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searching for F/X2 97 found (141 total)

alternate case: f/X2

Injective function (2,499 words) [view diff] no match in snippet view article find links to article

domain to distinct elements; that is, x1 ≠ x2 implies f(x1) ≠ f(x2). (Equivalently, f(x1) = f(x2) implies x1 = x2 in the equivalent contrapositive statement

Convex function (5,585 words) [view diff] no match in snippet view article find links to article

f(x1)≤f(x1){\displaystyle f\left(x_{1}\right)\leq f\left(x_{1}\right)} or f(x2)≤f(x2){\displaystyle f\left(x_{2}\right)\leq f\left(x_{2}\right)} at t=0{\displaystyle

Jensen's inequality (4,234 words) [view diff] no match in snippet view article find links to article

consists of weighted means of the convex function (for t ∈ [0,1]), tf(x1)+(1−t)f(x2),{\displaystyle tf(x_{1})+(1-t)f(x_{2}),} while the graph of the function

Lipschitz continuity (2,561 words) [view diff] no match in snippet view article find links to article

exists a real constant K ≥ 0 such that, for all x1 and x2 in X, dY(f(x1),f(x2))≤KdX(x1,x2).{\displaystyle d_{Y}(f(x_{1}),f(x_{2}))\leq Kd_{X}(x_{1},x_{2})

Symmetric function (835 words) [view diff] no match in snippet view article find links to article

x_{2}\right)} of two arguments is a symmetric function if and only if f(x1,x2)=f(x2,x1){\displaystyle f\left(x_{1},x_{2}\right)=f\left(x_{2},x_{1}\right)} for

Muller's method (1,394 words) [view diff] no match in snippet view article find links to article

range(iterations): w = div_diff(f, (x2, x1)) + div_diff(f, (x2, x0)) - div_diff(f, (x2, x1)) s_delta = sqrt(w ** 2 - 4 * f(x2) * div_diff(f, (x2, x1, x0))) denoms =

Monotone likelihood ratio (1,726 words) [view diff] no match in snippet view article find links to article

and g(x) {\displaystyle \ g(x)\ } bear the property if for every x2>x1,f(x2) g(x2) ≥f(x1) g(x1) {\displaystyle \ {\text{for every }}x_{2}>x_{1},\quad

Superposition principle (2,736 words) [view diff] no match in snippet view article find links to article

Superposition can be defined by two simpler properties: additivity F(x1+x2)=F(x1)+F(x2){\displaystyle F(x_{1}+x_{2})=F(x_{1})+F(x_{2})\,} and homogeneity

Involution (mathematics) (2,124 words) [view diff] no match in snippet view article

f(x1+x2)=f(x1)+f(x2){\displaystyle f(x_{1}+x_{2})=f(x_{1})+f(x_{2})} and f(λx)=λf(x){\displaystyle f(\lambda x)=\lambda f(x)} (it is linear) f(x1x2)=f(x1)f(x2){\displaystyle

Ridders' method (571 words) [view diff] no match in snippet view article find links to article

x_{2}}, which are on two different sides of the root being sought, i.e.,f(x0)f(x2)<0{\displaystyle f(x_{0})f(x_{2})<0}, the method begins by evaluating the

Reciprocal difference (206 words) [view diff] no match in snippet view article find links to article

x2)=x1−x2f(x1)−f(x2){\displaystyle \rho _{1}(x_{1},x_{2})={\frac {x_{1}-x_{2}}{f(x_{1})-f(x_{2})}}} ρ2(x1,x2,x3)=x1−x3ρ1(x1,x2)−ρ1(x2,x3)+f(x2){\displaystyle

Direct stiffness method (2,202 words) [view diff] no match in snippet view article find links to article

1k42k43k44][ux1uy1ux2uy2]{\displaystyle {\begin{bmatrix}f_{x1}\\f_{y1}\\f_{x2}\\f_{y2}\\\end{bmatrix}}={\begin{bmatrix}k_{11}&k_{12}&k_{13}&k_{14}\\k

