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Longer titles found: Delta Electric Company (view), Delta Electricity (view), Delta Electronics (view), Delta Entertainment Corporation (view), Delta Epsilon (fraternity) (view), Delta Epsilon Chi (view), Delta Epsilon Iota (view), Delta Epsilon Mu (view), Delta Epsilon Psi (view), Delta Epsilon Sigma (view), Delta Equulei (view), Delta Eridani (view), Delta Ethniki (view), Delta Express (view)

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alternate case: delta E

Quantum fluctuation (1,192 words) [view diff] exact match in snippet view article find links to article

uncertainty in energy and time can be related by ΔEΔt≥12ℏ {\displaystyle \Delta E\,\Delta t\geq {\tfrac {1}{2}}\hbar ~}, where 1/2ħ ≈ 5.27286×10−35 Js. This

interval between E{\displaystyle E} and E+δE{\displaystyle E+\delta E}. Here δE{\displaystyle \delta E} is a macroscopically small energy interval that is kept

{\displaystyle E+\delta E} to above E + δ E {\displaystyle E+\delta E} is given by N Y ( E + δ E ) {\displaystyle N_{Y}\left(E+\delta E\right)} . The difference

D(E)=N(E)/V{\displaystyle D(E)=N(E)/V}, where N(E)δE{\displaystyle N(E)\delta E} is the number of states in the system of volume V{\displaystyle V} whose

temperature T has the property Z(E+ΔE)=Z(E)eΔE/kBT,{\displaystyle Z(E+\Delta E)=Z(E)e^{\Delta E/k_{\text{B}}T},} where kB{\displaystyle k_{\text{B}}} is the Boltzmann

Euclidean distance: ΔEITP=720(I1−I2)2+(T1−T2)2+(P1−P2)2,{\displaystyle \Delta E_{\text{ITP}}=720{\sqrt {(I_{1}-I_{2})^{2}+(T_{1}-T_{2})^{2}+(P_{1}-P_{2})^{2}}}

energy that is linear in the field strength. (ΔE∼1/r2){\displaystyle (\Delta E\sim 1/r^{2})} Resonance broadening occurs when the perturbing particle

affinity (A) and the ionization potential (I): ΔE=A−I{\displaystyle {\Delta }E=A-I\,} Electron donors are components of many devices such as organic photovoltaic

{\displaystyle {\begin{aligned}\Delta E/\Delta t&=(\ \Delta E_{T}+\Delta E_{C}+\Delta E_{W}+\Delta E_{A}+\Delta E_{G}+\Delta E_{S}+\Delta E_{I}+...\ )/\Delta t\\\\&=ASR-OLR

x2+Pz2)+Pz4(Px2+Py2)]+12α123Px2Py2Pz2{\displaystyle {\begin{array}{ll}\Delta E=&{\frac {1}{2}}\alpha _{0}\left(T-T_{0}\right)\left(P_{x}^{2}+P_{y}^{2

\Delta E_{\text{total}}=Q+W=0} Also, total internal energy change ΔEtotal=ΔEsystem+ΔEsurroundings=0{\displaystyle \Delta E_{\text{total}}=\Delta E

ΔEi{\displaystyle \Delta E_{i}}, assuming a symmetric matrix of weights, is given by: ΔEi=∑j>iwijsj+∑j<iwjisj+θi{\displaystyle \Delta E_{i}=\sum _{j>i}w_{ij}\

that the net change in the energy is zero, ΔE1−ΔE2=0{\displaystyle \Delta E_{1}-\Delta E_{2}=0} where ΔE1 and ΔE2 are the energy entering through A1 and leaving

_{e\in E}c_{e}\delta _{e}} where ce{\displaystyle c_{e}} are in R and only finitely many of them are nonzero and δe{\displaystyle \delta _{e}} is given as

linear velocity and angular velocity of that body, W=ΔEk.{\displaystyle W=\Delta E_{\text{k}}.} The work of forces generated by a potential function is known

⇒ Δ ( E k + E p ) = 0 . {\displaystyle -\Delta E_{\mathrm {p} }=\Delta E_{\mathrm {k} }\Rightarrow \Delta (E_{\mathrm {k} }+E_{\mathrm {p} })=0\,.} This

launched on 6 November 1965 from Cape Canaveral, Florida, with a Thor-Delta E launch vehicle. Explorer 29 was a gravity-gradient-stabilized, solar cell

\log \left({\frac {k_{s}}{k_{{\ce {CH3}}}}}\right)=\rho ^{*}\sigma ^{*}+\delta E_{s}} where log⁡kskCH3{\displaystyle \log {\frac {k_{s}}{k_{{\ce {CH3}}}}}}

Gibbs' theory becomes neFΔE=neFΔE∘−RTln⁡Q{\displaystyle n_{e}F\Delta E=n_{e}F\Delta E^{\circ }-RT\ln Q} Here ne is the number of electrons (in moles)

{\displaystyle \Delta E\Delta t\gtrsim \hbar /2,} has a long, controversial history; the meaning of Δt{\displaystyle \Delta t} and ΔE{\displaystyle \Delta E} varies

v)=\delta (e,v)=22/2=11} We deduce the missing branch length: δ(u,v)=δ(e,v)−δ(a,u)=δ(e,v)−δ(b,u)=11−8.5=2.5{\displaystyle \delta (u,v)=\delta (e,v)-\delta

time scales, the uncertainty in the energy is by ΔEΔt≥ℏ2{\displaystyle \Delta E\Delta t\geq {\frac {\hbar }{2}}} which is similar in form to the Heisenberg

\Delta S=-(dS/dE)_{1}\cdot \Delta E+(dS/dE)_{2}\cdot \Delta E=\left({\frac {1}{T_{2}}}-{\frac {1}{T_{1}}}\right)\Delta E} and is thus positive if T 1

−qe2Rx+ΔE0=0{\displaystyle {\frac {-q_{e}^{2}}{R_{x}}}+\Delta E_{0}=0} With ΔE0=Ei−Eea{\displaystyle \Delta E_{0}=E_{i}-E_{e}a}, where Ei is the ionization potential

{\frac {n_{+}}{n_{0}}}={\frac {g_{+}}{g_{0}}}\exp {\Bigg (}{\frac {W-\Delta E_{\text{I}}}{kT}}{\Bigg )}} where n+n0{\displaystyle {\frac {n_{+}}{n_{0}}}}

\delta E\sin(\Omega t)+{\mathcal {O}}(\delta E^{2}),\\i_{2}(t)&={\tfrac {1}{2}}E_{0}^{2}+E_{0}\,\delta E\sin(\Omega t-\Phi )+{\mathcal {O}}(\delta E^{2})

by the equation ΔE=hνL=gμBB,{\displaystyle \Delta E=h\nu _{L}=g\mu _{B}B,} where ΔE{\displaystyle \Delta E} is the energy of the Zeeman interaction, νL{\displaystyle

total energy is: 2. ΔEtot=ΔEpot+ΔEkin{\displaystyle \Delta E_{\text{tot}}=\Delta E_{\text{pot}}+\Delta E_{\text{kin}}} Since 3. Potential energy is proportional

irreversible, ΔEtot=ΔEkin+ΔEpot+ΔU.{\displaystyle \Delta E^{\mathrm {tot} }=\Delta E^{\mathrm {kin} }+\Delta E^{\mathrm {pot} }+\Delta U\,\,.} The first law

Able Alfa Alfa B Baker Bravo Bravo C Charlie Charlie Charlie D Dog Delta Delta E Easy Echo Echo F Fox Foxtrot Foxtrot G George Golf Golf H How Hotel Hotel

\mu \nu }\\E^{\alpha \beta \gamma \delta }E_{\alpha \beta \gamma \delta }&=-24\\E^{\alpha \beta \gamma \delta }E_{\rho \beta \gamma \delta }&=-6\delta

ΔEC/ΔEV{\displaystyle \Delta E_{C}/\Delta E_{V}} tends to maintain the value 60/40. For comparison, Anderson's rule predicts ΔEC/ΔEV=0.73/0.27{\displaystyle \Delta E_{C}/\Delta

{\displaystyle \Delta E=h\,\Delta \nu \geq {\frac {h}{\Delta t}}.} From this it follows immediately that: ΔEΔt≥h{\displaystyle \Delta E\,\Delta t\geq h}

{\text{Eff}}}=E_{G}^{\text{well,relaxed}}+\Delta E_{G}^{\text{Strain}}+\Delta E_{G}^{\text{QSE}}+\Delta E_{G}^{\text{QCSE}}} The strain of the material

δe=1α/2=2α=2δp{\displaystyle \delta _{e}={\frac {1}{\alpha /2}}={\frac {2}{\alpha }}=2\delta _{p}} Note that δe{\displaystyle \delta _{e}} is identical to the

{\frac {\exp\{-(E-\langle E\rangle )^{2}/2\langle (\Delta E)^{2}\rangle \}}{\sqrt {2\pi (\Delta E)^{2}}}}.} This is the Gaussian, or normal, distribution

between two energy levels, nf and ni is: ΔE=(nf2−ni2)h28mL2{\displaystyle \Delta E={\frac {(n_{f}^{2}-n_{i}^{2})h^{2}}{8mL^{2}}}} The difference between the

Successful telemetry contact for about two hours. Launch of Pioneer 6 on a Delta-E rocket August 17, 1966 Launched from Cape Canaveral into solar orbit with

ΔE)=ΔE ∂Ω∂E=ΔE ρ(E),{\displaystyle \Sigma (E,\Delta E)=\Delta E\ {\frac {\partial \Omega }{\partial E}}=\Delta E\ \rho (E),} where ρ(E) is the density of states

(E)=\lim _{\delta \to 0}\mu _{\delta }(E),} where μδ(E)=inf{∑i=1∞τ(Ci)|Ci∈Σ,diam⁡(Ci)≤δ,⋃i=1∞Ci⊇E},{\displaystyle \mu _{\delta }(E)=\inf \left\{\left.\sum _{i=1}^{\infty

corresponding to n = 2, is given by ΔE2,1,mℓ=±|e|ℏ2/(mee2)E{\displaystyle \Delta E_{2,1,m_{\ell }}=\pm |e|\hbar ^{2}/(m_{e}e^{2})E}. Density of states Merzbacher

v)=\delta (e,v)=23/2=11.5} We deduce the missing branch length: δ(u,v)=δ(e,v)−δ(a,u)=δ(e,v)−δ(b,u)=11.5−8.5=3{\displaystyle \delta (u,v)=\delta (e,v)-\delta

\Gamma _{if}={\frac {2\pi }{\hbar }}\left|\langle f|H'|i\rangle \right|^{2}\delta (E_{f}-E_{i}\pm \hbar \omega ),} with H′≈eA0m0ε⋅p,{\displaystyle H'\approx

