⋅ σ → k + 1 ) . {\displaystyle P_{jk}={\frac {1}{2}}\,\left({\vec {\sigma }}_{j}\cdot {\vec {\sigma }}_{k}+1\right)~.} ItsVan der Waerden test (772 words) [view diff] exact match in snippet view article find links to article
1 > χ α , k − 1 2 {\displaystyle T_{1}>\chi _{\alpha ,k-1}^{2}} where Χα,k − 12 is the α-quantile of the chi-squared distribution with k − 1 degrees ofMeet-in-the-middle attack (3,219 words) [view diff] no match in snippet view article find links to article
k 2 ( E N C k 1 ( P ) ) P = D E C k 1 ( D E C k 2 ( C ) ) {\displaystyle {\begin{aligned}C&={\mathit {ENC}}_{k_{2}}({\mathit {ENC}}_{k_{1}}(P))\\P&={\mathitCaroline Evers-Swindell (555 words) [view diff] exact match in snippet view article find links to article
Canoeing: 2012 – K-1 200 m 2016 – K-1 200 m 2020 – K-1 200 m 2020 – K-2 500 m 2020 – K-1 500 m 2024 – K-4 500 m 2024 – K-2 500 m 2024 – K-1 500 m Four IanQuasinorm (936 words) [view diff] no match in snippet view article find links to article
+ ‖ y ‖ ) {\displaystyle \|x+y\|\leq K(\|x\|+\|y\|)} for some K > 1. {\displaystyle K>1.} A quasi-seminorm on a vector space X {\displaystyle X} is aBalding–Nichols model (214 words) [view diff] exact match in snippet view article find links to article
{F(1-p)p}}}}} MGF 1 + ∑ k = 1 ∞ ( ∏ r = 0 k − 1 α + r 1 − F F + r ) t k k ! {\displaystyle 1+\sum _{k=1}^{\infty }\left(\prod _{r=0}^{k-1}{\frac {\alpha +r}{{\fracMixed Poisson distribution (1,169 words) [view diff] no match in snippet view article find links to article
= p r ( 1 − p ) − r Γ ( r ) k ! ( 1 − p ) k + r ∫ 0 ∞ λ k + r − 1 e − λ d λ ⏟ = Γ ( r + k ) = Γ ( r + k ) Γ ( r ) k ! ( 1 − p ) k p r {\displaystyleBeta negative binomial distribution (1,541 words) [view diff] no match in snippet view article find links to article
+ r − 1 k ) ( 1 − q ) k q r ⋅ q α − 1 ( 1 − q ) β − 1 B ( α , β ) d q = 1 B ( α , β ) ( k + r − 1 k ) ∫ 0 1 q α + r − 1 ( 1 − q ) β + k − 1 d q {\displaystyleOperation K (1,326 words) [view diff] no match in snippet view article find links to article
Operation K (K作戦, Kē-Sakusen) was a Japanese naval operation in World War II, intended as reconnaissance of Pearl Harbor and disruption of repair and salvageHamilton–Jacobi equation (8,183 words) [view diff] exact match in snippet view article find links to article
… , q k − 1 , q k + 1 , … , q N ; p 1 , p 2 , … , p k − 1 , p k + 1 , … , p N ; ψ ; t ) . {\displaystyle H=H(q_{1},q_{2},\ldots ,q_{k-1},q_{k+1},\ldotsBound state (2,314 words) [view diff] no match in snippet view article find links to article
a stable bound state of n particles with masses { m k } k = 1 n {\displaystyle \{m_{k}\}_{k=1}^{n}} corresponds to a pole in the S-matrix with a center-of-massShell integration (549 words) [view diff] no match in snippet view article find links to article
rectangle, its made by obtaining a cylinder of radius a + ( k + 1 ) Δ x {\displaystyle a+(k+1)\Delta x} with height f ( a + k Δ x ) {\displaystyle f(a+k\Delta