Segre's theorem (1,780 words) [view diff] no match in snippet view article find links to article

P1P2¯{\displaystyle {\overline {P_{1}P_{2}}}}, that means: f′(x2)+f′(x1)−f(x2)−f(x1)x2−x1=f(x2)−f(x1)x2−x1{\displaystyle f'(x_{2})+f'(x_{1})-{\frac

Law of large numbers (6,036 words) [view diff] no match in snippet view article find links to article

variables on [a, b]. Evaluate f(X1), f(X2), ..., f(Xn) Take the average of f(X1), f(X2), ..., f(Xn) by computing (b−a)f(X1)+f(X2)+...+f(Xn)n{\displaystyle (b-a){\tfrac

Equivalence class (2,310 words) [view diff] no match in snippet view article find links to article

function from X{\displaystyle X} to another set Y{\displaystyle Y}; if f(x1)=f(x2){\displaystyle f\left(x_{1}\right)=f\left(x_{2}\right)} whenever x1∼x2,{\displaystyle

Approximation theory (2,162 words) [view diff] no match in snippet view article find links to article

of approximation), these equations need to be solved: P(x1)−f(x1)=+εP(x2)−f(x2)=−εP(x3)−f(x3)=+ε ⋮P(xN+2)−f(xN+2)=±ε.{\displaystyle

Generalized Stokes theorem (4,623 words) [view diff] no match in snippet view article find links to article

exists a smooth function f(x2,…,xn){\displaystyle f(x_{2},\dots ,x_{n})} such that P{\displaystyle P} is the graph {x1=f(x2,…,xn)}{\displaystyle \{x_{1}=f(x_{2}

Unit hyperbola (1,448 words) [view diff] no match in snippet view article find links to article

rectangular hyperbola f=x2−y2−1{\displaystyle f=x^{2}-y^{2}-1} in R2{\displaystyle \mathbb {R} ^{2}}, the corresponding projective curve is F=x2−y2−z2,{\displaystyle

Birthday attack (2,144 words) [view diff] no match in snippet view article find links to article

find two different inputs x1,x2{\displaystyle x_{1},x_{2}} such that f(x1)=f(x2){\displaystyle f(x_{1})=f(x_{2})}. Such a pair x1,x2{\displaystyle x_{1}

Divided differences (3,162 words) [view diff] no match in snippet view article find links to article

−x2)+f(x1)(x1−x0)⋅(x1−x2)+f(x2)(x2−x0)⋅(x2−x1)f[x0,x1,x2,x3]=f(x0)(x0−x1)⋅(x0−x2)⋅(x0−x3)+f(x1)(x1−x0)⋅(x1−x2)⋅(x1−x3)+f(x2)(x2−x0)⋅(x2−x1)⋅(x2−x3)+f

Anti-unification (2,969 words) [view diff] no match in snippet view article find links to article

y_{1})} is a variant of f(x2,a,g(z2),y2){\displaystyle f(x_{2},a,g(z_{2}),y_{2})}, since f(x1,a,g(z1),y1){x1↦x2,y1↦y2,z1↦z2}=f(x2,a,g(z2),y2){\displaystyle

Sukhoi Su-35 (13,064 words) [view diff] no match in snippet view article find links to article

fighter delivered to Latin America. With the tender relaunched in 2007 as the F-X2 competition, the Brazilian Defence Ministry looked to purchase at least 36

Reed–Muller expansion (1,990 words) [view diff] no match in snippet view article find links to article

expansion for n=2{\displaystyle n=2}: f=fx¯1⊕x1∂f∂x1=(fx¯2⊕x2∂f∂x2)x¯1⊕x1∂(fx¯2⊕x2∂f∂x2)∂x1=fx¯1x¯2⊕x2∂fx¯1∂x2⊕x1(∂fx¯2∂x1⊕x2∂2f∂x1∂x2)=fx¯1x¯2⊕x2∂fx

