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searching for Nakayama's lemma 1 found (27 total)

Dimension theory (algebra) (6,961 words) [view diff] exact match in snippet view article

with pd R ⁡ M = 1 {\displaystyle \operatorname {pd} _{R}M=1} . By Nakayama's lemma, there is a surjection F → M {\displaystyle F\to M} from a free module