\Delta E} can evolve into an orthogonal and hence distinguishable state to another, Δt=πℏ2ΔE.{\displaystyle \Delta t={\frac {\pi \hbar }{2\Delta E}}

+ N − = e − Δ E k T {\displaystyle {\frac {N_{+}}{N_{-}}}=e^{-{\frac {\Delta E}{kT}}}} where ΔE is the energy level difference between the two populations

r)-\delta (a,v)=\delta (b,r)-\delta (b,v)=\delta (c,r)-\delta (c,v)=\delta (e,r)-\delta (e,v)=14-10.5=3.5} The dendrogram is now complete. It is ultrametric

(\mathbf {r} ')}{|\mathbf {r} -\mathbf {r} '|}}\,d\mathbf {r} '+{\frac {\delta E_{\text{xc}}[\rho ]}{\delta \rho (\mathbf {r} )}},} where the last term

_{j}\delta e_{ik}-\nabla _{k}\delta e_{ij})+(\nabla _{k}\delta e_{ji}-\nabla _{i}\delta e_{jk})-(\nabla _{i}\delta e_{kj}-\nabla _{j}\delta e_{ki})\right\}

p)=V(x(q,p),y(q,p))=δep−γp+βeq−αq{\displaystyle H(q,p)=V(x(q,p),y(q,p))=\delta e^{p}-\gamma p+\beta e^{q}-\alpha q}: {q˙=∂H∂p=δep−γ,p˙=−∂H∂q=α−βeq.{\displaystyle

system: Ein−Eout=ΔEsystem{\displaystyle E_{\text{in}}-E_{\text{out}}=\Delta E_{\text{system}}} where Ein{\displaystyle E_{\text{in}}} is the energy into

the levels according to the Planck relation: ΔE=E2−E1=hν{\displaystyle \Delta E=E_{2}-E_{1}=h\nu }, where h{\displaystyle h} is Planck's constant. Other

v_{1}}{\partial e_{1}}}\delta e_{1}+{\frac {\partial v_{1}}{\partial x}}\delta x} Solving for the ratio δx/δe1{\displaystyle \delta x/\delta e_{1}} we obtain:

presence of a magnetic field B: ΔE=eℏB2m(mj,fgJ,f−mj,igJ,i){\displaystyle \Delta E={\frac {e\hbar B}{2m}}(m_{j,f}g_{J,f}-m_{j,i}g_{J,i})} Here mj are quantum

rise to the energy correction of the form ΔESO=ξ(r)L⋅S{\displaystyle \Delta E_{\mathrm {SO} }=\xi (r)\mathbf {L} \cdot \mathbf {S} } Notice that an important

can be used. The Borda–Carnot equation is ΔE=ξρ2(v1−v2)2,{\displaystyle \Delta E=\xi \,{\frac {\rho }{2}}\,(v_{1}-v_{2})^{2},} where ΔE is the fluid's mechanical

{\displaystyle \Delta E.} This gives rise to a self-capacitance C{\displaystyle C} of the island, defined as C=e2ΔE.{\displaystyle C={\frac {e^{2}}{\Delta E}}.} To

{1}{\epsilon _{\text{opt}}}}-{\frac {1}{\epsilon _{\text{s}}}}\right)\cdot (\Delta e)^{2}} Where r1 and r2 are the radii of the spheres and R is their separation

dx&\geq \int _{x_{0}-\delta }^{x_{0}+\delta }e^{nf(x)}\,dx\\&\geq e^{nf(x_{0})}\int _{x_{0}-\delta }^{x_{0}+\delta }e^{{\frac {n}{2}}(f''(x_{0})-\varepsilon

{\displaystyle i_{\$}=i_{c}+{\frac {{\Delta }E_{t}(S_{t+k})}{S_{t}}}} where Δ E t ( S t + k ) {\displaystyle {{\Delta }E_{t}(S_{t+k})}} is the change in the

energy shift can be calculated as ΔE=−ℏ2M∑i>j∫ψ∗∇i⋅∇jψd3r,{\displaystyle \Delta E=-{\frac {\hbar ^{2}}{M}}\sum _{i>j}\int \psi ^{*}\nabla _{i}\cdot \nabla

only valid if: the level spacing in the quantum-dot ΔE{\displaystyle \Delta E} is much greater than kT{\displaystyle \;kT} the pulse time scale τs{\displaystyle

v)=\delta (e,v)=22/2=11} We deduce the missing branch length: δ(u,v)=δ(e,v)−δ(a,u)=δ(e,v)−δ(b,u)=11−8.5=2.5{\displaystyle \delta (u,v)=\delta (e,v)-\delta

m_{l}=0,\pm 1} selection rule. The splitting ΔE=BμBΔml{\displaystyle \Delta E=B\mu _{\rm {B}}\Delta m_{l}} is independent of the unperturbed energies

For each sample, calculate the Euclidean distance ΔEi{\displaystyle \Delta E_{i}} between the pair of co-ordinates. Calculate the special (i.e., particular)

time-averaged. U(r)=ΔEi=3πc2Γ2ω03I(r)×∑jcij2Δij{\displaystyle U(\mathbf {r} )=\Delta E_{i}={\frac {3\pi c^{2}\Gamma }{2\omega _{0}^{3}}}I(\mathbf {r} )\times

between the lower and the upper state is Δ E = g e μ B B 0 {\displaystyle \Delta E=g_{e}\mu _{\text{B}}B_{0}} for unpaired free electrons. This equation implies

δE{\displaystyle \delta E} due to phonon noise near quasi-equilibrium is described using a similar formula,  δE=kBT2C,{\displaystyle \ \delta E={\sqrt {k_{\text{B}}T^{2}C}}

(640 lb) Start of mission Launch date 21 January 1967, 17:31 GMT Rocket Thor-Delta E Launch site Vandenberg Space Launch Complex 2 Entered service 21 January

Δe(w){\displaystyle \exists w.\Delta _{e}(w)} in e{\displaystyle e}, i.e. the class H:={e∣∃w.Δe(w)}{\displaystyle H:=\{e\mid \exists w.\Delta _{e}(w)\}} of partial

The Dickey E-Racer, also called the Sierra Delta E-Racer, is an American homebuilt aircraft that was designed by Shirl Dickey and produced by Shirl Dickey

yS{\displaystyle \Delta E=2\sigma _{x,y}S} (see the Hamiltonian for the Ising model). Flip the spin with probability 1/(1+eΔE/T){\displaystyle 1/(1+e^{\Delta E/T})}

}\left[\delta (E_{\alpha }-E_{0}-\omega )\left|\left\langle \alpha \mid \psi _{\mathbf {k} }^{\dagger }\mid 0\right\rangle \right|^{2}-\zeta \delta (E_{0}-E_{\alpha

both the valence band (ΔEv{\displaystyle \Delta E_{\rm {v}}}) and the conduction band (ΔEc{\displaystyle \Delta E_{\rm {c}}}). After applying Anderson's

Arrhenius and Eyring equations: k(T)=PZe−ΔE/RT,{\displaystyle k(T)=PZe^{-\Delta E/RT},} where P is the steric (or probability) factor and Z is the collision

{\mathcal {A}}(|\mathbf {p} \rangle \to |\mathbf {p} '\rangle )-1=2\pi \delta (E_{p}-E_{p'})(-i)\int d^{3}\mathbf {r} \,V(\mathbf {r} )e^{-i(\mathbf {p}

difference between the two states, given by ΔE12=E2−E1,{\displaystyle \Delta E_{12}=E_{2}-E_{1},} determines the characteristic frequency ν12{\textstyle

N_{0}-E_{0}}{kT}}+e^{\frac {\mu N_{0}-\mu -E_{0}-\Delta E_{\rm {I}}-q\phi }{kT}}+e^{\frac {\mu N_{0}+\mu -E_{0}+\Delta E_{\rm {A}}+q\phi }{kT}}{\Big )}.\\&=E_{0}-\mu

Baker Bravo C Canteen Chain Canada Cast Charlie D Diver Dog Damascus Dog Delta E Eagle Egg Ecuador Easy Echo F Fisher Fox France Fox Foxtrot G Gangway Gig

band-carrier. A polaron is characterized by its self-energy ΔE{\displaystyle \Delta E}, an effective mass m∗{\displaystyle m^{*}} and by its characteristic response

{a}{2}}({\sqrt {5}}+1)\;} and the base height of ΔE10E1M{\displaystyle \Delta \,E_{10}E_{1}M\,} (i.e. the length of [MD]{\displaystyle [M\,D]}) is

the law of conservation of energy can be written as ΔE=0{\displaystyle \Delta E=0}, where E{\displaystyle E} is the total amount of energy in the universe

ΔEMossbauer=ΔEs−ΔEa=−e∫δϕ(|ψs|2−|ψa|2)dτ.{\displaystyle \Delta E_{\text{Mossbauer}}=\Delta E_{\text{s}}-\Delta E_{\text{a}}=-e\int \delta \phi {\big (}|\psi

x^{2}}{\tau _{D}}}\right\rangle \sim {\frac {c^{2}\delta E^{2}}{B^{2}k_{\perp }^{2}\,D}}\sim {\frac {c\delta E}{Bk_{\perp }}}.} It clearly yields for the diffusion

Part */ q = 6 + 52/n; sum = 0; z = v[n-1]; for (; q > 0; --q) { sum += DELTA; e = (sum >> 2) & 3; for (p=0; p<n-1; p++) { y = v[p+1]; z = v[p] += MX; }

particle energy after n turns will be: E ( n ) = n Δ E {\displaystyle E(n)=n\Delta E} Combining this with the non-relativistic equation for the kinetic energy

fluctuation") is ⟨(ΔE)2⟩≡⟨(E−⟨E⟩)2⟩=⟨E2⟩−⟨E⟩2=∂2ln⁡Z∂β2.{\displaystyle \langle (\Delta E)^{2}\rangle \equiv \langle (E-\langle E\rangle )^{2}\rangle =\langle E^{2}\rangle

e-}}&&(\Delta E^{\circ }=-{\text{1.53 V}})\\&{\ce {6 H+ + 6 e- -> 3 H2}}&&(\Delta E^{\circ }={\text{0 V}})\\&{\ce {2 H2O -> O2 + 4 H+ + 4 e-}}&&(\Delta E^{\circ

shift itself is given by ΔELamb=α5mec2k(n,0)4n3 for ℓ=0{\displaystyle \Delta E_{\mathrm {Lamb} }=\alpha ^{5}m_{e}c^{2}{\frac {k(n,0)}{4n^{3}}}\ \mathrm

CHARLIE COCO Coca Coca Charlie D Danemark Dog DOG DAVID DADO Delta Delta Delta E Edison Easy EASY EDWARD ELSA Echo Echo Echo F Florida Fox FOX FREDDIE FIESTA