Golden-section search (2,500 words) [view diff] no match in snippet view article find links to article

x3{\displaystyle x_{3}}. From the diagram, it is clear that if the function yields f4a>f(x2){\displaystyle f_{4a}>f(x_{2})}, then a minimum lies between x1{\displaystyle

Five-point stencil (1,620 words) [view diff] no match in snippet view article find links to article

approximation of f ′(x) at the middle point x = x2 is f′(x2)=ℓ0′(x2)f(x0)+ℓ1′(x2)f(x1)+ℓ2′(x2)f(x2)+ℓ3′(x2)f(x3)+ℓ4′(x2)f(x4)+O(h4){\displaystyle f'(x_{2})=\ell

Brazilian Air Force (8,317 words) [view diff] no match in snippet view article find links to article

named as 14-X S. On 2006, the F-X Project was restarted under a new name: "F-X2 Project", and with a bigger budget. The competitors for acquisition were

Regula falsi (5,013 words) [view diff] no match in snippet view article find links to article

that f(x)=ax+c=0,{\displaystyle f(x)=ax+c=0,} if it is known that f(x1)=b1,f(x2)=b2.{\displaystyle f(x_{1})=b_{1},\qquad f(x_{2})=b_{2}.} Double false position

Abel transform (1,477 words) [view diff] no match in snippet view article find links to article

Referring to the figure on the right, the observer (I) will see F(y)=∫−∞∞f(x2+y2)dx,{\displaystyle F(y)=\int _{-\infty }^{\infty }f\left({\sqrt {x^{2}+y^{2}}}\right)\

Power set (2,415 words) [view diff] no match in snippet view article find links to article

sets) to the image morphism. That is, for A={x1,x2,...}∈P(S),Pf(A)={f(x1),f(x2),...}∈P(T){\displaystyle A=\{x_{1},x_{2},...\}\in {\mathsf {P}}(S),{\mathsf

Dirac operator (1,191 words) [view diff] no match in snippet view article find links to article

Rn, Ck ⊗ S) acting on spinor valued functions defined by f(x1,…,xk)↦(∂x1_f∂x2_f…∂xk_f){\displaystyle f(x_{1},\ldots ,x_{k})\mapsto {\begin{pmatrix}\partial

Secant method (1,419 words) [view diff] no match in snippet view article find links to article

small difference between xn and xn−1): x2=x1−f(x1)x1−x0f(x1)−f(x0),x3=x2−f(x2)x2−x1f(x2)−f(x1),⋮xn=xn−1−f(xn−1)xn−1−xn−2f(xn−1)−f(xn−2).{\displaystyle

Unification (computer science) (7,292 words) [view diff] no match in snippet view article

y_{1})} is a variant of f(x2,a,g(z2),y2){\displaystyle f(x_{2},a,g(z_{2}),y_{2})}, since f(x1,a,g(z1),y1){x1↦x2,y1↦y2,z1↦z2}=f(x2,a,g(z2),y2){\displaystyle

Bijective proof (700 words) [view diff] no match in snippet view article find links to article

complement taken in S. To show that f is a bijection, first assume that f(X1) = f(X2), that is to say, X1c = X2c. Take the complements of each side (in S), using

Shift operator (1,361 words) [view diff] no match in snippet view article find links to article

β(x)=1x{\displaystyle \beta (x)={\tfrac {1}{x}}} yields exp⁡(txddx)f(x)=f(x2+2t),{\displaystyle \exp \left({\frac {t}{x}}{\frac {d}{dx}}\right)f(x)=f\left({\sqrt

Surjective function (2,182 words) [view diff] no match in snippet view article find links to article

y3 in Y, but there are no x1, x2, and x3 in X such that y1 = f(x1), y2 = f(x2), and y3 = f(x3). Interpretation for surjective functions in the Cartesian

Average (3,230 words) [view diff] no match in snippet view article find links to article

create one's own average metric using the generalized f-mean: y=f−1(1n[f(x1)+f(x2)+⋯+f(xn)]){\displaystyle y=f^{-1}\left({\frac {1}{n}}\left[f(x_{1})+f(x_{2})+\cdots

