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searching for Delta Epsilon Mu 1 found (4 total)
alternate case: delta Epsilon Mu
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) d α = J μ ν ∂ G ∂ ϵ ν ( ϵ ( η , t ; α ) , t ) {\displaystyle \delta \epsilon ^{\mu }(\eta ,t;\alpha )=\delta \alpha \{\epsilon ^{\nu },G\}=\delta \alpha