_{-}-\psi _{-}\nabla ^{2}\psi _{+}={}-2\,\Delta E\,\psi _{-}\psi _{+}\;.} where ΔE=E−−E+{\displaystyle \Delta E=E_{-}-E_{+}} is the exchange energy splitting

{\displaystyle \Gamma _{\mu \to \nu }={\frac {2\pi }{\hbar }}|M_{\mu \nu }|^{2}\delta (E_{\mu }^{S}-E_{\nu }^{T}).} Solid-state systems are commonly described in

 {\displaystyle \Delta E_{Q}=(1-a_{0}^{2})(E_{\rm {CISD}}-E_{\rm {HF}}),\ } ECISDTQ≈ECISD+ΔEQ, {\displaystyle E_{\rm {CISDTQ}}\approx E_{\rm {CISD}}+\Delta E_{Q},\

interaction energy can be written as: ΔEint=E(A,B)−(E(A)+E(B)),{\displaystyle \Delta E_{\text{int}}=E(A,B)-\left(E(A)+E(B)\right),} where E(A){\displaystyle E(A)}

1994. Castor 2 stages were also used as the strap-on boosters for the Delta-E, and for the Japanese-built N-I, N-II and H-I rockets. It retained the

flux rate}}{\lambda _{v}E={\frac {\Delta (R_{n}-G)+\rho _{a}c_{p}\left(\delta e\right)g_{a}}{\Delta +\gamma \left(1+g_{a}/g_{s}\right)}}}}~\iff ~{\overset

{r} )={\frac {\delta E^{\mathrm {LDA} }}{\delta \rho _{\alpha \beta }(\mathbf {r} )}}={\frac {1}{2}}\delta _{\alpha \beta }{\frac {\delta E^{\mathrm {LDA}

}}|\langle f|H'|i\rangle |^{2}\delta (E_{f}-E_{i}-h\nu )\propto |\langle f|\mathbf {A} \cdot \mathbf {p} |i\rangle |^{2}\,\delta (E_{f}-E_{i}-h\nu )}, The delta

viewed visually and digitally, both depend on the customer's requirements. Delta E (dE-CMC) expresses the difference between the original standard and the

magnetic field. The difference in the energies is ΔE=±12gμBB{\textstyle \Delta E=\pm {\frac {1}{2}}g\mu _{\rm {B}}B} being g{\displaystyle g} a factor which

magnetic field. The difference in the energies is ΔE=±12gμBB{\textstyle \Delta E=\pm {\frac {1}{2}}g\mu _{\rm {B}}B} being g{\displaystyle g} a factor which

ΔEn{\displaystyle \Delta E_{n}} be the change in energy in |n⟩{\displaystyle |n\rangle }. So we get ΔEn=⟨n|ΔH|n⟩+∑m,Em≠En|⟨n|ΔH|m⟩|2En−Em.{\displaystyle \Delta E_{n}=\langle

to another with a difference in the function value of ΔE{\displaystyle \Delta E}. The acceptance probability of such a trial jump is in most cases chosen

is given by, ρ(E)=∫δ(E(x)−E)dx=∫δ(x2−E)dx,{\displaystyle \rho (E)=\int \delta (E(x)-E)\,dx=\int \delta (x^{2}-E)\,dx,} by performing the last integral we

detrimental to the gamut density and result in high ΔE{\displaystyle \Delta E} errors[further explanation needed]. More recent color spaces such as Rec

(t)|dt{\displaystyle \left|\int _{0}^{\delta }e^{-xt}\varphi (t)\,\mathrm {d} t\right|\leq \int _{0}^{\delta }e^{-xt}|\varphi (t)|\,\mathrm {d} t\leq \int

{[A]_{t}}{[B]_{t}}}\right)=\ln \left({\frac {k_{A}}{k_{B}}}\right)=-{\frac {\Delta E_{a}}{RT}}}     (equation 1) Unless equilibration is prevented (e.g., by

or Adobe RGB are shorthand notations. Color accuracy - measured in ΔE (delta-E); the lower the ΔE, the more accurate the color representation. A ΔE of

ΔEint=EAB−EA−EB{\displaystyle \Delta E_{\rm {int}}=E_{\rm {AB}}-E_{\rm {A}}-E_{\rm {B}}} where ΔEint{\textstyle \Delta E_{\rm {int}}} is the total interaction

Hamiltonian H) gives: ΔEΔT≥ℏ2{\displaystyle \Delta E\Delta T\geq {\frac {\hbar }{2}}} where ΔE{\displaystyle \Delta E} is the uncertainty in energy ΔT{\displaystyle

\Delta E} of the thermal system. Negative ΔE{\displaystyle \Delta E}, i. e. excess energy, is given to the demon by adding |ΔE|{\displaystyle |\Delta E|}

−cos⁡(Φ)⋅tan⁡(δ)⋅cos⁡(h)){\displaystyle {\displaystyle \Delta \alpha =\Delta e\cdot \tan {(\delta )}\cdot \sin(h)+\Delta a\cdot \left(\sin(\Phi )-\cos(\Phi

equation Δe4+[(A+C)2−4Δ]e2−[(A+C)2−4Δ]=0,{\displaystyle \Delta e^{4}+[(A+C)^{2}-4\Delta ]e^{2}-[(A+C)^{2}-4\Delta ]=0,} where again Δ=AC−B24.{\displaystyle

The energy difference between the two states is: ΔE=γℏB0,{\displaystyle \Delta {E}=\gamma \hbar B_{0}\,,} and this results in a small population bias favoring

{u}}}{n_{\rm {l}}}}={\frac {g_{\rm {u}}}{g_{\rm {l}}}}\exp {\left(-{\frac {\Delta E}{kT_{\rm {ex}}}}\right)},} where nu is the number of particles in an upper

}K\Phi (-d_{2})-Se^{-q\tau }\Phi (-d_{1})\,} delta ( Δ {\displaystyle \Delta } ) e − q τ Φ ( d 1 ) {\displaystyle e^{-q\tau }\Phi (d_{1})\,} − e − q τ Φ

Rαβ=RαγIJeβIeJγ,R=RαβIJeIαeJβ{\displaystyle {R_{\alpha \beta \gamma }}^{\delta }=e_{\gamma }^{I}{R_{\alpha \beta I}}^{J}e_{J}^{\delta },\quad R_{\alpha \beta

{4\left({\frac {\Delta I_{\text{obj}}}{I_{\text{obj}}}}\right)^{2}+\left({\frac {\Delta E}{V_{\text{acc}}}}\right)^{2}+\left({\frac {\Delta V_{\text{acc}}}{V_{\

p{\displaystyle \mathbf {D} ^{1,p}} that lies in the domain of δ{\displaystyle \delta }, E[(δu)2]=E∫|ut|2dt+E∫DsutDtusdsdt.{\displaystyle \mathbf {E} {\big [}(\delta

net change of energy of the system is zero: ΔE=Ein−Eout=0{\displaystyle \Delta E=E_{\text{in}}-E_{\text{out}}=0} The above states that the system (the mass

energy of a Bloch state with alloying is then ΔEk=ek−Ek{\displaystyle \Delta E_{k}=e_{k}-E_{k}} When the perturbation is fairly localized about the solute

δE[ϕk∗(xk)]=δ⟨ψHF|He|ψHF⟩−δ[∑i=1N∑j=1Nλij(⟨ϕi,ϕj⟩−δij)]=!0,{\displaystyle \delta E[\phi _{k}^{*}(x_{k})]=\delta \left\langle \psi ^{HF}|H^{e}|\psi ^{HF}\right\rangle

δ{\displaystyle \delta } is shown in the figure. When 0<δ<e−1{\displaystyle 0<\delta <e^{-1}}, the linear term eventually dominates and the system is able to reach

goddess Hatmehit. E. A. Wallis Budge writes: At several places in the Delta, e.g. Hermopolis, Lycopolis, and Mendes, the god Pan and a goat were worshipped;

es/2Δ1/2(Δ+es)−1=∫−∞∞e−isteπt+e−πtΔitdt.{\displaystyle e^{s/2}\Delta ^{1/2}\,(\Delta +e^{s})^{-1}=\int _{-\infty }^{\infty }{e^{-ist} \over e^{\pi t}+e^{-\pi t}}\

dndn→dn−1dn+1,ΔE=U=Udd{\displaystyle d^{n}d^{n}\rightarrow d^{n-1}d^{n+1},\quad \Delta E=U=U_{dd}}. In the charge-transfer case, the excitation happens from the

defined in local coordinates by δE(γ)(φ)=∂∂t|t=0E(γ+tφ).{\displaystyle \delta E(\gamma )(\varphi )=\left.{\frac {\partial }{\partial t}}\right|_{t=0}E(\gamma

\tan h/\delta \,(W-W^{*})\right\},\qquad W=\mathrm {cosh} [(1+i)(h-y)/\delta ]e^{i\omega t}} where δ=2ν/ω.{\displaystyle \delta ={\sqrt {2\nu /\omega }}

(hemolysis, etc.) or evidence of infective hepatitis (e.g., hepatitis A, B, C, delta, E, etc.). Hemoglobin acts to transport oxygen which the body receives to

loss tangent can be similarly defined: tan⁡δe=ε″ε′,{\displaystyle \tan \delta _{e}={\frac {\varepsilon ''}{\varepsilon '}},} upon introduction of an effective

wheels. The increase in kinetic energy is: δE=12m(Ukyr)2{\displaystyle \delta E={\frac {1}{2}}m\left({\frac {Uky}{r}}\right)^{2}} The motion will continue

{|J|^{2}}{\hbar }}{\sqrt {\frac {\pi }{\lambda kT}}}\exp \left[{\frac {-(\Delta E+\lambda )^{2}}{4\lambda kT}}\right]} The main difference is now the pre-exponential

ΔE=z2e2/(2Cs){\displaystyle \Delta E=z^{2}e^{2}/(2C_{s})}becomes large compared to the thermal energy per particle ( ΔE≫kBT{\displaystyle \Delta E\gg k_{\rm {B}}T})

ri¯=ΔE−ΔC+ΔI{\displaystyle {\bar {r_{i}}}=\Delta E-\Delta C+\Delta I\,} where, ΔE=Ei¯−∑i≠rqirEr¯{\displaystyle \Delta E={\bar {E_{i}}}-\sum _{i\neq r}q_{ir}{\bar

were measured in 64 contiguous energy bands with an energy resolution (delta E/E) of 0.16. A quadrispherical low-energy proton and electron differential

stress, μ{\displaystyle \mu } is the shear modulus, ΔE{\displaystyle \Delta E} is the energy barrier to dislocation glide, k is the Boltzmann constant

simply the Euclidean distance: ΔECIEUVW=(ΔU∗)2+(ΔV∗)2+(ΔW∗)2{\displaystyle \Delta E_{\text{CIEUVW}}={\sqrt {\left(\Delta U^{*}\right)^{2}+\left(\Delta