Saab JAS 39 Gripen (28,321 words) [view diff] no match in snippet view article find links to article

Gripen D aircraft. In October 2008, Brazil selected three finalists for its F-X2 fighter programme: the Dassault Rafale B/C, the Boeing F/A-18E/F Super Hornet

Binary quadratic form (4,603 words) [view diff] no match in snippet view article find links to article

y)&=g(x,y),\\\alpha \delta -\beta \gamma &=1.\end{aligned}}} For example, with f=x2+4xy+2y2{\displaystyle f=x^{2}+4xy+2y^{2}} and α=−3{\displaystyle \alpha =-3}

Boole's rule (762 words) [view diff] no match in snippet view article find links to article

real x2 x3 x4)) (* (/ (* 2 h) 45) (+ (* 7 (funcall f x1)) (* 32 (funcall f x2)) (* 12 (funcall f x3)) (* 32 (funcall f x4)) (* 7 (funcall f x5))))))) In

Kernel (set theory) (898 words) [view diff] no match in snippet view article

x_{2}\in X} are equivalent if f(x1){\displaystyle f\left(x_{1}\right)} and f(x2){\displaystyle f\left(x_{2}\right)} are equal, that is, are the same element

Initial algebra (1,100 words) [view diff] no match in snippet view article find links to article

of sets, X0 on which f′ is not defined, X1 which elements map into X0 by f′, X2 which elements map into X1 by f′, etc., and Xω containing the remaining

Hölder condition (2,240 words) [view diff] no match in snippet view article find links to article

x_{k}=x+{\frac {k}{n}}(y-x)}. Then |f(x)−f(y)|≤|f(x0)−f(x1)|+|f(x1)−f(x2)|+…+|f(xn−1)−f(xn)|≤∑i=1nC(|x−y|n)α=C|x−y|αn1−α→0{\displaystyle |f(x)-f(y)|\leq

Embedding (2,623 words) [view diff] no match in snippet view article find links to article

X{\displaystyle X} and Y{\displaystyle Y} such that ∀x1,x2∈X:x1≤x2⟺F(x1)≤F(x2).{\displaystyle \forall x_{1},x_{2}\in X:x_{1}\leq x_{2}\iff F(x_{1})\leq

Autonomous system (mathematics) (2,181 words) [view diff] no match in snippet view article

ds=dt{\displaystyle ds=dt}, thus ddtx2(t)=ddtx1(t−t0)=ddsx1(s)=f(x1(s))=f(x2(t)).{\displaystyle {\frac {d}{dt}}x_{2}(t)={\frac {d}{dt}}x_{1}(t-t_{0})={\frac

Surface of revolution (1,835 words) [view diff] no match in snippet view article find links to article

we revolve the curve around the y-axis, then the curve is described by y=f(x2+z2){\displaystyle y=f({\sqrt {x^{2}+z^{2}}})}, yielding the expression (xcos⁡(θ)

Analytical chemistry (3,742 words) [view diff] no match in snippet view article find links to article

the error in f{\displaystyle f}: εa(f)≈∑i=1N|∂f∂xi|εa(xi)=|∂f∂x1|εa(x1)+|∂f∂x2|εa(x2)+…+|∂f∂xN|εa(xN){\displaystyle \varepsilon _{\rm {a}}(f)\approx \sum

MATH-MATIC (606 words) [view diff] no match in snippet view article find links to article

(12) X2 = (3 ROOT (E-G)+LOG (D+N)) / (F2.6*EXP H) . (13) WRITE EDIT F D F X2 SERVO 6 . (16) JUMP TO SENTENCE 10 . (20) STOP . Ash (1957) Univac (1958)

Nelder–Mead method (2,317 words) [view diff] no match in snippet view article find links to article

\mathbf {x} _{n+1}}. 1. Order according to the values at the vertices: f(x1)≤f(x2)≤⋯≤f(xn+1).{\displaystyle f(\mathbf {x} _{1})\leq f(\mathbf {x} _{2})\leq

