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searching for Inverse element 8 found (44 total)

alternate case: inverse element

Multiplicative order (609 words) [view diff] exact match in snippet view article find links to article

s > t, such that as ≡ at (mod n). Since a and n are coprime, a has an inverse element a−1 and we can multiply both sides of the congruence with a−t, yielding
Regular representation (1,539 words) [view diff] exact match in snippet view article find links to article
case, the mapping on basis elements g of K[G] defined by taking the inverse element gives an isomorphism of K[G] to its opposite ring. For A general, such
Absolute value (algebra) (1,313 words) [view diff] exact match in snippet view article
sequence, and by taking pointwise inversion we can find a representative inverse element. Another theorem of Alexander Ostrowski has it that any field complete
Measurable group (368 words) [view diff] exact match in snippet view article find links to article
definition of a topological group, the group law and the formation of the inverse element is continuous, both operations are in this case also measurable from
Banach algebra (2,602 words) [view diff] exact match in snippet view article find links to article
singular in the given algebra A {\displaystyle A} have a multiplicative inverse element in a Banach algebra extension B . {\displaystyle B.} Topological divisors
Abelian group (5,288 words) [view diff] exact match in snippet view article find links to article
equation e ⋅ a = a ⋅ e = a {\displaystyle e\cdot a=a\cdot e=a} holds. Inverse element For each a {\displaystyle a} in A {\displaystyle A} there exists an
Hopf algebra (4,308 words) [view diff] exact match in snippet view article find links to article
means exactly that every element x∈H{\displaystyle x\in H} has an inverse element x−1∈H{\displaystyle x^{-1}\in H} with respect to the multiplication
Kaniadakis statistics (4,461 words) [view diff] exact match in snippet view article find links to article
{\kappa }{\oplus }}x=x} 3. inverse element:x⊗κx¯=x¯⊗κx=Iforx¯=κ−1sinh⁡(κ2/arcsinh(κx)){\displaystyle {\text{3. inverse element:}}\quad x{\stackrel {\kappa