ΔEij{\displaystyle \Delta E_{ij}}. Pij=P0exp⁡(−2αrij−ΔEijkBT){\displaystyle P_{ij}=P_{0}\exp \left(-2\alpha r_{ij}-{\frac {\Delta E_{ij}}{k_{B}T}}\right)}

\Delta E} of the energies of states or wave functions related to the wells on either side of the barrier, i.e. Ω=ΔE/ℏ{\displaystyle \Omega =\Delta E/\hbar

magnetic field is given by: ΔE=−μ0H⋅μe=−μ0H⋅(−geμBℏS)=±μ0μBH,{\displaystyle \Delta E=-\mu _{0}\mathbf {H} \cdot {\boldsymbol {\mu }}_{e}=-\mu _{0}\mathbf {H}

φδ(E)=inf{∑i=0∞p(Ai)|E⊆⋃i=0∞Ai,∀i∈N,Ai∈Cδ}.{\displaystyle \varphi _{\delta }(E)=\inf {\biggl \{}\sum _{i=0}^{\infty }p(A_{i})\,{\bigg |}\,E\subseteq

_{\text{Mulliken}}=-\chi _{\text{Mulliken}}=-{\frac {IP+EA}{2}}=\left[{\frac {\delta E[N]}{\delta N}}\right]_{N=N_{0}}.} In recent years,[when?] thermal physics

Synthetic fiber Red 9.4 0.555 0.328 All are Δ E a b ∙ ≤ 2.0 {\displaystyle \Delta E_{ab}^{\,\bullet }\leq 2.0} Gold 41.2 0.446 0.489 Silk Red 12.3 0.565 0

to energy being added or subtracted: Δm=ΔE/c2.{\displaystyle \Delta m=\Delta E/c^{2}.} This form involving changes was the form in which this famous equation

\delta W[e_{\;\mu }^{a}]=\int d^{4}x\;e\langle T_{\;a}^{\mu }\rangle \delta e_{\;\mu }^{a}} in which we denote a mean value with respect to the path

stabilization energy is given by ΔE =πr2γOW(1−|cos⁡θOW|)2{\displaystyle \Delta E\ =\pi r^{2}\gamma _{OW}(1-|\cos {\theta _{OW}}|)^{2}} where r is the particle

to energy being added or subtracted: Δm=ΔE/c2.{\displaystyle \Delta m=\Delta E/c^{2}.} This form involving changes was the form in which this famous equation

_{\text{Mulliken}}=-\chi _{\text{Mulliken}}=-{\frac {IP+EA}{2}}=\left[{\frac {\delta E[N]}{\delta N}}\right]_{N=N_{0}}.} In recent years,[when?] thermal physics

e_{n-1}}, subject to the Jones relations: ei2=δei{\displaystyle e_{i}^{2}=\delta e_{i}} for all 1≤i≤n−1{\displaystyle 1\leq i\leq n-1} eiei+1ei=ei{\displaystyle

The work results in a change in kinetic energy ΔEk=F⋅s.{\displaystyle \Delta E_{k}=F\cdot s.} Differentiating with respect to time, we obtain dEkdt=F⋅dsdt

later at speed v{\displaystyle v} is: ΔEk=W=12m(v2−v02){\displaystyle \Delta E_{k}=W={\frac {1}{2}}m(v^{2}-{v_{0}}^{2})} For a stretched spring fixed

{\displaystyle \Delta E.} This gives rise to a self-capacitance C{\displaystyle C} of the island, defined as: C=e2ΔE.{\displaystyle C={\tfrac {e^{2}}{\Delta E}}.}

Q=2π(EδE){\displaystyle Q=2{\pi }\left({\frac {E}{{\delta }E}}\right)} where δEE{\displaystyle {\frac {{\delta }E}{E}}} is the fraction of energy lost per cycle

E^{\ominus }\left({\ce {X}}\right)} ΔE⊖(X)=E⊖(X)−E⊖(Def){\displaystyle \Delta E^{\ominus }\left({\ce {X}}\right)=E^{\ominus }\left({\ce {X}}\right)-E^{\ominus

energy levels involved in the transition: Δ E = h ν . {\displaystyle \Delta E=h\nu .} This is a direct consequence of the Planck–Einstein relation. Compton

{1-r^{2}}}}{\begin{pmatrix}e^{i\varphi }&-r\cdot e^{-i\delta }\\-r\cdot e^{i\delta }&e^{-i\varphi }\end{pmatrix}}} with δ,φ∈[0;2π]{\displaystyle \delta ,\varphi

as d=ea∧∇ea,δ=ea⌟∇ea{\displaystyle d=e^{a}\wedge \nabla _{e_{a}},\quad \delta =e^{a}\lrcorner \nabla _{e_{a}}}. Then we can define a Dirac-Kähler operator

\Gamma }}:{\frac {1}{\Delta E}}:{\frac {1}{kT}}} where ΔΓ{\displaystyle \Delta \Gamma } is line width and ΔE{\displaystyle \Delta E} is the zero-field state

ΔEΔt≥ℏ2,{\displaystyle \Delta x\Delta p\geq {\frac {\hbar }{2}},\quad \Delta E\Delta t\geq {\frac {\hbar }{2}}\,,} which imply that small intervals in

\Delta E}. The uncertainty principle now allows the interactions of the asymptotic states to occur over a timescale ℏ/ΔE{\displaystyle \hbar /\Delta E}

energy change of trying to flip the spin i: ΔE=2σi∑j∈viziσj{\displaystyle \Delta E=2\sigma _{i}\sum _{j\in viz_{i}}\sigma _{j}} and its magnetization change:

E_{\mathrm {mass} }={\frac {mR_{n}+\rho _{a}c_{p}\left(\delta e\right)g_{a}}{\lambda _{v}\left(m+\gamma \right)}}} where: m = Slope of

compressibility m v = Δ e 1 + e 0 1 Δ σ v ′ {\displaystyle m_{v}={\frac {\Delta e}{1+e_{0}}}{\frac {1}{\Delta \sigma _{v}^{'}}}} derivied from Oedometer

such a change is exp⁡−ΔET{\displaystyle \exp {\frac {-\Delta E}{T}}}, where ΔE{\displaystyle \Delta E} is the change in the evaluation function, and T{\displaystyle

Heisenberg energy-time uncertainty principle: ΔEΔt≥ℏ2,{\displaystyle \Delta E\Delta t\geq {\frac {\hbar }{2}}\,,} (with ΔE and Δt being the energy and

P(k,k')={\frac {2\pi }{\hbar }}|\langle \ k'|H_{1}|k\rangle |^{2}\delta (E_{k'}-E_{k})} where Ek{\displaystyle E_{k}} and Ek′{\displaystyle E_{k'}}

δE[ψ,λ]δψ(x)|ψ=ψλ=0.{\displaystyle \left.{\frac {\delta E[\psi ,\lambda ]}{\delta \psi (x)}}\right|_{\psi =\psi _{\lambda }}=0.} (4)

(100 hp) Oberursel U.I 9-cylinder rotary engine, a licence built Gnome Delta. E.IV Powered by a Siemens-Halske Sh.I. Fuselage circular in cross-section

The overall equation is ΔE(r)=Egap+h28r2(1/me∗+1/mh∗).{\displaystyle \Delta E(r)=E_{\mathrm {gap} }+{\frac {h^{2}}{8r^{2}}}\left(1/m_{\mathrm {e} }^{*}+1/m_{\mathrm

displacement (usually small) meter (m) Dirac delta function Kronecker delta (e.g δij{\displaystyle \delta _{ij}}) ϵ{\displaystyle \epsilon } epsilon permittivity

by N N 0 = e − Δ E ‡ k T {\displaystyle {\frac {N}{N_{0}}}=e^{-{\frac {\Delta E^{\ddagger }}{kT}}}} where k is the Boltzmann constant. Thus some dissociation

e)\times (T(X)\setminus \operatorname {range} e)}\cup (\delta (e(x),e(y)))_{x,y\in X}\cup (\delta (e(x),g))_{x\in X,g\in T(X)\setminus \operatorname {range}

_{w\in W}\varepsilon (w)e^{w(\lambda +\rho )(H)}}{\prod _{\alpha \in \Delta ^{+}}(e^{\alpha (H)/2}-e^{-\alpha (H)/2})}}} where W{\displaystyle W} is the

_{n}^{N_{fs}}{\frac {1}{N_{p}}}\sum _{l}^{N_{p}}\Delta E_{0,n}(\mathbf {R} _{l})f_{0,n}(\mathbf {R} _{l})g\left(E-\Delta E_{0,n}(\mathbf {R} _{l}),\delta \right)}

δ<δE{\displaystyle \delta <\delta _{E}}, where δE{\displaystyle \delta _{E}} is the extinction Damköhler number. For δ>δE{\displaystyle \delta >\delta _{E}} with |γ|<1{\displaystyle

energy given by ΔE(1)=μ0μBℏ⟨g|(L+gS)⋅H|g⟩=gJμ0μBℏ⟨g|J⋅H|g⟩{\displaystyle \Delta E^{(1)}=\mu _{0}{\frac {\mu _{\rm {B}}}{\hbar }}\langle \mathrm {g} |(\mathbf

were measured in 64 contiguous energy bands with an energy resolution (delta E/E) of 0.16. A quadrispherical low-energy proton and electron differential

This change in angle causes a change in the energy ΔEi{\displaystyle \Delta E_{i}} of the system, which can be positive or negative. If negative, the

the quarks. The excited states with energy V(r)+ΔE{\displaystyle V(r)+\Delta E} are exponentially suppressed with time and so the expectation value goes

January 2015. Bernabò, Ferruccio (28 December 1979). "La nuova "Lancia Delta" è la vettura dell'anno". La Stampa. p. 8. Retrieved 23 January 2015. Fenu

E[αβ]γ=gεδE[αβδ][εγ],{\displaystyle E_{[\alpha \beta ]\gamma }=g^{\varepsilon \delta }E_{[\alpha \beta \delta ][\varepsilon \gamma ]},} Eα=gβγE[αβ]γ.{\displaystyle

yields P = Δ E Δ t = 1 2 m ˙ ( v 1 2 − v 2 2 ) . {\displaystyle P={\frac {\Delta E}{\Delta t}}={\tfrac {1}{2}}{\dot {m}}(v_{1}^{2}-v_{2}^{2}).} Substituting

formulated resulting in the equation: ΔE=2β(ar+as)=βNi{\displaystyle \Delta E=2\beta (a_{r}+a_{s})=\beta N_{i}} where β is the Huckel interaction parameter

Since the forward difference operator Δ equals Δ=eD−1{\displaystyle \Delta =e^{D}-1} where D is differentiation with respect to x, we have, from the