Field line (2,010 words) [view diff] no match in snippet view article find links to article

a further distance ds{\displaystyle ds} in that direction the next point F(x2){\displaystyle \mathbf {F} (\mathbf {x} _{\text{2}})} of the field line is

Cantor's theorem (3,155 words) [view diff] no match in snippet view article find links to article

columns are ordered by the argument to f, i.e. the column labels are f(x1), f(x2), ..., in this order. The intersection of each row x and column y records

Total order (3,071 words) [view diff] no match in snippet view article find links to article

induces a total ordering on X by setting x1 ≤ x2 if and only if f(x1) ≤ f(x2). The lexicographical order on the Cartesian product of a family of totally

Boeing F/A-18E/F Super Hornet (15,041 words) [view diff] no match in snippet view article find links to article

Retrieved 26 October 2018. Trimble, Stephen. "Brazil names three finalists for F-X2 contract, rejects three others" Archived 1 February 2009 at the Wayback Machine

Gradient descent (5,015 words) [view diff] no match in snippet view article find links to article

F(\mathbf {x} _{n}),\ n\geq 0.} We have a monotonic sequence F(x0)≥F(x1)≥F(x2)≥⋯,{\displaystyle F(\mathbf {x} _{0})\geq F(\mathbf {x} _{1})\geq F(\mathbf

Vector field (3,967 words) [view diff] no match in snippet view article find links to article

exists a real-valued function (a scalar field) f on S such that V=∇f=(∂f∂x1,∂f∂x2,∂f∂x3,…,∂f∂xn).{\displaystyle V=\nabla f=\left({\frac {\partial f}{\partial

Lagrange polynomial (3,647 words) [view diff] no match in snippet view article find links to article

3}{\displaystyle \{1,\,2,\,3\}}: x0=1,y0=f(x0)=1,x1=2,y1=f(x1)=4,x2=3,y2=f(x2)=9.{\displaystyle {\begin{aligned}x_{0}&=1,&&&y_{0}=f(x_{0})&=1,\\[3mu]x_{1}&=2

Cauchy-continuous function (809 words) [view diff] no match in snippet view article find links to article

\left(x_{1},x_{2},\ldots \right)} in X,{\displaystyle X,} the sequence (f(x1),f(x2),…){\displaystyle \left(f\left(x_{1}\right),f\left(x_{2}\right),\ldots \right)}

Minimal surface of revolution (915 words) [view diff] no match in snippet view article find links to article

the boundary conditions that f(x1)=y1{\displaystyle f(x_{1})=y_{1}} and f(x2)=y2{\displaystyle f(x_{2})=y_{2}}. In this case, the optimal curve will necessarily

FP (programming language) (897 words) [view diff] no match in snippet view article

,f:xn〉 insert-right /f where /f:〈x〉 = x and /f:〈x1,x2,...,xn〉 = f:〈x1,/f:〈x2,...,xn〉〉 and /f:〈〉 = unit f insert-left \f where \f:〈x〉 = x and \f:〈x1

Euler–Maclaurin formula (3,403 words) [view diff] no match in snippet view article find links to article

xi = a + (i − 1)h, so that x1 = a and xN = b. Then: I=∫abf(x)dx∼h(f(x1)2+f(x2)+⋯+f(xN−1)+f(xN)2)+h212[f′(x1)−f′(xN)]−h4720[f‴(x1)−f‴(xN)]+⋯{\displaystyle

Simon's problem (2,945 words) [view diff] no match in snippet view article find links to article

strings, x1{\displaystyle x_{1}} and x2{\displaystyle x_{2}}, such that f(x1)=f(x2)=z{\displaystyle f(x_{1})=f(x_{2})=z}, where z∈range(f){\displaystyle z\in

SWIFFT (1,893 words) [view diff] no match in snippet view article find links to article

x1+x2{\displaystyle x_{1}+x_{2}} is also a valid input, we have that f(x1)+f(x2)=f(x1+x2){\displaystyle f(x_{1})+f(x_{2})=f(x_{1}+x_{2})}. This relation

Coordinate descent (1,580 words) [view diff] no match in snippet view article find links to article

By doing line search in each iteration, one automatically has F(x0)≥F(x1)≥F(x2)≥….{\displaystyle F(\mathbf {x} ^{0})\geq F(\mathbf {x} ^{1})\geq F(\mathbf

Evolutionary algorithm (4,457 words) [view diff] no match in snippet view article find links to article

x′{\displaystyle x'} will occur with a probability P>0{\displaystyle P>0}. Thus: F(x1′)≤F(x2′)≤F(x3′)≤⋯≤F(xk′)≤⋯{\displaystyle F(x'_{1})\leq F(x'_{2})\leq F(x'_{3})\leq

Dassault Rafale (21,404 words) [view diff] no match in snippet view article find links to article

Eurofighter Typhoon. In October 2008, the service selected three finalists for F-X2 – Dassault Rafale, Gripen NG and Boeing F/A-18E/F. On 5 January 2010, media

Karamata's inequality (776 words) [view diff] no match in snippet view article find links to article

…, n − 1}. By Karamata's inequality (1) for the convex function f, f(x1)+f(x2)+⋯+f(xn)≥f(a)+f(a)+⋯+f(a)=nf(a).{\displaystyle f(x_{1})+f(x_{2})+\cdots +f(x_{n})\geq

Future of the Brazilian Navy (1,944 words) [view diff] no match in snippet view article find links to article

Portos e Navios. 2 June 2019. Jennings, Gareth (18 December 2013). "Brazilian F‐X2 gives fresh impetus to Saab's Sea Gripen concept". IHS Jane's Defence Weekly

Log–log plot (2,701 words) [view diff] no match in snippet view article find links to article

} where F1 is shorthand for F(x1) and F2 is shorthand for F(x2). The figure at right illustrates the formula. Notice that the slope in the

Gröbner basis (9,146 words) [view diff] no match in snippet view article find links to article

I=⟨f,g⟩{\displaystyle I=\langle f,g\rangle } generated by the polynomials f=x2−y{\displaystyle f=x^{2}-y}, g=x3−x{\displaystyle g=x^{3}-x}. By reducing

General Dynamics F-16 Fighting Falcon variants (16,800 words) [view diff] no match in snippet view article find links to article

Model 1600 lost to the Northrop/McDonnell Douglas F/A-18 Hornet. For the F-X2 fighter programme for the Brazilian Air Force, Lockheed Martin offered the

Piecewise linear continuation (1,167 words) [view diff] no match in snippet view article find links to article

s+t≤1{\displaystyle s+t\leq 1\,} lf(x,y)=f(x0,y0)+(f(x1,y1)−f(x0,y0))s+(f(x2,y2)−f(x0,y0))t{\displaystyle lf(x,y)=f(x_{0},y_{0})+(f(x_{1},y_{1})-f(x_{0}

Calculus of variations (8,759 words) [view diff] no match in snippet view article find links to article

_{x_{1}}^{x_{2}}{\sqrt {1+[y'(x)]^{2}}}\,dx\,,} with y′(x)=dydx, y1=f(x1), y2=f(x2).{\displaystyle y'(x)={\frac {dy}{dx}}\,,\ \ y_{1}=f(x_{1})\,,\ \ y_{2}=f(x_{2})\

Exchange operator (866 words) [view diff] no match in snippet view article find links to article

is the one-electron exchange operator, and f(x1){\displaystyle f(x_{1})},f(x2){\displaystyle f(x_{2})} are the one-electron wavefunctions acted upon by

Multivariate t-distribution (5,079 words) [view diff] no match in snippet view article find links to article