{\displaystyle C_{I}} be given by Δ ( e i ) = e i ⊗ e i {\displaystyle \Delta (e_{i})=e_{i}\otimes e_{i}} . Let the counit on C I {\displaystyle C_{I}}

a finite value: ΔE(U)=∑k=1+∞12k[ln⁡(w+2k−c)−ln⁡(w)]<+∞.{\displaystyle \Delta E(U)=\sum _{k=1}^{+\infty }{\frac {1}{2^{k}}}\left[\ln

}|\langle ck'|{e \over m}\mathbf {A} \cdot \mathbf {p} |vk\rangle |^{2}\delta [E_{c}(k')-E_{v}(k)-\hbar \omega ]} =πe22ℏm2A02|⟨ck′|exp⁡(ikp⋅r)e⋅p|vk⟩|2

cost. HEOS 1 was launched on December 5, 1968 from Cape Canaveral with a Delta E-1 rocket. Instruments were a magnetometer, particle detectors and a barium

L ^ j ⋅ S ^ j | n ′ ⟩ E n ′ − E m ′ ] {\displaystyle {\begin{aligned}\delta E=\sum _{m}&{\Biggl [}{\frac {\langle n|\lambda {\hat {\mathbf {L} }}_{i}\cdot

{1}{N}}\sum _{n}\langle n-1|H|n\rangle e^{+ika}=-\Delta e^{ika}{\frac {1}{N}}\sum _{n}1=-\Delta e^{ika}\ .} 1N∑n⟨n−1|n⟩e+ika=Seika1N∑n1=Seika .{\displaystyle

this gives an energy of: ΔED=12⟨A^⟩[F(F+1)−I(I+1)−J(J+1)].{\displaystyle \Delta E_{\text{D}}={\frac {1}{2}}\left\langle {\hat {A}}\right\rangle [F(F+1)-I(I+1)-J(J+1)]

\mathrm {eV} }. Hence, the total energy deviation is ΔE≈0.1eV{\displaystyle \Delta E\approx 0.1\,\mathrm {eV} }. Assuming the dispersion relation for simple

which is 1 when E ( x ) ∈ [ E , E + Δ E ] {\displaystyle E(x)\in [E,E+\Delta E]} and zero otherwise. Because E {\displaystyle E} is on the tail of P (

I Partial success Explorer 29 (GEOS A) 6 November 1965 1965-089A Thor-Delta E Vandenberg AFB Shared Success. SECOR 6 (EGRS-6), 9 June 1966 1966-051B

distribution gives the ratio of the two populations as e−ΔE/kT{\displaystyle e^{-\Delta E/kT}}, where k is the Boltzmann constant and T is the temperature in kelvins

δ E {\displaystyle t_{\perp }\geq {\frac {\pi \hbar }{2\,\delta E}}={\frac {h}{4\,\delta E}}} , where ( δ E ) 2 = ⟨ ψ | H 2 | ψ ⟩ − ( ⟨ ψ | H | ψ ⟩ )

cell, many materials are available with a band gap (ΔEe,g{\displaystyle \Delta E_{e,g}}) well matched to the solar photon spectrum, like Silicon or Gallium

wall is found by multiplying by the velocity: ΔE=v2Ec.{\displaystyle \Delta E=v{\frac {2E}{c}}.} This means that the change in frequency of the light

consolidation Coefficient of compressibility av=ΔeΔσ′{\displaystyle a_{v}={\frac {\Delta e}{\Delta \sigma _{'}}}}. The compressibility of saturated specimens of clay

k=AVϵξ4πη(E−ΔE){\displaystyle k={A \over V}{\epsilon \xi \over 4\pi \eta }(E-\Delta E)} w is the weight of solid particles deposited on the electrode, k the

whereas PMF is positive (similar to redox cell potential Δ E {\displaystyle \Delta E} ). It is worth noting that, as with any transmembrane transport process

t)=E0(p→)+δE(p→,x→,t){\displaystyle E({\vec {p}},{\vec {x}},t)=E_{0}({\vec {p}})+\delta E({\vec {p}},{\vec {x}},t)} is the energy of a quasiparticle of momentum

+1)-s(s+1){\big )}.} We can now say that ΔE=β2(j(j+1)−ℓ(ℓ+1)−s(s+1)),{\displaystyle \Delta E={\frac {\beta }{2}}{\big (}j(j+1)-\ell (\ell +1)-s(s+1){\big )},} where

n{\displaystyle n}. If E⊂F{\displaystyle E\subset F}, ΔE⊂RN{\displaystyle \Delta _{E}\subset \mathbb {R} ^{N}}can be identified with a face of ΔF⊂RM{\displaystyle

t)+∑jΛijψj(r,t),{\displaystyle \mu {\ddot {\psi }}_{i}(\mathbf {r} ,t)=-{\frac {\delta E}{\delta \psi _{i}^{*}(\mathbf {r} ,t)}}+\sum _{j}\Lambda _{ij}\psi _{j}(\mathbf

junction: ΔE=∫12IVdt=∫12IdΦ=∫φ1φ2Icsin⁡φd(Φ0φ2π)=−Φ0Ic2πΔcos⁡φ.{\displaystyle \Delta E=\int _{1}^{2}IV\operatorname {d} \!{t}=\int _{1}^{2}I\operatorname {d}

dxdt=L(x)⋅δEδx(x)+M(x)⋅δSδx(x).{\displaystyle {\frac {dx}{dt}}=L(x)\cdot {\frac {\delta E}{\delta x}}(x)+M(x)\cdot {\frac {\delta S}{\delta x}}(x).} Here: x{\displaystyle

built by the Mihailo Pupin Institute (first CER, then TIM lines) and Iskra Delta (e.g. model 800, derivative of PDP-11/34) continued to evolve through the

adjacent J{\displaystyle J} sub-levels is: ΔEFS=EJ−EJ−1=βLSJ{\displaystyle \Delta E_{\mathrm {FS} }=E_{J}-E_{J-1}=\beta _{LS}J} This is the Landé interval

eg) =−2π J2μ p2 3(54 sin2⁡i − 1) (−eh,eg){\displaystyle {\begin{aligned}\left(\Delta e_{g},\Delta e_{h}\right)\ =\ &-2\pi \ {\frac {J_{2}}{\mu \ p^{2}}}\ {\frac {3}{2}}\left({\frac

heuristically by examining the uncertainty relation ΔEΔt≥ℏ2,{\displaystyle \Delta E\Delta t\geq {\frac {\hbar }{2}},} which virtually allows such violations

quanta of light are absorbed. The formula is: ΔEmol=NAhν{\displaystyle \Delta E_{\text{mol}}=N_{\text{A}}h\nu } where NA is the Avogadro constant. The

distinguishable divided by the mean energy of those features: ΔE/E{\displaystyle \Delta E/E} In the case of EELS the first thing to think of in order to achieve

copulated with a goat. E. A. Wallis Budge writes, At several places in the Delta, e.g. Hermopolis, Lycopolis, and Mendes, the god Pan and a goat were worshipped;

H={e∈E∙∣Δe=0}.{\displaystyle {\mathcal {H}}=\{e\in {\mathcal {E}}^{\bullet }\mid \Delta e=0\}.} Let H:E∙→H{\displaystyle H:{\mathcal {E}}^{\bullet }\to {\mathcal

dz)=μX(dx)⋅δE(x)(dz){\displaystyle \mu _{E,X}(dx,dz)=\mu _{X}(dx)\cdot \delta _{E(x)}(dz)} is the probability distribution on ΩX×ΩZ{\displaystyle \Omega

formula and the relation: ei(θ+Δ)=eiθ×eiΔθ{\displaystyle e^{i(\theta +\Delta )}=e^{i\theta }\times e^{i\Delta \theta }} This leads to the following recurrence

energy difference between adjacent eigenstates is ΔE=ℏω{\displaystyle \Delta E=\hbar \omega }. The ground state can be found by assuming that the lowering

in a magnetic field according to the formula ΔE=−μ→⋅B→{\displaystyle \Delta E=-{\vec {\mu }}\cdot {\vec {B}}}. According to the principles of quantum

{\displaystyle \Delta \rho \simeq {\frac {3\rho }{2E_{\mathrm {F} }}}\Delta E_{\mathrm {F} }.} Inserting this into the above equation for Δμ yields e

which leads to dissipation of part of the energy (ΔEd{\displaystyle \Delta E_{d}}), taking the form of a transition (internal conversion) towards the

coefficient (C⋅m−2⋅K−1) Δ S = p i Δ E i {\displaystyle \Delta S=p_{i}\Delta E_{i}} Seebeck effect β, thermopower (V⋅K−1) E i = − β i j ∂ T ∂ x j {\displaystyle

the temperature. This means that an energy barrier of ΔE{\displaystyle \Delta E} on the energy spectrum is exponentially difficult to overcome. Systems

_{\;ij}^{k}e_{k}} for co-multiplication: Δei=∑j,kνijkej⊗ek{\displaystyle \Delta e_{i}=\sum _{j,k}\nu _{i}^{\;jk}e_{j}\otimes e_{k}} and the antipode:

})}{\partial x^{\prime \delta }}}e_{(b)}^{\delta }(x^{\prime })-{\frac {\partial e_{(b)}^{\beta }(x^{\prime })}{\partial x^{\prime \delta }}}e_{(a)}^{\delta }(x^{\prime

{2\pi }{\hbar }}|\langle \psi _{f}|{\hat {H}}'|\psi _{i}\rangle |^{2}\delta (E_{f}-E_{i}-h\nu )}, where Ei{\displaystyle E_{i}} and Ef{\displaystyle E_{f}}

j{\displaystyle j} is given by the expression: ΔE=Ej−Ei−e2/rij{\displaystyle \Delta E=E_{j}-E_{i}-e^{2}/r_{ij}}. The subtraction of the last term accounts for

radiation or heat) of amount ΔE{\displaystyle \Delta E}, its mass decreased by the amount ΔE/c2{\displaystyle \Delta E/c^{2}}. Hermann Minkowski showed in 1907

the hydrogen atom are given by ΔE(2S1/2)≈−1.122×10−7eV{\displaystyle \Delta E(2\mathrm {S} _{1/2})\approx -1{.}122\times 10^{-7}\,{\text{eV}}} up to

_{L}={\frac {g\cdot u_{N}\cdot B}{\hbar }}} ΔE=ℏ⋅ωL=−g⋅uN⋅B{\displaystyle \Delta E=\hbar \cdot \omega _{L}=-g\cdot u_{N}\cdot B} g{\displaystyle g} is the

mm (0.50 in) Isotta Fraschini-Scotti machine gun in a Caproni-Lanciani Delta E dorsal turret 3 × 7.7 mm (0.303 in) Breda-SAFAT machine guns Bombs: **