}}_{11}^{-1}({\mathbf {X} _{1}}-{{\boldsymbol {\mu }}_{1}})\right]^{-(\nu \,+\,p_{1})/2}} f(X2)=Γ[(ν+p2)/2]Γ(ν/2)(νπ)p2/2|Σ22|1/2[1+1ν(X2−μ2)TΣ22−1(X2−μ2)]−(ν+p2)/2{\displaystyle

Newton polynomial (5,262 words) [view diff] no match in snippet view article find links to article

xn{\displaystyle x_{0},\ldots ,x_{n}}. Write x0f(x0)f(x1)−f(x0)x1−x0x1f(x1)f(x2)−f(x1)x2−x1−f(x1)−f(x0)x1−x0x2−x0f(x2)−f(x1)x2−x1x2f(x2)⋮⋮⋮⋮⋮xnf(xn){\displaystyle

Sukhoi Su-57 (14,687 words) [view diff] no match in snippet view article find links to article

chooses Gripen over Rafale". Business Standard India. Retrieved 19 July 2021. "F-X2: Brazils Saab Contract for Gripens a Done Deal". Defense Industry Daily.

Summation of Grandi's series (1,759 words) [view diff] no match in snippet view article find links to article

satisfies a functional equation: F(x)=x−x2+x4−x8+⋯=x−[(x2)−(x2)2+(x2)4−⋯]=x−F(x2).{\displaystyle {\begin{array}{rcl}F(x)&=&\displaystyle x-x^{2}+x^{4}-x^{8}+\cdots

Metric space (10,884 words) [view diff] no match in snippet view article find links to article

whenever a sequence (xn) converges to a point x in M1, the sequence f(x1),f(x2),…{\displaystyle f(x_{1}),f(x_{2}),\ldots } converges to the point f(x) in

Point process notation (1,518 words) [view diff] no match in snippet view article find links to article

in N{\displaystyle {N}} can be written in a number of ways such as: f(x1)+f(x2)+⋯{\displaystyle f(x_{1})+f(x_{2})+\cdots } which has the random sequence

Controversy over Cantor's theory (3,008 words) [view diff] no match in snippet view article find links to article

which maps A{\displaystyle A} onto P1.{\displaystyle P_{1}.} Since f(x1)=f(x2){\displaystyle f(x_{1})=f(x_{2})} implies x1=x2,f{\displaystyle x_{1}=x_{2}

Metric tensor (8,147 words) [view diff] no match in snippet view article find links to article

X=v1[f]X1+v2[f]X2+⋯+vn[f]Xn=f[v1[f]v2[f]⋮vn[f]]=fv[f]{\displaystyle X=v^{1}[\mathbf {f} ]X_{1}+v^{2}[\mathbf {f} ]X_{2}+\dots +v^{n}[\mathbf {f} ]X_{n}=\mathbf

Minkowski space (10,041 words) [view diff] no match in snippet view article find links to article

\otimes V^{*}} _{k{\text{ times}}}.} It is defined by F∗(α)(X1,X2,…,Xk)=α(F∗X1,F∗X2,…,F∗Xk),{\displaystyle F^{*}(\alpha )\left(X_{1},\,X_{2},\,\ldots ,\,X_{k}\right)=\alpha

Length of a module (1,990 words) [view diff] no match in snippet view article find links to article

h=x03+x13+x23+x23{\displaystyle h=x_{0}^{3}+x_{1}^{3}+x_{2}^{3}+x_{2}^{3}} and f=x2+y2{\displaystyle f=x^{2}+y^{2}} and g=h2(x0+x1−x3){\displaystyle

Real coordinate space (4,099 words) [view diff] no match in snippet view article find links to article

are continuous. If ∀x1 ∈ R : f(x1, ·) is continuous (by x2) ∀x2 ∈ R : f(·, x2) is continuous (by x1) then F is not necessarily continuous. Continuity

Fourier transform (20,270 words) [view diff] no match in snippet view article find links to article

around x = 0 may be measured by the dispersion about zero defined by D0(f)=∫−∞∞x2|f(x)|2dx.{\displaystyle D_{0}(f)=\int _{-\infty }^{\infty }x^{2}|f(x)|^{2}\

Ziggurat algorithm (2,080 words) [view diff] no match in snippet view article find links to article

A/x1, and intersects the density function at a point (x2, y2), where y2 = f(x2). This layer includes every point in the density function between y1 and

Northrop F-5 (20,227 words) [view diff] no match in snippet view article find links to article

Retrieved: 27 December 2011. "Burnier: primeiros F-5 darão baixa em 2017, F-X2 não pode ser mais postergado" (in Portuguese). Archived 23 November 2011

International Traffic in Arms Regulations (8,644 words) [view diff] no match in snippet view article find links to article

or replaced it with technology derived from non-military sources. For the F-X2 program, the Brazilian government have chosen the French Dassault Rafale

Spectral theory of ordinary differential equations (8,833 words) [view diff] no match in snippet view article find links to article

expansion associated with the Legendre differential operator D Df=−((x2−1)f′)′=−(x2−1)f″−2xf′{\displaystyle Df=-((x^{2}-1)f')'=-(x^{2}-1)f''-2xf'} on (1,

Matrix calculus (6,664 words) [view diff] no match in snippet view article find links to article

and its result can be easily collected in vector form. ∇f=(∂f∂x)T=[∂f∂x1∂f∂x2∂f∂x3]T.{\displaystyle \nabla f=\left({\frac {\partial f}{\partial \mathbf

Equicontinuity (3,717 words) [view diff] no match in snippet view article find links to article

equicontinuous if for every ε > 0, there exists a δ > 0 such that d(ƒ(x1), ƒ(x2)) < ε for all ƒ ∈ F and all x1, x2 ∈ X such that d(x1, x2) < δ. For comparison

Formal power series (9,058 words) [view diff] no match in snippet view article find links to article

they belong to the ideal (X){\displaystyle (X)}): f(0){\displaystyle f(0)}, f(X2−X){\displaystyle f(X^{2}-X)} and f((1−X)−1−1){\displaystyle f((1-X)^{-1}-1)}

Embraer C-390 Millennium (7,424 words) [view diff] no match in snippet view article find links to article

DC. Retrieved 14 May 2010. Wall, Robert (21 July 2010). "KC-390 advances, F-X2 doesn't". Aviation Week. Archived from the original on 29 September 2012

Moser–de Bruijn sequence (2,390 words) [view diff] no match in snippet view article find links to article

given by the Moser–de Bruijn sequence, obeys the functional equations F(x)F(x2)=11−x{\displaystyle F(x)F(x^{2})={\frac {1}{1-x}}} and F(x)=(1+x)F(x4).{\displaystyle

Equivalent definitions of mathematical structures (3,272 words) [view diff] no match in snippet view article find links to article

scale sets. Namely, the bijection X × X → Y × Y sends (x1,x2) to (f(x1),f(x2)); the bijection P(X) → P(Y) sends a subset A of X into its image f(A) in

General Dynamics F-16 Fighting Falcon operators (17,273 words) [view diff] no match in snippet view article find links to article

Down Under. Fyshwick, ACT: Phantom Media. pp. 51–62. ISBN 0646443984. f-x2. "F-X2: Brazil Buys Saab’s JAS-39E/F Gripen over Rafale, Super Hornet." Defense

Big Brother (Portuguese TV series) season 6 (3,314 words) [view diff] no match in snippet view article

F., Carina Pedro, Michel, Rui Pedro, Rui Pedro (x2), Rui (x2), Jéssica F. (x2) Pedro, Joana, Andreia Pedro, Joana, Renato Pedro, Joana Carina (x3), Jéssica

General Concept Lattice (9,589 words) [view diff] no match in snippet view article find links to article

∀X1∀X2∈EF X1≠X2{\textstyle \forall X_{1}\forall X_{2}\in E_{F}\ X_{1}\neq X_{2}} iff [X1]F∩[X2]F=∅{\textstyle [X_{1}]_{F}\cap [X_{2}]_{F}=\emptyset }, X1⊂X2{\textstyle