AδC{\displaystyle A\;\delta \;C}) (For all E,{\displaystyle E,} AδE{\displaystyle A\;\delta \;E} or Bδ(X∖E){\displaystyle B\;\delta \;(X\setminus E)}) implies AδB{\displaystyle

function: ∫δ(E2−k2−m2)|E,k⟩⟨E,k|dEdk=∫dk2E|k⟩⟨k|.{\displaystyle \int \delta (E^{2}-k^{2}-m^{2})|E,k\rangle \langle E,k|\,dE\,dk=\int {dk \over 2E}|k\rangle

{1}{2}}})} −12ΔE(T3)+ΔF+ΔHform298∘{\displaystyle -\textstyle {\frac {1}{2}}\Delta E(T^{3})+\Delta F+\Delta H_{form298}^{\circ }} For most substances, ΔG°form

for n ≥ 1 are eigenfunctions of Δ. Indeed, Δen=−n2π2L2en.{\displaystyle \Delta e_{n}=-{\frac {n^{2}\pi ^{2}}{L^{2}}}e_{n}.} Moreover, any eigenfunction

T{\displaystyle T} as: Γ=ω2πe−ΔEkT.{\displaystyle \Gamma ={\omega \over 2\pi }e^{{-\Delta E} \over kT}.} Taking Γ≈1 Hz{\displaystyle \Gamma \approx 1{\text{ Hz}}}

surface energies (ΔEc=Ec0−Ec{\displaystyle \Delta E_{c}=E_{c}^{0}-E_{c}}, ΔEs=Es0−Es{\displaystyle \Delta E_{s}=E_{s}^{0}-E_{s}}) are equal, the nucleus

\Delta z} gives ΔExΔy−ΔEyΔx=2L′∂Hz∂t{\displaystyle {\frac {\Delta E_{x}}{\Delta y}}-{\frac {\Delta E_{y}}{\Delta x}}=2L'{\frac {\partial H_{z}}{\partial t}}}

\Delta z} gives ΔExΔy−ΔEyΔx=2L′∂Hz∂t{\displaystyle {\frac {\Delta E_{x}}{\Delta y}}-{\frac {\Delta E_{y}}{\Delta x}}=2L'{\frac {\partial H_{z}}{\partial t}}}

Heisenberg energy-time uncertainty principle: ΔEΔt≥ℏ2,{\displaystyle \Delta E\Delta t\geq {\frac {\hbar }{2}}\,,} (where ΔE and Δt are energy and time

the coherence factors F(Δ,E,E'). F(Δ,E,E′)=12(1±Δ2EE′){\displaystyle F(\Delta ,E,E')={\frac {1}{2}}\left(1\pm {\frac {\Delta ^{2}}{EE'}}\right)} Then, the

original on 22 October 2019. Fenu, Michele (2 February 1980). "Con la Delta e la Nuova Panda un modo diverso di Vivere l'auto". La Stampa (in Italian)

_{<l,m>}\delta _{\sigma '_{l},\sigma '_{m}}J_{lm}\right]}}=e^{-\beta \Delta E}} since Δ E = − ∑ < l , m > J l m ( σ l ′ σ m ′ − σ l σ m ) = − ∑ < l

gain, and the Energy-Time uncertainty relation. ΔEΔt≳ℏ/2{\displaystyle \Delta E\Delta t\gtrsim \hbar /2} The photons, ignoring the uncertainty in frequency

expressed by the exponential integral as δ=−eEi⁡(−1).{\displaystyle \delta =-e\operatorname {Ei} (-1).} Applying the Taylor expansion of Ei{\displaystyle

\Delta M=M_{\Sigma }-M_{\mathrm {nuc} }\,\!} ΔE=ΔMc2{\displaystyle \Delta E=\Delta Mc^{2}\,\!} Nuclear radius r0 ≈ 1.2 fm r=r0A1/3{\displaystyle r=r_{0}A^{1/3}\

operator given above can be expanded as Δ=eD−1=∑k=1∞Dkk!.{\displaystyle \Delta =e^{D}-1=\sum _{k=1}^{\infty }{\frac {D^{k}}{k!}}.} The generalized derivative

\limits _{i}^{{N}_{p}}{\Delta {{E}_{0n}}\left({{\mathbf {x} }_{i}}\right){{f}_{0n}}\left({{\mathbf {x} }_{i}}\right)g\left(E-\Delta {{E}_{0n}}\left({{\mathbf

energy (a) Prove that (ΔE)(N−1,Z)≥(ΔE)(N,Z){\displaystyle (\Delta E)(N-1,Z)\geq (\Delta E)(N,Z)}.[clarification needed] Open as of 1984.[needs update]

}(E)=QHQ+\lim _{\varepsilon \to 0}QHP{1 \over E+i\varepsilon -PHP}PHQ=QHQ+\Delta (E)-i\Gamma (E)/2,\,} whose dimension is equal to the number of interacting

corresponding to different orientations of the nuclear spin ΔE=γℏB{\displaystyle \Delta E=\gamma \hbar B}. The ratio of nuclei in the lower energy state, with spin

U\leq 0,\\\ell _{i}^{\text{new}},&{\text{if }}\Delta U>0{\text{ and }}\delta <e^{-\Delta U/T},\ell _{i}^{\text{old}}\end{cases}}} the algorithm selects

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difference between two colors as: ΔE=(0.5ΔVJ)2+(ΔWX)2+(0.4ΔWZ)2{\displaystyle \Delta E={\sqrt {(0.5\Delta V_{J})^{2}+(\Delta W_{X})^{2}+(0.4\Delta W_{Z})^{2}}}}

A^{\alpha }B_{\beta }{}^{\gamma }C_{\gamma \delta }+D^{\alpha }{}_{\delta }E_{\beta }=T^{\alpha }{}_{\beta }{}_{\delta }} as for an erroneous expression:

nuclei in the medium, losing up to a maximum of ΔEmax=(1−α)E{\displaystyle \Delta E_{max}=(1-\alpha )E} α=(A−1A+1)2{\displaystyle \alpha =\left({\frac

and boundary energy (Doherty, 2005): Δ E≈ρGb2or≈3γs/ds{\displaystyle \Delta \ E\approx \;\rho \;Gb^{2}\;{\rm {or}}\;\approx \;3\gamma _{s}/d_{s}\,\!}

uncertainty time δt=ℏ/2ΔE{\displaystyle \delta t=\hbar /2\Delta E}, where ΔE{\displaystyle \Delta E} is the extra energy that the system needed to make the

\sigma (t)=E\epsilon (t)\implies \sigma _{0}\sin {(\omega t+\delta )}=E\epsilon _{0}\sin {\omega t}\implies \delta =0} Now for the purely viscous

Exactas y Naturales (FCEN), Universidad de Buenos Aires (UBA). Ecorregión Delta e Islas del Paraná[permanent dead link]. (in Spanish) Administración de Parques

given by: Δ=e−ρtS or tS=ln⁡1Δρ=τ22ln⁡1Δ1+τ2τ1≈2τ2ln⁡1Δ,{\displaystyle \Delta =e^{-\rho t_{S}}{\text{ or }}t_{S}={\frac {\ln {\frac {1}{\Delta }}}{\rho

its AC Stark Shift, ΔEAC Stark=3πc2Γμ2ω03δI(r,z){\displaystyle \mathbf {\Delta E} _{\text{AC Stark}}={\frac {3\pi c^{2}\Gamma \mu }{2\omega _{0}^{3}\delta

\Delta E_{C}\,} where the term ℏωq{\displaystyle \hbar \omega _{q}} accounts for phonon emission or absorption and the term ΔEC{\displaystyle \Delta E_{C}}

e^{\Im s\,|\arg u|}\,e^{-R\cos \arg u}\leq \delta \,R^{\Re s}\,e^{\Im s\,\delta }\,e^{-R\cos \delta }=M\,(R\,\cos \delta )^{\Re s}\,e^{-R\cos \delta }} where

as follows: dln⁡kdT=ΔERT2{\displaystyle {\frac {d\ln k}{dT}}={\frac {\Delta E}{RT^{2}}}} Integration of this expression leads to the Arrhenius equation

|Δrπ|ε=2RPΔE/EP{\displaystyle |\Delta r_{\pi }|_{\varepsilon }=2R_{P}\,\Delta E/E_{P}}. It follows that the instrumental energy resolution, given as a

at a voltage just below the gap voltage (|V|=2Δ/e{\displaystyle |V|=2\Delta /e}). A high frequency signal from an astronomical object of interest is focused

with nonuniform spacing between energy levels, denoted ΔE{\displaystyle \Delta E}. In contrast, the quantum harmonic oscillator cannot be used as a qubit

linear (not logarithmic): i=i0nFRTΔE{\displaystyle i=i_{0}{\frac {nF}{RT}}\Delta E} This linear region is called polarization resistance due to its formal

suppressed by a factor ℏωS/ΔE{\displaystyle \hbar \omega _{S}/\Delta E} where ΔE{\displaystyle \Delta E} is the separation between adjacent levels of the orbital

v_{f}^{2}=v_{i}^{2}+2a\Delta x} The work-energy theorem states that ΔEK=W{\displaystyle \Delta E_{K}=W} m2(vf2−vi2)=FΔx{\displaystyle {\frac {m}{2}}\left(v_{f}^{2}-v_{

N_{0}}=\exp({-\Delta E_{\text{act}} \over RT})\,} N is the number of defects in a matrix of N0 self-assembled particles or features and ΔEact{\displaystyle \Delta E_{\text{act}}\

{\frac {d^{2}\psi }{dr^{2}}}+{\frac {L}{r}}{\frac {d\psi }{dr}}=e^{\psi }-\delta e^{-\psi }} It uses a dimensionless potential ψ=eΦkT{\displaystyle \psi ={\frac

}}\left\vert \langle {\vec {k}}'|V|{\vec {k}}\rangle \right\vert ^{2}\delta (E_{{\vec {k}}'}-E_{\vec {k}})}. (1) By inserting a complete set of position

1\colon \ \Delta E(\zeta )=\Delta E_{strain}+\Delta E_{int}} Equation 2: ΔEint=ΔVelst.+ΔEpauli+ΔEoi+ΔEdisp{\displaystyle Equation\ 2\colon \ \Delta E_{int}=\Delta

={\frac {\Delta d}{d_{0}}}={\frac {\Delta \theta }{\theta _{0}}}={\frac {\Delta E}{E_{0}}}={\frac {\Delta t}{t_{0}}}\,} The details of the technique are

of external perturbation the levels would have crossed if the original energy states were degenerate, i.e. ΔE=0{\displaystyle \textstyle \Delta E=0}

^{2}}}eE_{0}\ell _{s}e^{z/\ell _{s}},} ΔE=β21−β2eE0ℓsez/ℓs,{\displaystyle \Delta E={\frac {\beta ^{2}}{1-\beta ^{2}}}eE_{0}\ell _{s}e^{z/\ell _{s}},} where

experiment (for example, from Raman spectroscopy) then ΔE=ℏω{\displaystyle \Delta E=\hbar \omega }, where ω=k/μ{\textstyle \omega ={\sqrt {k/\mu }}} and μ=m/2{\displaystyle

momentum onto the z-axis, and is proportional to ΔE∝−mFBZ{\displaystyle \Delta E\propto -m_{F}B_{Z}} From this relation it can be seen that only the |mF=-1⟩

} So b=−a(E0+Δ−E+)W1−iW2.{\displaystyle b=-{\frac {a\left(E_{0}+\Delta -E_{+}\right)}{W_{1}-iW_{2}}}.} Applying the normalization condition on the

conductance steps should disappear for T≲ΔE/4kB≈4K{\displaystyle T\lesssim \Delta E/4k_{\rm {B}}\approx 4\;\mathrm {K} } (here ∆E is the subband splitting

}(e^{X})={\sum _{\sigma \in W}{\rm {sign}}(\sigma )e^{i\lambda (\sigma X)} \over \delta (e^{X})},} where W is the Weyl group W=NU(T)/T{\displaystyle W=N_{U}(T)/T}

\propto e^{-\beta V(r)}(1+{\mathcal {O}}(e^{-\beta \Delta E(r)})),} where ΔE{\displaystyle \Delta E} is the energy difference between the potential and

d=ea∧∇ea,δ=−ea⌟∇ea{\displaystyle d=e^{a}\wedge \nabla _{e_{a}},\quad \delta =-e^{a}\lrcorner \nabla _{e_{a}}}. Using these definitions, the Dirac-Kähler

2ex]{\frac {dx}{dt}}\Delta j&=\Delta (vj^{2}+p)\\[1.2ex]{\frac {dx}{dt}}\Delta E^{t}&=\Delta (jv(E^{t}+p)).\end{aligned}}\right.} In the steady one dimensional

\mathrm {VB} ,j\in \mathrm {CB} }\sum _{\kappa }w_{\kappa }|p_{ij}|^{2}\delta (E_{\kappa ,j}-E_{\kappa ,i}-\hbar \omega ),} where V is the unit-cell volume

θ(x){\displaystyle \theta (x)\,} is a localized solution of δE=0{\displaystyle \delta E=0\,}. Define θλ(x)=θ(λx){\displaystyle \theta _{\lambda }(x)=\theta (\lambda

difference between the dressed states is: δE=E+−E−=ℏΔ2+nΩ2{\displaystyle \delta E=E_{+}-E_{-}=\hbar {\sqrt {\Delta ^{2}+n\Omega ^{2}}}} Of particular interest

splitting and is given by: ΔE=Eu−Eg=4eRe−R[1+12R+O(R−2)]{\displaystyle \Delta E=E_{u}-E_{g}={\frac {4}{e}}\,R\,e^{-R}\left[\,1+{\frac {1}{2R}}+O\left(R^{-2}\right)\

}{E_{i}-E_{n}+\hbar \omega _{k}+i{\frac {\Gamma _{n}}{2}}}}\right|^{2}\delta (E_{i}-E_{f}+\hbar \omega _{k}-\hbar \omega _{k}^{\prime })} It represents

Laplace–Beltrami operator is given by Δ=e−φ(∂2∂x2+∂2∂y2){\displaystyle \Delta =e^{-\varphi }\left({\frac {\partial ^{2}}{\partial x^{2}}}+{\frac {\partial

to be f∗δ(e)=supa∈Rn1m(Teδ(a))∫Teδ(a)|f(y)|dm(y){\displaystyle f_{*}^{\delta }(e)=\sup _{a\in \mathbf {R} ^{n}}{\frac {1}{m(T_{e}^{\delta }(a))}}\int _{T_{e}^{\delta

; do do_something $x done to the form of: pexec -r alpha bravo charlie delta -e x -o - -c \ 'do_something $x' where the set with the 4 elements of "alpha"

YΔ(Y,X){\displaystyle Y_{\Delta (Y,X)}} or simply YΔ{\displaystyle Y_{\Delta }} (e.g. for σ(Y,X){\displaystyle \sigma (Y,X)} we would have Δ=σ{\displaystyle

lifetime, Δt, of the excited state are related by ΔEΔt⪆ℏ{\displaystyle \Delta E\Delta t\gtrapprox \hbar } This determines the minimum possible line width

can be utilized k(ξ,δ)=e−(|ξ|/δ)21Bδ(x′);{\displaystyle k({\bf {\xi }},\delta )=e^{-(|{\bf {\xi }}|/\delta )^{2}}{\bf {{1}_{B_{\delta }({\bf {x}}')};}}}

hydraulic jump expressed as a head loss is: ΔE=(h1−h0)34h0h1{\displaystyle \Delta E={\frac {(h_{1}-h_{0})^{3}}{4h_{0}h_{1}}}} In the design of a dam the energy

{\begin{aligned}\Delta (k_{\lambda })&=k_{\lambda }\otimes k_{\lambda }\\\Delta (e_{i})&=e_{i}\otimes k_{i}^{-1}+1\otimes e_{i}\\\Delta (f_{i})&=f_{i}\otimes

Prob_{bound}={\frac {1}{1+{\frac {N_{N}S}{P}}*{e}^{-{\frac {\Delta E}{KbT}}}}}} Where, ΔE=ES−ENS{\displaystyle \Delta E=E_{S}-E_{NS}} An important result of this model

{\displaystyle \int _{0}^{\infty }R_{E\ell }^{\ast }(r)R_{E'\ell }(r)r^{2}dr=\delta (E-E')\,.} The radial wave functions defined in the previous section are normalized

P≠0(x−x(P))−6 .{\displaystyle \Theta _{\mathbf {a} }(P)=\alpha ^{-12}\Delta _{E}^{N\mathbf {a} -1}\prod _{\mathbf {a} P=0,P\neq 0}(x-x(P))^{-6}\ .} where

δx can be written: (4)   δx=δE2E2Srel−1{\displaystyle \delta x={\frac {\delta E_{2}}{E_{2}}}S_{rel}^{-1}} where Srel is the relative energy loss factor

Operation Niagara, while Commando Club was used for GDB of the Red River Delta (e.g., Hanoi). Post-Vietnam War GDB Strategic Air Command missions were occasionally

simplification allows us to make the substitution ΔE=E2(t)−E1(t)≡αt,{\displaystyle \Delta E=E_{2}(t)-E_{1}(t)\equiv \alpha t,\,} where E1(t){\displaystyle E_{1}(t)}

{\frac {\delta J}{J}}=0=C_{2}^{J}{\frac {\delta e_{2}}{e_{2}}}+C_{3}^{J}{\frac {\delta e_{3}}{e_{3}}}} There are only two terms because only

{\frac {\delta J}{J}}=C_{e_{1}}^{J}{\frac {\delta e_{1}}{e_{1}}}+C_{e_{2}}^{J}{\frac {\delta e_{2}}{e_{2}}}} δss=Ce1sδe1e1+Ce2sδe2e2=0{\displaystyle

ϵi{\displaystyle \epsilon _{i}} and then D(E)=∑iδ(E−ϵi){\displaystyle D(E)=\sum _{i}\delta (E-\epsilon _{i})}. Stephen Blundell, Magnetism in Condensed Matter (Oxford

Ω 2 ( | e ⟩ ⟨ g | + | g ⟩ ⟨ e | ) . {\displaystyle {\hat {H}}=-\hbar \Delta |e\rangle \langle e|+{\frac {\hbar \Omega }{2}}(|e\rangle \langle g|+|g\rangle

Letter Code word A Alfa B Bravo C Charlie D Delta E Echo F Foxtrot G Golf H Hotel I India J Juliett K Kilo L Lima M Mike N November O Oscar P Papa Q Quebec

so that ΔEγLG=ΔALG+ΔASGcos⁡(θ)=ΔALG−ΔASLcos⁡(θ){\displaystyle {\frac {\Delta E}{\gamma _{LG}}}=\Delta A_{LG}+\Delta A_{SG}\cos(\theta )=\Delta A_{LG}-\Delta

ΔEG=1G∫dr(ga(r)−gb(r))2,{\displaystyle \Delta E_{G}={\frac {1}{G}}\int d{\boldsymbol {r}}\,{\big (}g_{a}({\boldsymbol {r}})-g_{b}({\boldsymbol {r}}){\big

separation characteristics of the spectrometer. The energy resolution, (delta E)/E (internal), was 5%. The mass resolution M/(delta M) was less than or

YΔ(Y,X){\displaystyle Y_{\Delta (Y,X)}} or simply YΔ{\displaystyle Y_{\Delta }} (e.g. for σ(Y,X,b){\displaystyle \sigma (Y,X,b)} we'd have Δ=σ{\displaystyle

by: εϕ=∫SΔEωrfdϕ{\displaystyle \varepsilon _{\phi }=\int _{S}{\frac {\Delta E}{\omega _{rf}}}d\phi } where the integral is taken along a path S{\displaystyle

temperature at which the line strengths are known, ΔE=(E1−E2){\displaystyle \Delta E=(E_{1}-E_{2})\!} is the difference in the lower energy levels involved

particular realization of the disorder, P(E)=δ(E−H(σ)){\displaystyle P(E)=\delta (E-H(\sigma ))} where σ=(σi){\displaystyle \sigma =(\sigma _{i})} refers to

virtually identical. The results of tests that measured the color shift (Delta E) between the exterior and interior surfaces of old and new automotive secondary

polyenes, the energy gap is given as: ΔE=−4βsin⁡π2(n+1){\displaystyle \Delta E=-4\beta \sin {\frac {\pi }{2(n+1)}}} from which a value for β can be obtained

\int _{|\xi |\leq R}\left(1-{\frac {|\xi |^{2}}{R^{2}}}\right)^{\delta }e^{2\pi ix\cdot \xi }\,d\xi } General multiplier m(ξ){\displaystyle m(\xi

over the rational numbers. It has discriminant ΔE=212⋅36{\displaystyle \Delta _{E}=2^{12}\cdot 3^{6}} (and this polynomial can be used to define a global

photon. 6. Hence, c2ΔmΔt=ΔEΔt>h.{\displaystyle c^{2}\Delta m\Delta t=\Delta E\Delta t>h.} The accuracy with which the energy of the photon is measured

QCSE can be approximated to: ΔE≈−24(23π)6e2F2mtot∗L4ℏ2.{\displaystyle \Delta E\approx -24\left({\frac {2}{3\pi }}\right)^{6}{\frac {e^{2}F^{2}m_{tot}^{*}L^{4}}{\hbar

∑sunocc.−∑socc.∑runocc.2(∑a,bcracsbβab)2Er−Es){\displaystyle \Delta E={\Big (}-\sum _{a,b}(q_{a}+q_{b})\beta _{ab}S_{ab}{\Big )}+{\Big (}\sum

with unprecedented accuracy. It was the first payload to be launched by a Delta E rocket. The Italian luxury ocean liner Raffaello arrived in Genoa with

PM=∑A⊆Eβ~(M/A)ΔE−A{\displaystyle P_{M}=\sum _{A\subseteq E}{\tilde {\beta }}(M/A)\Delta _{E-A}} where E{\displaystyle E} is the ground set of the matroid M{\displaystyle

t(e_{x}|f_{y})\leftarrow {\frac {t(e_{x}|f_{y})}{\lambda _{y}}}\sum _{k,i,j}{\frac {\delta (e_{x},e_{i}^{(k)})\delta (f_{y},f_{j}^{(k)})}{\sum _{j'}t(e_{i}^{(k)}|f_{j'}^{(k)})}}}

e−iHNT=[e−iHNδ]T/δ=[eδ2FeδGeδ2F]n{\displaystyle e^{-iH_{N}T}=[e^{-iH_{N}\delta }]^{T/{\delta }}=[e^{{\frac {\delta }{2}}F}e^{{\delta }G}e^{{\frac {\delta }{2}}F}]^{n}}

P=2πℏ∑f|Mfs|2δ(Ei+ℏω−Ef),{\displaystyle P={\frac {2\pi }{\hbar }}\sum _{f}|M_{fs}|^{2}\delta (E_{i}+\hbar \omega -E_{f}),} Mfs=⟨f|eϵ⋅r|i⟩,{\displaystyle M_{fs}=\langle

Almost-idempotent relation: ei2=δei{\displaystyle e_{i}^{2}=\delta e_{i}} Commutation: eiej=ejei{\displaystyle e_{i}e_{j}=e_{j}e_{i}} siej=ejsi{\displaystyle

the standard deviation in fluorescence is ΔE=dEgdx⋅x⋅1−xN{\displaystyle \Delta E={\frac {\mathrm {d} E_{g}}{\mathrm {d} x}}\cdot {\sqrt {x\cdot {\frac {1-x}{N}}}}}

is U0(x,y)=ejknΔe−jk2f[x2+y2]Ui(x,y),{\displaystyle U_{0}(x,y)=e^{jkn\Delta }e^{-j{\frac {k}{2f}}[x^{2}+y^{2}]}U_{i}(x,y),} where f is the focal length

depths. ΔE=E1−E2=(y1+q22gy12)−(y2+q22gy22)=(y2−y1)34y1y2{\displaystyle \Delta E=E_{1}-E_{2}=\left(y_{1}+{\frac {q^{2}}{2gy_{1}^{2}}}\right)-\left(y_{2}+{\frac

generated can be expressed by the equation ΔE=mg(h1−h2){\displaystyle \Delta E=mg(h_{1}-h_{2})} where E is the total amount of energy generated and h1

{\displaystyle \partial _{t}e=De_{0}\nabla ^{2}\left({\frac {\delta F}{\delta e}}\right)-{\mathbf {\nabla } }\cdot {\mathbf {q} }_{e}(\mathbf {r} ,t).}

concentration of enzyme e1{\displaystyle e_{1}} by an amount δe1{\displaystyle \delta e_{1}}. This will cause the steady state flux and concentration of S{\displaystyle

another on the Saskatchewan River 25 kilometres (16 mi) upstream of the delta (E.B. Campbell Dam, Saskatchewan). The Grand Rapids Dam raised the surface

34u2){\displaystyle ET_{o}={\frac {0.408\Delta (R_{n}-G)+{\frac {900}{T}}\gamma u_{2}\delta e}{\Delta +\gamma (1+0.34u_{2})}}} ET0 = Potential evapotranspiration, Water

resolution r is approximately: r≈dΔEeU{\displaystyle r\approx {\frac {d\,\Delta \,E}{e\,U}}} In the equation, d is the distance between the specimen and the

on the Donskoy plantation, models of boats used for fishing in the Don delta (e.g.: kayak, kayuk, baida, oak, boat, etc.) as well as related items such

− k s y n R {\displaystyle g_{s,2}={\dfrac {\Delta E_{s,1}}{\Delta E_{s,2}}}*{\dfrac {-k_{syn}R}{\Delta E_{s,1}-k_{syn}R}}} The excitation pathway synaptic

path and the amount of energy deposited in each voxel, ΔEh{\displaystyle \Delta E_{h}}, depends on this and the voxel's RSP, xj{\displaystyle x_{j}}. The

\mathbb {C} }, consider the function ΔE(z,s)−s(1−s)E(z,s){\displaystyle \Delta E(z,s)-s(1-s)E(z,s)}. By explicitly calculating the Fourier expansion of

extinguish, given by δE=e[(1−γ)−(1−γ)2+0.26(1−γ)3+0.055(1−γ)4]{\displaystyle \delta _{E}=e\left[(1-\gamma )-(1-\gamma )^{2}+0.26(1-\gamma )^{3}+0.055(1-\gamma

momentum exchange throughout the encounter: ΔE=|Ei−Es|=ℏω{\displaystyle \Delta E=|E_{i}-E_{s}|=\hbar \omega } ΔK=ki(sin⁡θi)−ks(sin⁡θs)=G+q{\displaystyle

range 15 keV - 10 MeV, with an energy resolution of 2.0 keV @ 1.0 MeV (E/delta E = 500). The third US Small Astronomy Satellite (SAS-3) was launched on

{\displaystyle \zeta _{2}'={\frac {3}{8}}-{\frac {1}{8}}e^{-2y/\delta }-e^{-y/\delta }\left[\sin {\frac {y}{\delta }}+{\frac {1}{4}}\cos {\frac

δJ1J1=0{\displaystyle C_{e_{2}}^{J_{1}}{\frac {\delta e_{2}}{e_{2}}}+C_{e_{3}}^{J_{1}}{\frac {\delta e_{3}}{e_{3}}}={\frac {\delta J_{1}}{J_{1}}}=0} Because

{u}}_{i}\delta u_{i}\,d\Omega dx_{3}+\int _{\Omega }\int _{-h/2}^{h/2}\sigma _{ij}\delta E_{ij}\,d\Omega dx_{3}+\int _{\Omega }\int _{-h/2}^{h/2}p_{i}\delta u_{i}\

}\sum _{\mathbf {k} }{\frac {f_{\mathbf {k} -\mathbf {q} }-f_{\mathbf {k} }}{\hbar (\omega +i\delta )+E_{\mathbf {k} -\mathbf {q} }-E_{\mathbf {k} }}}.}

suo porto alla Jugoslavia. La Jugoslavia pretende il Porto Baross e il Delta e si oppone all'annessione della città che deve restare libera e indipendente

X′){\displaystyle X_{\Delta \left(X,X'\right)}} or XΔ{\displaystyle X_{\Delta }} (e.g. for σ(X,X′){\displaystyle \sigma \left(X,X'\right)} we'd have Δ=σ{\displaystyle

non-profit organization in form of a registered association Rewilding Oder Delta e.V. has been established and registered in Germany in 2019 in order to facilitate

years. In addition to conceiving the L,a,b color scale and its companion Delta E (color difference) scale, he authored the textbook, The Measurement of

{\langle } {f}|{e}}^{-i\mathbf {q} \cdot \mathbf {r} }|i\rangle |^{2}\delta (E_{i}+E_{f}+\hbar \omega )} where q = kf - ki is the momentum transfer and

activation energy: ln⁡A=ln⁡A0+αΔE0{\displaystyle \ln A=\ln A_{0}+\alpha \Delta E_{0}} Meyer-Neldel rule (MNR) : primarily used in materials science and

action invariant are δeμa=12MPϵ¯γaψμ,        δψμ=MPDμϵ,{\displaystyle \delta e_{\mu }^{a}={\frac {1}{2M_{P}}}{\bar {\epsilon }}\gamma ^{a}\psi _{\mu }

(Arthur), Defiance (CC) St. John, Defiance (CC, E&R union) Lytton Zion, Delta (E&R) Trinity, Elliston (E&R) St. John's, Elmore (E&R) First, Findlay (E&R)

"Refrene yjesh", Poezi, Shtëpia botuese "Fahri Fazliu"- Kastriot, 2013 "Te delta e mjellmave", Poezi, Shtëpia botuese "Fahri Fazliu", Kastriot- 2013 "Rinjohja"

HDR10, HDR10+, HLG DOLBY VISION, HDR10, HDR10+, HLG None Colour Gamut - Delta E<2, DCI-P3 93% DCI-P3 93% NTSC 120% DCI-P3 93% Sound Output 20W (Y1S)/24W

e−tδ[etδG1,etδG2],{\displaystyle [G_{1},G_{2}]\;{\overset {?}{=}}\;e^{-t\delta }[e^{t\delta }G_{1},e^{t\delta }G_{2}],} and differentiate the rhs of this

within the range 0.4 to 1.0 mm2 (0.0016 sq in)-sr and the energy bandwidth, delta E/E, was 3%. The objective of this investigation was to study the three-dimensional

G=(V,E){\displaystyle G=(V,E)} is a graph and δ:E→R|E|{\displaystyle \delta :E\rightarrow \mathbb {R} ^{|E|}} is an assignment of distances onto the edges

UL):=ker⁡(N)/im(Δ)=EL/K/ULσ−1{\displaystyle H^{-1}(G,U_{L}):=\ker(N)/\mathrm {im} (\Delta )=E_{L/K}/U_{L}^{\sigma -1}} of the group EL/K={E∈UL|N(E)=1}{\displaystyle

Y_{t}=\alpha +\sum _{i=0}^{4}m_{i}\Delta M_{t-1}+\sum _{i=0}^{4}e_{i}\Delta E_{t-1}+\sum _{i=0}^{4}z_{i}\Delta Z_{t-1}} (2) where α is a constant; Y

{\phi } _{\mathbb {\gamma } }(t_{n},\mathbf {z} _{n};\delta )=\int _{0}^{\delta }e^{\mathbf {f} _{\mathbf {x} }(t_{n},\mathbf {y} _{n})(\delta -u)}(\mathbf

Sije˙kk=(Sijδkl)δekl{\displaystyle S_{ij}{\dot {e}}_{kk}=(S_{ij}\delta _{kl})\delta e_{kl}}, the transformation can further correct for the absence of the term

well-known one of Kohn-Sham DFT δEHxc[n]δn(r)=vHxc(r){\displaystyle {\frac {\delta E_{\rm {Hxc}}[n]}{\delta n(\mathbf {r} )}}=v_{\rm {Hxc}}(\mathbf {r} )}

}{\frac {dE}{E}}\;\rho _{\Omega }(E),\quad \rho _{\Omega }(E)=\sum _{i}\delta (E-e_{i})|\langle i|V|\Omega \rangle |^{2}\geq 0} where the sum runs over

Troop (Annihilators) B Troop (Banshee) C Troop (Condors) D Troop (Dirty Delta) E Troop (Iron Horse) F Troop (Firehawk) 96th Aviation Support Battalion (Troubleshooters)